Searching Index from list of tuples












0















I have a sentence = "hi there, my car number is H 11231, and my card number is 11122" . I tokenized the sentence then POS tagged the tokenized sentence. I want to grab the car number, I created a loop to check if the index is at a number lets say (11231). Then check 1 tuple before or after if it has the tag NNP (which stands for 1 Letter)



import nltk



sentence = 'hi there, my car number is H 11231, and my card number is 11122'



tokenizedSent = nltk.word_tokenize(sentence)

tagged = nltk.pos_tag(tokenizedSent)

print(tagged)

output = 



print(tagged)

for i in tagged: 

    if i[1] == 'CD':

        output.append(i[0])

    elif i[1] == 'NNP':

        output.append(i[0])


The sentence has two numbers which are 11231 and 11122. However, only one of them is the car number which is the one before is tagged by NNP






python







share|improve this question




















  • 1





    Please type-in the code and the output in the question instead of posting screenshot

    – Andreas
    Nov 28 '18 at 8:26
















0















I have a sentence = "hi there, my car number is H 11231, and my card number is 11122" . I tokenized the sentence then POS tagged the tokenized sentence. I want to grab the car number, I created a loop to check if the index is at a number lets say (11231). Then check 1 tuple before or after if it has the tag NNP (which stands for 1 Letter)



import nltk



sentence = 'hi there, my car number is H 11231, and my card number is 11122'



tokenizedSent = nltk.word_tokenize(sentence)

tagged = nltk.pos_tag(tokenizedSent)

print(tagged)

output = 



print(tagged)

for i in tagged: 

    if i[1] == 'CD':

        output.append(i[0])

    elif i[1] == 'NNP':

        output.append(i[0])


The sentence has two numbers which are 11231 and 11122. However, only one of them is the car number which is the one before is tagged by NNP






python







share|improve this question




















  • 1





    Please type-in the code and the output in the question instead of posting screenshot

    – Andreas
    Nov 28 '18 at 8:26














0












0








0








I have a sentence = "hi there, my car number is H 11231, and my card number is 11122" . I tokenized the sentence then POS tagged the tokenized sentence. I want to grab the car number, I created a loop to check if the index is at a number lets say (11231). Then check 1 tuple before or after if it has the tag NNP (which stands for 1 Letter)



import nltk



sentence = 'hi there, my car number is H 11231, and my card number is 11122'



tokenizedSent = nltk.word_tokenize(sentence)

tagged = nltk.pos_tag(tokenizedSent)

print(tagged)

output = 



print(tagged)

for i in tagged: 

    if i[1] == 'CD':

        output.append(i[0])

    elif i[1] == 'NNP':

        output.append(i[0])


The sentence has two numbers which are 11231 and 11122. However, only one of them is the car number which is the one before is tagged by NNP






python







share|improve this question
















I have a sentence = "hi there, my car number is H 11231, and my card number is 11122" . I tokenized the sentence then POS tagged the tokenized sentence. I want to grab the car number, I created a loop to check if the index is at a number lets say (11231). Then check 1 tuple before or after if it has the tag NNP (which stands for 1 Letter)



import nltk



sentence = 'hi there, my car number is H 11231, and my card number is 11122'



tokenizedSent = nltk.word_tokenize(sentence)

tagged = nltk.pos_tag(tokenizedSent)

print(tagged)

output = 



print(tagged)

for i in tagged: 

    if i[1] == 'CD':

        output.append(i[0])

    elif i[1] == 'NNP':

        output.append(i[0])


The sentence has two numbers which are 11231 and 11122. However, only one of them is the car number which is the one before is tagged by NNP






python




python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 28 '18 at 8:52









Andreas

2,05731323




2,05731323










asked Nov 28 '18 at 8:21









Abdulla AhliAbdulla Ahli

52




52








  • 1





    Please type-in the code and the output in the question instead of posting screenshot

    – Andreas
    Nov 28 '18 at 8:26














  • 1





    Please type-in the code and the output in the question instead of posting screenshot

    – Andreas
    Nov 28 '18 at 8:26








1




1





Please type-in the code and the output in the question instead of posting screenshot

– Andreas
Nov 28 '18 at 8:26





Please type-in the code and the output in the question instead of posting screenshot

– Andreas
Nov 28 '18 at 8:26












1 Answer
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Your solution traverse the collection of tag and only takes CD and NNP tags.



You want only numbers.



so first thing to do : get the numbers : 



IndexTag = namedtuple('IndexTag', ['tag', 'index'])

numbers = 

for i, tag in enumerate(tagged):

    if tag[1] == 'number':

        numbers.append(IndexTag(tag, i))


now that you have your numbers you can check that the "previous tag is NNP" :



car_ids = 

for number in numbers:

    if number.index > 0 and tagged[number.index - 1][1] == 'NNP':

       car_ids.append(number)





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    Your solution traverse the collection of tag and only takes CD and NNP tags.



    You want only numbers.



    so first thing to do : get the numbers : 



    IndexTag = namedtuple('IndexTag', ['tag', 'index'])
    
numbers = 
    
for i, tag in enumerate(tagged):
    
    if tag[1] == 'number':
    
        numbers.append(IndexTag(tag, i))


    now that you have your numbers you can check that the "previous tag is NNP" :



    car_ids = 
    
for number in numbers:
    
    if number.index > 0 and tagged[number.index - 1][1] == 'NNP':
    
       car_ids.append(number)





    share|improve this answer




























      0














      Your solution traverse the collection of tag and only takes CD and NNP tags.



      You want only numbers.



      so first thing to do : get the numbers : 



      IndexTag = namedtuple('IndexTag', ['tag', 'index'])
      
numbers = 
      
for i, tag in enumerate(tagged):
      
    if tag[1] == 'number':
      
        numbers.append(IndexTag(tag, i))


      now that you have your numbers you can check that the "previous tag is NNP" :



      car_ids = 
      
for number in numbers:
      
    if number.index > 0 and tagged[number.index - 1][1] == 'NNP':
      
       car_ids.append(number)





      share|improve this answer


























        0












        0








        0







        Your solution traverse the collection of tag and only takes CD and NNP tags.



        You want only numbers.



        so first thing to do : get the numbers : 



        IndexTag = namedtuple('IndexTag', ['tag', 'index'])
        
numbers = 
        
for i, tag in enumerate(tagged):
        
    if tag[1] == 'number':
        
        numbers.append(IndexTag(tag, i))


        now that you have your numbers you can check that the "previous tag is NNP" :



        car_ids = 
        
for number in numbers:
        
    if number.index > 0 and tagged[number.index - 1][1] == 'NNP':
        
       car_ids.append(number)





        share|improve this answer













        Your solution traverse the collection of tag and only takes CD and NNP tags.



        You want only numbers.



        so first thing to do : get the numbers : 



        IndexTag = namedtuple('IndexTag', ['tag', 'index'])
        
numbers = 
        
for i, tag in enumerate(tagged):
        
    if tag[1] == 'number':
        
        numbers.append(IndexTag(tag, i))


        now that you have your numbers you can check that the "previous tag is NNP" :



        car_ids = 
        
for number in numbers:
        
    if number.index > 0 and tagged[number.index - 1][1] == 'NNP':
        
       car_ids.append(number)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 28 '18 at 8:30









        artragisartragis

        3,47911225




        3,47911225
































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