Reading YAML with Jackson ignores keys without values
I have the following YAML file:
---
-
id: 001
start: 21.11.2018
additional:
dependency:
result: 2
which I like to read in with jackson as a simple List<Map<String, Object>>.
For this I use the following code
private List<Map<String, Object>> readDefaultInputAsMap() {
var objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
return objectMapper.readValue(inputResource, new TypeReference<List<Map<String, Object>>>() {
});
} catch (IOException e) {
e.printStackTrace();
return new ArrayList<>();
}
}
Unfortunately, this returns a map with only id, start and result, so the two others are ignored.
How can I get Jackson to parse the file and create the full map and with e.g. null as values for the empy keys ? (Or any other default value)?
java jackson yaml
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
add a comment |
I have the following YAML file:
---
-
id: 001
start: 21.11.2018
additional:
dependency:
result: 2
which I like to read in with jackson as a simple List<Map<String, Object>>.
For this I use the following code
private List<Map<String, Object>> readDefaultInputAsMap() {
var objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
return objectMapper.readValue(inputResource, new TypeReference<List<Map<String, Object>>>() {
});
} catch (IOException e) {
e.printStackTrace();
return new ArrayList<>();
}
}
Unfortunately, this returns a map with only id, start and result, so the two others are ignored.
How can I get Jackson to parse the file and create the full map and with e.g. null as values for the empy keys ? (Or any other default value)?
java jackson yaml
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
add a comment |
I have the following YAML file:
---
-
id: 001
start: 21.11.2018
additional:
dependency:
result: 2
which I like to read in with jackson as a simple List<Map<String, Object>>.
For this I use the following code
private List<Map<String, Object>> readDefaultInputAsMap() {
var objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
return objectMapper.readValue(inputResource, new TypeReference<List<Map<String, Object>>>() {
});
} catch (IOException e) {
e.printStackTrace();
return new ArrayList<>();
}
}
Unfortunately, this returns a map with only id, start and result, so the two others are ignored.
How can I get Jackson to parse the file and create the full map and with e.g. null as values for the empy keys ? (Or any other default value)?
java jackson yaml
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
I have the following YAML file:
---
-
id: 001
start: 21.11.2018
additional:
dependency:
result: 2
which I like to read in with jackson as a simple List<Map<String, Object>>.
For this I use the following code
private List<Map<String, Object>> readDefaultInputAsMap() {
var objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
return objectMapper.readValue(inputResource, new TypeReference<List<Map<String, Object>>>() {
});
} catch (IOException e) {
e.printStackTrace();
return new ArrayList<>();
}
}
Unfortunately, this returns a map with only id, start and result, so the two others are ignored.
How can I get Jackson to parse the file and create the full map and with e.g. null as values for the empy keys ? (Or any other default value)?
java jackson yaml
java jackson yaml
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
asked Nov 24 '18 at 22:47
Emerson CodEmerson Cod
1,1371722
1,1371722
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Actually, it does that by default. Double-check the format of your YML (because your example seems to be invalid). Here is what worked for me:
test.yml:
---
- id: 001
start: 21.11.2018
additional:
dependency:
result: 2
Test.java:
public class App {
public static void main(String args) {
ObjectMapper objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
final Object value = objectMapper.readValue(App.class.getResource("test.yml"), new TypeReference<List<Map<String, Object>>>() {
});
System.out.println(value);
} catch (IOException e) {
e.printStackTrace();
}
}
}
And I got the result:
[{id=1, start=21.11.2018, additional=null, dependency=null, result=2}]
As you see, additional and dependency are both null.
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
acutally, the format of the yaml file seems not to be a problem. But I have found my error, which is false check at another part of the code, so you are absolutely right about the default behavior
– Emerson Cod
Nov 25 '18 at 1:38
add a comment |
You should create your own Object (new class) with all possible attributes you want, for instance:
class MyCompleteInfo {
String id;
String start;
String additional;
String dependency;
String result;
}
And use a List of it (as method return, and in your reader):
List<MyCompleteInfo >
Edit: You may have used @JsonInclude(Include.NON_EMPTY) somewhere?
