why is my callback function not updating my var in React
How can I access "string value"
outside the scope of the callback
function. Please forgive my primitive knowledge as i'm new to callbacks.
render() {
let test = '';
let callback = (string) => {
test = string
console.log <----returns "string value"
}
console.log(test) <-----returns empty string
console.log()
return (
<div>
{callback("string value")}
</div>
);
}
}
javascript reactjs ecmascript-6
add a comment |
How can I access "string value"
outside the scope of the callback
function. Please forgive my primitive knowledge as i'm new to callbacks.
render() {
let test = '';
let callback = (string) => {
test = string
console.log <----returns "string value"
}
console.log(test) <-----returns empty string
console.log()
return (
<div>
{callback("string value")}
</div>
);
}
}
javascript reactjs ecmascript-6
1
Because when youconsole.log(test)
, thecallback
function has not yet been called (it happens later in thereturn
statement).
– Bergi
Nov 24 '18 at 22:50
When you call console.log the callback function hasn't been called yet so the value oftest
is still the empty string. I'm not sure what is the point though, what are you trying to do?
– Stefan
Nov 24 '18 at 22:50
Btw, I don't see any callback function here that would be passed around, it's just a normal local function. Is this your actual code?
– Bergi
Nov 24 '18 at 22:51
add a comment |
How can I access "string value"
outside the scope of the callback
function. Please forgive my primitive knowledge as i'm new to callbacks.
render() {
let test = '';
let callback = (string) => {
test = string
console.log <----returns "string value"
}
console.log(test) <-----returns empty string
console.log()
return (
<div>
{callback("string value")}
</div>
);
}
}
javascript reactjs ecmascript-6
How can I access "string value"
outside the scope of the callback
function. Please forgive my primitive knowledge as i'm new to callbacks.
render() {
let test = '';
let callback = (string) => {
test = string
console.log <----returns "string value"
}
console.log(test) <-----returns empty string
console.log()
return (
<div>
{callback("string value")}
</div>
);
}
}
javascript reactjs ecmascript-6
javascript reactjs ecmascript-6
asked Nov 24 '18 at 22:44
RayRay
347
347
1
Because when youconsole.log(test)
, thecallback
function has not yet been called (it happens later in thereturn
statement).
– Bergi
Nov 24 '18 at 22:50
When you call console.log the callback function hasn't been called yet so the value oftest
is still the empty string. I'm not sure what is the point though, what are you trying to do?
– Stefan
Nov 24 '18 at 22:50
Btw, I don't see any callback function here that would be passed around, it's just a normal local function. Is this your actual code?
– Bergi
Nov 24 '18 at 22:51
add a comment |
1
Because when youconsole.log(test)
, thecallback
function has not yet been called (it happens later in thereturn
statement).
– Bergi
Nov 24 '18 at 22:50
When you call console.log the callback function hasn't been called yet so the value oftest
is still the empty string. I'm not sure what is the point though, what are you trying to do?
– Stefan
Nov 24 '18 at 22:50
Btw, I don't see any callback function here that would be passed around, it's just a normal local function. Is this your actual code?
– Bergi
Nov 24 '18 at 22:51
1
1
Because when you
console.log(test)
, the callback
function has not yet been called (it happens later in the return
statement).– Bergi
Nov 24 '18 at 22:50
Because when you
console.log(test)
, the callback
function has not yet been called (it happens later in the return
statement).– Bergi
Nov 24 '18 at 22:50
When you call console.log the callback function hasn't been called yet so the value of
test
is still the empty string. I'm not sure what is the point though, what are you trying to do?– Stefan
Nov 24 '18 at 22:50
When you call console.log the callback function hasn't been called yet so the value of
test
is still the empty string. I'm not sure what is the point though, what are you trying to do?– Stefan
Nov 24 '18 at 22:50
Btw, I don't see any callback function here that would be passed around, it's just a normal local function. Is this your actual code?
– Bergi
Nov 24 '18 at 22:51
Btw, I don't see any callback function here that would be passed around, it's just a normal local function. Is this your actual code?
– Bergi
Nov 24 '18 at 22:51
add a comment |
1 Answer
1
active
oldest
votes
You simply need to return test (or string) at the end of your callback function.
The return statement ends function execution and specifies a value to
be returned to the function caller.
Check the below code:
render() {
let test = '';
let callback = (string) => {
test = string;
return test;
}
return (
<div>
{callback("string value")}
</div>
);
}
}
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You simply need to return test (or string) at the end of your callback function.
The return statement ends function execution and specifies a value to
be returned to the function caller.
Check the below code:
render() {
let test = '';
let callback = (string) => {
test = string;
return test;
}
return (
<div>
{callback("string value")}
</div>
);
}
}
add a comment |
You simply need to return test (or string) at the end of your callback function.
The return statement ends function execution and specifies a value to
be returned to the function caller.
Check the below code:
render() {
let test = '';
let callback = (string) => {
test = string;
return test;
}
return (
<div>
{callback("string value")}
</div>
);
}
}
add a comment |
You simply need to return test (or string) at the end of your callback function.
The return statement ends function execution and specifies a value to
be returned to the function caller.
Check the below code:
render() {
let test = '';
let callback = (string) => {
test = string;
return test;
}
return (
<div>
{callback("string value")}
</div>
);
}
}
You simply need to return test (or string) at the end of your callback function.
The return statement ends function execution and specifies a value to
be returned to the function caller.
Check the below code:
render() {
let test = '';
let callback = (string) => {
test = string;
return test;
}
return (
<div>
{callback("string value")}
</div>
);
}
}
edited Nov 24 '18 at 23:06
answered Nov 24 '18 at 22:57
Hassan AlMandilHassan AlMandil
2315
2315
add a comment |
add a comment |
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1
Because when you
console.log(test)
, thecallback
function has not yet been called (it happens later in thereturn
statement).– Bergi
Nov 24 '18 at 22:50
When you call console.log the callback function hasn't been called yet so the value of
test
is still the empty string. I'm not sure what is the point though, what are you trying to do?– Stefan
Nov 24 '18 at 22:50
Btw, I don't see any callback function here that would be passed around, it's just a normal local function. Is this your actual code?
– Bergi
Nov 24 '18 at 22:51