Asp.Net Web Api 2 Json deserialization parsing unquoted character
I am trying to understand a deserialization quirk around an invalid json request when trying to set a double with unquoted values. Given the example controller
public class TestController : ApiController
{
public IHttpActionResult Post([FromBody] Foo foo)
{
return Ok();
}
}
public class Foo
{
public string StringOne { get; set; }
public double Bah { get; set; }
public string StringTwo { get; set; }
}
The valid case with a JSON object such as:
{
"StringOne": "Lorem",
"Bah" : 1.2,
"StringTwo" : "Ipsum"
}
will build a foo object as you would expect, setting all three values correctly. The following invalid JSON will result in foo being set to null. Again this seems expected
{
"StringOne": "Lorem",
"Bah" : ThisIsntRight,
"StringTwo" : "Ipsum"
}
However when the following JSON is used
{
"StringOne": "Lorem",
"Bah" : Q,
"StringTwo" : "Ipsum"
}
foo is deserialized and Bah has a value of 0. I expected this to behave like the second example and to have foo set to null. I was hoping to understand what is going on in this case.
Note: This was recreated with the default empty web.api project and adding the above Controller.
c# json asp.net-web-api2
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
add a comment |
I am trying to understand a deserialization quirk around an invalid json request when trying to set a double with unquoted values. Given the example controller
public class TestController : ApiController
{
public IHttpActionResult Post([FromBody] Foo foo)
{
return Ok();
}
}
public class Foo
{
public string StringOne { get; set; }
public double Bah { get; set; }
public string StringTwo { get; set; }
}
The valid case with a JSON object such as:
{
"StringOne": "Lorem",
"Bah" : 1.2,
"StringTwo" : "Ipsum"
}
will build a foo object as you would expect, setting all three values correctly. The following invalid JSON will result in foo being set to null. Again this seems expected
{
"StringOne": "Lorem",
"Bah" : ThisIsntRight,
"StringTwo" : "Ipsum"
}
However when the following JSON is used
{
"StringOne": "Lorem",
"Bah" : Q,
"StringTwo" : "Ipsum"
}
foo is deserialized and Bah has a value of 0. I expected this to behave like the second example and to have foo set to null. I was hoping to understand what is going on in this case.
Note: This was recreated with the default empty web.api project and adding the above Controller.
c# json asp.net-web-api2
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
Have you trieddecimalinstead ofdouble?
– Hanjun Chen
Nov 27 '18 at 4:11
decimalhas the same behaviour
– Paul Wild
Nov 27 '18 at 9:11
What happens if you send two letters? could it be because it tries to parse it as a char?
– Pablo Ferro
Nov 27 '18 at 14:08
Two letters will return a null object. So some char related magic seems like a good bet
– Paul Wild
Nov 27 '18 at 20:34
add a comment |
I am trying to understand a deserialization quirk around an invalid json request when trying to set a double with unquoted values. Given the example controller
public class TestController : ApiController
{
public IHttpActionResult Post([FromBody] Foo foo)
{
return Ok();
}
}
public class Foo
{
public string StringOne { get; set; }
public double Bah { get; set; }
public string StringTwo { get; set; }
}
The valid case with a JSON object such as:
{
"StringOne": "Lorem",
"Bah" : 1.2,
"StringTwo" : "Ipsum"
}
will build a foo object as you would expect, setting all three values correctly. The following invalid JSON will result in foo being set to null. Again this seems expected
{
"StringOne": "Lorem",
"Bah" : ThisIsntRight,
"StringTwo" : "Ipsum"
}
However when the following JSON is used
{
"StringOne": "Lorem",
"Bah" : Q,
"StringTwo" : "Ipsum"
}
foo is deserialized and Bah has a value of 0. I expected this to behave like the second example and to have foo set to null. I was hoping to understand what is going on in this case.
Note: This was recreated with the default empty web.api project and adding the above Controller.
c# json asp.net-web-api2
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
I am trying to understand a deserialization quirk around an invalid json request when trying to set a double with unquoted values. Given the example controller
public class TestController : ApiController
{
public IHttpActionResult Post([FromBody] Foo foo)
{
return Ok();
}
}
public class Foo
{
public string StringOne { get; set; }
public double Bah { get; set; }
public string StringTwo { get; set; }
}
The valid case with a JSON object such as:
{
"StringOne": "Lorem",
"Bah" : 1.2,
"StringTwo" : "Ipsum"
}
will build a foo object as you would expect, setting all three values correctly. The following invalid JSON will result in foo being set to null. Again this seems expected
{
"StringOne": "Lorem",
"Bah" : ThisIsntRight,
"StringTwo" : "Ipsum"
}
However when the following JSON is used
{
"StringOne": "Lorem",
"Bah" : Q,
"StringTwo" : "Ipsum"
}
foo is deserialized and Bah has a value of 0. I expected this to behave like the second example and to have foo set to null. I was hoping to understand what is going on in this case.
Note: This was recreated with the default empty web.api project and adding the above Controller.
c# json asp.net-web-api2
c# json asp.net-web-api2
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
asked Nov 27 '18 at 0:02
Paul WildPaul Wild
13318
13318
Have you trieddecimalinstead ofdouble?
– Hanjun Chen
Nov 27 '18 at 4:11
decimalhas the same behaviour
– Paul Wild
Nov 27 '18 at 9:11
What happens if you send two letters? could it be because it tries to parse it as a char?
– Pablo Ferro
Nov 27 '18 at 14:08
Two letters will return a null object. So some char related magic seems like a good bet
– Paul Wild
Nov 27 '18 at 20:34
add a comment |
Have you trieddecimalinstead ofdouble?
– Hanjun Chen
Nov 27 '18 at 4:11
decimalhas the same behaviour
– Paul Wild
Nov 27 '18 at 9:11
What happens if you send two letters? could it be because it tries to parse it as a char?
– Pablo Ferro
Nov 27 '18 at 14:08
Two letters will return a null object. So some char related magic seems like a good bet
– Paul Wild
Nov 27 '18 at 20:34
Have you tried
decimal instead of double?– Hanjun Chen
Nov 27 '18 at 4:11
Have you tried
decimal instead of double?– Hanjun Chen
Nov 27 '18 at 4:11
decimal has the same behaviour– Paul Wild
Nov 27 '18 at 9:11
decimal has the same behaviour– Paul Wild
Nov 27 '18 at 9:11
What happens if you send two letters? could it be because it tries to parse it as a char?
– Pablo Ferro
Nov 27 '18 at 14:08
What happens if you send two letters? could it be because it tries to parse it as a char?
– Pablo Ferro
Nov 27 '18 at 14:08
Two letters will return a null object. So some char related magic seems like a good bet
– Paul Wild
Nov 27 '18 at 20:34
Two letters will return a null object. So some char related magic seems like a good bet
– Paul Wild
Nov 27 '18 at 20:34
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53490894%2fasp-net-web-api-2-json-deserialization-parsing-unquoted-character%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53490894%2fasp-net-web-api-2-json-deserialization-parsing-unquoted-character%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Have you tried
decimalinstead ofdouble?– Hanjun Chen
Nov 27 '18 at 4:11
decimalhas the same behaviour– Paul Wild
Nov 27 '18 at 9:11
What happens if you send two letters? could it be because it tries to parse it as a char?
– Pablo Ferro
Nov 27 '18 at 14:08
Two letters will return a null object. So some char related magic seems like a good bet
– Paul Wild
Nov 27 '18 at 20:34