Function calling same parameter own parameters(Array) Swift
My question so basic.I cant call function with same array parameter as shown in the below.
import UIKit
var myArray = [String]() // <= This line from one class
func myArrayFunc1(arg_myArray: String...) { . //This function from same class with array
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) { //This function from another class
myArrayFunc1(arg_myArray: arg2_myArray) // <= This line gives error
}
My error is :
Cannot convert value of type '[String]' to expected argument type 'String'
arrays swift
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
add a comment |
My question so basic.I cant call function with same array parameter as shown in the below.
import UIKit
var myArray = [String]() // <= This line from one class
func myArrayFunc1(arg_myArray: String...) { . //This function from same class with array
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) { //This function from another class
myArrayFunc1(arg_myArray: arg2_myArray) // <= This line gives error
}
My error is :
Cannot convert value of type '[String]' to expected argument type 'String'
arrays swift
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
Please show the complete code along with the classes which hold the methods.
– Rakesha Shastri
Nov 26 '18 at 7:05
1
Known problem: bugs.swift.org/browse/SR-128
– Gereon
Nov 26 '18 at 7:07
1
Possible duplicate of How to forward functions with variadic parameters?
– Cristik
Nov 26 '18 at 7:47
add a comment |
My question so basic.I cant call function with same array parameter as shown in the below.
import UIKit
var myArray = [String]() // <= This line from one class
func myArrayFunc1(arg_myArray: String...) { . //This function from same class with array
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) { //This function from another class
myArrayFunc1(arg_myArray: arg2_myArray) // <= This line gives error
}
My error is :
Cannot convert value of type '[String]' to expected argument type 'String'
arrays swift
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
My question so basic.I cant call function with same array parameter as shown in the below.
import UIKit
var myArray = [String]() // <= This line from one class
func myArrayFunc1(arg_myArray: String...) { . //This function from same class with array
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) { //This function from another class
myArrayFunc1(arg_myArray: arg2_myArray) // <= This line gives error
}
My error is :
Cannot convert value of type '[String]' to expected argument type 'String'
arrays swift
arrays swift
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
asked Nov 26 '18 at 7:02
Qwe QweQwe Qwe
458
458
Please show the complete code along with the classes which hold the methods.
– Rakesha Shastri
Nov 26 '18 at 7:05
1
Known problem: bugs.swift.org/browse/SR-128
– Gereon
Nov 26 '18 at 7:07
1
Possible duplicate of How to forward functions with variadic parameters?
– Cristik
Nov 26 '18 at 7:47
add a comment |
Please show the complete code along with the classes which hold the methods.
– Rakesha Shastri
Nov 26 '18 at 7:05
1
Known problem: bugs.swift.org/browse/SR-128
– Gereon
Nov 26 '18 at 7:07
1
Possible duplicate of How to forward functions with variadic parameters?
– Cristik
Nov 26 '18 at 7:47
Please show the complete code along with the classes which hold the methods.
– Rakesha Shastri
Nov 26 '18 at 7:05
Please show the complete code along with the classes which hold the methods.
– Rakesha Shastri
Nov 26 '18 at 7:05
1
1
Known problem: bugs.swift.org/browse/SR-128
– Gereon
Nov 26 '18 at 7:07
Known problem: bugs.swift.org/browse/SR-128
– Gereon
Nov 26 '18 at 7:07
1
1
Possible duplicate of How to forward functions with variadic parameters?
– Cristik
Nov 26 '18 at 7:47
Possible duplicate of How to forward functions with variadic parameters?
– Cristik
Nov 26 '18 at 7:47
add a comment |
2 Answers
2
active
oldest
votes
You can't assign arg_myArray as myArray because arg_myArray isn't array of strings but just single string.
If you need to assign new array as myArray replace this:
func myArrayFunc1(arg_myArray: String...) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
with
func myArrayFunc1(arg_myArray: [String]) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: [String]) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
But if you need to just add single string to your string array you can use myArray.append(/* string */) to append new object (in your case string value) to array
func myArrayFunc1(arg_myArray: String) {
myArray.append(arg_myArray)
}
func myArrayFunc2(arg2_myArray: String) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
add a comment |
You can update this line like below.
var myArray: [String] = [String]()
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
2
Although this code might solve the question, a good answer should always explain what the problem was and how this code helps.
