Oracle SQL - How to aggregate rows with the same value in one column
up vote
-2
down vote
favorite
I need help. Have done this when using aggregating functions but since I am not using them here don`t know how to do it.
ID num1 num2 num3 num4
180919113541070 0 0 0 4
180919113541070 0 0 0 0
180919113541070 4 0 0 0
this is a simple select
select *
from tableX
order by ID;
I would like this data to appear in one row as below:
ID num1 num2 num3 num4
180919113541070 4 0 0 4
and not even have rows where all are 0.
Thank you!
sql oracle oracle-sqldeveloper
asked Nov 22 at 16:41
bobypoz
11
add a comment |
up vote
-2
down vote
favorite
I need help. Have done this when using aggregating functions but since I am not using them here don`t know how to do it.
ID num1 num2 num3 num4
180919113541070 0 0 0 4
180919113541070 0 0 0 0
180919113541070 4 0 0 0
this is a simple select
select *
from tableX
order by ID;
I would like this data to appear in one row as below:
ID num1 num2 num3 num4
180919113541070 4 0 0 4
and not even have rows where all are 0.
Thank you!
sql oracle oracle-sqldeveloper
asked Nov 22 at 16:41
bobypoz
11
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
I need help. Have done this when using aggregating functions but since I am not using them here don`t know how to do it.
ID num1 num2 num3 num4
180919113541070 0 0 0 4
180919113541070 0 0 0 0
180919113541070 4 0 0 0
this is a simple select
select *
from tableX
order by ID;
I would like this data to appear in one row as below:
ID num1 num2 num3 num4
180919113541070 4 0 0 4
and not even have rows where all are 0.
Thank you!
sql oracle oracle-sqldeveloper
asked Nov 22 at 16:41
bobypoz
11
I need help. Have done this when using aggregating functions but since I am not using them here don`t know how to do it.
ID num1 num2 num3 num4
180919113541070 0 0 0 4
180919113541070 0 0 0 0
180919113541070 4 0 0 0
this is a simple select
select *
from tableX
order by ID;
I would like this data to appear in one row as below:
ID num1 num2 num3 num4
180919113541070 4 0 0 4
and not even have rows where all are 0.
Thank you!
sql oracle oracle-sqldeveloper
sql oracle oracle-sqldeveloper
asked Nov 22 at 16:41
bobypoz
11
asked Nov 22 at 16:41
bobypoz
11
asked Nov 22 at 16:41
bobypoz
11
asked Nov 22 at 16:41
bobypoz
11
asked Nov 22 at 16:41
bobypoz
11
11
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
use aggregate function
select id,sum(num1) num1,sum(num2) num2,
sum(num3) num3,sum(num4) num4 from t group by id
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
Perfect!! Thank you. Easy
– bobypoz
Nov 22 at 17:23
@bobypoz stackoverflow.com/help/someone-answers
– Zaynul Abadin Tuhin
Nov 22 at 17:40
add a comment |
up vote
0
down vote
You seem to want simple aggregation:
select id, max(num1) as num1, max(num2) as num2, max(num3) as num3, max(num4) as num4
from t
group by id;
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
Thank you!! Should`ve realized this myself but you helped a lot.
– bobypoz
Nov 22 at 17:24
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
use aggregate function
select id,sum(num1) num1,sum(num2) num2,
sum(num3) num3,sum(num4) num4 from t group by id
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
Perfect!! Thank you. Easy
– bobypoz
Nov 22 at 17:23
@bobypoz stackoverflow.com/help/someone-answers
– Zaynul Abadin Tuhin
Nov 22 at 17:40
add a comment |
up vote
1
down vote
use aggregate function
select id,sum(num1) num1,sum(num2) num2,
sum(num3) num3,sum(num4) num4 from t group by id
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
Perfect!! Thank you. Easy
– bobypoz
Nov 22 at 17:23
@bobypoz stackoverflow.com/help/someone-answers
– Zaynul Abadin Tuhin
Nov 22 at 17:40
add a comment |
up vote
1
down vote
up vote
1
down vote
use aggregate function
select id,sum(num1) num1,sum(num2) num2,
sum(num3) num3,sum(num4) num4 from t group by id
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
use aggregate function
select id,sum(num1) num1,sum(num2) num2,
sum(num3) num3,sum(num4) num4 from t group by id
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
answered Nov 22 at 16:43
Zaynul Abadin Tuhin
11.2k2831
11.2k2831
Perfect!! Thank you. Easy
– bobypoz
Nov 22 at 17:23
@bobypoz stackoverflow.com/help/someone-answers
– Zaynul Abadin Tuhin
Nov 22 at 17:40
add a comment |
Perfect!! Thank you. Easy
– bobypoz
Nov 22 at 17:23
@bobypoz stackoverflow.com/help/someone-answers
– Zaynul Abadin Tuhin
Nov 22 at 17:40
Perfect!! Thank you. Easy
– bobypoz
Nov 22 at 17:23
Perfect!! Thank you. Easy
– bobypoz
Nov 22 at 17:23
@bobypoz stackoverflow.com/help/someone-answers
– Zaynul Abadin Tuhin
Nov 22 at 17:40
@bobypoz stackoverflow.com/help/someone-answers
– Zaynul Abadin Tuhin
Nov 22 at 17:40
add a comment |
up vote
0
down vote
You seem to want simple aggregation:
select id, max(num1) as num1, max(num2) as num2, max(num3) as num3, max(num4) as num4
from t
group by id;
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
Thank you!! Should`ve realized this myself but you helped a lot.
– bobypoz
Nov 22 at 17:24
add a comment |
up vote
0
down vote
You seem to want simple aggregation:
select id, max(num1) as num1, max(num2) as num2, max(num3) as num3, max(num4) as num4
from t
group by id;
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
Thank you!! Should`ve realized this myself but you helped a lot.
– bobypoz
Nov 22 at 17:24
add a comment |
up vote
0
down vote
up vote
0
down vote
You seem to want simple aggregation:
select id, max(num1) as num1, max(num2) as num2, max(num3) as num3, max(num4) as num4
from t
group by id;
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
You seem to want simple aggregation:
select id, max(num1) as num1, max(num2) as num2, max(num3) as num3, max(num4) as num4
from t
group by id;
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
answered Nov 22 at 16:43
Gordon Linoff
754k35289397
754k35289397
Thank you!! Should`ve realized this myself but you helped a lot.
– bobypoz
Nov 22 at 17:24
add a comment |
Thank you!! Should`ve realized this myself but you helped a lot.
– bobypoz
Nov 22 at 17:24
Thank you!! Should`ve realized this myself but you helped a lot.
– bobypoz
Nov 22 at 17:24
Thank you!! Should`ve realized this myself but you helped a lot.
– bobypoz
Nov 22 at 17:24
add a comment |
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