Photos Displayed












-1















How do I disable the submit button once the photos is displayed on the page? Anyone knows?
Here's my code:



        if("#pic" == true){
}
else{
$("#submit").click(function () {
var button = $(this);
button.attr('disabled', 'disabled');
});

}









share|improve this question

























  • stackoverflow.com/questions/15122526/disable-button-in-jquery

    – JP4
    Nov 27 '18 at 0:36











  • the submit button need to disabled when the photo is displayed

    – Rod
    Nov 27 '18 at 0:37






  • 1





    Do you have some sort of variable keeping track of whether the photo is displayed or not?

    – JP4
    Nov 27 '18 at 0:39











  • Just to let you know you're missing a closing bracket for the first if statement. if("#pic" == true){ //if block }else{ //else block }

    – Sarah
    Nov 27 '18 at 0:42













  • Possible duplicate of Disable button in jQuery

    – Rob
    Nov 27 '18 at 0:46
















-1















How do I disable the submit button once the photos is displayed on the page? Anyone knows?
Here's my code:



        if("#pic" == true){
}
else{
$("#submit").click(function () {
var button = $(this);
button.attr('disabled', 'disabled');
});

}









share|improve this question

























  • stackoverflow.com/questions/15122526/disable-button-in-jquery

    – JP4
    Nov 27 '18 at 0:36











  • the submit button need to disabled when the photo is displayed

    – Rod
    Nov 27 '18 at 0:37






  • 1





    Do you have some sort of variable keeping track of whether the photo is displayed or not?

    – JP4
    Nov 27 '18 at 0:39











  • Just to let you know you're missing a closing bracket for the first if statement. if("#pic" == true){ //if block }else{ //else block }

    – Sarah
    Nov 27 '18 at 0:42













  • Possible duplicate of Disable button in jQuery

    – Rob
    Nov 27 '18 at 0:46














-1












-1








-1








How do I disable the submit button once the photos is displayed on the page? Anyone knows?
Here's my code:



        if("#pic" == true){
}
else{
$("#submit").click(function () {
var button = $(this);
button.attr('disabled', 'disabled');
});

}









share|improve this question
















How do I disable the submit button once the photos is displayed on the page? Anyone knows?
Here's my code:



        if("#pic" == true){
}
else{
$("#submit").click(function () {
var button = $(this);
button.attr('disabled', 'disabled');
});

}






javascript jquery ajax






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 27 '18 at 1:12







Rod

















asked Nov 27 '18 at 0:13









RodRod

307




307













  • stackoverflow.com/questions/15122526/disable-button-in-jquery

    – JP4
    Nov 27 '18 at 0:36











  • the submit button need to disabled when the photo is displayed

    – Rod
    Nov 27 '18 at 0:37






  • 1





    Do you have some sort of variable keeping track of whether the photo is displayed or not?

    – JP4
    Nov 27 '18 at 0:39











  • Just to let you know you're missing a closing bracket for the first if statement. if("#pic" == true){ //if block }else{ //else block }

    – Sarah
    Nov 27 '18 at 0:42













  • Possible duplicate of Disable button in jQuery

    – Rob
    Nov 27 '18 at 0:46



















  • stackoverflow.com/questions/15122526/disable-button-in-jquery

    – JP4
    Nov 27 '18 at 0:36











  • the submit button need to disabled when the photo is displayed

    – Rod
    Nov 27 '18 at 0:37






  • 1





    Do you have some sort of variable keeping track of whether the photo is displayed or not?

    – JP4
    Nov 27 '18 at 0:39











  • Just to let you know you're missing a closing bracket for the first if statement. if("#pic" == true){ //if block }else{ //else block }

    – Sarah
    Nov 27 '18 at 0:42













  • Possible duplicate of Disable button in jQuery

    – Rob
    Nov 27 '18 at 0:46

















stackoverflow.com/questions/15122526/disable-button-in-jquery

– JP4
Nov 27 '18 at 0:36





stackoverflow.com/questions/15122526/disable-button-in-jquery

– JP4
Nov 27 '18 at 0:36













the submit button need to disabled when the photo is displayed

– Rod
Nov 27 '18 at 0:37





the submit button need to disabled when the photo is displayed

– Rod
Nov 27 '18 at 0:37




1




1





Do you have some sort of variable keeping track of whether the photo is displayed or not?

– JP4
Nov 27 '18 at 0:39





Do you have some sort of variable keeping track of whether the photo is displayed or not?

