C - Print an array filled with Unicode-Symbols
I want to print an array(/string), which is filled with unicode (and normal) symbols , for example squares.
Here's my code:
#include <stdio.h>
int main()
{
char array[5];
for (int i = 0; i < 4; i++){
array[i]='u25A1';
}
array[4]='A';
printf("%s", array);
return 0;
}
It just prints " ííííA◊".
Why doesn't it print the squares, and how to fix it?
According to fileformat.info the square's
C/C++/Java source code is "u25A0"
i also tried the square's
UTF-8 (hex), which is "0xE2 0x96 0xA0 (e296a0)"
Neither work.
c arrays unicode char printf
add a comment |
I want to print an array(/string), which is filled with unicode (and normal) symbols , for example squares.
Here's my code:
#include <stdio.h>
int main()
{
char array[5];
for (int i = 0; i < 4; i++){
array[i]='u25A1';
}
array[4]='A';
printf("%s", array);
return 0;
}
It just prints " ííííA◊".
Why doesn't it print the squares, and how to fix it?
According to fileformat.info the square's
C/C++/Java source code is "u25A0"
i also tried the square's
UTF-8 (hex), which is "0xE2 0x96 0xA0 (e296a0)"
Neither work.
c arrays unicode char printf
add a comment |
I want to print an array(/string), which is filled with unicode (and normal) symbols , for example squares.
Here's my code:
#include <stdio.h>
int main()
{
char array[5];
for (int i = 0; i < 4; i++){
array[i]='u25A1';
}
array[4]='A';
printf("%s", array);
return 0;
}
It just prints " ííííA◊".
Why doesn't it print the squares, and how to fix it?
According to fileformat.info the square's
C/C++/Java source code is "u25A0"
i also tried the square's
UTF-8 (hex), which is "0xE2 0x96 0xA0 (e296a0)"
Neither work.
c arrays unicode char printf
I want to print an array(/string), which is filled with unicode (and normal) symbols , for example squares.
Here's my code:
#include <stdio.h>
int main()
{
char array[5];
for (int i = 0; i < 4; i++){
array[i]='u25A1';
}
array[4]='A';
printf("%s", array);
return 0;
}
It just prints " ííííA◊".
Why doesn't it print the squares, and how to fix it?
According to fileformat.info the square's
C/C++/Java source code is "u25A0"
i also tried the square's
UTF-8 (hex), which is "0xE2 0x96 0xA0 (e296a0)"
Neither work.
c arrays unicode char printf
c arrays unicode char printf
asked Nov 23 at 0:24
flogg1
1
1
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
array[i] = 'u25A1'
will not compile correctly in C. You should at least get a compiler warning.
'u25A1'
is of type char16_t
(two bytes per character), it is not relevant here.
u
can be used as a escape sequence in a string literal, to represent Unicode code points below 0x10000
. Example:
strcpy(array, u8"u25A0");
printf(array);
Output: ■
Note that u8"u25A0"
is stored as 4 bytes (0xE2, 0x96, 0xA0
+ null-character) based on UTF8 conversion. It can also be printed as follow (if the console supports UTF8 output):
strcpy(array, "xE2x96xA0");
printf(array);
Output: ■
Moreover the string should be null-terminated, the last character in the string should be zero.
To store UTF8 in bytes, you can assign values as follows:
array[0] = 0xE2;
array[1] = 0x96;
array[2] = 0xA0;
array[3] = '';
If your development environment supports it you can also declare
char array = u8"■";
Thanks @chux. I cleaned up the answer a bit.
– Barmak Shemirani
Nov 23 at 8:08
1
Other minor: "u8"u25A0" is turned in to 3 bytes" --> 4 bytes (3 + ) as string literals always append a null character.
– chux
Nov 23 at 8:13
it just prints "öüä" for everything you said :/
– flogg1
Nov 23 at 15:10
It depends on your operating system, the version of your operating system, and if the console supports UTF8. I don't know anything about your environment you are using.
– Barmak Shemirani
Nov 23 at 17:13
@flogg1: maybe you should specify your OS in your question. The Windows console, for example, may need some forced coercing before it does something as wildly far-fetched as defaulting to UTF8...
