how to merge two columns to one column with the repeating word on column2 as a header
up vote
0
down vote
favorite
1
i've been trying to figure this for a couple of hours now, here's what i need
my table:
- 161.226.252.55 NY
- 171.226.252.60 NY
- 131.226.252.50 NY
- 150.178.157.16 LA
- 162.163.137.23 LA
- 142.163.137.27 WY
- 182.163.137.22 NL
desired output:
- NY
- 161.226.252.55
- 171.226.252.60
- 131.226.252.50
- LA
- 150.178.157.16
- and so on...
sorry for the bad format, it's my first question, thanks
bash
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
asked Nov 22 at 11:38
locutos
31
add a comment |
up vote
0
down vote
favorite
1
i've been trying to figure this for a couple of hours now, here's what i need
my table:
- 161.226.252.55 NY
- 171.226.252.60 NY
- 131.226.252.50 NY
- 150.178.157.16 LA
- 162.163.137.23 LA
- 142.163.137.27 WY
- 182.163.137.22 NL
desired output:
- NY
- 161.226.252.55
- 171.226.252.60
- 131.226.252.50
- LA
- 150.178.157.16
- and so on...
sorry for the bad format, it's my first question, thanks
bash
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
asked Nov 22 at 11:38
locutos
31
Welcome to SO. Please provide a Minimal, Complete, and Verifiable example. Show us the code for your latest attempt and where you got stuck. and explain why the result is not what you expected. Edit your question to include the code, please don't add it in a comment, as it will probably be unreadable. stackoverflow.com/help/mcve
– Dragonthoughts
Nov 22 at 11:54
i tried various grep/sort/gawk/awk, the list is great, i'm stuck in the part that brings the duplicate word from column 2 and sorts beneath it the matching rows
– locutos
Nov 22 at 11:59
1
Please show us your code, if you would like assistance.
– Dragonthoughts
Nov 22 at 12:00
add a comment |
up vote
0
down vote
favorite
1
up vote
0
down vote
favorite
1
1
i've been trying to figure this for a couple of hours now, here's what i need
my table:
- 161.226.252.55 NY
- 171.226.252.60 NY
- 131.226.252.50 NY
- 150.178.157.16 LA
- 162.163.137.23 LA
- 142.163.137.27 WY
- 182.163.137.22 NL
desired output:
- NY
- 161.226.252.55
- 171.226.252.60
- 131.226.252.50
- LA
- 150.178.157.16
- and so on...
sorry for the bad format, it's my first question, thanks
bash
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
asked Nov 22 at 11:38
locutos
31
i've been trying to figure this for a couple of hours now, here's what i need
my table:
- 161.226.252.55 NY
- 171.226.252.60 NY
- 131.226.252.50 NY
- 150.178.157.16 LA
- 162.163.137.23 LA
- 142.163.137.27 WY
- 182.163.137.22 NL
desired output:
- NY
- 161.226.252.55
- 171.226.252.60
- 131.226.252.50
- LA
- 150.178.157.16
- and so on...
sorry for the bad format, it's my first question, thanks
bash
bash
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
asked Nov 22 at 11:38
locutos
31
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
asked Nov 22 at 11:38
locutos
31
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
edited Nov 22 at 15:33
RavinderSingh13
25.1k41437
25.1k41437
asked Nov 22 at 11:38
locutos
31
asked Nov 22 at 11:38
locutos
31
asked Nov 22 at 11:38
locutos
31
31
Welcome to SO. Please provide a Minimal, Complete, and Verifiable example. Show us the code for your latest attempt and where you got stuck. and explain why the result is not what you expected. Edit your question to include the code, please don't add it in a comment, as it will probably be unreadable. stackoverflow.com/help/mcve
– Dragonthoughts
Nov 22 at 11:54
i tried various grep/sort/gawk/awk, the list is great, i'm stuck in the part that brings the duplicate word from column 2 and sorts beneath it the matching rows
– locutos
Nov 22 at 11:59
1
Please show us your code, if you would like assistance.
– Dragonthoughts
Nov 22 at 12:00
add a comment |
Welcome to SO. Please provide a Minimal, Complete, and Verifiable example. Show us the code for your latest attempt and where you got stuck. and explain why the result is not what you expected. Edit your question to include the code, please don't add it in a comment, as it will probably be unreadable. stackoverflow.com/help/mcve
– Dragonthoughts
Nov 22 at 11:54
i tried various grep/sort/gawk/awk, the list is great, i'm stuck in the part that brings the duplicate word from column 2 and sorts beneath it the matching rows
– locutos
Nov 22 at 11:59
1
Please show us your code, if you would like assistance.
