Looping on a JSON object to check if a given value exists
Here is my JSON Object, i want to know in Angular 6 how can we search in key "name" if a value for example Tennis exist on it.
{
"id":2,
"name":"Sports",
"url":"/sports"
"children":[
{
"id":1,
"name":"Football"
},
{
"id":2,
"name":"Tennis"
},
{
"id":3,
"name":"Soccer"
}
}
Thanks.
javascript json
angular asked Nov 27 '18 at 7:51
Java.netJava.net
479
add a comment |
Here is my JSON Object, i want to know in Angular 6 how can we search in key "name" if a value for example Tennis exist on it.
{
"id":2,
"name":"Sports",
"url":"/sports"
"children":[
{
"id":1,
"name":"Football"
},
{
"id":2,
"name":"Tennis"
},
{
"id":3,
"name":"Soccer"
}
}
Thanks.
javascript json
angular asked Nov 27 '18 at 7:51
Java.netJava.net
479
add a comment |
Here is my JSON Object, i want to know in Angular 6 how can we search in key "name" if a value for example Tennis exist on it.
{
"id":2,
"name":"Sports",
"url":"/sports"
"children":[
{
"id":1,
"name":"Football"
},
{
"id":2,
"name":"Tennis"
},
{
"id":3,
"name":"Soccer"
}
}
Thanks.
javascript json
angular asked Nov 27 '18 at 7:51
Java.netJava.net
479
Here is my JSON Object, i want to know in Angular 6 how can we search in key "name" if a value for example Tennis exist on it.
{
"id":2,
"name":"Sports",
"url":"/sports"
"children":[
{
"id":1,
"name":"Football"
},
{
"id":2,
"name":"Tennis"
},
{
"id":3,
"name":"Soccer"
}
}
Thanks.
javascript json
angular javascript json
angular asked Nov 27 '18 at 7:51
Java.netJava.net
479
asked Nov 27 '18 at 7:51
Java.netJava.net
479
asked Nov 27 '18 at 7:51
Java.netJava.net
479
asked Nov 27 '18 at 7:51
Java.netJava.net
479
asked Nov 27 '18 at 7:51
Java.netJava.net
479
479
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
You can use array.some() to check whether value present,
var result = yurObj.children.some(t=>t.name === "Tennis");
DEMO
var yourObj = {
"id": 2,
"name": "Sports",
"url": "/sports",
"children": [
{
"id": 1,
"name": "Football"
},
{
"id": 2,
"name": "Tennis"
},
{
"id": 3,
"name": "Soccer"
}
]
};
var result = yourObj.children.some(t=>t.name === "Tennis");
console.log(result);answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
is that pratical if i use JSON.stringify() to my JSON object ?
– Java.net
Nov 27 '18 at 7:55
you dont need to use, just check the demo
– Sajeetharan
Nov 27 '18 at 7:55
yourObj.children is not known result in my case is a list i only can map,filter,foreach .. methods to manage lists
– Java.net
Nov 27 '18 at 8:01
i meant yourObj as the one you pasted above
– Sajeetharan
Nov 27 '18 at 8:44
add a comment |
You can use the following Array filter method:
const result = Object.children.filter(item => item.name === 'Tennis')
The result array will contain all elements of children where the name is equal to 'Tennis'.
Hope this helps.
Lloyd
answered Nov 27 '18 at 7:54
LloydLloyd
916
add a comment |
This is super easy using lodash. You can use find or filter methods. find will give you specific value whereas filter will return collection of values matching search criteria.
const result = _.find(yourObj, {name: 'Tennis'});
In case, you need to search within childern of your object, you can also do that so:
const result = _.find(yourObj, function(o) { return o.children.name === 'Tennis' });
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53495009%2flooping-on-a-json-object-to-check-if-a-given-value-exists%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use array.some() to check whether value present,
var result = yurObj.children.some(t=>t.name === "Tennis");
DEMO
var yourObj = {
"id": 2,
"name": "Sports",
"url": "/sports",
"children": [
{
"id": 1,
"name": "Football"
},
{
"id": 2,
"name": "Tennis"
},
{
"id": 3,
"name": "Soccer"
}
]
};
var result = yourObj.children.some(t=>t.name === "Tennis");
console.log(result);answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
is that pratical if i use JSON.stringify() to my JSON object ?
