How can I group multiple columns into an object when making a database call in Laravel?
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
add a comment |
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
add a comment |
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
Let's say I am fetching users
Each user has 10 columns associated with it
How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?
I could do
foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}
But surely there is a way to group columns into an object on Laravel?
For example, something like
$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();
Or is there a way for me to update my User model to do this?
php mysql laravel eloquent
php mysql laravel eloquent
edited Nov 24 '18 at 23:14
Dazzle
asked Nov 24 '18 at 21:32
DazzleDazzle
5802626
5802626
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
add a comment |
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43
add a comment |
2 Answers
2
active
oldest
votes
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends
attribute inside that model:
protected $appends = [
'new_obj',
];
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends
attribute inside that model:
protected $appends = [
'new_obj',
];
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends
attribute inside that model:
protected $appends = [
'new_obj',
];
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends
attribute inside that model:
protected $appends = [
'new_obj',
];
You can use mutators in your model:
public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}
And in $appends
attribute inside that model:
protected $appends = [
'new_obj',
];
answered Nov 25 '18 at 8:42
Ali FarhoudiAli Farhoudi
81411134
81411134
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
This is the correct answer. Thank you sir!!!
– Dazzle
Nov 25 '18 at 13:55
1
1
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication
– Dazzle
Nov 25 '18 at 15:06
add a comment |
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
you can do something like this:
$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});
edited Nov 24 '18 at 22:00
answered Nov 24 '18 at 21:49
Eriks KlotinsEriks Klotins
1,139516
1,139516
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?
– Dazzle
Nov 24 '18 at 21:58
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)
– Eriks Klotins
Nov 24 '18 at 22:04
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!
– Dazzle
Nov 24 '18 at 22:07
add a comment |
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Use collections to manipulate data within the PHP. Good Luck!
– Kyslik
Nov 24 '18 at 21:43