You must not.
See documentation.
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
i do not know beforehand the attributes to build a class
– Emerson Cod
Nov 25 '18 at 1:30
You may have used @JsonInclude(Include.NON_EMPTY) somewhere? You shouldn't.
– Bsquare
Nov 25 '18 at 1:51
On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Dec 30 '18 at 14:49
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Actually, it does that by default. Double-check the format of your YML (because your example seems to be invalid). Here is what worked for me:
test.yml:
---
- id: 001
start: 21.11.2018
additional:
dependency:
result: 2
Test.java:
public class App {
public static void main(String args) {
ObjectMapper objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
final Object value = objectMapper.readValue(App.class.getResource("test.yml"), new TypeReference<List<Map<String, Object>>>() {
});
System.out.println(value);
} catch (IOException e) {
e.printStackTrace();
}
}
}
And I got the result:
[{id=1, start=21.11.2018, additional=null, dependency=null, result=2}]
As you see, additional and dependency are both null.
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
acutally, the format of the yaml file seems not to be a problem. But I have found my error, which is false check at another part of the code, so you are absolutely right about the default behavior
– Emerson Cod
Nov 25 '18 at 1:38
add a comment |
Actually, it does that by default. Double-check the format of your YML (because your example seems to be invalid). Here is what worked for me:
test.yml:
---
- id: 001
start: 21.11.2018
additional:
dependency:
result: 2
Test.java:
public class App {
public static void main(String args) {
ObjectMapper objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
final Object value = objectMapper.readValue(App.class.getResource("test.yml"), new TypeReference<List<Map<String, Object>>>() {
});
System.out.println(value);
} catch (IOException e) {
e.printStackTrace();
}
}
}
And I got the result:
[{id=1, start=21.11.2018, additional=null, dependency=null, result=2}]
As you see, additional and dependency are both null.
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
acutally, the format of the yaml file seems not to be a problem. But I have found my error, which is false check at another part of the code, so you are absolutely right about the default behavior
– Emerson Cod
Nov 25 '18 at 1:38
add a comment |
Actually, it does that by default. Double-check the format of your YML (because your example seems to be invalid). Here is what worked for me:
test.yml:
---
- id: 001
start: 21.11.2018
additional:
dependency:
result: 2
Test.java:
public class App {
public static void main(String args) {
ObjectMapper objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
final Object value = objectMapper.readValue(App.class.getResource("test.yml"), new TypeReference<List<Map<String, Object>>>() {
});
System.out.println(value);
} catch (IOException e) {
e.printStackTrace();
}
}
}
And I got the result:
[{id=1, start=21.11.2018, additional=null, dependency=null, result=2}]
As you see, additional and dependency are both null.
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
Actually, it does that by default. Double-check the format of your YML (because your example seems to be invalid). Here is what worked for me:
test.yml:
---
- id: 001
start: 21.11.2018
additional:
dependency:
result: 2
Test.java:
public class App {
public static void main(String args) {
ObjectMapper objectMapper = new ObjectMapper(new YAMLFactory());
objectMapper.setDateFormat(new SimpleDateFormat("dd.MM.yyyy"));
try {
final Object value = objectMapper.readValue(App.class.getResource("test.yml"), new TypeReference<List<Map<String, Object>>>() {
});
System.out.println(value);
} catch (IOException e) {
e.printStackTrace();
}
}
}
And I got the result:
[{id=1, start=21.11.2018, additional=null, dependency=null, result=2}]
As you see, additional and dependency are both null.