– JP4
Nov 27 '18 at 0:39













Just to let you know you're missing a closing bracket for the first if statement. if("#pic" == true){ //if block }else{ //else block }

– Sarah
Nov 27 '18 at 0:42







Just to let you know you're missing a closing bracket for the first if statement. if("#pic" == true){ //if block }else{ //else block }

– Sarah
Nov 27 '18 at 0:42















Possible duplicate of Disable button in jQuery

– Rob
Nov 27 '18 at 0:46





Possible duplicate of Disable button in jQuery

– Rob
Nov 27 '18 at 0:46












1 Answer
1






active

oldest

votes


















0














here's the modified code






$('#pic').on('load', function() {
console.log("loaded");

$('#submit').attr('disabled',true);
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="pic" src="https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png" />

<button id="submit">hello</button>





if the img source is improper it won't render and the load method is hence not called, so we are sure of the proper image source and after rendering it calls the Load method in which you can disable your button






share|improve this answer
























  • If I want to display 5 photos that the user uploaded how should I write the source load method?

    – Rod
    Nov 27 '18 at 5:54











  • the photos are in the loop $("#photo" + i)

    – Rod
    Nov 27 '18 at 5:55











  • pls share entire snippet of upload + html

    – Yash Soni
    Nov 27 '18 at 5:59











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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









0














here's the modified code






$('#pic').on('load', function() {
console.log("loaded");

$('#submit').attr('disabled',true);
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="pic" src="https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png" />

<button id="submit">hello</button>





if the img source is improper it won't render and the load method is hence not called, so we are sure of the proper image source and after rendering it calls the Load method in which you can disable your button






share|improve this answer
























  • If I want to display 5 photos that the user uploaded how should I write the source load method?

    – Rod
    Nov 27 '18 at 5:54











  • the photos are in the loop $("#photo" + i)

    – Rod
    Nov 27 '18 at 5:55











  • pls share entire snippet of upload + html

    – Yash Soni
    Nov 27 '18 at 5:59
















0














here's the modified code






$('#pic').on('load', function() {
console.log("loaded");

$('#submit').attr('disabled',true);
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="pic" src="https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png" />

<button id="submit">hello</button>





if the img source is improper it won't render and the load method is hence not called, so we are sure of the proper image source and after rendering it calls the Load method in which you can disable your button






share|improve this answer
























  • If I want to display 5 photos that the user uploaded how should I write the source load method?

    – Rod
    Nov 27 '18 at 5:54











  • the photos are in the loop $("#photo" + i)

    – Rod
    Nov 27 '18 at 5:55











  • pls share entire snippet of upload + html

    – Yash Soni
    Nov 27 '18 at 5:59














0












0








0







here's the modified code






$('#pic').on('load', function() {
console.log("loaded");

$('#submit').attr('disabled',true);
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="pic" src="https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png" />

<button id="submit">hello</button>





if the img source is improper it won't render and the load method is hence not called, so we are sure of the proper image source and after rendering it calls the Load method in which you can disable your button






share|improve this answer













here's the modified code






$('#pic').on('load', function() {
console.log("loaded");

$('#submit').attr('disabled',true);
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="pic" src="https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png" />

<button id="submit">hello</button>





if the img source is improper it won't render and the load method is hence not called, so we are sure of the proper image source and after rendering it calls the Load method in which you can disable your button






$('#pic').on('load', function() {
console.log("loaded");

$('#submit').attr('disabled',true);
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="pic" src="https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png" />

<button id="submit">hello</button>





$('#pic').on('load', function() {
console.log("loaded");

$('#submit').attr('disabled',true);
})

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<img id="pic" src="https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png" />

<button id="submit">hello</button>






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 27 '18 at 5:04









Yash SoniYash Soni

48510




48510













  • If I want to display 5 photos that the user uploaded how should I write the source load method?

    – Rod
    Nov 27 '18 at 5:54











  • the photos are in the loop $("#photo" + i)

    – Rod
    Nov 27 '18 at 5:55











  • pls share entire snippet of upload + html

    – Yash Soni
    Nov 27 '18 at 5:59



















  • If I want to display 5 photos that the user uploaded how should I write the source load method?

    – Rod
    Nov 27 '18 at 5:54











  • the photos are in the loop $("#photo" + i)

    – Rod
    Nov 27 '18 at 5:55











  • pls share entire snippet of upload + html

    – Yash Soni
    Nov 27 '18 at 5:59

















If I want to display 5 photos that the user uploaded how should I write the source load method?

– Rod
Nov 27 '18 at 5:54





If I want to display 5 photos that the user uploaded how should I write the source load method?

– Rod
Nov 27 '18 at 5:54













the photos are in the loop $("#photo" + i)

– Rod
Nov 27 '18 at 5:55





the photos are in the loop $("#photo" + i)

– Rod
Nov 27 '18 at 5:55













pls share entire snippet of upload + html

– Yash Soni
Nov 27 '18 at 5:59





pls share entire snippet of upload + html

– Yash Soni
Nov 27 '18 at 5:59




















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