– BDL
Nov 26 '18 at 9:19
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can't assign arg_myArray as myArray because arg_myArray isn't array of strings but just single string.
If you need to assign new array as myArray replace this:
func myArrayFunc1(arg_myArray: String...) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
with
func myArrayFunc1(arg_myArray: [String]) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: [String]) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
But if you need to just add single string to your string array you can use myArray.append(/* string */) to append new object (in your case string value) to array
func myArrayFunc1(arg_myArray: String) {
myArray.append(arg_myArray)
}
func myArrayFunc2(arg2_myArray: String) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
add a comment |
You can't assign arg_myArray as myArray because arg_myArray isn't array of strings but just single string.
If you need to assign new array as myArray replace this:
func myArrayFunc1(arg_myArray: String...) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
with
func myArrayFunc1(arg_myArray: [String]) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: [String]) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
But if you need to just add single string to your string array you can use myArray.append(/* string */) to append new object (in your case string value) to array
func myArrayFunc1(arg_myArray: String) {
myArray.append(arg_myArray)
}
func myArrayFunc2(arg2_myArray: String) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
add a comment |
You can't assign arg_myArray as myArray because arg_myArray isn't array of strings but just single string.
If you need to assign new array as myArray replace this:
func myArrayFunc1(arg_myArray: String...) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
with
func myArrayFunc1(arg_myArray: [String]) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: [String]) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
But if you need to just add single string to your string array you can use myArray.append(/* string */) to append new object (in your case string value) to array
func myArrayFunc1(arg_myArray: String) {
myArray.append(arg_myArray)
}
func myArrayFunc2(arg2_myArray: String) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
You can't assign arg_myArray as myArray because arg_myArray isn't array of strings but just single string.
If you need to assign new array as myArray replace this:
func myArrayFunc1(arg_myArray: String...) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: String...) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
with
func myArrayFunc1(arg_myArray: [String]) {
myArray = arg_myArray
}
func myArrayFunc2(arg2_myArray: [String]) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
But if you need to just add single string to your string array you can use myArray.append(/* string */) to append new object (in your case string value) to array
func myArrayFunc1(arg_myArray: String) {
myArray.append(arg_myArray)
}
func myArrayFunc2(arg2_myArray: String) {
myArrayFunc1(arg_myArray: arg2_myArray)
}
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
edited Nov 26 '18 at 7:11
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
answered Nov 26 '18 at 7:05
Robert DreslerRobert Dresler
6,0802626
6,0802626
add a comment |
add a comment |
You can update this line like below.
var myArray: [String] = [String]()
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
2
Although this code might solve the question, a good answer should always explain what the problem was and how this code helps.
– BDL
Nov 26 '18 at 9:19
add a comment |
You can update this line like below.
var myArray: [String] = [String]()
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
2
Although this code might solve the question, a good answer should always explain what the problem was and how this code helps.
– BDL
Nov 26 '18 at 9:19
add a comment |
You can update this line like below.
var myArray: [String] = [String]()
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
You can update this line like below.
var myArray: [String] = [String]()
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
answered Nov 26 '18 at 7:14
ktr kathirktr kathir
912624
912624
2
Although this code might solve the question, a good answer should always explain what the problem was and how this code helps.
– BDL
Nov 26 '18 at 9:19
add a comment |
2
Although this code might solve the question, a good answer should always explain what the problem was and how this code helps.
– BDL
Nov 26 '18 at 9:19
2
2
Although this code might solve the question, a good answer should always explain what the problem was and how this code helps.
– BDL
Nov 26 '18 at 9:19
Although this code might solve the question, a good answer should always explain what the problem was and how this code helps.
– BDL
Nov 26 '18 at 9:19
add a comment |
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Please show the complete code along with the classes which hold the methods.
– Rakesha Shastri
Nov 26 '18 at 7:05
1
Known problem: bugs.swift.org/browse/SR-128
– Gereon
Nov 26 '18 at 7:07
1
Possible duplicate of How to forward functions with variadic parameters?
– Cristik
Nov 26 '18 at 7:47