Populating function inputs from lists
2
$begingroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked 12 hours ago
BranBran
1365
$endgroup$
add a comment |
2
$begingroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked 12 hours ago
BranBran
1365
$endgroup$
add a comment |
2
2
2
$begingroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
asked 12 hours ago
BranBran
1365
$endgroup$
I have several lists containing variables, e.g. list1={x1,x2,x3}, list2={y1,y2,y3}, etc. I would like to define a function in those variables, i.e. f[x1,x2,x3,y1,y2,y3]. I have tried to use Do and AppendTo but this seems to reset f at every iteration. Any help is appreciated.
functions procedural-programming
functions procedural-programming
asked 12 hours ago
BranBran
1365
asked 12 hours ago
BranBran
1365
asked 12 hours ago
BranBran
1365
asked 12 hours ago
BranBran
1365
asked 12 hours ago
BranBran
1365
1365
add a comment |
add a comment |
1 Answer
1
active
oldest
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7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 11 hours ago
MarcoB
38.4k557115
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
12 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
12 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
12 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
12 hours ago
|
show 1 more comment
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 11 hours ago
MarcoB
38.4k557115
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
12 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
12 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
12 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
12 hours ago
|
show 1 more comment
7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 11 hours ago
MarcoB
38.4k557115
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
$endgroup$
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
12 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
12 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
12 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
12 hours ago
|
show 1 more comment
7
7
7
$begingroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 11 hours ago
MarcoB
38.4k557115
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
$endgroup$
f@@(list1 ~Join~ list2)
Or, more generally, use @@ to "open" the structure of List:
list1 = {x1, x2, x3}; list2 = {y1, y2, y3};
f @@ (list1~Join~list2)
f[x1, x2, x3, y1, y2, y3]
For a list of lists:
listOflists = {list1, list2}
f @@ (Flatten@listOflists)
f[x1, x2, x3, y1, y2, y3]
edited 11 hours ago
MarcoB
38.4k557115
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
edited 11 hours ago
MarcoB
38.4k557115
edited 11 hours ago
MarcoB
38.4k557115
edited 11 hours ago
MarcoB
38.4k557115
38.4k557115
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
answered 12 hours ago
Slepecky MamutSlepecky Mamut
710111
710111
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
12 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
12 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
12 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
12 hours ago
|
show 1 more comment
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
12 hours ago
$begingroup$
@Bran it gives exactly what you asked for,f[x1, x2, x3, y1, y2, y3]...
$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
12 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Likef[z1,z2,x1,x2,x3,y1,y2,y3].
$endgroup$
– Bran
12 hours ago
1
$begingroup$
@Branf[whatever, ##, whatever2]& @@ ...
$endgroup$
– Kuba♦
12 hours ago
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
12 hours ago
$begingroup$
Yes, it does. Thanks. I will accept your answer.
$endgroup$
– Bran
12 hours ago
$begingroup$
@Bran it gives exactly what you asked for,
f[x1, x2, x3, y1, y2, y3]...$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran it gives exactly what you asked for,
f[x1, x2, x3, y1, y2, y3]...$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
12 hours ago
$begingroup$
@Bran I'm not understand. They are! Try it, pls.
$endgroup$
– Slepecky Mamut
12 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Like
f[z1,z2,x1,x2,x3,y1,y2,y3].$endgroup$
– Bran
12 hours ago
$begingroup$
@SlepeckyMamut How can I add more variables to the function not from a list? Like
f[z1,z2,x1,x2,x3,y1,y2,y3].$endgroup$
– Bran
12 hours ago
1
1
$begingroup$
@Bran
f[whatever, ##, whatever2]& @@ ...$endgroup$
– Kuba♦
12 hours ago
$begingroup$
@Bran
f[whatever, ##, whatever2]& @@ ...$endgroup$
– Kuba♦
12 hours ago
|
show 1 more comment
draft saved
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