Simple sql query with 3 tables
Consider the following database with 3 tables:
persons, cars, persons_cars (join table).
Each with the its fields described below:
persons: id, phone, address
cars: id, model, manufacturer
persons_cars: id, id_car, id_person
For current case consider all fields varchar
expect the id
(of course primary and foreign keys).
How would look like a query which returns me the id
of the person who owns multiple cars (at least two) of the same manufacturer. (As manufacturer can be the same e.g. 'volkswagen', 'volvo', 'honda', etc.). Is it possible to do this in one query?
mysql postgresql-9.3
add a comment |
Consider the following database with 3 tables:
persons, cars, persons_cars (join table).
Each with the its fields described below:
persons: id, phone, address
cars: id, model, manufacturer
persons_cars: id, id_car, id_person
For current case consider all fields varchar
expect the id
(of course primary and foreign keys).
How would look like a query which returns me the id
of the person who owns multiple cars (at least two) of the same manufacturer. (As manufacturer can be the same e.g. 'volkswagen', 'volvo', 'honda', etc.). Is it possible to do this in one query?
mysql postgresql-9.3
1
MySQL or PostgreSQL ? Please specify the exact RDBMS you are using.
– Madhur Bhaiya
Nov 26 '18 at 7:14
And go on . Try something. Note also that the id column in the third table serves no purpose (unless (model,manufacturer) is unique
– Strawberry
Nov 26 '18 at 7:17
add a comment |
Consider the following database with 3 tables:
persons, cars, persons_cars (join table).
Each with the its fields described below:
persons: id, phone, address
cars: id, model, manufacturer
persons_cars: id, id_car, id_person
For current case consider all fields varchar
expect the id
(of course primary and foreign keys).
How would look like a query which returns me the id
of the person who owns multiple cars (at least two) of the same manufacturer. (As manufacturer can be the same e.g. 'volkswagen', 'volvo', 'honda', etc.). Is it possible to do this in one query?
mysql postgresql-9.3
Consider the following database with 3 tables:
persons, cars, persons_cars (join table).
Each with the its fields described below:
persons: id, phone, address
cars: id, model, manufacturer
persons_cars: id, id_car, id_person
For current case consider all fields varchar
expect the id
(of course primary and foreign keys).
How would look like a query which returns me the id
of the person who owns multiple cars (at least two) of the same manufacturer. (As manufacturer can be the same e.g. 'volkswagen', 'volvo', 'honda', etc.). Is it possible to do this in one query?
mysql postgresql-9.3
mysql postgresql-9.3
edited Nov 26 '18 at 7:22
Strawberry
26k83149
26k83149
asked Nov 26 '18 at 7:14
han7elhan7el
32
32
1
MySQL or PostgreSQL ? Please specify the exact RDBMS you are using.
– Madhur Bhaiya
Nov 26 '18 at 7:14
And go on . Try something. Note also that the id column in the third table serves no purpose (unless (model,manufacturer) is unique
– Strawberry
Nov 26 '18 at 7:17
add a comment |
1
MySQL or PostgreSQL ? Please specify the exact RDBMS you are using.
– Madhur Bhaiya
Nov 26 '18 at 7:14
And go on . Try something. Note also that the id column in the third table serves no purpose (unless (model,manufacturer) is unique
– Strawberry
Nov 26 '18 at 7:17
1
1
MySQL or PostgreSQL ? Please specify the exact RDBMS you are using.
– Madhur Bhaiya
Nov 26 '18 at 7:14
MySQL or PostgreSQL ? Please specify the exact RDBMS you are using.
– Madhur Bhaiya
Nov 26 '18 at 7:14
And go on . Try something. Note also that the id column in the third table serves no purpose (unless (model,manufacturer) is unique
– Strawberry
Nov 26 '18 at 7:17
And go on . Try something. Note also that the id column in the third table serves no purpose (unless (model,manufacturer) is unique
– Strawberry
Nov 26 '18 at 7:17
add a comment |
1 Answer
1
active
oldest
votes
Here is a simple way to do this. We can aggregate the persons_cars
table by person, and then compare the total manufacturer count against the distinct manufacturer count. If the former be larger than the latter, then we may assume that a duplicate manufacturer exists, i.e. that the person owns two or more cars from a single manufacturer.
