Encode the date in Christmas Eve format












7














The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.










share|improve this question
























  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    2 hours ago
















7














The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.










share|improve this question
























  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    2 hours ago














7












7








7







The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.










share|improve this question















The day this post was published was Christmas Eve. Tomorrow will be Christmas. Yesterday was Christmas Eve Eve. In two days it will be



Christmas Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve Eve.


Your job is to take the date the program is run and encode it in Christmas Eve format.




  • If your program is run on Christmas, it should output the string "Christmas".

  • If your program is not run on Christmas, it should output the string "Christmas", followed by the string " Eve" repeated n times, where n is the number of days until Christmas.


    • Note that this must be based on the next Christmas. For example, if the day is April 26, 2019, you must do your calculation based on December 25, 2019, not any other Christmas.

    • Remember to count leap days.



  • Christmas is December 25th of every year.


This is code-golf, so the shortest code wins! Note though that the goal is not to find the shortest program in any language, but to find the shortest program in every particular language. For example, if you find the shortest C++ program, then it wins this contest for C++, even if someone finds a shorter program in Python.







code-golf string date






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 47 mins ago

























asked 4 hours ago









PyRulez

3,34742054




3,34742054












  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    2 hours ago


















  • Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai what cartoon?
    – PyRulez
    4 hours ago






  • 2




    A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
    – Black Owl Kai
    4 hours ago










  • @BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
    – PyRulez
    4 hours ago










  • You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
    – Sparr
    2 hours ago
















Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
– Black Owl Kai
4 hours ago




Somehow I knew that this was going to be a PPCG challenge the moment I saw the cartoon - +1 from me
– Black Owl Kai
4 hours ago












@BlackOwlKai what cartoon?
– PyRulez
4 hours ago




@BlackOwlKai what cartoon?
– PyRulez
4 hours ago




2




2




A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
– Black Owl Kai
4 hours ago




A xkcd cartoon that was published today. imgs.xkcd.com/comics/christmas_eve_eve.png
– Black Owl Kai
4 hours ago












@BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
– PyRulez
4 hours ago




@BlackOwlKai LMBO I didn't even see that comic until your comment. I had already planned to post this, and was just waiting for Christmas Eve. Great minds think alike, I guess?
– PyRulez
4 hours ago












You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
– Sparr
2 hours ago




You should specify that you mean Dec 25 for "Christmas", unless you want submissions that use a local date or calendar.
– Sparr
2 hours ago










2 Answers
2






active

oldest

votes


















2















R, 112 106 bytes





function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


Try it online!



Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



Pick the non-negative one and cat "Christmas" with that many "Eves".






share|improve this answer























  • You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    1 hour ago










  • Also would z[z>=0][1] work instead of min?
    – Giuseppe
    1 hour ago



















0















Perl 6, 61 bytes



say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


Try it online!



Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






share|improve this answer





















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    2 Answers
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    2 Answers
    2






    active

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    active

    oldest

    votes






    active

    oldest

    votes









    2















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer























    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago
















    2















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer























    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago














    2












    2








    2







    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".






    share|improve this answer















    R, 112 106 bytes





    function(x,z=as.Date(paste0(strtoi(format(x,"%Y"))+0:1,"-12-25"))-x)cat("Christmas",rep("Eve",z[z>=0][1]))


    Try it online!



    Explanation: everyone's at church so I have time to do this. Extract the year, coerce to integer. Make vector of that year's Xmas and the next year's Xmas and subtract the input date to get a vector of two differences between the input date and those two Xmases.



    Pick the non-negative one and cat "Christmas" with that many "Eves".







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 1 hour ago

























    answered 1 hour ago









    ngm

    3,21924




    3,21924












    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago


















    • You only use y once so you can just use it directly for 108 bytes.
      – Giuseppe
      1 hour ago










    • Also would z[z>=0][1] work instead of min?
      – Giuseppe
      1 hour ago
















    You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    1 hour ago




    You only use y once so you can just use it directly for 108 bytes.
    – Giuseppe
    1 hour ago












    Also would z[z>=0][1] work instead of min?
    – Giuseppe
    1 hour ago




    Also would z[z>=0][1] work instead of min?
    – Giuseppe
    1 hour ago











    0















    Perl 6, 61 bytes



    say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


    Try it online!



    Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






    share|improve this answer


























      0















      Perl 6, 61 bytes



      say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


      Try it online!



      Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






      share|improve this answer
























        0












        0








        0







        Perl 6, 61 bytes



        say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


        Try it online!



        Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".






        share|improve this answer













        Perl 6, 61 bytes



        say 'Christmas'~' Eve'x(Date.today...^{.month==12&&.day==25})


        Try it online!



        Date.today ...^ { .month == 12 && .day == 25 } is the sequence of dates starting at today and ending the day before Christmas. The string " Eve" is replicated a number of times equal to the length of that sequence, and is output after the string "Christmas".







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 27 mins ago









        Sean

        3,28636




        3,28636






























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