OOP Enquery in PHP [closed]

up vote
-3
down vote

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I have below code

class student implements studentInterface {

    private $amount = null;



    public function amount() {

        echo gettype($this -> amount); // Why object

    }

}

Why I am getting Object type ?

asked Nov 21 at 14:28

abu abu

1,01921439

closed as off-topic by iainn, Rasclatt, yivi, Michael Dodd, eyllanesc Nov 21 at 16:08

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – iainn, Rasclatt, yivi, Michael Dodd, eyllanesc

If this question can be reworded to fit the rules in the help center, please edit the question.

1

Because $this -> amount is object? Fiddle with your code shows what expected 3v4l.org/eKKdO
– u_mulder
Nov 21 at 14:34

Thanks @u_mulder. But I know that $this is a Object. Thanks.
– abu abu
Nov 21 at 14:38

3

The code you've posted doesn't so anything other than declare a class. Unless that class also has a setter method for $amount or a constructor, the property can't ever be anything other than null. If we can't see any more code, there's no help we can give you.
– iainn
Nov 21 at 14:42

add a comment |

up vote
-3
down vote

favorite

I have below code

class student implements studentInterface {

    private $amount = null;



    public function amount() {

        echo gettype($this -> amount); // Why object

    }

}

Why I am getting Object type ?

asked Nov 21 at 14:28

abu abu

1,01921439

closed as off-topic by iainn, Rasclatt, yivi, Michael Dodd, eyllanesc Nov 21 at 16:08

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – iainn, Rasclatt, yivi, Michael Dodd, eyllanesc

If this question can be reworded to fit the rules in the help center, please edit the question.

1

Because $this -> amount is object? Fiddle with your code shows what expected 3v4l.org/eKKdO
– u_mulder
Nov 21 at 14:34

Thanks @u_mulder. But I know that $this is a Object. Thanks.
– abu abu
Nov 21 at 14:38

3

The code you've posted doesn't so anything other than declare a class. Unless that class also has a setter method for $amount or a constructor, the property can't ever be anything other than null. If we can't see any more code, there's no help we can give you.
– iainn
Nov 21 at 14:42

add a comment |

up vote
-3
down vote

favorite

I have below code

class student implements studentInterface {

    private $amount = null;



    public function amount() {

        echo gettype($this -> amount); // Why object

    }

}

Why I am getting Object type ?

asked Nov 21 at 14:28

abu abu

1,01921439

I have below code

class student implements studentInterface {

    private $amount = null;



    public function amount() {

        echo gettype($this -> amount); // Why object

    }

}

Why I am getting Object type ?

php oop

asked Nov 21 at 14:28

abu abu

1,01921439

asked Nov 21 at 14:28

abu abu

1,01921439

asked Nov 21 at 14:28

abu abu

1,01921439

asked Nov 21 at 14:28

abu abu

1,01921439

asked Nov 21 at 14:28

abu abu

1,01921439

closed as off-topic by iainn, Rasclatt, yivi, Michael Dodd, eyllanesc Nov 21 at 16:08

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – iainn, Rasclatt, yivi, Michael Dodd, eyllanesc

If this question can be reworded to fit the rules in the help center, please edit the question.

closed as off-topic by iainn, Rasclatt, yivi, Michael Dodd, eyllanesc Nov 21 at 16:08

This question appears to be off-topic. The users who voted to close gave this specific reason:

"Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example." – iainn, Rasclatt, yivi, Michael Dodd, eyllanesc

If this question can be reworded to fit the rules in the help center, please edit the question.

1

Because $this -> amount is object? Fiddle with your code shows what expected 3v4l.org/eKKdO
– u_mulder
Nov 21 at 14:34

Thanks @u_mulder. But I know that $this is a Object. Thanks.
– abu abu
Nov 21 at 14:38

3

The code you've posted doesn't so anything other than declare a class. Unless that class also has a setter method for $amount or a constructor, the property can't ever be anything other than null. If we can't see any more code, there's no help we can give you.
– iainn
Nov 21 at 14:42

add a comment |

1

Because $this -> amount is object? Fiddle with your code shows what expected 3v4l.org/eKKdO
– u_mulder
Nov 21 at 14:34

Thanks @u_mulder. But I know that $this is a Object. Thanks.
– abu abu
Nov 21 at 14:38

3

The code you've posted doesn't so anything other than declare a class. Unless that class also has a setter method for $amount or a constructor, the property can't ever be anything other than null. If we can't see any more code, there's no help we can give you.
– iainn
Nov 21 at 14:42

Because $this -> amount is object? Fiddle with your code shows what expected 3v4l.org/eKKdO
– u_mulder
Nov 21 at 14:34

Thanks @u_mulder. But I know that $this is a Object. Thanks.
– abu abu
Nov 21 at 14:38

The code you've posted doesn't so anything other than declare a class. Unless that class also has a setter method for $amount or a constructor, the property can't ever be anything other than null. If we can't see any more code, there's no help we can give you.
– iainn
Nov 21 at 14:42

add a comment |

1 Answer
1

active

oldest

votes

up vote
0
down vote

accepted

You've defined $amount as null. null is untyped so, if you expect something besides "object", you need to call settype($amount, ...) or assign a typed value to $amount.

answered Nov 21 at 15:01

user1361991

581613

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
0
down vote

accepted

You've defined $amount as null. null is untyped so, if you expect something besides "object", you need to call settype($amount, ...) or assign a typed value to $amount.

answered Nov 21 at 15:01

user1361991

581613

add a comment |

up vote
0
down vote

accepted

You've defined $amount as null. null is untyped so, if you expect something besides "object", you need to call settype($amount, ...) or assign a typed value to $amount.

answered Nov 21 at 15:01

user1361991

581613

add a comment |

up vote
0
down vote

accepted

You've defined $amount as null. null is untyped so, if you expect something besides "object", you need to call settype($amount, ...) or assign a typed value to $amount.

answered Nov 21 at 15:01

user1361991

581613

You've defined $amount as null. null is untyped so, if you expect something besides "object", you need to call settype($amount, ...) or assign a typed value to $amount.

answered Nov 21 at 15:01

user1361991

581613

answered Nov 21 at 15:01

user1361991

581613

answered Nov 21 at 15:01

user1361991

581613

answered Nov 21 at 15:01

user1361991

581613

add a comment |

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