laravel Get all models that have array of relations












0















I have a Product model with Tags relation:



class Product
{
public function tags()
{
return $this->belongsToMany('tags')


and



class Tags
{
public function products()
{
return $this->belongsToMany('products')


how can i retrieve products that have all of tags with id of [1,2,3]










share|improve this question




















  • 1





    try: $products->with(['tags' => function($query){ $query->whereIn('id', [1,2,3]);}]);

    – Fatemeh Majd
    Nov 24 '18 at 11:48











  • @FatemehMajd this will return products that has tags in this array. i mean a product with 1 tag_id also is in your solution

    – Joseph Rback
    Nov 24 '18 at 12:08






  • 1





    In that case, i'm now aware of the eloquent way, but you can query the tables as in: DB::table('blah_blah-1')-join('...')->...;

    – Fatemeh Majd
    Nov 24 '18 at 12:49






  • 2





    Should the products have one of these tags or all of them?

    – Jonas Staudenmeir
    Nov 24 '18 at 17:58






  • 1





    Are you wanting products that have all 3 tags?

    – Ross Wilson
    Nov 24 '18 at 18:50
















0















I have a Product model with Tags relation:



class Product
{
public function tags()
{
return $this->belongsToMany('tags')


and



class Tags
{
public function products()
{
return $this->belongsToMany('products')


how can i retrieve products that have all of tags with id of [1,2,3]










share|improve this question




















  • 1





    try: $products->with(['tags' => function($query){ $query->whereIn('id', [1,2,3]);}]);

    – Fatemeh Majd
    Nov 24 '18 at 11:48











  • @FatemehMajd this will return products that has tags in this array. i mean a product with 1 tag_id also is in your solution

    – Joseph Rback
    Nov 24 '18 at 12:08






  • 1





    In that case, i'm now aware of the eloquent way, but you can query the tables as in: DB::table('blah_blah-1')-join('...')->...;

    – Fatemeh Majd
    Nov 24 '18 at 12:49






  • 2





    Should the products have one of these tags or all of them?

    – Jonas Staudenmeir
    Nov 24 '18 at 17:58






  • 1





    Are you wanting products that have all 3 tags?

    – Ross Wilson
    Nov 24 '18 at 18:50














0












0








0


1






I have a Product model with Tags relation:



class Product
{
public function tags()
{
return $this->belongsToMany('tags')


and



class Tags
{
public function products()
{
return $this->belongsToMany('products')


how can i retrieve products that have all of tags with id of [1,2,3]










share|improve this question
















I have a Product model with Tags relation:



class Product
{
public function tags()
{
return $this->belongsToMany('tags')


and



class Tags
{
public function products()
{
return $this->belongsToMany('products')


how can i retrieve products that have all of tags with id of [1,2,3]







php laravel eloquent






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 26 '18 at 10:49







Joseph Rback

















asked Nov 24 '18 at 11:07









Joseph RbackJoseph Rback

182113




182113








  • 1





    try: $products->with(['tags' => function($query){ $query->whereIn('id', [1,2,3]);}]);

    – Fatemeh Majd
    Nov 24 '18 at 11:48











  • @FatemehMajd this will return products that has tags in this array. i mean a product with 1 tag_id also is in your solution

    – Joseph Rback
    Nov 24 '18 at 12:08






  • 1





    In that case, i'm now aware of the eloquent way, but you can query the tables as in: DB::table('blah_blah-1')-join('...')->...;

    – Fatemeh Majd
    Nov 24 '18 at 12:49






  • 2





    Should the products have one of these tags or all of them?

    – Jonas Staudenmeir
    Nov 24 '18 at 17:58






  • 1





    Are you wanting products that have all 3 tags?

    – Ross Wilson
    Nov 24 '18 at 18:50














  • 1





    try: $products->with(['tags' => function($query){ $query->whereIn('id', [1,2,3]);}]);

    – Fatemeh Majd
    Nov 24 '18 at 11:48











  • @FatemehMajd this will return products that has tags in this array. i mean a product with 1 tag_id also is in your solution

    – Joseph Rback
    Nov 24 '18 at 12:08






  • 1





    In that case, i'm now aware of the eloquent way, but you can query the tables as in: DB::table('blah_blah-1')-join('...')->...;

    – Fatemeh Majd
    Nov 24 '18 at 12:49






  • 2





    Should the products have one of these tags or all of them?

