Btukfyl

I am trying to create an html file when the django project is started, by including code in the project/settings.py as follows:

def Brander():

    import configparser

    config = configparser.ConfigParser()

    config.read('settings.ini')

    version = config['PROJECT']['version']

    APPNAME = config['BRANDING']['appname']

    APPCOMPANY = config['BRANDING']['appcompany']

    APPCOMPANYLINK = config['BRANDING']['appcompanysite']

    APPLINK = config['BRANDING']['appsite']

    from django.contrib.staticfiles import finders

    filen = finders.find('clinic/brandedfooter.html')

    f = open(filen, "w")

    s = f"""

    <div class="col-lg-8 col-md-8 d-none d-md-block d-lg-block">

        <span class="text-muted float-right"><i>My OP and IP Clinic - <a href="{APPLINK}">{APPCOMPANY} by </a><a href="{APPCOMPANYLINK}">{APPCOMPANY}</a></i></span>

    </div>

    """

    f.write(s)

My project/settings.ini contains:

[PROJECT]

version = 0.0.1



[BRANDING]

appname = MyOPIP

appcompany = Droidzone

appcompanysite = https://droidzone.in

appsite = https://myopip.com

When the above code is run as standalone python script, everything works fine, and the html file is generated. However, when this is executed as part of manage.py runserver, I get the following error:

joel@hp:~/myappointments$ ./manage.py runserver

Traceback (most recent call last):

File "./manage.py", line 15, in <module>

    execute_from_command_line(sys.argv)

File "/home/joel/.local/lib/python3.6/site-packages/django/core/management/__init__.py", line 381, in execute_from_command_line

    utility.execute()

File "/home/joel/.local/lib/python3.6/site-packages/django/core/management/__init__.py", line 325, in execute

    settings.INSTALLED_APPS

File "/home/joel/.local/lib/python3.6/site-packages/django/conf/__init__.py", line 57, in __getattr__

    self._setup(name)

File "/home/joel/.local/lib/python3.6/site-packages/django/conf/__init__.py", line 44, in _setup

    self._wrapped = Settings(settings_module)

File "/home/joel/.local/lib/python3.6/site-packages/django/conf/__init__.py", line 107, in __init__

    mod = importlib.import_module(self.SETTINGS_MODULE)

File "/usr/lib/python3.6/importlib/__init__.py", line 126, in import_module

    return _bootstrap._gcd_import(name[level:], package, level)

File "<frozen importlib._bootstrap>", line 994, in _gcd_import

File "<frozen importlib._bootstrap>", line 971, in _find_and_load

File "<frozen importlib._bootstrap>", line 955, in _find_and_load_unlocked

File "<frozen importlib._bootstrap>", line 665, in _load_unlocked

File "<frozen importlib._bootstrap_external>", line 678, in exec_module

File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed

File "/home/joel/myappointments/myappointments/settings.py", line 258, in <module>

    Brander()

File "/home/joel/myappointments/myappointments/settings.py", line 16, in Brander

    version = config['PROJECT']['version']

File "/usr/lib/python3.6/configparser.py", line 959, in __getitem__

    raise KeyError(key)

KeyError: 'PROJECT'

I'm unable to understand why this error occurs only on starting the code in django.

You can use Django Constance for defining the settings. For example:

CONSTANCE_CONFIG = {

    'VERSION': ('0.0.1', 'Version'),

}

Then add 'constance.context_processors.config' in you context processors like the documentation mentioned. Then use it in template:

{{ config.VERSION }}