How to find second,third,etc maximum peak of list











up vote
2
down vote

favorite












I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection







share|improve this question




















  • 1




    Did you try FindPeaks?
    – J42161217
    6 hours ago










  • Yes, I did. I added the result above.
    – John
    6 hours ago















up vote
2
down vote

favorite












I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection







share|improve this question




















  • 1




    Did you try FindPeaks?
    – J42161217
    6 hours ago










  • Yes, I did. I added the result above.
    – John
    6 hours ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection







share|improve this question















I need to find all values of peaks.
I have Table with 10000 elements in it and I plot a graphic using ListPlot.
enter image description here



Then I tried to find peaks:



tbl1 = Table[tbl[[i, 2]], {i, 1, Length[tbl]}];

gA = Max[tbl1]

gAm = Part[tbl, Position[tbl1 , gA ][[1, 1]], 1]


Here tbl my Table with Data
And get:



0.15

8.751


So I find the last peak starting. How I can find other?
enter image description here
I upload a .txt file with data to my google drive
here .



I also tried to use FindPeaks but it's wrong:



peakpositions = FindPeaks[tbl[[All, 2]]]



{{116, 0.}, {1441, 0.}}




peakwavelengths = tbl[[#1, 1]] & @@@ peakpositions



{0.115, 1.44}




ListPlot[tbl, PlotRange -> All, GridLines -> {peakwavelengths, None}, 

GridLinesStyle -> Directive[Red, Thick]]


enter image description here






plotting list-manipulation mathematical-optimization peak-detection




plotting list-manipulation mathematical-optimization peak-detection






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 6 hours ago

























asked 6 hours ago









John

1996




1996








  • 1




    Did you try FindPeaks?
    – J42161217
    6 hours ago










  • Yes, I did. I added the result above.
    – John
    6 hours ago














  • 1




    Did you try FindPeaks?
    – J42161217
    6 hours ago










  • Yes, I did. I added the result above.
    – John
    6 hours ago








1




1




Did you try FindPeaks?
– J42161217
6 hours ago




Did you try FindPeaks?
– J42161217
6 hours ago












Yes, I did. I added the result above.
– John
6 hours ago




Yes, I did. I added the result above.
– John
6 hours ago










2 Answers
2






active

oldest

votes

















up vote
3
down vote



accepted










jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



{{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 

 GridLines -> Transpose[jumps]]


enter image description here






share|improve this answer




























    up vote
    2
    down vote













    Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



    {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







    share|improve this answer





















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes








      up vote
      3
      down vote



      accepted










      jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



      {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




      ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
      
 GridLines -> Transpose[jumps]]


      enter image description here






      share|improve this answer

























        up vote
        3
        down vote



        accepted










        jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



        {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




        ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
        
 GridLines -> Transpose[jumps]]


        enter image description here






        share|improve this answer























          up vote
          3
          down vote



          accepted







          up vote
          3
          down vote



          accepted






          jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



          {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




          ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
          
 GridLines -> Transpose[jumps]]


          enter image description here






          share|improve this answer












          jumps = tbl[[1 + Flatten@Position[Sign@Differences[tbl[[All, 2]]], 1]]]



          {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}




          ListStepPlot[tbl,  Epilog -> {Red, PointSize[Large], Point[jumps]}, 
          
 GridLines -> Transpose[jumps]]


          enter image description here







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 6 hours ago









          kglr

          173k8194400




          173k8194400






















              up vote
              2
              down vote













              Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



              {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







              share|improve this answer

























                up vote
                2
                down vote













                Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



                {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







                share|improve this answer























                  up vote
                  2
                  down vote










                  up vote
                  2
                  down vote









                  Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



                  {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}







                  share|improve this answer












                  Pick[tbl,Join[{0},Sign@Differences[Last/@tbl]],1]



                  {{0.232, 0.05}, {2.411, 0.05}, {5.449, 0.1}, {8.751, 0.15}}








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 5 hours ago









                  J42161217

                  3,177219




                  3,177219






























                       

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