– Dragonthoughts
Nov 22 at 12:00
Welcome to SO. Please provide a Minimal, Complete, and Verifiable example. Show us the code for your latest attempt and where you got stuck. and explain why the result is not what you expected. Edit your question to include the code, please don't add it in a comment, as it will probably be unreadable. stackoverflow.com/help/mcve
– Dragonthoughts
Nov 22 at 11:54
Welcome to SO. Please provide a Minimal, Complete, and Verifiable example. Show us the code for your latest attempt and where you got stuck. and explain why the result is not what you expected. Edit your question to include the code, please don't add it in a comment, as it will probably be unreadable. stackoverflow.com/help/mcve
– Dragonthoughts
Nov 22 at 11:54
i tried various grep/sort/gawk/awk, the list is great, i'm stuck in the part that brings the duplicate word from column 2 and sorts beneath it the matching rows
– locutos
Nov 22 at 11:59
i tried various grep/sort/gawk/awk, the list is great, i'm stuck in the part that brings the duplicate word from column 2 and sorts beneath it the matching rows
– locutos
Nov 22 at 11:59
1
1
Please show us your code, if you would like assistance.
– Dragonthoughts
Nov 22 at 12:00
Please show us your code, if you would like assistance.
– Dragonthoughts
Nov 22 at 12:00
add a comment |
3 Answers
3
active
oldest
votes
up vote
0
down vote
accepted
AWK solution using associative array:
awk '{ ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table
Output:
WY
142.163.137.27
NL
182.163.137.22
LA
150.178.157.16
162.163.137.23
NY
161.226.252.55
171.226.252.60
131.226.252.50
In case You need order as in Your provided output:
awk '!ips[$2] { ipso[++order]=$2; } { ips[$2]=ips[$2] $1 RS; } END { for (i=1;i<=order;i++) printf("%s%s%s",ipso[i],RS,ips[ipso[i]]); }' table
Output:
NY
161.226.252.55
171.226.252.60
131.226.252.50
LA
150.178.157.16
162.163.137.23
WY
142.163.137.27
NL
182.163.137.22
answered Nov 22 at 12:17
Kubator
5579
thanks a lot for the reply, it worked. my bad but i forgot to mention that my columns has titles, and it shows up above the location, how can i remove them and only them?
– locutos
Nov 22 at 12:26
in case you have one header just add condition NR>1. Like: awk ' NR>1 { ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table_headers
– Kubator
Nov 22 at 12:50
add a comment |
up vote
0
down vote
You said you tried gawk/awk, you can create an array, in fact, a hashtable in awk, the key is your 2nd column. The values are those ips. When you put value in it, you check if there is value with that key, if true, append to the existing value. Finally, you can loop through the array, print the keys and values out, it should be in your desired format.
answered Nov 22 at 12:14
Kent
143k25152213
1
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
– hivert
Nov 22 at 14:05
@hivert this is not a comment. it is exactly an answer to the question, even if it doesn't contain any codes. It explainshow to merge two columns to one column with the repeating word on column2 as a header
– Kent
Nov 22 at 14:16
add a comment |
up vote
0
down vote
Could you please try following, it will give you output in same order in which ids are present in Input_file then try following.
awk '
!a[$NF]++{
b[++count]=$NF
}
{
c[$NF]=c[$NF]?c[$NF] ORS $1:$1
}
END{
for(i=1;i<=count;i++){
print b[i] ORS c[b[i]]
}
}' Input_file
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
AWK solution using associative array:
awk '{ ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table
Output:
WY
142.163.137.27
NL
182.163.137.22
LA
150.178.157.16
162.163.137.23
NY
161.226.252.55
171.226.252.60
131.226.252.50
In case You need order as in Your provided output:
awk '!ips[$2] { ipso[++order]=$2; } { ips[$2]=ips[$2] $1 RS; } END { for (i=1;i<=order;i++) printf("%s%s%s",ipso[i],RS,ips[ipso[i]]); }' table
Output:
NY
161.226.252.55
171.226.252.60
131.226.252.50
LA
150.178.157.16
162.163.137.23
WY
142.163.137.27
NL
182.163.137.22
answered Nov 22 at 12:17
Kubator
5579
thanks a lot for the reply, it worked. my bad but i forgot to mention that my columns has titles, and it shows up above the location, how can i remove them and only them?
