How do I exit BASH while loop using modulus operator?












2















So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?



while true

do

    echo "Please input anything here: "

    read INPUT



    if [ `expr $INPUT % 5` -eq 0 ]; then

        echo "you entered wrong"

    else

        echo "you entered right"

        break

fi

done





command-line bash scripts







share|improve this question




















  • 2





    If the assignment specifies bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))

    – steeldriver
    7 hours ago











  • the loop does not end when entering 25 @steeldriver

    – Roosevelt Mendieta
    7 hours ago
















2















So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?



while true

do

    echo "Please input anything here: "

    read INPUT



    if [ `expr $INPUT % 5` -eq 0 ]; then

        echo "you entered wrong"

    else

        echo "you entered right"

        break

fi

done





command-line bash scripts







share|improve this question




















  • 2





    If the assignment specifies bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))

    – steeldriver
    7 hours ago











  • the loop does not end when entering 25 @steeldriver

    – Roosevelt Mendieta
    7 hours ago














2












2








2








So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?



while true

do

    echo "Please input anything here: "

    read INPUT



    if [ `expr $INPUT % 5` -eq 0 ]; then

        echo "you entered wrong"

    else

        echo "you entered right"

        break

fi

done





command-line bash scripts







share|improve this question
















So practically for my assignment I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0, ex: (25 % 5 = 0 break loop) Where in my attempt below have I gone wrong?



while true

do

    echo "Please input anything here: "

    read INPUT



    if [ `expr $INPUT % 5` -eq 0 ]; then

        echo "you entered wrong"

    else

        echo "you entered right"

        break

fi

done





command-line bash scripts




command-line bash scripts






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 hours ago







Roosevelt Mendieta

















asked 8 hours ago









Roosevelt MendietaRoosevelt Mendieta

3915




3915








  • 2





    If the assignment specifies bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))

    – steeldriver
    7 hours ago











  • the loop does not end when entering 25 @steeldriver

    – Roosevelt Mendieta
    7 hours ago














  • 2





    If the assignment specifies bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))

    – steeldriver
    7 hours ago











  • the loop does not end when entering 25 @steeldriver

    – Roosevelt Mendieta
    7 hours ago








2




2





If the assignment specifies bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))

– steeldriver
7 hours ago





If the assignment specifies bash, then you might consider using its built-in arithmetic expansion syntax e.g. (( INPUT % 5 == 0 ))

– steeldriver
7 hours ago













the loop does not end when entering 25 @steeldriver

– Roosevelt Mendieta
7 hours ago





the loop does not end when entering 25 @steeldriver

– Roosevelt Mendieta
7 hours ago










3 Answers
3






active

oldest

votes


















3














Move the break from the else part to the if part:



#!/bin/bash



while true

do

    echo "Please input anything here: "

    read INPUT



    if [ `expr $INPUT % 5` -eq 0 ]; then

        echo "you entered wrong"

        break

    else

        echo "you entered right"

    fi

done





share|improve this answer
























  • this doesn't work, when I enter 40 the code exits

    – Roosevelt Mendieta
    7 hours ago






  • 2





    @RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.

    – Kulfy
    7 hours ago













  • @Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.

    – Roosevelt Mendieta
    7 hours ago











  • @RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.

    – Kulfy
    7 hours ago











  • i version controlled the code back to it's original state @Kulfy

    – Roosevelt Mendieta
    7 hours ago



















4














It works for me according to @steeldriver's tips,





  • make sure you use bash



    #!/bin/bash



  • use the bash syntax for arithmetic evaluation



    ((...))



Otherwise the shellscript can remain the same,



#!/bin/bash



while true

do

    echo "Please input anything here: "

    read INPUT



    if (( INPUT % 5 == 0 )) ; then

        echo "you entered right"

        break

    else

        echo "you entered wrong"

    fi

done


Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)






share|improve this answer

































    3














    Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))



    $ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
    
Enter number:11
    
alright
    
Enter number:7
    
alright
    
Enter number:10
    
Wrong


    Portably, you might want to use [ aka test



    $ [ $((25%5)) -eq 0 ]  && echo "Zero"
    
Zero
    
$ [ $((26%5)) -eq 0 ]  && echo "Zero"
    
$





    share|improve this answer


























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      Move the break from the else part to the if part:



      #!/bin/bash
      

      
while true
      
do
      
    echo "Please input anything here: "
      
    read INPUT
      

      
    if [ `expr $INPUT % 5` -eq 0 ]; then
      
        echo "you entered wrong"
      
        break
      
    else
      
        echo "you entered right"
      
    fi
      
done





      share|improve this answer
























      • this doesn't work, when I enter 40 the code exits

        – Roosevelt Mendieta
        7 hours ago






      • 2





        @RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.