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
answered Nov 25 '18 at 0:16
madheadmadhead
14.4k1383123
14.4k1383123
acutally, the format of the yaml file seems not to be a problem. But I have found my error, which is false check at another part of the code, so you are absolutely right about the default behavior
– Emerson Cod
Nov 25 '18 at 1:38
add a comment |
acutally, the format of the yaml file seems not to be a problem. But I have found my error, which is false check at another part of the code, so you are absolutely right about the default behavior
– Emerson Cod
Nov 25 '18 at 1:38
acutally, the format of the yaml file seems not to be a problem. But I have found my error, which is false check at another part of the code, so you are absolutely right about the default behavior
– Emerson Cod
Nov 25 '18 at 1:38
acutally, the format of the yaml file seems not to be a problem. But I have found my error, which is false check at another part of the code, so you are absolutely right about the default behavior
– Emerson Cod
Nov 25 '18 at 1:38
add a comment |
You should create your own Object (new class) with all possible attributes you want, for instance:
class MyCompleteInfo {
String id;
String start;
String additional;
String dependency;
String result;
}
And use a List of it (as method return, and in your reader):
List<MyCompleteInfo >
Edit: You may have used @JsonInclude(Include.NON_EMPTY) somewhere?
You must not.
See documentation.
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
i do not know beforehand the attributes to build a class
– Emerson Cod
Nov 25 '18 at 1:30
You may have used @JsonInclude(Include.NON_EMPTY) somewhere? You shouldn't.
– Bsquare
Nov 25 '18 at 1:51
On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Dec 30 '18 at 14:49
add a comment |
You should create your own Object (new class) with all possible attributes you want, for instance:
class MyCompleteInfo {
String id;
String start;
String additional;
String dependency;
String result;
}
And use a List of it (as method return, and in your reader):
List<MyCompleteInfo >
Edit: You may have used @JsonInclude(Include.NON_EMPTY) somewhere?
You must not.
See documentation.
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
i do not know beforehand the attributes to build a class
– Emerson Cod
Nov 25 '18 at 1:30
You may have used @JsonInclude(Include.NON_EMPTY) somewhere? You shouldn't.
– Bsquare
Nov 25 '18 at 1:51
On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Dec 30 '18 at 14:49
add a comment |
You should create your own Object (new class) with all possible attributes you want, for instance:
class MyCompleteInfo {
String id;
String start;
String additional;
String dependency;
String result;
}
And use a List of it (as method return, and in your reader):
List<MyCompleteInfo >
Edit: You may have used @JsonInclude(Include.NON_EMPTY) somewhere?
You must not.
See documentation.
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
You should create your own Object (new class) with all possible attributes you want, for instance:
class MyCompleteInfo {
String id;
String start;
String additional;
String dependency;
String result;
}
And use a List of it (as method return, and in your reader):
List<MyCompleteInfo >
Edit: You may have used @JsonInclude(Include.NON_EMPTY) somewhere?
You must not.
See documentation.
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
edited Nov 25 '18 at 1:52
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
answered Nov 25 '18 at 0:14
BsquareBsquare
3,31131034
3,31131034
i do not know beforehand the attributes to build a class
– Emerson Cod
Nov 25 '18 at 1:30
You may have used @JsonInclude(Include.NON_EMPTY) somewhere? You shouldn't.
– Bsquare
Nov 25 '18 at 1:51
On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Dec 30 '18 at 14:49
add a comment |
i do not know beforehand the attributes to build a class
– Emerson Cod
Nov 25 '18 at 1:30
You may have used @JsonInclude(Include.NON_EMPTY) somewhere? You shouldn't.
– Bsquare
Nov 25 '18 at 1:51
On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Dec 30 '18 at 14:49
i do not know beforehand the attributes to build a class
– Emerson Cod
Nov 25 '18 at 1:30
i do not know beforehand the attributes to build a class
– Emerson Cod
Nov 25 '18 at 1:30
You may have used @JsonInclude(Include.NON_EMPTY) somewhere? You shouldn't.
– Bsquare
Nov 25 '18 at 1:51
You may have used @JsonInclude(Include.NON_EMPTY) somewhere? You shouldn't.
– Bsquare
Nov 25 '18 at 1:51
On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Dec 30 '18 at 14:49
On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Dec 30 '18 at 14:49
add a comment |
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