– usr2564301
Nov 25 at 11:00
|
show 1 more comment
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
array[i] = 'u25A1'
will not compile correctly in C. You should at least get a compiler warning.
'u25A1'
is of type char16_t
(two bytes per character), it is not relevant here.
u
can be used as a escape sequence in a string literal, to represent Unicode code points below 0x10000
. Example:
strcpy(array, u8"u25A0");
printf(array);
Output: ■
Note that u8"u25A0"
is stored as 4 bytes (0xE2, 0x96, 0xA0
+ null-character) based on UTF8 conversion. It can also be printed as follow (if the console supports UTF8 output):
strcpy(array, "xE2x96xA0");
printf(array);
Output: ■
Moreover the string should be null-terminated, the last character in the string should be zero.
To store UTF8 in bytes, you can assign values as follows:
array[0] = 0xE2;
array[1] = 0x96;
array[2] = 0xA0;
array[3] = '';
If your development environment supports it you can also declare
char array = u8"■";
Thanks @chux. I cleaned up the answer a bit.
– Barmak Shemirani
Nov 23 at 8:08
1
Other minor: "u8"u25A0" is turned in to 3 bytes" --> 4 bytes (3 + ) as string literals always append a null character.
– chux
Nov 23 at 8:13
it just prints "öüä" for everything you said :/
– flogg1
Nov 23 at 15:10
It depends on your operating system, the version of your operating system, and if the console supports UTF8. I don't know anything about your environment you are using.
– Barmak Shemirani
Nov 23 at 17:13
@flogg1: maybe you should specify your OS in your question. The Windows console, for example, may need some forced coercing before it does something as wildly far-fetched as defaulting to UTF8...
– usr2564301
Nov 25 at 11:00
|
show 1 more comment
array[i] = 'u25A1'
will not compile correctly in C. You should at least get a compiler warning.
'u25A1'
is of type char16_t
(two bytes per character), it is not relevant here.
u
can be used as a escape sequence in a string literal, to represent Unicode code points below 0x10000
. Example:
strcpy(array, u8"u25A0");
printf(array);
Output: ■
Note that u8"u25A0"
is stored as 4 bytes (0xE2, 0x96, 0xA0
+ null-character) based on UTF8 conversion. It can also be printed as follow (if the console supports UTF8 output):
strcpy(array, "xE2x96xA0");
printf(array);
Output: ■
Moreover the string should be null-terminated, the last character in the string should be zero.
To store UTF8 in bytes, you can assign values as follows:
array[0] = 0xE2;
array[1] = 0x96;
array[2] = 0xA0;
array[3] = '';
If your development environment supports it you can also declare
char array = u8"■";
Thanks @chux. I cleaned up the answer a bit.
– Barmak Shemirani
Nov 23 at 8:08
1
Other minor: "u8"u25A0" is turned in to 3 bytes" --> 4 bytes (3 + ) as string literals always append a null character.
– chux
Nov 23 at 8:13
it just prints "öüä" for everything you said :/
– flogg1
Nov 23 at 15:10
It depends on your operating system, the version of your operating system, and if the console supports UTF8. I don't know anything about your environment you are using.
– Barmak Shemirani
Nov 23 at 17:13
@flogg1: maybe you should specify your OS in your question. The Windows console, for example, may need some forced coercing before it does something as wildly far-fetched as defaulting to UTF8...
– usr2564301
Nov 25 at 11:00
|
show 1 more comment
array[i] = 'u25A1'
will not compile correctly in C. You should at least get a compiler warning.
'u25A1'
is of type char16_t
(two bytes per character), it is not relevant here.
u
can be used as a escape sequence in a string literal, to represent Unicode code points below 0x10000
. Example:
strcpy(array, u8"u25A0");
printf(array);
Output: ■
Note that u8"u25A0"
is stored as 4 bytes (0xE2, 0x96, 0xA0
+ null-character) based on UTF8 conversion. It can also be printed as follow (if the console supports UTF8 output):
strcpy(array, "xE2x96xA0");
printf(array);
Output: ■
Moreover the string should be null-terminated, the last character in the string should be zero.