– Java.net
Nov 27 '18 at 7:55
you dont need to use, just check the demo
– Sajeetharan
Nov 27 '18 at 7:55
yourObj.children is not known result in my case is a list i only can map,filter,foreach .. methods to manage lists
– Java.net
Nov 27 '18 at 8:01
i meant yourObj as the one you pasted above
– Sajeetharan
Nov 27 '18 at 8:44
add a comment |
You can use array.some() to check whether value present,
var result = yurObj.children.some(t=>t.name === "Tennis");
DEMO
var yourObj = {
"id": 2,
"name": "Sports",
"url": "/sports",
"children": [
{
"id": 1,
"name": "Football"
},
{
"id": 2,
"name": "Tennis"
},
{
"id": 3,
"name": "Soccer"
}
]
};
var result = yourObj.children.some(t=>t.name === "Tennis");
console.log(result);answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
is that pratical if i use JSON.stringify() to my JSON object ?
– Java.net
Nov 27 '18 at 7:55
you dont need to use, just check the demo
– Sajeetharan
Nov 27 '18 at 7:55
yourObj.children is not known result in my case is a list i only can map,filter,foreach .. methods to manage lists
– Java.net
Nov 27 '18 at 8:01
i meant yourObj as the one you pasted above
– Sajeetharan
Nov 27 '18 at 8:44
add a comment |
You can use array.some() to check whether value present,
var result = yurObj.children.some(t=>t.name === "Tennis");
DEMO
var yourObj = {
"id": 2,
"name": "Sports",
"url": "/sports",
"children": [
{
"id": 1,
"name": "Football"
},
{
"id": 2,
"name": "Tennis"
},
{
"id": 3,
"name": "Soccer"
}
]
};
var result = yourObj.children.some(t=>t.name === "Tennis");
console.log(result);answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
You can use array.some() to check whether value present,
var result = yurObj.children.some(t=>t.name === "Tennis");
DEMO
var yourObj = {
"id": 2,
"name": "Sports",
"url": "/sports",
"children": [
{
"id": 1,
"name": "Football"
},
{
"id": 2,
"name": "Tennis"
},
{
"id": 3,
"name": "Soccer"
}
]
};
var result = yourObj.children.some(t=>t.name === "Tennis");
console.log(result);var yourObj = {
"id": 2,
"name": "Sports",
"url": "/sports",
"children": [
{
"id": 1,
"name": "Football"
},
{
"id": 2,
"name": "Tennis"
},
{
"id": 3,
"name": "Soccer"
}
]
};
var result = yourObj.children.some(t=>t.name === "Tennis");
console.log(result);var yourObj = {
"id": 2,
"name": "Sports",
"url": "/sports",
"children": [
{
"id": 1,
"name": "Football"
},
{
"id": 2,
"name": "Tennis"
},
{
"id": 3,
"name": "Soccer"
}
]
};
var result = yourObj.children.some(t=>t.name === "Tennis");
console.log(result);answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
edited Nov 27 '18 at 7:55
answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
answered Nov 27 '18 at 7:54
SajeetharanSajeetharan
123k30176236
123k30176236
is that pratical if i use JSON.stringify() to my JSON object ?
– Java.net
Nov 27 '18 at 7:55
you dont need to use, just check the demo
– Sajeetharan
Nov 27 '18 at 7:55
yourObj.children is not known result in my case is a list i only can map,filter,foreach .. methods to manage lists
– Java.net
Nov 27 '18 at 8:01
i meant yourObj as the one you pasted above
– Sajeetharan
Nov 27 '18 at 8:44
add a comment |
is that pratical if i use JSON.stringify() to my JSON object ?
