Generate this sequence more efficiently
$begingroup$
Is there a more effecient way to generate the sequence shown below.
createOrder[n_] :=
Which[OddQ[n],
Join[Table[2 i - 1, {i, 1, (n + 1)/2}],Reverse@Table[2 i, {i, 1, (n + 1)/2}]],
EvenQ[n],
Join[Table[2 i - 1, {i, 1, n/2 + 1}],Reverse@Table[2 i, {i, 1, n/2}]]]
createOrder[#] & /@ Range[8] // MatrixForm
table sequence
$endgroup$
add a comment |
$begingroup$
Is there a more effecient way to generate the sequence shown below.
createOrder[n_] :=
Which[OddQ[n],
Join[Table[2 i - 1, {i, 1, (n + 1)/2}],Reverse@Table[2 i, {i, 1, (n + 1)/2}]],
EvenQ[n],
Join[Table[2 i - 1, {i, 1, n/2 + 1}],Reverse@Table[2 i, {i, 1, n/2}]]]
createOrder[#] & /@ Range[8] // MatrixForm
table sequence
$endgroup$
add a comment |
$begingroup$
Is there a more effecient way to generate the sequence shown below.
createOrder[n_] :=
Which[OddQ[n],
Join[Table[2 i - 1, {i, 1, (n + 1)/2}],Reverse@Table[2 i, {i, 1, (n + 1)/2}]],
EvenQ[n],
Join[Table[2 i - 1, {i, 1, n/2 + 1}],Reverse@Table[2 i, {i, 1, n/2}]]]
createOrder[#] & /@ Range[8] // MatrixForm
table sequence
$endgroup$
Is there a more effecient way to generate the sequence shown below.
createOrder[n_] :=
Which[OddQ[n],
Join[Table[2 i - 1, {i, 1, (n + 1)/2}],Reverse@Table[2 i, {i, 1, (n + 1)/2}]],
EvenQ[n],
Join[Table[2 i - 1, {i, 1, n/2 + 1}],Reverse@Table[2 i, {i, 1, n/2}]]]
createOrder[#] & /@ Range[8] // MatrixForm
table sequence
table sequence
asked 42 mins ago
Hubble07Hubble07
2,971721
2,971721
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
f[n_Integer] := Join[Range[1, #, 2], Reverse[Range[2, #, 2]]] & /@ Range[2, n];
TeXForm @ MatrixForm @ f[8]
$left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
end{array}
right)$
$endgroup$
add a comment |
$begingroup$
fGetList[n_]:= (Select[Range[#], OddQ]~Join~Reverse@Select[Range[#], EvenQ]) & /@Range[n] // Rest
fGetList[10]
$
left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
{1,3,5,7,9,8,6,4,2} \
{1,3,5,7,9,10,8,6,4,2} \
end{array}
right)$
$endgroup$
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
f[n_Integer] := Join[Range[1, #, 2], Reverse[Range[2, #, 2]]] & /@ Range[2, n];
TeXForm @ MatrixForm @ f[8]
$left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
end{array}
right)$
$endgroup$
add a comment |
$begingroup$
f[n_Integer] := Join[Range[1, #, 2], Reverse[Range[2, #, 2]]] & /@ Range[2, n];
TeXForm @ MatrixForm @ f[8]
$left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
end{array}
right)$
$endgroup$
add a comment |
$begingroup$
f[n_Integer] := Join[Range[1, #, 2], Reverse[Range[2, #, 2]]] & /@ Range[2, n];
TeXForm @ MatrixForm @ f[8]
$left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
end{array}
right)$
$endgroup$
f[n_Integer] := Join[Range[1, #, 2], Reverse[Range[2, #, 2]]] & /@ Range[2, n];
TeXForm @ MatrixForm @ f[8]
$left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
end{array}
right)$
answered 16 mins ago
kglrkglr
179k9199410
179k9199410
add a comment |
add a comment |
$begingroup$
fGetList[n_]:= (Select[Range[#], OddQ]~Join~Reverse@Select[Range[#], EvenQ]) & /@Range[n] // Rest
fGetList[10]
$
left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
{1,3,5,7,9,8,6,4,2} \
{1,3,5,7,9,10,8,6,4,2} \
end{array}
right)$
$endgroup$
add a comment |
$begingroup$
fGetList[n_]:= (Select[Range[#], OddQ]~Join~Reverse@Select[Range[#], EvenQ]) & /@Range[n] // Rest
fGetList[10]
$
left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
{1,3,5,7,9,8,6,4,2} \
{1,3,5,7,9,10,8,6,4,2} \
end{array}
right)$
$endgroup$
add a comment |
$begingroup$
fGetList[n_]:= (Select[Range[#], OddQ]~Join~Reverse@Select[Range[#], EvenQ]) & /@Range[n] // Rest
fGetList[10]
$
left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
{1,3,5,7,9,8,6,4,2} \
{1,3,5,7,9,10,8,6,4,2} \
end{array}
right)$
$endgroup$
fGetList[n_]:= (Select[Range[#], OddQ]~Join~Reverse@Select[Range[#], EvenQ]) & /@Range[n] // Rest
fGetList[10]
$
left(
begin{array}{c}
{1,2} \
{1,3,2} \
{1,3,4,2} \
{1,3,5,4,2} \
{1,3,5,6,4,2} \
{1,3,5,7,6,4,2} \
{1,3,5,7,8,6,4,2} \
{1,3,5,7,9,8,6,4,2} \
{1,3,5,7,9,10,8,6,4,2} \
end{array}
right)$
answered 17 mins ago
JerryJerry
939112
939112
add a comment |
add a comment |
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