– locutos
Nov 22 at 12:26
in case you have one header just add condition NR>1. Like: awk ' NR>1 { ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table_headers
– Kubator
Nov 22 at 12:50
add a comment |
up vote
0
down vote
accepted
AWK solution using associative array:
awk '{ ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table
Output:
WY
142.163.137.27
NL
182.163.137.22
LA
150.178.157.16
162.163.137.23
NY
161.226.252.55
171.226.252.60
131.226.252.50
In case You need order as in Your provided output:
awk '!ips[$2] { ipso[++order]=$2; } { ips[$2]=ips[$2] $1 RS; } END { for (i=1;i<=order;i++) printf("%s%s%s",ipso[i],RS,ips[ipso[i]]); }' table
Output:
NY
161.226.252.55
171.226.252.60
131.226.252.50
LA
150.178.157.16
162.163.137.23
WY
142.163.137.27
NL
182.163.137.22
answered Nov 22 at 12:17
Kubator
5579
thanks a lot for the reply, it worked. my bad but i forgot to mention that my columns has titles, and it shows up above the location, how can i remove them and only them?
– locutos
Nov 22 at 12:26
in case you have one header just add condition NR>1. Like: awk ' NR>1 { ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table_headers
– Kubator
Nov 22 at 12:50
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
AWK solution using associative array:
awk '{ ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table
Output:
WY
142.163.137.27
NL
182.163.137.22
LA
150.178.157.16
162.163.137.23
NY
161.226.252.55
171.226.252.60
131.226.252.50
In case You need order as in Your provided output:
awk '!ips[$2] { ipso[++order]=$2; } { ips[$2]=ips[$2] $1 RS; } END { for (i=1;i<=order;i++) printf("%s%s%s",ipso[i],RS,ips[ipso[i]]); }' table
Output:
NY
161.226.252.55
171.226.252.60
131.226.252.50
LA
150.178.157.16
162.163.137.23
WY
142.163.137.27
NL
182.163.137.22
answered Nov 22 at 12:17
Kubator
5579
AWK solution using associative array:
awk '{ ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table
Output:
WY
142.163.137.27
NL
182.163.137.22
LA
150.178.157.16
162.163.137.23
NY
161.226.252.55
171.226.252.60
131.226.252.50
In case You need order as in Your provided output:
awk '!ips[$2] { ipso[++order]=$2; } { ips[$2]=ips[$2] $1 RS; } END { for (i=1;i<=order;i++) printf("%s%s%s",ipso[i],RS,ips[ipso[i]]); }' table
Output:
NY
161.226.252.55
171.226.252.60
131.226.252.50
LA
150.178.157.16
162.163.137.23
WY
142.163.137.27
NL
182.163.137.22
answered Nov 22 at 12:17
Kubator
5579
edited Nov 22 at 13:40
answered Nov 22 at 12:17
Kubator
5579
answered Nov 22 at 12:17
Kubator
5579
answered Nov 22 at 12:17
Kubator
5579
5579
thanks a lot for the reply, it worked. my bad but i forgot to mention that my columns has titles, and it shows up above the location, how can i remove them and only them?
– locutos
Nov 22 at 12:26
in case you have one header just add condition NR>1. Like: awk ' NR>1 { ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table_headers
– Kubator
Nov 22 at 12:50
add a comment |
thanks a lot for the reply, it worked. my bad but i forgot to mention that my columns has titles, and it shows up above the location, how can i remove them and only them?
– locutos
Nov 22 at 12:26
in case you have one header just add condition NR>1. Like: awk ' NR>1 { ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table_headers
– Kubator
Nov 22 at 12:50
thanks a lot for the reply, it worked. my bad but i forgot to mention that my columns has titles, and it shows up above the location, how can i remove them and only them?
– locutos
Nov 22 at 12:26
thanks a lot for the reply, it worked. my bad but i forgot to mention that my columns has titles, and it shows up above the location, how can i remove them and only them?
– locutos
Nov 22 at 12:26
in case you have one header just add condition NR>1. Like: awk ' NR>1 { ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table_headers
– Kubator
Nov 22 at 12:50
in case you have one header just add condition NR>1. Like: awk ' NR>1 { ips[$2]=ips[$2] $1 RS; } END { for ( i in ips ) printf("%s%s%s",i,RS,ips[i]); }' table_headers
– Kubator
Nov 22 at 12:50
add a comment |
up vote
0
down vote
You said you tried gawk/awk, you can create an array, in fact, a hashtable in awk, the key is your 2nd column. The values are those ips. When you put value in it, you check if there is value with that key, if true, append to the existing value. Finally, you can loop through the array, print the keys and values out, it should be in your desired format.
answered Nov 22 at 12:14
Kent
143k25152213
1
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
– hivert
Nov 22 at 14:05
@hivert this is not a comment. it is exactly an answer to the question, even if it doesn't contain any codes. It explainshow to merge two columns to one column with the repeating word on column2 as a header
– Kent
Nov 22 at 14:16
add a comment |
up vote
0
down vote
You said you tried gawk/awk, you can create an array, in fact, a hashtable in awk, the key is your 2nd column. The values are those ips. When you put value in it, you check if there is value with that key, if true, append to the existing value. Finally, you can loop through the array, print the keys and values out, it should be in your desired format.
