How can I group multiple columns into an object when making a database call in Laravel?












0















Let's say I am fetching users



Each user has 10 columns associated with it



How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?



I could do



foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}


But surely there is a way to group columns into an object on Laravel?



For example, something like



$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();


Or is there a way for me to update my User model to do this?










share|improve this question

























  • Use collections to manipulate data within the PHP. Good Luck!

    – Kyslik
    Nov 24 '18 at 21:43
















0















Let's say I am fetching users



Each user has 10 columns associated with it



How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?



I could do



foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}


But surely there is a way to group columns into an object on Laravel?



For example, something like



$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();


Or is there a way for me to update my User model to do this?










share|improve this question

























  • Use collections to manipulate data within the PHP. Good Luck!

    – Kyslik
    Nov 24 '18 at 21:43














0












0








0








Let's say I am fetching users



Each user has 10 columns associated with it



How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?



I could do



foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}


But surely there is a way to group columns into an object on Laravel?



For example, something like



$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();


Or is there a way for me to update my User model to do this?










share|improve this question
















Let's say I am fetching users



Each user has 10 columns associated with it



How can I group 5 columns together into an object on each user so I can more easily map over them with javascript?



I could do



foreach ($users as $user)
{
$user['new_object']['col_1'] = $user->col_1;
unset($user->col_1);
$user['new_object']['col_2'] = $user->col_2;
// etc
}


But surely there is a way to group columns into an object on Laravel?



For example, something like



$users = User::where('verified', 1)
->group('new_object', ['col_1', 'col_2', 'col_3']),
->get();


Or is there a way for me to update my User model to do this?







php mysql laravel eloquent






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 23:14







Dazzle

















asked Nov 24 '18 at 21:32









DazzleDazzle

5802626




5802626













  • Use collections to manipulate data within the PHP. Good Luck!

    – Kyslik
    Nov 24 '18 at 21:43



















  • Use collections to manipulate data within the PHP. Good Luck!

    – Kyslik
    Nov 24 '18 at 21:43

















Use collections to manipulate data within the PHP. Good Luck!

– Kyslik
Nov 24 '18 at 21:43





Use collections to manipulate data within the PHP. Good Luck!

– Kyslik
Nov 24 '18 at 21:43












2 Answers
2






active

oldest

votes


















1














You can use mutators in your model:



public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}


And in $appends attribute inside that model:



protected $appends = [
'new_obj',
];





share|improve this answer
























  • This is the correct answer. Thank you sir!!!

    – Dazzle
    Nov 25 '18 at 13:55






  • 1





    Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication

    – Dazzle
    Nov 25 '18 at 15:06



















2














you can do something like this:



$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});





share|improve this answer


























  • That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?

    – Dazzle
    Nov 24 '18 at 21:58













  • See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)

    – Eriks Klotins
    Nov 24 '18 at 22:04











  • Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!

    – Dazzle
    Nov 24 '18 at 22:07













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














You can use mutators in your model:



public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}


And in $appends attribute inside that model:



protected $appends = [
'new_obj',
];





share|improve this answer
























  • This is the correct answer. Thank you sir!!!

    – Dazzle
    Nov 25 '18 at 13:55






  • 1





    Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication

    – Dazzle
    Nov 25 '18 at 15:06
















1














You can use mutators in your model:



public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}


And in $appends attribute inside that model:



protected $appends = [
'new_obj',
];





share|improve this answer
























  • This is the correct answer. Thank you sir!!!

    – Dazzle
    Nov 25 '18 at 13:55






  • 1





    Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication

    – Dazzle
    Nov 25 '18 at 15:06














1












1








1







You can use mutators in your model:



public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}


And in $appends attribute inside that model:



protected $appends = [
'new_obj',
];





share|improve this answer













You can use mutators in your model:



public function getNewObjAttribute() {
return [
$this->col1,
$this->col2,
$this->col3,
];
}


And in $appends attribute inside that model:



protected $appends = [
'new_obj',
];






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 25 '18 at 8:42









Ali FarhoudiAli Farhoudi

81411134




81411134













  • This is the correct answer. Thank you sir!!!

    – Dazzle
    Nov 25 '18 at 13:55






  • 1





    Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication

    – Dazzle
    Nov 25 '18 at 15:06



















  • This is the correct answer. Thank you sir!!!

    – Dazzle
    Nov 25 '18 at 13:55






  • 1





    Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication

    – Dazzle
    Nov 25 '18 at 15:06

















This is the correct answer. Thank you sir!!!

– Dazzle
Nov 25 '18 at 13:55





This is the correct answer. Thank you sir!!!

– Dazzle
Nov 25 '18 at 13:55




1




1





Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication

– Dazzle
Nov 25 '18 at 15:06





Also remember to add protected $hidden = ['col_1', 'col_2']; to avoid duplication

– Dazzle
Nov 25 '18 at 15:06













2














you can do something like this:



$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});





share|improve this answer


























  • That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?

    – Dazzle
    Nov 24 '18 at 21:58













  • See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)

    – Eriks Klotins
    Nov 24 '18 at 22:04











  • Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!

    – Dazzle
    Nov 24 '18 at 22:07


















2














you can do something like this:



$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});





share|improve this answer


























  • That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?

    – Dazzle
    Nov 24 '18 at 21:58













  • See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)

    – Eriks Klotins
    Nov 24 '18 at 22:04











  • Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!

    – Dazzle
    Nov 24 '18 at 22:07
















2












2








2







you can do something like this:



$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});





share|improve this answer















you can do something like this:



$users = User::where('verified', 1)->get()->map(function($row)
{
$row->new_obj = [$row->col1, $row->col2, $row->col3];
unset($row->col1, $row->col2, $row->col3);
return $row;
});






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 24 '18 at 22:00

























answered Nov 24 '18 at 21:49









Eriks KlotinsEriks Klotins

1,139516




1,139516













  • That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?

    – Dazzle
    Nov 24 '18 at 21:58













  • See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)

    – Eriks Klotins
    Nov 24 '18 at 22:04











  • Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!

    – Dazzle
    Nov 24 '18 at 22:07





















  • That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?

    – Dazzle
    Nov 24 '18 at 21:58













  • See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)

    – Eriks Klotins
    Nov 24 '18 at 22:04











  • Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!

    – Dazzle
    Nov 24 '18 at 22:07



















That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?

– Dazzle
Nov 24 '18 at 21:58







That works but I was hoping not to have to map / loop over all of them and build this query on the fly. Also, how to drop the columns that are now grouped?

– Dazzle
Nov 24 '18 at 21:58















See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)

– Eriks Klotins
Nov 24 '18 at 22:04





See my updated solution. Looping over the items is that expensive (well as long as you do not have zillions of them)

– Eriks Klotins
Nov 24 '18 at 22:04













Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!

– Dazzle
Nov 24 '18 at 22:07







Good call on the unset. Happy to give this the correct answer for now until a refactor comes along ;-) Thank you!

– Dazzle
Nov 24 '18 at 22:07




















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