To store UTF8 in bytes, you can assign values as follows:
array[0] = 0xE2;
array[1] = 0x96;
array[2] = 0xA0;
array[3] = '';
If your development environment supports it you can also declare
char array = u8"■";
array[i] = 'u25A1'
will not compile correctly in C. You should at least get a compiler warning.
'u25A1'
is of type char16_t
(two bytes per character), it is not relevant here.
u
can be used as a escape sequence in a string literal, to represent Unicode code points below 0x10000
. Example:
strcpy(array, u8"u25A0");
printf(array);
Output: ■
Note that u8"u25A0"
is stored as 4 bytes (0xE2, 0x96, 0xA0
+ null-character) based on UTF8 conversion. It can also be printed as follow (if the console supports UTF8 output):
strcpy(array, "xE2x96xA0");
printf(array);
Output: ■
Moreover the string should be null-terminated, the last character in the string should be zero.
To store UTF8 in bytes, you can assign values as follows:
array[0] = 0xE2;
array[1] = 0x96;
array[2] = 0xA0;
array[3] = '';
If your development environment supports it you can also declare
char array = u8"■";
edited Nov 23 at 8:34
answered Nov 23 at 0:56
Barmak Shemirani
20.8k42045
20.8k42045
Thanks @chux. I cleaned up the answer a bit.
– Barmak Shemirani
Nov 23 at 8:08
1
Other minor: "u8"u25A0" is turned in to 3 bytes" --> 4 bytes (3 + ) as string literals always append a null character.
– chux
Nov 23 at 8:13
it just prints "öüä" for everything you said :/
– flogg1
Nov 23 at 15:10
It depends on your operating system, the version of your operating system, and if the console supports UTF8. I don't know anything about your environment you are using.
– Barmak Shemirani
Nov 23 at 17:13
@flogg1: maybe you should specify your OS in your question. The Windows console, for example, may need some forced coercing before it does something as wildly far-fetched as defaulting to UTF8...
– usr2564301
Nov 25 at 11:00
|
show 1 more comment
Thanks @chux. I cleaned up the answer a bit.
– Barmak Shemirani
Nov 23 at 8:08
1
Other minor: "u8"u25A0" is turned in to 3 bytes" --> 4 bytes (3 + ) as string literals always append a null character.
– chux
Nov 23 at 8:13
it just prints "öüä" for everything you said :/
– flogg1
Nov 23 at 15:10
It depends on your operating system, the version of your operating system, and if the console supports UTF8. I don't know anything about your environment you are using.
– Barmak Shemirani
Nov 23 at 17:13
@flogg1: maybe you should specify your OS in your question. The Windows console, for example, may need some forced coercing before it does something as wildly far-fetched as defaulting to UTF8...
– usr2564301
Nov 25 at 11:00
Thanks @chux. I cleaned up the answer a bit.
– Barmak Shemirani
Nov 23 at 8:08
Thanks @chux. I cleaned up the answer a bit.
– Barmak Shemirani
Nov 23 at 8:08
1
1
Other minor: "u8"u25A0" is turned in to 3 bytes" --> 4 bytes (3 + ) as string literals always append a null character.
– chux
Nov 23 at 8:13
Other minor: "u8"u25A0" is turned in to 3 bytes" --> 4 bytes (3 + ) as string literals always append a null character.
– chux
Nov 23 at 8:13
it just prints "öüä" for everything you said :/
– flogg1
Nov 23 at 15:10
it just prints "öüä" for everything you said :/
– flogg1
Nov 23 at 15:10
It depends on your operating system, the version of your operating system, and if the console supports UTF8. I don't know anything about your environment you are using.
– Barmak Shemirani
Nov 23 at 17:13
It depends on your operating system, the version of your operating system, and if the console supports UTF8. I don't know anything about your environment you are using.
– Barmak Shemirani
Nov 23 at 17:13
@flogg1: maybe you should specify your OS in your question. The Windows console, for example, may need some forced coercing before it does something as wildly far-fetched as defaulting to UTF8...
– usr2564301
Nov 25 at 11:00
@flogg1: maybe you should specify your OS in your question. The Windows console, for example, may need some forced coercing before it does something as wildly far-fetched as defaulting to UTF8...
– usr2564301
Nov 25 at 11:00
|
show 1 more comment
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