How do I implement collision detection?











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from graphics import*
import time
import random

def main():

numx=random.randint(10,700)

wn=GraphWin("AK",700,700)
wn.setBackground("white")

msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)

inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)

sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)

blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)


xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)

main()


I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.










share|improve this question
























  • Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
    – Grant McCloskey
    Nov 21 at 23:00















up vote
-2
down vote

favorite












from graphics import*
import time
import random

def main():

numx=random.randint(10,700)

wn=GraphWin("AK",700,700)
wn.setBackground("white")

msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)

inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)

sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)

blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)


xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)

main()


I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.










share|improve this question
























  • Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
    – Grant McCloskey
    Nov 21 at 23:00













up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











from graphics import*
import time
import random

def main():

numx=random.randint(10,700)

wn=GraphWin("AK",700,700)
wn.setBackground("white")

msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)

inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)

sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)

blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)


xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)

main()


I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.










share|improve this question















from graphics import*
import time
import random

def main():

numx=random.randint(10,700)

wn=GraphWin("AK",700,700)
wn.setBackground("white")

msg=Text(Point(25,30),"Score")
msg.setSize(12)
msg.setTextColor('blue')
msg.draw(wn)

inch=Entry(Point(60,30),2)
inch.setFill('white')
inch.draw(wn)

sqrg=Rectangle(Point(330,650),Point(430,665))
sqrg.setFill("red")
sqrg.draw(wn)

blx=Circle(Point(numx,80),20)
blx.setFill("blue")
blx.draw(wn)


xval=10
yval=0
wn.getMouse()
for i in range(150):
sqrg.move(xval,yval)
symbl=wn.checkKey()
if symbl=="Right":
xval=10
yval=0
if symbl=="Left":
xval=-10
yval=0
time.sleep(0.08)
blx.move(0,20)

main()


I'm very confused my professor is very confusing, and I need to do this for a project where when collision is detected the score goes up.







python python-3.x collision-detection zelle-graphics






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edited Nov 23 at 21:11









cdlane

16.7k21043




16.7k21043










asked Nov 21 at 22:54









joseph viviano

122




122












  • Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
    – Grant McCloskey
    Nov 21 at 23:00


















  • Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
    – Grant McCloskey
    Nov 21 at 23:00
















Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– Grant McCloskey
Nov 21 at 23:00




Looks like if you know the location of sqrg and blx with the dimensions, you should be able to determine if those points intersect each iteration.
– Grant McCloskey
Nov 21 at 23:00












2 Answers
2






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0
down vote













Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.






share|improve this answer




























    up vote
    0
    down vote













    Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:



    from random import randint
    from time import sleep
    from graphics import *

    def distance(p1, p2):
    return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5

    wn = GraphWin("AK", 700, 700)

    sqrg = Rectangle(Point(325, 625), Point(375, 675))
    sqrg.setFill("red")
    sqrg.draw(wn)

    numx = randint(10, 700)

    blx = Circle(Point(numx, 80), 20)
    blx.setFill("blue")
    blx.draw(wn)

    xval, yval = 10, 0

    bheading = 1

    wn.getMouse()

    for i in range(150):
    sqrg.move(xval, yval)

    if distance(blx.getCenter(), sqrg.getCenter()) < 25:
    bheading *= -1

    symbl = wn.checkKey()

    if symbl == "Right":
    xval = 10
    elif symbl == "Left":
    xval = -10

    sleep(0.1)

    blx.move(0, bheading * 20)


    Cleary not a viable game as-is, but a demonstration of collision detection.






    share|improve this answer





















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      2 Answers
      2






      active

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      2 Answers
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      up vote
      0
      down vote













      Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.






      share|improve this answer

























        up vote
        0
        down vote













        Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.






        share|improve this answer























          up vote
          0
          down vote










          up vote
          0
          down vote









          Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.






          share|improve this answer












          Your radius is twenty. Inside the loop, just test whether Euclidean distance between sqrg and blx is within 20.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 at 1:45









