how can I insert a Tensor into another Tensor in pytorch
I have pytorch Tensor with shape (batch_size, step, vec_size)
, for example, a Tensor(32, 64, 128)
, let's call it A.
I have another Tensor(batch_size, vec_size)
, e.g. Tensor(32, 128)
, let's call it B.
I want to insert B into a certain position at axis 1 of A. The insert positions are given in a Tensor(batch_size)
, named P.
I understand there is no Empty tensor(like an empty list) in pytorch, so, I initialize A as zeros, and add B at a certain position at axis 1 of A.
A = Variable(torch.zeros(batch_size, step, vec_size))
What I'm doing is like:
for i in range(batch_size):
pos = P[i]
A[i][pos] = A[i][pos] + B[i]
But I get an Error:
RuntimeError: one of the variables needed for gradient computation has been modified by an inplace operation
Then, I make a clone of A each inside the loop:
for i in range(batch_size):
A_clone = A.clone()
pos = P[i]
A_clone[i][pos] = A_clone[i][pos] + B[i]
This is very slow for autograd, I wonder if there any better solutions? Thank you.
pytorch
add a comment |
I have pytorch Tensor with shape (batch_size, step, vec_size)
, for example, a Tensor(32, 64, 128)
, let's call it A.
I have another Tensor(batch_size, vec_size)
, e.g. Tensor(32, 128)
, let's call it B.
I want to insert B into a certain position at axis 1 of A. The insert positions are given in a Tensor(batch_size)
, named P.
I understand there is no Empty tensor(like an empty list) in pytorch, so, I initialize A as zeros, and add B at a certain position at axis 1 of A.
A = Variable(torch.zeros(batch_size, step, vec_size))
What I'm doing is like:
for i in range(batch_size):
pos = P[i]
A[i][pos] = A[i][pos] + B[i]
But I get an Error:
RuntimeError: one of the variables needed for gradient computation has been modified by an inplace operation
Then, I make a clone of A each inside the loop:
for i in range(batch_size):
A_clone = A.clone()
pos = P[i]
A_clone[i][pos] = A_clone[i][pos] + B[i]
This is very slow for autograd, I wonder if there any better solutions? Thank you.
pytorch
add a comment |
I have pytorch Tensor with shape (batch_size, step, vec_size)
, for example, a Tensor(32, 64, 128)
, let's call it A.
I have another Tensor(batch_size, vec_size)
, e.g. Tensor(32, 128)
, let's call it B.
I want to insert B into a certain position at axis 1 of A. The insert positions are given in a Tensor(batch_size)
, named P.
I understand there is no Empty tensor(like an empty list) in pytorch, so, I initialize A as zeros, and add B at a certain position at axis 1 of A.
A = Variable(torch.zeros(batch_size, step, vec_size))
What I'm doing is like:
for i in range(batch_size):
pos = P[i]
A[i][pos] = A[i][pos] + B[i]
But I get an Error:
RuntimeError: one of the variables needed for gradient computation has been modified by an inplace operation
Then, I make a clone of A each inside the loop:
for i in range(batch_size):
A_clone = A.clone()
pos = P[i]
A_clone[i][pos] = A_clone[i][pos] + B[i]
This is very slow for autograd, I wonder if there any better solutions? Thank you.
pytorch
I have pytorch Tensor with shape (batch_size, step, vec_size)
, for example, a Tensor(32, 64, 128)
, let's call it A.
I have another Tensor(batch_size, vec_size)
, e.g. Tensor(32, 128)
, let's call it B.
I want to insert B into a certain position at axis 1 of A. The insert positions are given in a Tensor(batch_size)
, named P.
I understand there is no Empty tensor(like an empty list) in pytorch, so, I initialize A as zeros, and add B at a certain position at axis 1 of A.
A = Variable(torch.zeros(batch_size, step, vec_size))
What I'm doing is like:
for i in range(batch_size):
pos = P[i]
A[i][pos] = A[i][pos] + B[i]
But I get an Error:
RuntimeError: one of the variables needed for gradient computation has been modified by an inplace operation
Then, I make a clone of A each inside the loop:
for i in range(batch_size):
A_clone = A.clone()
pos = P[i]
A_clone[i][pos] = A_clone[i][pos] + B[i]
This is very slow for autograd, I wonder if there any better solutions? Thank you.
pytorch
pytorch
edited Nov 22 at 21:57
Umang Gupta
2,88511533
2,88511533
asked Nov 22 at 21:15
Tong
32
32
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can use a mask instead of cloning.
See the code below
# setup
batch, step, vec_size = 64, 10, 128
A = torch.rand((batch, step, vec_size))
B = torch.rand((batch, vec_size))
pos = torch.randint(10, (64,)).long()
# computations
# create a mask where pos is 0 if it is to be replaced
mask = torch.ones( (batch, step)).view(batch,step,1).float()
mask[torch.arange(batch), pos]=0
# expand B to have same dimension as A and compute the result
result = A*mask + B.unsqueeze(dim=1).expand([-1, step, -1])*(1-mask)
This way you avoid using for loops and cloning as well.
Hi Umang. Thanks for the great answer. Would you mind elaborating on that last line a bit? I am confused with theunsqueeze
call.
– user2268997
Dec 8 at 13:28
1
@user2268997unsqueeze
call makesb
of shape[batch_size, 1, vec_size]
. Note that shape ofb
was[batch_size, vec_size]
and expand broadcasts it to make it same size as mask so as to be able to multiply
– Umang Gupta
Dec 8 at 17:39
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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oldest
votes
You can use a mask instead of cloning.
