TypeError: 'type' object is not subscriptable, when checking length of a nested-list












0















I have been getting a TypeError when running the code below. I don't understand why it won't take the length of listLicencePlates, when its a list? I tried to figure out for about an hour now and can't seem to see the mistake. Maybe someone can point out why this happens and how to fix it?



When I run this code:



for x in range[len(listLicencePlates)]:


I get this error:



TypeError: 'type' object is not subscriptable


Here's my full code:



def match_list(witnessedLicensePlate, listLicencePlates):
matchPlates = len(listLicencePlates)*[len((witnessedLicensePlate))*[""]]
for x in range[len(listLicencePlates)]:
y = 0
for y in range(len(witnessedLicensePlate)):
if witnessedLicensePlate[y] != listLicencePlates[x][y] and witnessedLicensePlate[y] != "?":
y = len(witnessedLicensePlate)
else:
matchPlates[x][y] = listLicencePlates[x][y]
return matchPlates


print(match_list("VF???55",["VX33322","VF12355","VF77455","DA?????","VF10055"]))









share|improve this question




















  • 7





    range(, not range[.

    – melpomene
    Nov 27 '18 at 22:10






  • 3





    But anyway, iterating over range(len(something)) is almost always the wrong thing to do in Python.

    – Daniel Roseman
    Nov 27 '18 at 22:17
















0















I have been getting a TypeError when running the code below. I don't understand why it won't take the length of listLicencePlates, when its a list? I tried to figure out for about an hour now and can't seem to see the mistake. Maybe someone can point out why this happens and how to fix it?



When I run this code:



for x in range[len(listLicencePlates)]:


I get this error:



TypeError: 'type' object is not subscriptable


Here's my full code:



def match_list(witnessedLicensePlate, listLicencePlates):
matchPlates = len(listLicencePlates)*[len((witnessedLicensePlate))*[""]]
for x in range[len(listLicencePlates)]:
y = 0
for y in range(len(witnessedLicensePlate)):
if witnessedLicensePlate[y] != listLicencePlates[x][y] and witnessedLicensePlate[y] != "?":
y = len(witnessedLicensePlate)
else:
matchPlates[x][y] = listLicencePlates[x][y]
return matchPlates


print(match_list("VF???55",["VX33322","VF12355","VF77455","DA?????","VF10055"]))









share|improve this question




















  • 7





    range(, not range[.

    – melpomene
    Nov 27 '18 at 22:10






  • 3





    But anyway, iterating over range(len(something)) is almost always the wrong thing to do in Python.

    – Daniel Roseman
    Nov 27 '18 at 22:17














0












0








0








I have been getting a TypeError when running the code below. I don't understand why it won't take the length of listLicencePlates, when its a list? I tried to figure out for about an hour now and can't seem to see the mistake. Maybe someone can point out why this happens and how to fix it?



When I run this code:



for x in range[len(listLicencePlates)]:


I get this error:



TypeError: 'type' object is not subscriptable


Here's my full code:



def match_list(witnessedLicensePlate, listLicencePlates):
matchPlates = len(listLicencePlates)*[len((witnessedLicensePlate))*[""]]
for x in range[len(listLicencePlates)]:
y = 0
for y in range(len(witnessedLicensePlate)):
if witnessedLicensePlate[y] != listLicencePlates[x][y] and witnessedLicensePlate[y] != "?":
y = len(witnessedLicensePlate)
else:
matchPlates[x][y] = listLicencePlates[x][y]
return matchPlates


print(match_list("VF???55",["VX33322","VF12355","VF77455","DA?????","VF10055"]))









share|improve this question
















I have been getting a TypeError when running the code below. I don't understand why it won't take the length of listLicencePlates, when its a list? I tried to figure out for about an hour now and can't seem to see the mistake. Maybe someone can point out why this happens and how to fix it?