SELECT pc.id_person
FROM persons_cars pc
INNER JOIN cars c
ON pc.id_car = c.id
GROUP BY pc.id_person
HAVING COUNT(*) > COUNT(DISTINCT c.manufacturer);
You tagged with both MySQL and Postgres, though this answer should run on either database without any problems.
I did not think about this approach, but it is quite a good one. Thank you!
– han7el
Nov 27 '18 at 10:20
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
Here is a simple way to do this. We can aggregate the persons_cars
table by person, and then compare the total manufacturer count against the distinct manufacturer count. If the former be larger than the latter, then we may assume that a duplicate manufacturer exists, i.e. that the person owns two or more cars from a single manufacturer.
SELECT pc.id_person
FROM persons_cars pc
INNER JOIN cars c
ON pc.id_car = c.id
GROUP BY pc.id_person
HAVING COUNT(*) > COUNT(DISTINCT c.manufacturer);
You tagged with both MySQL and Postgres, though this answer should run on either database without any problems.
I did not think about this approach, but it is quite a good one. Thank you!
– han7el
Nov 27 '18 at 10:20
add a comment |
Here is a simple way to do this. We can aggregate the persons_cars
table by person, and then compare the total manufacturer count against the distinct manufacturer count. If the former be larger than the latter, then we may assume that a duplicate manufacturer exists, i.e. that the person owns two or more cars from a single manufacturer.
SELECT pc.id_person
FROM persons_cars pc
INNER JOIN cars c
ON pc.id_car = c.id
GROUP BY pc.id_person
HAVING COUNT(*) > COUNT(DISTINCT c.manufacturer);
You tagged with both MySQL and Postgres, though this answer should run on either database without any problems.
I did not think about this approach, but it is quite a good one. Thank you!
– han7el
Nov 27 '18 at 10:20
add a comment |
Here is a simple way to do this. We can aggregate the persons_cars
table by person, and then compare the total manufacturer count against the distinct manufacturer count. If the former be larger than the latter, then we may assume that a duplicate manufacturer exists, i.e. that the person owns two or more cars from a single manufacturer.
SELECT pc.id_person
FROM persons_cars pc
INNER JOIN cars c
ON pc.id_car = c.id
GROUP BY pc.id_person
HAVING COUNT(*) > COUNT(DISTINCT c.manufacturer);
You tagged with both MySQL and Postgres, though this answer should run on either database without any problems.
Here is a simple way to do this. We can aggregate the persons_cars
table by person, and then compare the total manufacturer count against the distinct manufacturer count. If the former be larger than the latter, then we may assume that a duplicate manufacturer exists, i.e. that the person owns two or more cars from a single manufacturer.
SELECT pc.id_person
FROM persons_cars pc
INNER JOIN cars c
ON pc.id_car = c.id
GROUP BY pc.id_person
HAVING COUNT(*) > COUNT(DISTINCT c.manufacturer);
You tagged with both MySQL and Postgres, though this answer should run on either database without any problems.
answered Nov 26 '18 at 7:17
Tim BiegeleisenTim Biegeleisen
224k1391143
224k1391143
I did not think about this approach, but it is quite a good one. Thank you!
– han7el
Nov 27 '18 at 10:20
add a comment |
I did not think about this approach, but it is quite a good one. Thank you!
– han7el
Nov 27 '18 at 10:20
I did not think about this approach, but it is quite a good one. Thank you!
– han7el
Nov 27 '18 at 10:20
I did not think about this approach, but it is quite a good one. Thank you!
– han7el
Nov 27 '18 at 10:20
add a comment |
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1
MySQL or PostgreSQL ? Please specify the exact RDBMS you are using.
– Madhur Bhaiya
Nov 26 '18 at 7:14
And go on . Try something. Note also that the id column in the third table serves no purpose (unless (model,manufacturer) is unique
– Strawberry
Nov 26 '18 at 7:17