        – Kulfy
        7 hours ago













      • @Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.

        – Roosevelt Mendieta
        7 hours ago











      • @RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.

        – Kulfy
        7 hours ago











      • i version controlled the code back to it's original state @Kulfy

        – Roosevelt Mendieta
        7 hours ago
















      3














      Move the break from the else part to the if part:



      #!/bin/bash
      

      
while true
      
do
      
    echo "Please input anything here: "
      
    read INPUT
      

      
    if [ `expr $INPUT % 5` -eq 0 ]; then
      
        echo "you entered wrong"
      
        break
      
    else
      
        echo "you entered right"
      
    fi
      
done





      share|improve this answer
























      • this doesn't work, when I enter 40 the code exits

        – Roosevelt Mendieta
        7 hours ago






      • 2





        @RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.

        – Kulfy
        7 hours ago













      • @Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.

        – Roosevelt Mendieta
        7 hours ago











      • @RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.

        – Kulfy
        7 hours ago











      • i version controlled the code back to it's original state @Kulfy

        – Roosevelt Mendieta
        7 hours ago














      3












      3








      3







      Move the break from the else part to the if part:



      #!/bin/bash
      

      
while true
      
do
      
    echo "Please input anything here: "
      
    read INPUT
      

      
    if [ `expr $INPUT % 5` -eq 0 ]; then
      
        echo "you entered wrong"
      
        break
      
    else
      
        echo "you entered right"
      
    fi
      
done





      share|improve this answer













      Move the break from the else part to the if part:



      #!/bin/bash
      

      
while true
      
do
      
    echo "Please input anything here: "
      
    read INPUT
      

      
    if [ `expr $INPUT % 5` -eq 0 ]; then
      
        echo "you entered wrong"
      
        break
      
    else
      
        echo "you entered right"
      
    fi
      
done






      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered 8 hours ago









      PerlDuckPerlDuck

      7,90611636




      7,90611636













      • this doesn't work, when I enter 40 the code exits

        – Roosevelt Mendieta
        7 hours ago






      • 2





        @RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.

        – Kulfy
        7 hours ago













      • @Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.

        – Roosevelt Mendieta
        7 hours ago











      • @RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.

        – Kulfy
        7 hours ago











      • i version controlled the code back to it's original state @Kulfy

        – Roosevelt Mendieta
        7 hours ago



















      • this doesn't work, when I enter 40 the code exits

        – Roosevelt Mendieta
        7 hours ago






      • 2





        @RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.

        – Kulfy
        7 hours ago













      • @Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.

        – Roosevelt Mendieta
        7 hours ago











      • @RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.

        – Kulfy
        7 hours ago











      • i version controlled the code back to it's original state @Kulfy

        – Roosevelt Mendieta
        7 hours ago

















      this doesn't work, when I enter 40 the code exits

      – Roosevelt Mendieta
      7 hours ago





      this doesn't work, when I enter 40 the code exits

      – Roosevelt Mendieta
      7 hours ago




      2




      2





      @RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.

      – Kulfy
      7 hours ago







      @RooseveltMendieta Isn't it what you want? I need to break out of a true while loop when the user inputs a number that gives a modulus remainder of 0. 40%5 is also 0.

      – Kulfy
      7 hours ago















      @Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.

      – Roosevelt Mendieta
      7 hours ago





      @Kulfy i was thinking of division in my head instead of modulus, how embarrassing lol yes this solution in fact does work and is exactly what I needed. I need to go to sleep i've been up to late working on this assignment.

      – Roosevelt Mendieta
      7 hours ago













      @RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.

      – Kulfy
      7 hours ago





      @RooseveltMendieta It seems that you changed the original code in your question. So, PerlDuck might need to modify explanation of the answer.

      – Kulfy
      7 hours ago













      i version controlled the code back to it's original state @Kulfy

      – Roosevelt Mendieta
      7 hours ago





      i version controlled the code back to it's original state @Kulfy

      – Roosevelt Mendieta
      7 hours ago













      4














      It works for me according to @steeldriver's tips,





      • make sure you use bash



        #!/bin/bash



      • use the bash syntax for arithmetic evaluation



        ((...))