When I run this code:



for x in range[len(listLicencePlates)]:


I get this error:



TypeError: 'type' object is not subscriptable


Here's my full code:



def match_list(witnessedLicensePlate, listLicencePlates):
matchPlates = len(listLicencePlates)*[len((witnessedLicensePlate))*[""]]
for x in range[len(listLicencePlates)]:
y = 0
for y in range(len(witnessedLicensePlate)):
if witnessedLicensePlate[y] != listLicencePlates[x][y] and witnessedLicensePlate[y] != "?":
y = len(witnessedLicensePlate)
else:
matchPlates[x][y] = listLicencePlates[x][y]
return matchPlates


print(match_list("VF???55",["VX33322","VF12355","VF77455","DA?????","VF10055"]))






python typeerror nested-lists






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share|improve this question








edited Nov 27 '18 at 23:13









Supa Mega Ducky Momo da Waffle

2,00651129




2,00651129










asked Nov 27 '18 at 22:04









Sindre KateSindre Kate

9




9








  • 7





    range(, not range[.

    – melpomene
    Nov 27 '18 at 22:10






  • 3





    But anyway, iterating over range(len(something)) is almost always the wrong thing to do in Python.

    – Daniel Roseman
    Nov 27 '18 at 22:17














  • 7





    range(, not range[.

    – melpomene
    Nov 27 '18 at 22:10






  • 3





    But anyway, iterating over range(len(something)) is almost always the wrong thing to do in Python.

    – Daniel Roseman
    Nov 27 '18 at 22:17








7




7





range(, not range[.

– melpomene
Nov 27 '18 at 22:10





range(, not range[.

– melpomene
Nov 27 '18 at 22:10




3




3





But anyway, iterating over range(len(something)) is almost always the wrong thing to do in Python.

– Daniel Roseman
Nov 27 '18 at 22:17





But anyway, iterating over range(len(something)) is almost always the wrong thing to do in Python.

– Daniel Roseman
Nov 27 '18 at 22:17












2 Answers
2






active

oldest

votes


















1














I dont know exactly what you want to achieve but I ran the same code and it works fine. Although I must say, I changed range[ to range( as corrected above.






share|improve this answer































    0














    Fixing the TypeError:



    The interpreter is telling you exactly where and why you're getting the issue. Here's your MVCE:



    >>> range[1]
    Traceback (most recent call last):
    File "<stdin>", line 1, in <module>
    TypeError: 'type' object is not subscriptable


    You can't use square brackets, or subscripts (i.e. ) on the built-in range. Rather, use parenthesis (()):



    >>> range(1)
    range(0, 1)


    So change this line:



    for x in range[len(listLicencePlates)] # bad news, range[...]


    to be



    for x in range(len(listLicencePlates)) # Better, range(...)


    and you'll get past the TypeError.



    Fixing the core issue:



    I am guessing, however, that the output you get from this fix isn't what you want. This is the output:



    [['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5']]


    Which doesn't look useful.



    What I think you probably want is an array of bools, where each bool describes whether or not the plate matched character by character, and the "?" represents a wildcard character.



    Let's try a more Pythonic and less C-style approach to the problem with some extraordinarily verbose comments:



    def match_list2(witnessed_plate, license_plates):
    matching_plates =
    # just loop through the items, no need for range/indices
    for possible_match in license_plates:
    # If they match, create 2-elt list with
    # the plate as first elt and whether or not it matches as second
    # Worry about do_plates_match later. Just get the high level logic
    # down pat and sound first.
    matching_plates.append([possible_match,
    do_plates_match(possible_match, witnessed_plate)])
    return matching_plates

    def do_plates_match(plate1, plate2): # Define if they match (the time to worry is upon us)
    # Loop through characters from plate1 and plate2 simultaneously
    for first_char, second_char in zip(plate1, plate2):
    if first_char == "?" or second_char == "?":
    # If we get a question mark, go to the next character
    continue
    elif first_char != second_char:
    # If they don't match at *some* character,
    # we know they can't match regardless of what's next, so return False
    return False
    # Only way to get here is we must have matched for all characters, return True.
    return True


    and for those who find the comments distracting and would rather just read the code straight away:



    def match_list2(witnessed_plate, license_plates):
    matching_plates =
    for possible_match in license_plates:
    matching_plates.append([possible_match, do_plates_match(possible_match, witnessed_plate)])
    return matching_plates

    def do_plates_match(plate1, plate2):
    for first_char, second_char in zip(plate1, plate2):
    if first_char == "?" or second_char == "?": continue
    elif first_char != second_char: return False
    return True


    Now calling:



    plate = "VF???55"
    print("Plate: ", plate)
    print(match_list2(plate,["VX33322","VF12355","VF77455","DA?????","VF10055"]))


    outputs:



    Plate:  VF???55
    [['VX33322', False], ['VF12355', True], ['VF77455', True], ['DA?????', False], ['VF10055', True]]


    clearly showing which plates match, and which don't.