          J_H

          2,9811615




          2,9811615
























              up vote
              0
              down vote













              Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:



              from random import randint
              from time import sleep
              from graphics import *

              def distance(p1, p2):
              return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5

              wn = GraphWin("AK", 700, 700)

              sqrg = Rectangle(Point(325, 625), Point(375, 675))
              sqrg.setFill("red")
              sqrg.draw(wn)

              numx = randint(10, 700)

              blx = Circle(Point(numx, 80), 20)
              blx.setFill("blue")
              blx.draw(wn)

              xval, yval = 10, 0

              bheading = 1

              wn.getMouse()

              for i in range(150):
              sqrg.move(xval, yval)

              if distance(blx.getCenter(), sqrg.getCenter()) < 25:
              bheading *= -1

              symbl = wn.checkKey()

              if symbl == "Right":
              xval = 10
              elif symbl == "Left":
              xval = -10

              sleep(0.1)

              blx.move(0, bheading * 20)


              Cleary not a viable game as-is, but a demonstration of collision detection.






              share|improve this answer

























                up vote
                0
                down vote













                Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:



                from random import randint
                from time import sleep
                from graphics import *

                def distance(p1, p2):
                return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5

                wn = GraphWin("AK", 700, 700)

                sqrg = Rectangle(Point(325, 625), Point(375, 675))
                sqrg.setFill("red")
                sqrg.draw(wn)

                numx = randint(10, 700)

                blx = Circle(Point(numx, 80), 20)
                blx.setFill("blue")
                blx.draw(wn)

                xval, yval = 10, 0

                bheading = 1

                wn.getMouse()

                for i in range(150):
                sqrg.move(xval, yval)

                if distance(blx.getCenter(), sqrg.getCenter()) < 25:
                bheading *= -1

                symbl = wn.checkKey()

                if symbl == "Right":
                xval = 10
                elif symbl == "Left":
                xval = -10

                sleep(0.1)

                blx.move(0, bheading * 20)


                Cleary not a viable game as-is, but a demonstration of collision detection.






                share|improve this answer























                  up vote
                  0
                  down vote










                  up vote
                  0
                  down vote









                  Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:



                  from random import randint
                  from time import sleep
                  from graphics import *

                  def distance(p1, p2):
                  return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5

                  wn = GraphWin("AK", 700, 700)

                  sqrg = Rectangle(Point(325, 625), Point(375, 675))
                  sqrg.setFill("red")
                  sqrg.draw(wn)

                  numx = randint(10, 700)

                  blx = Circle(Point(numx, 80), 20)
                  blx.setFill("blue")
                  blx.draw(wn)

                  xval, yval = 10, 0

                  bheading = 1

                  wn.getMouse()

                  for i in range(150):
                  sqrg.move(xval, yval)

                  if distance(blx.getCenter(), sqrg.getCenter()) < 25:
                  bheading *= -1

                  symbl = wn.checkKey()

                  if symbl == "Right":
                  xval = 10
                  elif symbl == "Left":
                  xval = -10

                  sleep(0.1)

                  blx.move(0, bheading * 20)


                  Cleary not a viable game as-is, but a demonstration of collision detection.






                  share|improve this answer












                  Below is a stripped down example based on your code. It measures the distance between the centers of the two moving objects to determine if a collision has occurred. If you manage to get the ball to hit the square, the ball should bounce straight up:



                  from random import randint
                  from time import sleep
                  from graphics import *

                  def distance(p1, p2):
                  return ((p2.x - p1.x) ** 2 + (p2.y - p1.y) ** 2) ** 0.5

                  wn = GraphWin("AK", 700, 700)

                  sqrg = Rectangle(Point(325, 625), Point(375, 675))
                  sqrg.setFill("red")
                  sqrg.draw(wn)

                  numx = randint(10, 700)

                  blx = Circle(Point(numx, 80), 20)
                  blx.setFill("blue")
                  blx.draw(wn)

                  xval, yval = 10, 0

                  bheading = 1

                  wn.getMouse()

                  for i in range(150):
                  sqrg.move(xval, yval)

                  if distance(blx.getCenter(), sqrg.getCenter()) < 25:
                  bheading *= -1

                  symbl = wn.checkKey()

                  if symbl == "Right":
                  xval = 10
                  elif symbl == "Left":
                  xval = -10

                  sleep(0.1)

                  blx.move(0, bheading * 20)


                  Cleary not a viable game as-is, but a demonstration of collision detection.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 23 at 21:10









                  cdlane

                  16.7k21043




                  16.7k21043






























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