      Otherwise the shellscript can remain the same,



      #!/bin/bash
      

      
while true
      
do
      
    echo "Please input anything here: "
      
    read INPUT
      

      
    if (( INPUT % 5 == 0 )) ; then
      
        echo "you entered right"
      
        break
      
    else
      
        echo "you entered wrong"
      
    fi
      
done


      Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)






      share|improve this answer






























        4














        It works for me according to @steeldriver's tips,





        • make sure you use bash



          #!/bin/bash



        • use the bash syntax for arithmetic evaluation



          ((...))



        Otherwise the shellscript can remain the same,



        #!/bin/bash
        

        
while true
        
do
        
    echo "Please input anything here: "
        
    read INPUT
        

        
    if (( INPUT % 5 == 0 )) ; then
        
        echo "you entered right"
        
        break
        
    else
        
        echo "you entered wrong"
        
    fi
        
done


        Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)






        share|improve this answer




























          4












          4








          4







          It works for me according to @steeldriver's tips,





          • make sure you use bash



            #!/bin/bash



          • use the bash syntax for arithmetic evaluation



            ((...))



          Otherwise the shellscript can remain the same,



          #!/bin/bash
          

          
while true
          
do
          
    echo "Please input anything here: "
          
    read INPUT
          

          
    if (( INPUT % 5 == 0 )) ; then
          
        echo "you entered right"
          
        break
          
    else
          
        echo "you entered wrong"
          
    fi
          
done


          Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)






          share|improve this answer















          It works for me according to @steeldriver's tips,





          • make sure you use bash



            #!/bin/bash



          • use the bash syntax for arithmetic evaluation



            ((...))



          Otherwise the shellscript can remain the same,



          #!/bin/bash
          

          
while true
          
do
          
    echo "Please input anything here: "
          
    read INPUT
          

          
    if (( INPUT % 5 == 0 )) ; then
          
        echo "you entered right"
          
        break
          
    else
          
        echo "you entered wrong"
          
    fi
          
done


          Edit: You have modified the question. This answer corresponds to a previous version of the question. (It is not clear to me, if you want to break the loop, when there is no remainder or when there is a remainder.)







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 7 hours ago

























          answered 7 hours ago









          sudodussudodus

          25.6k33078




          25.6k33078























              3














              Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))



              $ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
              
Enter number:11
              
alright
              
Enter number:7
              
alright
              
Enter number:10
              
Wrong


              Portably, you might want to use [ aka test



              $ [ $((25%5)) -eq 0 ]  && echo "Zero"
              
Zero
              
$ [ $((26%5)) -eq 0 ]  && echo "Zero"
              
$





              share|improve this answer






























                3














                Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))



                $ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
                
Enter number:11
                
alright
                
Enter number:7
                
alright
                
Enter number:10
                
Wrong


                Portably, you might want to use [ aka test



                $ [ $((25%5)) -eq 0 ]  && echo "Zero"
                
Zero
                
$ [ $((26%5)) -eq 0 ]  && echo "Zero"
                
$





                share|improve this answer




























                  3












                  3








                  3







                  Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))



                  $ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
                  
Enter number:11
                  
alright
                  
Enter number:7
                  
alright
                  
Enter number:10
                  
Wrong


                  Portably, you might want to use [ aka test



                  $ [ $((25%5)) -eq 0 ]  && echo "Zero"
                  
Zero
                  
$ [ $((26%5)) -eq 0 ]  && echo "Zero"
                  
$





                  share|improve this answer















                  Since this is bash script we're talking about, you may want to use read -p and arithmetic evaluation ((...))



                  $ while read -p "Enter number:" input ; do (( input%5 == 0 )) && { echo "Wrong"; break;} || echo "alright"; done
                  
Enter number:11
                  
alright
                  
Enter number:7
                  
alright
                  
Enter number:10
                  
Wrong


                  Portably, you might want to use [ aka test



                  $ [ $((25%5)) -eq 0 ]  && echo "Zero"
                  
Zero
                  
$ [ $((26%5)) -eq 0 ]  && echo "Zero"
                  
$






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 7 hours ago

























                  answered 7 hours ago









                  Sergiy KolodyazhnyySergiy Kolodyazhnyy

                  74.8k9155325




                  74.8k9155325






























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