answered Nov 22 at 12:14
Kent
143k25152213
1
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
– hivert
Nov 22 at 14:05
@hivert this is not a comment. it is exactly an answer to the question, even if it doesn't contain any codes. It explainshow to merge two columns to one column with the repeating word on column2 as a header
– Kent
Nov 22 at 14:16
add a comment |
up vote
0
down vote
up vote
0
down vote
You said you tried gawk/awk, you can create an array, in fact, a hashtable in awk, the key is your 2nd column. The values are those ips. When you put value in it, you check if there is value with that key, if true, append to the existing value. Finally, you can loop through the array, print the keys and values out, it should be in your desired format.
answered Nov 22 at 12:14
Kent
143k25152213
You said you tried gawk/awk, you can create an array, in fact, a hashtable in awk, the key is your 2nd column. The values are those ips. When you put value in it, you check if there is value with that key, if true, append to the existing value. Finally, you can loop through the array, print the keys and values out, it should be in your desired format.
answered Nov 22 at 12:14
Kent
143k25152213
answered Nov 22 at 12:14
Kent
143k25152213
answered Nov 22 at 12:14
Kent
143k25152213
answered Nov 22 at 12:14
Kent
143k25152213
143k25152213
1
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
– hivert
Nov 22 at 14:05
@hivert this is not a comment. it is exactly an answer to the question, even if it doesn't contain any codes. It explainshow to merge two columns to one column with the repeating word on column2 as a header
– Kent
Nov 22 at 14:16
add a comment |
1
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
– hivert
Nov 22 at 14:05
@hivert this is not a comment. it is exactly an answer to the question, even if it doesn't contain any codes. It explainshow to merge two columns to one column with the repeating word on column2 as a header
– Kent
Nov 22 at 14:16
1
1
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
– hivert
Nov 22 at 14:05
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post. - From Review
– hivert
Nov 22 at 14:05
@hivert this is not a comment. it is exactly an answer to the question, even if it doesn't contain any codes. It explains
how to merge two columns to one column with the repeating word on column2 as a header– Kent
Nov 22 at 14:16
@hivert this is not a comment. it is exactly an answer to the question, even if it doesn't contain any codes. It explains
how to merge two columns to one column with the repeating word on column2 as a header– Kent
Nov 22 at 14:16
add a comment |
up vote
0
down vote
Could you please try following, it will give you output in same order in which ids are present in Input_file then try following.
awk '
!a[$NF]++{
b[++count]=$NF
}
{
c[$NF]=c[$NF]?c[$NF] ORS $1:$1
}
END{
for(i=1;i<=count;i++){
print b[i] ORS c[b[i]]
}
}' Input_file
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
add a comment |
up vote
0
down vote
Could you please try following, it will give you output in same order in which ids are present in Input_file then try following.
awk '
!a[$NF]++{
b[++count]=$NF
}
{
c[$NF]=c[$NF]?c[$NF] ORS $1:$1
}
END{
for(i=1;i<=count;i++){
print b[i] ORS c[b[i]]
}
}' Input_file
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
add a comment |
up vote
0
down vote
up vote
0
down vote
Could you please try following, it will give you output in same order in which ids are present in Input_file then try following.
awk '
!a[$NF]++{
b[++count]=$NF
}
{
c[$NF]=c[$NF]?c[$NF] ORS $1:$1
}
END{
for(i=1;i<=count;i++){
print b[i] ORS c[b[i]]
}
}' Input_file
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
Could you please try following, it will give you output in same order in which ids are present in Input_file then try following.
awk '
!a[$NF]++{
b[++count]=$NF
}
{
c[$NF]=c[$NF]?c[$NF] ORS $1:$1
}
END{
for(i=1;i<=count;i++){
print b[i] ORS c[b[i]]
}
}' Input_file
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
answered Nov 22 at 13:11
RavinderSingh13
25.1k41437
25.1k41437
add a comment |
add a comment |
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Welcome to SO. Please provide a Minimal, Complete, and Verifiable example. Show us the code for your latest attempt and where you got stuck. and explain why the result is not what you expected. Edit your question to include the code, please don't add it in a comment, as it will probably be unreadable. stackoverflow.com/help/mcve
– Dragonthoughts
Nov 22 at 11:54
i tried various grep/sort/gawk/awk, the list is great, i'm stuck in the part that brings the duplicate word from column 2 and sorts beneath it the matching rows
– locutos
Nov 22 at 11:59
1
Please show us your code, if you would like assistance.
– Dragonthoughts
Nov 22 at 12:00