    – Jonas Staudenmeir
    Nov 24 '18 at 17:58






  • 1





    Are you wanting products that have all 3 tags?

    – Ross Wilson
    Nov 24 '18 at 18:50








1




1





try: $products->with(['tags' => function($query){ $query->whereIn('id', [1,2,3]);}]);

– Fatemeh Majd
Nov 24 '18 at 11:48





try: $products->with(['tags' => function($query){ $query->whereIn('id', [1,2,3]);}]);

– Fatemeh Majd
Nov 24 '18 at 11:48













@FatemehMajd this will return products that has tags in this array. i mean a product with 1 tag_id also is in your solution

– Joseph Rback
Nov 24 '18 at 12:08





@FatemehMajd this will return products that has tags in this array. i mean a product with 1 tag_id also is in your solution

– Joseph Rback
Nov 24 '18 at 12:08




1




1





In that case, i'm now aware of the eloquent way, but you can query the tables as in: DB::table('blah_blah-1')-join('...')->...;

– Fatemeh Majd
Nov 24 '18 at 12:49





In that case, i'm now aware of the eloquent way, but you can query the tables as in: DB::table('blah_blah-1')-join('...')->...;

– Fatemeh Majd
Nov 24 '18 at 12:49




2




2





Should the products have one of these tags or all of them?

– Jonas Staudenmeir
Nov 24 '18 at 17:58





Should the products have one of these tags or all of them?

– Jonas Staudenmeir
Nov 24 '18 at 17:58




1




1





Are you wanting products that have all 3 tags?

– Ross Wilson
Nov 24 '18 at 18:50





Are you wanting products that have all 3 tags?

– Ross Wilson
Nov 24 '18 at 18:50












1 Answer
1






active

oldest

votes


















0














Use whereHas() with all four parameters:



$tagIds = [1, 2, 3];
$products = Product::whereHas('tags', function($query) use($tagIds) {
$query->whereIn('tags.id', $tagIds);
}, '=', count($tagIds))->get();





share|improve this answer
























  • Intelligently method!!

    – Joseph Rback
    Nov 26 '18 at 12:21











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

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0














Use whereHas() with all four parameters:



$tagIds = [1, 2, 3];
$products = Product::whereHas('tags', function($query) use($tagIds) {
$query->whereIn('tags.id', $tagIds);
}, '=', count($tagIds))->get();





share|improve this answer
























  • Intelligently method!!

    – Joseph Rback
    Nov 26 '18 at 12:21
















0














Use whereHas() with all four parameters:



$tagIds = [1, 2, 3];
$products = Product::whereHas('tags', function($query) use($tagIds) {
$query->whereIn('tags.id', $tagIds);
}, '=', count($tagIds))->get();





share|improve this answer
























  • Intelligently method!!

    – Joseph Rback
    Nov 26 '18 at 12:21














0












0








0







Use whereHas() with all four parameters:



$tagIds = [1, 2, 3];
$products = Product::whereHas('tags', function($query) use($tagIds) {
$query->whereIn('tags.id', $tagIds);
}, '=', count($tagIds))->get();





share|improve this answer













Use whereHas() with all four parameters:



$tagIds = [1, 2, 3];
$products = Product::whereHas('tags', function($query) use($tagIds) {
$query->whereIn('tags.id', $tagIds);
}, '=', count($tagIds))->get();






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 26 '18 at 11:44









Jonas StaudenmeirJonas Staudenmeir

12.2k2933




12.2k2933













  • Intelligently method!!

    – Joseph Rback
    Nov 26 '18 at 12:21



















  • Intelligently method!!

    – Joseph Rback
    Nov 26 '18 at 12:21

















Intelligently method!!

– Joseph Rback
Nov 26 '18 at 12:21





Intelligently method!!

– Joseph Rback
Nov 26 '18 at 12:21


















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