    HTH.






    share|improve this answer























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      2 Answers
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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      I dont know exactly what you want to achieve but I ran the same code and it works fine. Although I must say, I changed range[ to range( as corrected above.






      share|improve this answer




























        1














        I dont know exactly what you want to achieve but I ran the same code and it works fine. Although I must say, I changed range[ to range( as corrected above.






        share|improve this answer


























          1












          1








          1







          I dont know exactly what you want to achieve but I ran the same code and it works fine. Although I must say, I changed range[ to range( as corrected above.






          share|improve this answer













          I dont know exactly what you want to achieve but I ran the same code and it works fine. Although I must say, I changed range[ to range( as corrected above.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 27 '18 at 22:22









          Mr.TeeyMr.Teey

          112




          112

























              0














              Fixing the TypeError:



              The interpreter is telling you exactly where and why you're getting the issue. Here's your MVCE:



              >>> range[1]
              Traceback (most recent call last):
              File "<stdin>", line 1, in <module>
              TypeError: 'type' object is not subscriptable


              You can't use square brackets, or subscripts (i.e. ) on the built-in range. Rather, use parenthesis (()):



              >>> range(1)
              range(0, 1)


              So change this line:



              for x in range[len(listLicencePlates)] # bad news, range[...]


              to be



              for x in range(len(listLicencePlates)) # Better, range(...)


              and you'll get past the TypeError.



              Fixing the core issue:



              I am guessing, however, that the output you get from this fix isn't what you want. This is the output:



              [['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5']]


              Which doesn't look useful.



              What I think you probably want is an array of bools, where each bool describes whether or not the plate matched character by character, and the "?" represents a wildcard character.



              Let's try a more Pythonic and less C-style approach to the problem with some extraordinarily verbose comments:



              def match_list2(witnessed_plate, license_plates):
              matching_plates =
              # just loop through the items, no need for range/indices
              for possible_match in license_plates:
              # If they match, create 2-elt list with
              # the plate as first elt and whether or not it matches as second
              # Worry about do_plates_match later. Just get the high level logic
              # down pat and sound first.
              matching_plates.append([possible_match,
              do_plates_match(possible_match, witnessed_plate)])
              return matching_plates

              def do_plates_match(plate1, plate2): # Define if they match (the time to worry is upon us)
              # Loop through characters from plate1 and plate2 simultaneously
              for first_char, second_char in zip(plate1, plate2):
              if first_char == "?" or second_char == "?":
              # If we get a question mark, go to the next character
              continue
              elif first_char != second_char:
              # If they don't match at *some* character,
              # we know they can't match regardless of what's next, so return False
              return False
              # Only way to get here is we must have matched for all characters, return True.
              return True


              and for those who find the comments distracting and would rather just read the code straight away:



              def match_list2(witnessed_plate, license_plates):
              matching_plates =
              for possible_match in license_plates:
              matching_plates.append([possible_match, do_plates_match(possible_match, witnessed_plate)])
              return matching_plates

              def do_plates_match(plate1, plate2):
              for first_char, second_char in zip(plate1, plate2):
              if first_char == "?" or second_char == "?": continue
              elif first_char != second_char: return False
              return True


              Now calling:



              plate = "VF???55"
              print("Plate: ", plate)
              print(match_list2(plate,["VX33322","VF12355","VF77455","DA?????","VF10055"]))


              outputs:



              Plate:  VF???55
              [['VX33322', False], ['VF12355', True], ['VF77455', True], ['DA?????', False], ['VF10055', True]]


              clearly showing which plates match, and which don't.



              HTH.






              share|improve this answer




























                0














                Fixing the TypeError:



                The interpreter is telling you exactly where and why you're getting the issue. Here's your MVCE:



                >>> range[1]
                Traceback (most recent call last):
                File "<stdin>", line 1, in <module>
                TypeError: 'type' object is not subscriptable


                You can't use square brackets, or subscripts (i.e. ) on the built-in range. Rather, use parenthesis (()):



                >>> range(1)
                range(0, 1)


                So change this line:



                for x in range[len(listLicencePlates)] # bad news, range[...]


                to be



                for x in range(len(listLicencePlates)) # Better, range(...)


                and you'll get past the TypeError.



