How to convert json into json array in pgsql
I face some issue to convert the data into json object. There is a table called milestone with the following data:
id name parentId
a test1 A
b test2 B
c test3 C
d test4 A
e test5 B
I want to convert the result into a json type in Postgres:
content(json type) parentId
"assignees": [{"id": "a", "name": "test1"},{"id": "d", "name": "test4"}] A
"assignees": [{"id": "b", "name": "test2"},{"id": "e", "name": "test5"}] B
"assignees": [{"id": "c", "name": "test3"}] C
sql json postgresql
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
asked Nov 23 at 2:21
mres
82
add a comment |
I face some issue to convert the data into json object. There is a table called milestone with the following data:
id name parentId
a test1 A
b test2 B
c test3 C
d test4 A
e test5 B
I want to convert the result into a json type in Postgres:
content(json type) parentId
"assignees": [{"id": "a", "name": "test1"},{"id": "d", "name": "test4"}] A
"assignees": [{"id": "b", "name": "test2"},{"id": "e", "name": "test5"}] B
"assignees": [{"id": "c", "name": "test3"}] C
sql json postgresql
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
asked Nov 23 at 2:21
mres
82
add a comment |
I face some issue to convert the data into json object. There is a table called milestone with the following data:
id name parentId
a test1 A
b test2 B
c test3 C
d test4 A
e test5 B
I want to convert the result into a json type in Postgres:
content(json type) parentId
"assignees": [{"id": "a", "name": "test1"},{"id": "d", "name": "test4"}] A
"assignees": [{"id": "b", "name": "test2"},{"id": "e", "name": "test5"}] B
"assignees": [{"id": "c", "name": "test3"}] C
sql json postgresql
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
asked Nov 23 at 2:21
mres
82
I face some issue to convert the data into json object. There is a table called milestone with the following data:
id name parentId
a test1 A
b test2 B
c test3 C
d test4 A
e test5 B
I want to convert the result into a json type in Postgres:
content(json type) parentId
"assignees": [{"id": "a", "name": "test1"},{"id": "d", "name": "test4"}] A
"assignees": [{"id": "b", "name": "test2"},{"id": "e", "name": "test5"}] B
"assignees": [{"id": "c", "name": "test3"}] C
sql json postgresql
sql json postgresql
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
asked Nov 23 at 2:21
mres
82
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
asked Nov 23 at 2:21
mres
82
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
edited Nov 23 at 6:49
a_horse_with_no_name
291k46444537
291k46444537
asked Nov 23 at 2:21
mres
82
asked Nov 23 at 2:21
mres
82
asked Nov 23 at 2:21
mres
82
82
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can use jsonb_build_object() to create the id/name pairs, and then aggregate that into an array using jsonb_agg():
select parentid,
jsonb_build_object('assignees', jsonb_agg(jsonb_build_object('id', id, 'name', name)))
from milestone
group by parentid
order by parentid;
If you don't want to repeat the column names, or if you have more columns than you have shown you could also use to_jsonb() and then remove the parentid:
select m.parentid,
jsonb_build_object('assignees', jsonb_agg(to_jsonb(m) - 'parentid')))
from milestone m
group by m.parentid
order by m.parentid;
Online example: https://rextester.com/JXVFF71777
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use jsonb_build_object() to create the id/name pairs, and then aggregate that into an array using jsonb_agg():
select parentid,
jsonb_build_object('assignees', jsonb_agg(jsonb_build_object('id', id, 'name', name)))
from milestone
group by parentid
order by parentid;
If you don't want to repeat the column names, or if you have more columns than you have shown you could also use to_jsonb() and then remove the parentid:
select m.parentid,
jsonb_build_object('assignees', jsonb_agg(to_jsonb(m) - 'parentid')))
from milestone m
group by m.parentid
order by m.parentid;
Online example: https://rextester.com/JXVFF71777
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
add a comment |
You can use jsonb_build_object() to create the id/name pairs, and then aggregate that into an array using jsonb_agg():
select parentid,
jsonb_build_object('assignees', jsonb_agg(jsonb_build_object('id', id, 'name', name)))
from milestone
group by parentid
order by parentid;
If you don't want to repeat the column names, or if you have more columns than you have shown you could also use to_jsonb() and then remove the parentid:
select m.parentid,
jsonb_build_object('assignees', jsonb_agg(to_jsonb(m) - 'parentid')))
from milestone m
group by m.parentid
order by m.parentid;
Online example: https://rextester.com/JXVFF71777
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
add a comment |
You can use jsonb_build_object() to create the id/name pairs, and then aggregate that into an array using jsonb_agg():
select parentid,
jsonb_build_object('assignees', jsonb_agg(jsonb_build_object('id', id, 'name', name)))
from milestone
group by parentid
order by parentid;
If you don't want to repeat the column names, or if you have more columns than you have shown you could also use to_jsonb() and then remove the parentid:
select m.parentid,
jsonb_build_object('assignees', jsonb_agg(to_jsonb(m) - 'parentid')))
from milestone m
group by m.parentid
order by m.parentid;
Online example: https://rextester.com/JXVFF71777
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
You can use jsonb_build_object() to create the id/name pairs, and then aggregate that into an array using jsonb_agg():
select parentid,
jsonb_build_object('assignees', jsonb_agg(jsonb_build_object('id', id, 'name', name)))
from milestone
group by parentid
order by parentid;
If you don't want to repeat the column names, or if you have more columns than you have shown you could also use to_jsonb() and then remove the parentid:
select m.parentid,
jsonb_build_object('assignees', jsonb_agg(to_jsonb(m) - 'parentid')))
from milestone m
group by m.parentid
order by m.parentid;
Online example: https://rextester.com/JXVFF71777
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
edited Nov 23 at 7:03
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
answered Nov 23 at 6:52
a_horse_with_no_name
291k46444537
291k46444537
add a comment |
add a comment |
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