Intersection of a circle and a line “path”
(With all the questions about the intersection of a straight line and a circle, I hope this not a duplicate.)
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[
plotmark/.style = {%
solid, fill = red, circle, inner sep = 0pt, minimum size = 6pt
}
]
coordinate (A) at (0,0);
coordinate (B) at (1,1);
coordinate (C) at (3,1);
coordinate (D) at (4,0);
draw[->] (A)--(B);
draw[->] (D)--(C);
draw[dashed] (A) circle [radius=2];
coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)});
node[plotmark, label={below:$A$}] at (A) {};
node[plotmark, label={below:$D$}] at (D) {};
node[plotmark, label={above:$I$}] at (I) {};
end{tikzpicture}
end{document}
In the above code, even though the line segments (A)--(B) and (D)--(C) do not meet, coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)}); calculates the intersection point, and outputs:
Is there a way to use the intersection cs syntax to locate the intersection of the path AB with the circle?
The following syntax requires that the line segment and the circle actually meet:
path[name path=Circle] (A) circle [radius=2];
path[name path=AB] (A)--(B);
path [name intersections={of=Circle and AB}];
coordinate (I) at (intersection-1);
tikz-pgf intersections
asked 12 mins ago
blackened
1,376713
add a comment |
(With all the questions about the intersection of a straight line and a circle, I hope this not a duplicate.)
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[
plotmark/.style = {%
solid, fill = red, circle, inner sep = 0pt, minimum size = 6pt
}
]
coordinate (A) at (0,0);
coordinate (B) at (1,1);
coordinate (C) at (3,1);
coordinate (D) at (4,0);
draw[->] (A)--(B);
draw[->] (D)--(C);
draw[dashed] (A) circle [radius=2];
coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)});
node[plotmark, label={below:$A$}] at (A) {};
node[plotmark, label={below:$D$}] at (D) {};
node[plotmark, label={above:$I$}] at (I) {};
end{tikzpicture}
end{document}
In the above code, even though the line segments (A)--(B) and (D)--(C) do not meet, coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)}); calculates the intersection point, and outputs:
Is there a way to use the intersection cs syntax to locate the intersection of the path AB with the circle?
The following syntax requires that the line segment and the circle actually meet:
path[name path=Circle] (A) circle [radius=2];
path[name path=AB] (A)--(B);
path [name intersections={of=Circle and AB}];
coordinate (I) at (intersection-1);
tikz-pgf intersections
asked 12 mins ago
blackened
1,376713
Nice question! I do not believe that there is a way using `intersection cs: as is. Would you also be interested in a style that computes the intersections of the extension of an arbitrary line with a circle?
– marmot
13 secs ago
add a comment |
(With all the questions about the intersection of a straight line and a circle, I hope this not a duplicate.)
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[
plotmark/.style = {%
solid, fill = red, circle, inner sep = 0pt, minimum size = 6pt
}
]
coordinate (A) at (0,0);
coordinate (B) at (1,1);
coordinate (C) at (3,1);
coordinate (D) at (4,0);
draw[->] (A)--(B);
draw[->] (D)--(C);
draw[dashed] (A) circle [radius=2];
coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)});
node[plotmark, label={below:$A$}] at (A) {};
node[plotmark, label={below:$D$}] at (D) {};
node[plotmark, label={above:$I$}] at (I) {};
end{tikzpicture}
end{document}
In the above code, even though the line segments (A)--(B) and (D)--(C) do not meet, coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)}); calculates the intersection point, and outputs:
Is there a way to use the intersection cs syntax to locate the intersection of the path AB with the circle?
The following syntax requires that the line segment and the circle actually meet:
path[name path=Circle] (A) circle [radius=2];
path[name path=AB] (A)--(B);
path [name intersections={of=Circle and AB}];
coordinate (I) at (intersection-1);
tikz-pgf intersections
asked 12 mins ago
blackened
1,376713
(With all the questions about the intersection of a straight line and a circle, I hope this not a duplicate.)
documentclass{standalone}
usepackage{tikz}
usetikzlibrary{intersections}
begin{document}
begin{tikzpicture}[
plotmark/.style = {%
solid, fill = red, circle, inner sep = 0pt, minimum size = 6pt
}
]
coordinate (A) at (0,0);
coordinate (B) at (1,1);
coordinate (C) at (3,1);
coordinate (D) at (4,0);
draw[->] (A)--(B);
draw[->] (D)--(C);
draw[dashed] (A) circle [radius=2];
coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)});
node[plotmark, label={below:$A$}] at (A) {};
node[plotmark, label={below:$D$}] at (D) {};
node[plotmark, label={above:$I$}] at (I) {};
end{tikzpicture}
end{document}
In the above code, even though the line segments (A)--(B) and (D)--(C) do not meet, coordinate (I) at (intersection cs:first line={(A)--(B)}, second line={(C)--(D)}); calculates the intersection point, and outputs:
Is there a way to use the intersection cs syntax to locate the intersection of the path AB with the circle?
The following syntax requires that the line segment and the circle actually meet:
path[name path=Circle] (A) circle [radius=2];
path[name path=AB] (A)--(B);
path [name intersections={of=Circle and AB}];
coordinate (I) at (intersection-1);
tikz-pgf intersections
tikz-pgf intersections
asked 12 mins ago
blackened
1,376713
asked 12 mins ago
blackened
1,376713
asked 12 mins ago
blackened
1,376713
asked 12 mins ago
blackened
1,376713
asked 12 mins ago
blackened
1,376713
1,376713
Nice question! I do not believe that there is a way using `intersection cs: as is. Would you also be interested in a style that computes the intersections of the extension of an arbitrary line with a circle?
– marmot
13 secs ago
add a comment |
Nice question! I do not believe that there is a way using `intersection cs: as is. Would you also be interested in a style that computes the intersections of the extension of an arbitrary line with a circle?
– marmot
13 secs ago
Nice question! I do not believe that there is a way using `intersection cs: as is. Would you also be interested in a style that computes the intersections of the extension of an arbitrary line with a circle?
– marmot
13 secs ago
Nice question! I do not believe that there is a way using `intersection cs: as is. Would you also be interested in a style that computes the intersections of the extension of an arbitrary line with a circle?
– marmot
13 secs ago
add a comment |
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Nice question! I do not believe that there is a way using `intersection cs: as is. Would you also be interested in a style that computes the intersections of the extension of an arbitrary line with a circle?
– marmot
13 secs ago