First index is not integer using foreach loop from 0












1















I am trying to draw a tree using tikzpicture like this:



begin{tikzpicture}
tikzstyle{node}=[circle, fill=blue!25, minimum size=0.1 cm];
foreach ilayer in {0,...,3} {
tikzmath {nnodes = 3 ^ ilayer; }
tikzmath {leftnum = 1 - floor(nnodes / 2) - 1; }
tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
foreach isibling in {leftnum,...,rightnum} {
tikzmath {d = 3 ^ (- ilayer) * 15; }
tikzmath {x = isibling * d; }
tikzmath {y = - ilayer * 2; }
node[node] (node_ilayer_isibling) at (x cm, y cm) {isibling};
}
}
end{tikzpicture}


I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



enter image description here










share|improve this question







New contributor




landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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    1















    I am trying to draw a tree using tikzpicture like this:



    begin{tikzpicture}
    tikzstyle{node}=[circle, fill=blue!25, minimum size=0.1 cm];
    foreach ilayer in {0,...,3} {
    tikzmath {nnodes = 3 ^ ilayer; }
    tikzmath {leftnum = 1 - floor(nnodes / 2) - 1; }
    tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
    foreach isibling in {leftnum,...,rightnum} {
    tikzmath {d = 3 ^ (- ilayer) * 15; }
    tikzmath {x = isibling * d; }
    tikzmath {y = - ilayer * 2; }
    node[node] (node_ilayer_isibling) at (x cm, y cm) {isibling};
    }
    }
    end{tikzpicture}


    I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



    enter image description here










    share|improve this question







    New contributor




    landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      1












      1








      1








      I am trying to draw a tree using tikzpicture like this:



      begin{tikzpicture}
      tikzstyle{node}=[circle, fill=blue!25, minimum size=0.1 cm];
      foreach ilayer in {0,...,3} {
      tikzmath {nnodes = 3 ^ ilayer; }
      tikzmath {leftnum = 1 - floor(nnodes / 2) - 1; }
      tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
      foreach isibling in {leftnum,...,rightnum} {
      tikzmath {d = 3 ^ (- ilayer) * 15; }
      tikzmath {x = isibling * d; }
      tikzmath {y = - ilayer * 2; }
      node[node] (node_ilayer_isibling) at (x cm, y cm) {isibling};
      }
      }
      end{tikzpicture}


      I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



      enter image description here










      share|improve this question







      New contributor




      landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I am trying to draw a tree using tikzpicture like this:



      begin{tikzpicture}
      tikzstyle{node}=[circle, fill=blue!25, minimum size=0.1 cm];
      foreach ilayer in {0,...,3} {
      tikzmath {nnodes = 3 ^ ilayer; }
      tikzmath {leftnum = 1 - floor(nnodes / 2) - 1; }
      tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
      foreach isibling in {leftnum,...,rightnum} {
      tikzmath {d = 3 ^ (- ilayer) * 15; }
      tikzmath {x = isibling * d; }
      tikzmath {y = - ilayer * 2; }
      node[node] (node_ilayer_isibling) at (x cm, y cm) {isibling};
      }
      }
      end{tikzpicture}


      I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



      enter image description here







      tikz-pgf foreach






      share|improve this question







      New contributor




      landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 1 hour ago









      landingslandings

      81




      81




      New contributor




      landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      landings is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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      Check out our Code of Conduct.






















          1 Answer
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          0














          You could just tell TikZ explicitly that you want an integer.



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {nnodes = 3 ^ ilayer; }
          tikzmath {leftnum = int(1 - floor(nnodes / 2) - 1); }
          tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15; }
          tikzmath {x = isibling * d; }
          tikzmath {y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here



          Or



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {int nnodes,leftnum,rightnum;
          nnodes = 3 ^ ilayer;
          leftnum = 1 - floor(nnodes / 2) - 1;
          rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15;
          x = isibling * d;
          y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          In principle you do not need the math library here.



          documentclass[tikz,border=3.14mm]{standalone}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer [evaluate=ilayer as nnodes using {int(3 ^ ilayer)},
          evaluate=nnodes as leftnum using {int(1 - floor(nnodes / 2) - 1)},
          evaluate=nnodes as rightnum using {int(nnodes - floor(nnodes / 2) - 1)}]
          in {0,...,3} {
          foreach isibling
          [evaluate=ilayer as d using {3 ^ (- ilayer) * 15},
          evaluate=isibling as x using {isibling * d},
          evaluate=ilayer as y using {- ilayer * 2}]
          in {leftnum,...,rightnum} {
          node[mynode] (node_ilayer_isibling) at (x cm, y cm)
          {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer


























          • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

            – landings
            45 mins ago











          • @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

            – marmot
            39 mins ago











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          1 Answer
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          1 Answer
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          active

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          active

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          0














          You could just tell TikZ explicitly that you want an integer.



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {nnodes = 3 ^ ilayer; }
          tikzmath {leftnum = int(1 - floor(nnodes / 2) - 1); }
          tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15; }
          tikzmath {x = isibling * d; }
          tikzmath {y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here



          Or



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {int nnodes,leftnum,rightnum;
          nnodes = 3 ^ ilayer;
          leftnum = 1 - floor(nnodes / 2) - 1;
          rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15;
          x = isibling * d;
          y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          In principle you do not need the math library here.



          documentclass[tikz,border=3.14mm]{standalone}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer [evaluate=ilayer as nnodes using {int(3 ^ ilayer)},
          evaluate=nnodes as leftnum using {int(1 - floor(nnodes / 2) - 1)},
          evaluate=nnodes as rightnum using {int(nnodes - floor(nnodes / 2) - 1)}]
          in {0,...,3} {
          foreach isibling
          [evaluate=ilayer as d using {3 ^ (- ilayer) * 15},
          evaluate=isibling as x using {isibling * d},
          evaluate=ilayer as y using {- ilayer * 2}]
          in {leftnum,...,rightnum} {
          node[mynode] (node_ilayer_isibling) at (x cm, y cm)
          {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer


























          • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

            – landings
            45 mins ago











          • @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

            – marmot
            39 mins ago
















          0














          You could just tell TikZ explicitly that you want an integer.