– Java.net
Nov 27 '18 at 7:55
you dont need to use, just check the demo
– Sajeetharan
Nov 27 '18 at 7:55
yourObj.children is not known result in my case is a list i only can map,filter,foreach .. methods to manage lists
– Java.net
Nov 27 '18 at 8:01
i meant yourObj as the one you pasted above
– Sajeetharan
Nov 27 '18 at 8:44
is that pratical if i use JSON.stringify() to my JSON object ?
– Java.net
Nov 27 '18 at 7:55
is that pratical if i use JSON.stringify() to my JSON object ?
– Java.net
Nov 27 '18 at 7:55
you dont need to use, just check the demo
– Sajeetharan
Nov 27 '18 at 7:55
you dont need to use, just check the demo
– Sajeetharan
Nov 27 '18 at 7:55
yourObj.children is not known result in my case is a list i only can map,filter,foreach .. methods to manage lists
– Java.net
Nov 27 '18 at 8:01
yourObj.children is not known result in my case is a list i only can map,filter,foreach .. methods to manage lists
– Java.net
Nov 27 '18 at 8:01
i meant yourObj as the one you pasted above
– Sajeetharan
Nov 27 '18 at 8:44
i meant yourObj as the one you pasted above
– Sajeetharan
Nov 27 '18 at 8:44
add a comment |
You can use the following Array filter method:
const result = Object.children.filter(item => item.name === 'Tennis')
The result array will contain all elements of children where the name is equal to 'Tennis'.
Hope this helps.
Lloyd
answered Nov 27 '18 at 7:54
LloydLloyd
916
add a comment |
You can use the following Array filter method:
const result = Object.children.filter(item => item.name === 'Tennis')
The result array will contain all elements of children where the name is equal to 'Tennis'.
Hope this helps.
Lloyd
answered Nov 27 '18 at 7:54
LloydLloyd
916
add a comment |
You can use the following Array filter method:
const result = Object.children.filter(item => item.name === 'Tennis')
The result array will contain all elements of children where the name is equal to 'Tennis'.
Hope this helps.
Lloyd
answered Nov 27 '18 at 7:54
LloydLloyd
916
You can use the following Array filter method:
const result = Object.children.filter(item => item.name === 'Tennis')
The result array will contain all elements of children where the name is equal to 'Tennis'.
Hope this helps.
Lloyd
answered Nov 27 '18 at 7:54
LloydLloyd
916
answered Nov 27 '18 at 7:54
LloydLloyd
916
answered Nov 27 '18 at 7:54
LloydLloyd
916
answered Nov 27 '18 at 7:54
LloydLloyd
916
916
add a comment |
add a comment |
This is super easy using lodash. You can use find or filter methods. find will give you specific value whereas filter will return collection of values matching search criteria.
const result = _.find(yourObj, {name: 'Tennis'});
In case, you need to search within childern of your object, you can also do that so:
const result = _.find(yourObj, function(o) { return o.children.name === 'Tennis' });
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
add a comment |
This is super easy using lodash. You can use find or filter methods. find will give you specific value whereas filter will return collection of values matching search criteria.
const result = _.find(yourObj, {name: 'Tennis'});
In case, you need to search within childern of your object, you can also do that so:
const result = _.find(yourObj, function(o) { return o.children.name === 'Tennis' });
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
add a comment |
This is super easy using lodash. You can use find or filter methods. find will give you specific value whereas filter will return collection of values matching search criteria.
const result = _.find(yourObj, {name: 'Tennis'});
In case, you need to search within childern of your object, you can also do that so:
const result = _.find(yourObj, function(o) { return o.children.name === 'Tennis' });
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
This is super easy using lodash. You can use find or filter methods. find will give you specific value whereas filter will return collection of values matching search criteria.
const result = _.find(yourObj, {name: 'Tennis'});
In case, you need to search within childern of your object, you can also do that so:
const result = _.find(yourObj, function(o) { return o.children.name === 'Tennis' });
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
answered Nov 27 '18 at 8:33
UmeshUmesh
1,9141017
1,9141017
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53495009%2flooping-on-a-json-object-to-check-if-a-given-value-exists%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
