Why are the eigenvalues of eig() sorted in ascending order?












2















I'm trying to find eigenvalues of a matrix with eig.
I define the matrix with example data:



A = magic(5)

A =

17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9


and



D = eig(A,'matrix')

D =


65.0000 0 0 0 0

0 -21.2768 0 0 0

0 0 -13.1263 0 0

0 0 0 21.2768 0

0 0 0 0 13.1263


But if I use



C = cov(A)


and get eigenvalues from the covariance matrix, this is the result:



DC = eig(C,'matrix')

DC =


-0.0000 0 0 0 0

0 35.4072 0 0 0

0 0 44.9139 0 0

0 0 0 117.5861 0

0 0 0 0 127.0928


Why are the eigenvalues from the covariance matrix sorted in ascending order?










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  • Related. Duplicate?

    – Luis Mendo
    Nov 27 '18 at 16:03
















2















I'm trying to find eigenvalues of a matrix with eig.
I define the matrix with example data:



A = magic(5)

A =

17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9


and



D = eig(A,'matrix')

D =


65.0000 0 0 0 0

0 -21.2768 0 0 0

0 0 -13.1263 0 0

0 0 0 21.2768 0

0 0 0 0 13.1263


But if I use



C = cov(A)


and get eigenvalues from the covariance matrix, this is the result:



DC = eig(C,'matrix')

DC =


-0.0000 0 0 0 0

0 35.4072 0 0 0

0 0 44.9139 0 0

0 0 0 117.5861 0

0 0 0 0 127.0928


Why are the eigenvalues from the covariance matrix sorted in ascending order?










share|improve this question

























  • Related. Duplicate?

    – Luis Mendo
    Nov 27 '18 at 16:03














2












2








2








I'm trying to find eigenvalues of a matrix with eig.
I define the matrix with example data:



A = magic(5)

A =

17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9


and



D = eig(A,'matrix')

D =


65.0000 0 0 0 0

0 -21.2768 0 0 0

0 0 -13.1263 0 0

0 0 0 21.2768 0

0 0 0 0 13.1263


But if I use



C = cov(A)


and get eigenvalues from the covariance matrix, this is the result:



DC = eig(C,'matrix')

DC =


-0.0000 0 0 0 0

0 35.4072 0 0 0

0 0 44.9139 0 0

0 0 0 117.5861 0

0 0 0 0 127.0928


Why are the eigenvalues from the covariance matrix sorted in ascending order?










share|improve this question
















I'm trying to find eigenvalues of a matrix with eig.
I define the matrix with example data:



A = magic(5)

A =

17 24 1 8 15
23 5 7 14 16
4 6 13 20 22
10 12 19 21 3
11 18 25 2 9


and



D = eig(A,'matrix')

D =


65.0000 0 0 0 0

0 -21.2768 0 0 0

0 0 -13.1263 0 0

0 0 0 21.2768 0

0 0 0 0 13.1263


But if I use



C = cov(A)


and get eigenvalues from the covariance matrix, this is the result:



DC = eig(C,'matrix')

DC =


-0.0000 0 0 0 0

0 35.4072 0 0 0

0 0 44.9139 0 0

0 0 0 117.5861 0

0 0 0 0 127.0928


Why are the eigenvalues from the covariance matrix sorted in ascending order?







matlab matrix linear-algebra pca eigenvalue






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edited Nov 27 '18 at 15:46









Adriaan

12.9k63162




12.9k63162










asked Nov 27 '18 at 15:36









Wanarase Cs SinhashthitaWanarase Cs Sinhashthita

132




132













  • Related. Duplicate?

    – Luis Mendo
    Nov 27 '18 at 16:03



















  • Related. Duplicate?

    – Luis Mendo
    Nov 27 '18 at 16:03

















Related. Duplicate?

– Luis Mendo
Nov 27 '18 at 16:03





Related. Duplicate?

– Luis Mendo
Nov 27 '18 at 16:03












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Sorting is merely a choice of convenience. There's no such thing as a 'real' position of an eigenvector, just as (x,y) is just as valid as (y,x). Since a lot of matrix techniques work on eigenvectors in order of decreasing eigenvalue (i.e. most important first), it makes sense to structure them accordingly.






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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3














    Sorting is merely a choice of convenience. There's no such thing as a 'real' position of an eigenvector, just as (x,y) is just as valid as (y,x). Since a lot of matrix techniques work on eigenvectors in order of decreasing eigenvalue (i.e. most important first), it makes sense to structure them accordingly.






    share|improve this answer




























      3














      Sorting is merely a choice of convenience. There's no such thing as a 'real' position of an eigenvector, just as (x,y) is just as valid as (y,x). Since a lot of matrix techniques work on eigenvectors in order of decreasing eigenvalue (i.e. most important first), it makes sense to structure them accordingly.






      share|improve this answer


























        3












        3








        3







        Sorting is merely a choice of convenience. There's no such thing as a 'real' position of an eigenvector, just as (x,y) is just as valid as (y,x). Since a lot of matrix techniques work on eigenvectors in order of decreasing eigenvalue (i.e. most important first), it makes sense to structure them accordingly.






        share|improve this answer













        Sorting is merely a choice of convenience. There's no such thing as a 'real' position of an eigenvector, just as (x,y) is just as valid as (y,x). Since a lot of matrix techniques work on eigenvectors in order of decreasing eigenvalue (i.e. most important first), it makes sense to structure them accordingly.







        share|improve this answer












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        answered Nov 27 '18 at 15:45









        AdriaanAdriaan

        12.9k63162




        12.9k63162
































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