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {nnodes = 3 ^ ilayer; }
          tikzmath {leftnum = int(1 - floor(nnodes / 2) - 1); }
          tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15; }
          tikzmath {x = isibling * d; }
          tikzmath {y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here



          Or



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {int nnodes,leftnum,rightnum;
          nnodes = 3 ^ ilayer;
          leftnum = 1 - floor(nnodes / 2) - 1;
          rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15;
          x = isibling * d;
          y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          In principle you do not need the math library here.



          documentclass[tikz,border=3.14mm]{standalone}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer [evaluate=ilayer as nnodes using {int(3 ^ ilayer)},
          evaluate=nnodes as leftnum using {int(1 - floor(nnodes / 2) - 1)},
          evaluate=nnodes as rightnum using {int(nnodes - floor(nnodes / 2) - 1)}]
          in {0,...,3} {
          foreach isibling
          [evaluate=ilayer as d using {3 ^ (- ilayer) * 15},
          evaluate=isibling as x using {isibling * d},
          evaluate=ilayer as y using {- ilayer * 2}]
          in {leftnum,...,rightnum} {
          node[mynode] (node_ilayer_isibling) at (x cm, y cm)
          {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer


























          • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

            – landings
            45 mins ago











          • @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

            – marmot
            39 mins ago














          0












          0








          0







          You could just tell TikZ explicitly that you want an integer.



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {nnodes = 3 ^ ilayer; }
          tikzmath {leftnum = int(1 - floor(nnodes / 2) - 1); }
          tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15; }
          tikzmath {x = isibling * d; }
          tikzmath {y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here



          Or



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {int nnodes,leftnum,rightnum;
          nnodes = 3 ^ ilayer;
          leftnum = 1 - floor(nnodes / 2) - 1;
          rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15;
          x = isibling * d;
          y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          In principle you do not need the math library here.



          documentclass[tikz,border=3.14mm]{standalone}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer [evaluate=ilayer as nnodes using {int(3 ^ ilayer)},
          evaluate=nnodes as leftnum using {int(1 - floor(nnodes / 2) - 1)},
          evaluate=nnodes as rightnum using {int(nnodes - floor(nnodes / 2) - 1)}]
          in {0,...,3} {
          foreach isibling
          [evaluate=ilayer as d using {3 ^ (- ilayer) * 15},
          evaluate=isibling as x using {isibling * d},
          evaluate=ilayer as y using {- ilayer * 2}]
          in {leftnum,...,rightnum} {
          node[mynode] (node_ilayer_isibling) at (x cm, y cm)
          {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here






          share|improve this answer















          You could just tell TikZ explicitly that you want an integer.



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {nnodes = 3 ^ ilayer; }
          tikzmath {leftnum = int(1 - floor(nnodes / 2) - 1); }
          tikzmath {rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15; }
          tikzmath {x = isibling * d; }
          tikzmath {y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here



          Or



          documentclass[tikz,border=3.14mm]{standalone}
          usetikzlibrary{math}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer in {0,...,3} {
          tikzmath {int nnodes,leftnum,rightnum;
          nnodes = 3 ^ ilayer;
          leftnum = 1 - floor(nnodes / 2) - 1;
          rightnum = nnodes - floor(nnodes / 2) - 1; }
          foreach isibling in {leftnum,...,rightnum} {
          tikzmath {d = 3 ^ (- ilayer) * 15;
          x = isibling * d;
          y = - ilayer * 2; }
          node[mynode] (node_ilayer_isibling) at (x cm, y cm) {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          In principle you do not need the math library here.



          documentclass[tikz,border=3.14mm]{standalone}
          begin{document}
          begin{tikzpicture}
          tikzset{mynode/.style={circle, fill=blue!25, minimum size=0.1 cm}}
          foreach ilayer [evaluate=ilayer as nnodes using {int(3 ^ ilayer)},
          evaluate=nnodes as leftnum using {int(1 - floor(nnodes / 2) - 1)},
          evaluate=nnodes as rightnum using {int(nnodes - floor(nnodes / 2) - 1)}]
          in {0,...,3} {
          foreach isibling
          [evaluate=ilayer as d using {3 ^ (- ilayer) * 15},
          evaluate=isibling as x using {isibling * d},
          evaluate=ilayer as y using {- ilayer * 2}]
          in {leftnum,...,rightnum} {
          node[mynode] (node_ilayer_isibling) at (x cm, y cm)
          {isibling};
          }
          }
          end{tikzpicture}
          end{document}


          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 43 mins ago

























          answered 56 mins ago









          marmotmarmot

          112k5141267




          112k5141267













          • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

            – landings
            45 mins ago











          • @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

            – marmot
            39 mins ago



















          • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

            – landings
            45 mins ago











          • @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

            – marmot
            39 mins ago

















          Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

          – landings
          45 mins ago





          Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

          – landings
          45 mins ago













          @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

          – marmot
          39 mins ago





          @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

          – marmot
          39 mins ago










          landings is a new contributor. Be nice, and check out our Code of Conduct.










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          landings is a new contributor. Be nice, and check out our Code of Conduct.













          landings is a new contributor. Be nice, and check out our Code of Conduct.












          landings is a new contributor. Be nice, and check out our Code of Conduct.
















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