See the code below
# setup
batch, step, vec_size = 64, 10, 128
A = torch.rand((batch, step, vec_size))
B = torch.rand((batch, vec_size))
pos = torch.randint(10, (64,)).long()
# computations
# create a mask where pos is 0 if it is to be replaced
mask = torch.ones( (batch, step)).view(batch,step,1).float()
mask[torch.arange(batch), pos]=0
# expand B to have same dimension as A and compute the result
result = A*mask + B.unsqueeze(dim=1).expand([-1, step, -1])*(1-mask)
This way you avoid using for loops and cloning as well.
Hi Umang. Thanks for the great answer. Would you mind elaborating on that last line a bit? I am confused with theunsqueeze
call.
– user2268997
Dec 8 at 13:28
1
@user2268997unsqueeze
call makesb
of shape[batch_size, 1, vec_size]
. Note that shape ofb
was[batch_size, vec_size]
and expand broadcasts it to make it same size as mask so as to be able to multiply
– Umang Gupta
Dec 8 at 17:39
add a comment |
You can use a mask instead of cloning.
See the code below
# setup
batch, step, vec_size = 64, 10, 128
A = torch.rand((batch, step, vec_size))
B = torch.rand((batch, vec_size))
pos = torch.randint(10, (64,)).long()
# computations
# create a mask where pos is 0 if it is to be replaced
mask = torch.ones( (batch, step)).view(batch,step,1).float()
mask[torch.arange(batch), pos]=0
# expand B to have same dimension as A and compute the result
result = A*mask + B.unsqueeze(dim=1).expand([-1, step, -1])*(1-mask)
This way you avoid using for loops and cloning as well.
Hi Umang. Thanks for the great answer. Would you mind elaborating on that last line a bit? I am confused with theunsqueeze
call.
– user2268997
Dec 8 at 13:28
1
@user2268997unsqueeze
call makesb
of shape[batch_size, 1, vec_size]
. Note that shape ofb
was[batch_size, vec_size]
and expand broadcasts it to make it same size as mask so as to be able to multiply
– Umang Gupta
Dec 8 at 17:39
add a comment |
You can use a mask instead of cloning.
See the code below
# setup
batch, step, vec_size = 64, 10, 128
A = torch.rand((batch, step, vec_size))
B = torch.rand((batch, vec_size))
pos = torch.randint(10, (64,)).long()
# computations
# create a mask where pos is 0 if it is to be replaced
mask = torch.ones( (batch, step)).view(batch,step,1).float()
mask[torch.arange(batch), pos]=0
# expand B to have same dimension as A and compute the result
result = A*mask + B.unsqueeze(dim=1).expand([-1, step, -1])*(1-mask)
This way you avoid using for loops and cloning as well.
You can use a mask instead of cloning.
See the code below
# setup
batch, step, vec_size = 64, 10, 128
A = torch.rand((batch, step, vec_size))
B = torch.rand((batch, vec_size))
pos = torch.randint(10, (64,)).long()
# computations
# create a mask where pos is 0 if it is to be replaced
mask = torch.ones( (batch, step)).view(batch,step,1).float()
mask[torch.arange(batch), pos]=0
# expand B to have same dimension as A and compute the result
result = A*mask + B.unsqueeze(dim=1).expand([-1, step, -1])*(1-mask)
This way you avoid using for loops and cloning as well.
answered Nov 22 at 22:11
Umang Gupta
2,88511533
2,88511533
Hi Umang. Thanks for the great answer. Would you mind elaborating on that last line a bit? I am confused with theunsqueeze
call.
– user2268997
Dec 8 at 13:28
1
@user2268997unsqueeze
call makesb
of shape[batch_size, 1, vec_size]
. Note that shape ofb
was[batch_size, vec_size]
and expand broadcasts it to make it same size as mask so as to be able to multiply
– Umang Gupta
Dec 8 at 17:39
add a comment |
Hi Umang. Thanks for the great answer. Would you mind elaborating on that last line a bit? I am confused with theunsqueeze
call.
– user2268997
Dec 8 at 13:28
1
@user2268997unsqueeze
call makesb
of shape[batch_size, 1, vec_size]
. Note that shape ofb
was[batch_size, vec_size]
and expand broadcasts it to make it same size as mask so as to be able to multiply
– Umang Gupta
Dec 8 at 17:39
Hi Umang. Thanks for the great answer. Would you mind elaborating on that last line a bit? I am confused with the
unsqueeze
call.– user2268997
Dec 8 at 13:28
Hi Umang. Thanks for the great answer. Would you mind elaborating on that last line a bit? I am confused with the
unsqueeze
call.– user2268997
Dec 8 at 13:28
1
1
@user2268997
unsqueeze
call makes b
of shape [batch_size, 1, vec_size]
. Note that shape of b
was [batch_size, vec_size]
and expand broadcasts it to make it same size as mask so as to be able to multiply– Umang Gupta
Dec 8 at 17:39
@user2268997
unsqueeze
call makes b
of shape [batch_size, 1, vec_size]
. Note that shape of b
was [batch_size, vec_size]
and expand broadcasts it to make it same size as mask so as to be able to multiply– Umang Gupta
Dec 8 at 17:39
add a comment |
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