Semaphore thinks lock file already exists











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I'm using link to create a semaphore - the idea is to lock out of writing to a db.



Here I have a script to create a table in a database:



#!/bin/bash


if [ "$#" -lt 3 ]; then
echo "Not enough parameters"
exit 1
elif [ "$#" -gt 3 ]; then
echo "Too many parameters"
exit 1
fi


if [ ! -d "$1" ]; then
echo "That database doesn't exist!"
exit 1
fi

./P.sh $1
if [ -f "$1/$2.txt" ]; then
echo "That table already exists!"
./V.sh $1
exit 1
else
touch "$1/$2.txt"
fi
./V.sh $1

echo "$3" > "$1/$2.txt"

echo "Ok, table created"

exit 0


Here's my P file:



#!/bin/bash

if [ -z "$1" ]; then
echo "Usage $0 mutex-name"
exit 1
elif [ ! -e "$1" ]; then
echo "Target for the lock must exist"
exit 2
else
while ! ln "$1" "$1.lock"; do
sleep 1
done
exit 0
fi


and my V:



#! /bin/bash
if [ -z "$1" ]; then
echo "Usage $1 mutex-name"
exit 1
else
rm "$1.lock"
exit 0
fi


let's say I create a table by running ./create_table people footballers age,height



This should create a file footballers.lock (created by P) and then once the writing has happened the V should remove it. But for some reason the P thinks that the .lock file already exists, and it definitely doesn't.



Can anyone spot what's going wrong?










share|improve this question


























    up vote
    0
    down vote

    favorite












    I'm using link to create a semaphore - the idea is to lock out of writing to a db.



    Here I have a script to create a table in a database:



    #!/bin/bash


    if [ "$#" -lt 3 ]; then
    echo "Not enough parameters"
    exit 1
    elif [ "$#" -gt 3 ]; then
    echo "Too many parameters"
    exit 1
    fi


    if [ ! -d "$1" ]; then
    echo "That database doesn't exist!"
    exit 1
    fi

    ./P.sh $1
    if [ -f "$1/$2.txt" ]; then
    echo "That table already exists!"
    ./V.sh $1
    exit 1
    else
    touch "$1/$2.txt"
    fi
    ./V.sh $1

    echo "$3" > "$1/$2.txt"

    echo "Ok, table created"

    exit 0


    Here's my P file:



    #!/bin/bash

    if [ -z "$1" ]; then
    echo "Usage $0 mutex-name"
    exit 1
    elif [ ! -e "$1" ]; then
    echo "Target for the lock must exist"
    exit 2
    else
    while ! ln "$1" "$1.lock"; do
    sleep 1
    done
    exit 0
    fi


    and my V:



    #! /bin/bash
    if [ -z "$1" ]; then
    echo "Usage $1 mutex-name"
    exit 1
    else
    rm "$1.lock"
    exit 0
    fi


    let's say I create a table by running ./create_table people footballers age,height



    This should create a file footballers.lock (created by P) and then once the writing has happened the V should remove it. But for some reason the P thinks that the .lock file already exists, and it definitely doesn't.



    Can anyone spot what's going wrong?










    share|improve this question
























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I'm using link to create a semaphore - the idea is to lock out of writing to a db.



      Here I have a script to create a table in a database:



      #!/bin/bash


      if [ "$#" -lt 3 ]; then
      echo "Not enough parameters"
      exit 1
      elif [ "$#" -gt 3 ]; then
      echo "Too many parameters"
      exit 1
      fi


      if [ ! -d "$1" ]; then
      echo "That database doesn't exist!"
      exit 1
      fi

      ./P.sh $1
      if [ -f "$1/$2.txt" ]; then
      echo "That table already exists!"
      ./V.sh $1
      exit 1
      else
      touch "$1/$2.txt"
      fi
      ./V.sh $1

      echo "$3" > "$1/$2.txt"

      echo "Ok, table created"

      exit 0


      Here's my P file:



      #!/bin/bash

      if [ -z "$1" ]; then
      echo "Usage $0 mutex-name"
      exit 1
      elif [ ! -e "$1" ]; then
      echo "Target for the lock must exist"
      exit 2
      else
      while ! ln "$1" "$1.lock"; do
      sleep 1
      done
      exit 0
      fi


      and my V:



      #! /bin/bash
      if [ -z "$1" ]; then
      echo "Usage $1 mutex-name"
      exit 1
      else
      rm "$1.lock"
      exit 0
      fi


      let's say I create a table by running ./create_table people footballers age,height



      This should create a file footballers.lock (created by P) and then once the writing has happened the V should remove it. But for some reason the P thinks that the .lock file already exists, and it definitely doesn't.



      Can anyone spot what's going wrong?










      share|improve this question













      I'm using link to create a semaphore - the idea is to lock out of writing to a db.



      Here I have a script to create a table in a database:



      #!/bin/bash


      if [ "$#" -lt 3 ]; then
      echo "Not enough parameters"
      exit 1
      elif [ "$#" -gt 3 ]; then
      echo "Too many parameters"
      exit 1
      fi


      if [ ! -d "$1" ]; then
      echo "That database doesn't exist!"
      exit 1
      fi

      ./P.sh $1
      if [ -f "$1/$2.txt" ]; then
      echo "That table already exists!"
      ./V.sh $1
      exit 1
      else
      touch "$1/$2.txt"
      fi
      ./V.sh $1

      echo "$3" > "$1/$2.txt"

      echo "Ok, table created"

      exit 0


      Here's my P file:



      #!/bin/bash

      if [ -z "$1" ]; then
      echo "Usage $0 mutex-name"
      exit 1
      elif [ ! -e "$1" ]; then
      echo "Target for the lock must exist"
      exit 2
      else
      while ! ln "$1" "$1.lock"; do
      sleep 1
      done
      exit 0
      fi


      and my V:



      #! /bin/bash
      if [ -z "$1" ]; then
      echo "Usage $1 mutex-name"
      exit 1
      else
      rm "$1.lock"
      exit 0
      fi


      let's say I create a table by running ./create_table people footballers age,height



      This should create a file footballers.lock (created by P) and then once the writing has happened the V should remove it. But for some reason the P thinks that the .lock file already exists, and it definitely doesn't.



      Can anyone spot what's going wrong?







      bash semaphore ln






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      asked Nov 22 at 15:47









      Raph117

      171111




      171111
























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          Found it - you can't use ln on directories...






          share|improve this answer





















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            up vote
            0
            down vote













            Found it - you can't use ln on directories...






            share|improve this answer

























              up vote
              0
              down vote













              Found it - you can't use ln on directories...






              share|improve this answer























                up vote
                0
                down vote










                up vote
                0
                down vote









                Found it - you can't use ln on directories...






                share|improve this answer












                Found it - you can't use ln on directories...







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 22 at 16:01









                Raph117

                171111




                171111






























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