                Fixing the core issue:



                I am guessing, however, that the output you get from this fix isn't what you want. This is the output:



                [['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5']]


                Which doesn't look useful.



                What I think you probably want is an array of bools, where each bool describes whether or not the plate matched character by character, and the "?" represents a wildcard character.



                Let's try a more Pythonic and less C-style approach to the problem with some extraordinarily verbose comments:



                def match_list2(witnessed_plate, license_plates):
                matching_plates =
                # just loop through the items, no need for range/indices
                for possible_match in license_plates:
                # If they match, create 2-elt list with
                # the plate as first elt and whether or not it matches as second
                # Worry about do_plates_match later. Just get the high level logic
                # down pat and sound first.
                matching_plates.append([possible_match,
                do_plates_match(possible_match, witnessed_plate)])
                return matching_plates

                def do_plates_match(plate1, plate2): # Define if they match (the time to worry is upon us)
                # Loop through characters from plate1 and plate2 simultaneously
                for first_char, second_char in zip(plate1, plate2):
                if first_char == "?" or second_char == "?":
                # If we get a question mark, go to the next character
                continue
                elif first_char != second_char:
                # If they don't match at *some* character,
                # we know they can't match regardless of what's next, so return False
                return False
                # Only way to get here is we must have matched for all characters, return True.
                return True


                and for those who find the comments distracting and would rather just read the code straight away:



                def match_list2(witnessed_plate, license_plates):
                matching_plates =
                for possible_match in license_plates:
                matching_plates.append([possible_match, do_plates_match(possible_match, witnessed_plate)])
                return matching_plates

                def do_plates_match(plate1, plate2):
                for first_char, second_char in zip(plate1, plate2):
                if first_char == "?" or second_char == "?": continue
                elif first_char != second_char: return False
                return True


                Now calling:



                plate = "VF???55"
                print("Plate: ", plate)
                print(match_list2(plate,["VX33322","VF12355","VF77455","DA?????","VF10055"]))


                outputs:



                Plate:  VF???55
                [['VX33322', False], ['VF12355', True], ['VF77455', True], ['DA?????', False], ['VF10055', True]]


                clearly showing which plates match, and which don't.



                HTH.






                share|improve this answer


























                  0












                  0








                  0







                  Fixing the TypeError:



                  The interpreter is telling you exactly where and why you're getting the issue. Here's your MVCE:



                  >>> range[1]
                  Traceback (most recent call last):
                  File "<stdin>", line 1, in <module>
                  TypeError: 'type' object is not subscriptable


                  You can't use square brackets, or subscripts (i.e. ) on the built-in range. Rather, use parenthesis (()):



                  >>> range(1)
                  range(0, 1)


                  So change this line:



                  for x in range[len(listLicencePlates)] # bad news, range[...]


                  to be



                  for x in range(len(listLicencePlates)) # Better, range(...)


                  and you'll get past the TypeError.



                  Fixing the core issue:



                  I am guessing, however, that the output you get from this fix isn't what you want. This is the output:



                  [['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5']]


                  Which doesn't look useful.



                  What I think you probably want is an array of bools, where each bool describes whether or not the plate matched character by character, and the "?" represents a wildcard character.



                  Let's try a more Pythonic and less C-style approach to the problem with some extraordinarily verbose comments:



                  def match_list2(witnessed_plate, license_plates):
                  matching_plates =
                  # just loop through the items, no need for range/indices
                  for possible_match in license_plates:
                  # If they match, create 2-elt list with
                  # the plate as first elt and whether or not it matches as second
                  # Worry about do_plates_match later. Just get the high level logic
                  # down pat and sound first.
                  matching_plates.append([possible_match,
                  do_plates_match(possible_match, witnessed_plate)])
                  return matching_plates

                  def do_plates_match(plate1, plate2): # Define if they match (the time to worry is upon us)
                  # Loop through characters from plate1 and plate2 simultaneously
                  for first_char, second_char in zip(plate1, plate2):
                  if first_char == "?" or second_char == "?":
                  # If we get a question mark, go to the next character
                  continue
                  elif first_char != second_char:
                  # If they don't match at *some* character,
                  # we know they can't match regardless of what's next, so return False
                  return False
                  # Only way to get here is we must have matched for all characters, return True.
                  return True


                  and for those who find the comments distracting and would rather just read the code straight away:



                  def match_list2(witnessed_plate, license_plates):
                  matching_plates =
                  for possible_match in license_plates:
                  matching_plates.append([possible_match, do_plates_match(possible_match, witnessed_plate)])
                  return matching_plates

                  def do_plates_match(plate1, plate2):
                  for first_char, second_char in zip(plate1, plate2):
                  if first_char == "?" or second_char == "?": continue
                  elif first_char != second_char: return False
                  return True


                  Now calling:



                  plate = "VF???55"
                  print("Plate: ", plate)
                  print(match_list2(plate,["VX33322","VF12355","VF77455","DA?????","VF10055"]))


                  outputs:



                  Plate:  VF???55
                  [['VX33322', False], ['VF12355', True], ['VF77455', True], ['DA?????', False], ['VF10055', True]]


                  clearly showing which plates match, and which don't.



                  HTH.






                  share|improve this answer













                  Fixing the TypeError:



                  The interpreter is telling you exactly where and why you're getting the issue. Here's your MVCE:



                  >>> range[1]
                  Traceback (most recent call last):
                  File "<stdin>", line 1, in <module>
                  TypeError: 'type' object is not subscriptable


                  You can't use square brackets, or subscripts (i.e. ) on the built-in range. Rather, use parenthesis (()):



                  >>> range(1)
                  range(0, 1)


                  So change this line:



                  for x in range[len(listLicencePlates)] # bad news, range[...]


                  to be



                  for x in range(len(listLicencePlates)) # Better, range(...)


                  and you'll get past the TypeError.



                  Fixing the core issue:



                  I am guessing, however, that the output you get from this fix isn't what you want. This is the output:



                  [['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5'], ['V', 'F', '1', '0', '0', '5', '5']]


                  Which doesn't look useful.



                  What I think you probably want is an array of bools, where each bool describes whether or not the plate matched character by character, and the "?" represents a wildcard character.



                  Let's try a more Pythonic and less C-style approach to the problem with some extraordinarily verbose comments:



                  def match_list2(witnessed_plate, license_plates):
                  matching_plates =
                  # just loop through the items, no need for range/indices
                  for possible_match in license_plates:
                  # If they match, create 2-elt list with
                  # the plate as first elt and whether or not it matches as second
                  # Worry about do_plates_match later. Just get the high level logic
                  # down pat and sound first.
                  matching_plates.append([possible_match,
                  do_plates_match(possible_match, witnessed_plate)])
                  return matching_plates

                  def do_plates_match(plate1, plate2): # Define if they match (the time to worry is upon us)
                  # Loop through characters from plate1 and plate2 simultaneously
                  for first_char, second_char in zip(plate1, plate2):
                  if first_char == "?" or second_char == "?":
                  # If we get a question mark, go to the next character
                  continue
                  elif first_char != second_char:
                  # If they don't match at *some* character,
                  # we know they can't match regardless of what's next, so return False
                  return False
                  # Only way to get here is we must have matched for all characters, return True.
                  return True


                  and for those who find the comments distracting and would rather just read the code straight away:



                  def match_list2(witnessed_plate, license_plates):
                  matching_plates =
                  for possible_match in license_plates:
                  matching_plates.append([possible_match, do_plates_match(possible_match, witnessed_plate)])
                  return matching_plates

                  def do_plates_match(plate1, plate2):
                  for first_char, second_char in zip(plate1, plate2):
                  if first_char == "?" or second_char == "?": continue
                  elif first_char != second_char: return False
                  return True


                  Now calling:



                  plate = "VF???55"
                  print("Plate: ", plate)
                  print(match_list2(plate,["VX33322","VF12355","VF77455","DA?????","VF10055"]))


                  outputs:



                  Plate:  VF???55
                  [['VX33322', False], ['VF12355', True], ['VF77455', True], ['DA?????', False], ['VF10055', True]]


                  clearly showing which plates match, and which don't.



                  HTH.







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                  answered Nov 27 '18 at 22:58









                  Matt MessersmithMatt Messersmith

                  6,24921832




                  6,24921832






























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