loop through 2 vectors simultaneously and save in new vector












1















I have 2 vectors : 



index <- as.integer(c(3, 5, 7))

sen <- c("first", "second", "third", "fourth", "fifth", "sixth", "seventh")


I want to save each string, according to its index in a new vector :



 mySen <- vector(mode = "character", length = length(index))


such that 



> mySen

[1] "third"

[2] "fifth"

[3] "seventh"


I've tried nested loops but they output indices i and j of length 6



for (j in index){

  for(i in 1:length(index)){

    print(c(i,j))

  }

}



[1] 1 3

[1] 2 3

[1] 3 3

[1] 1 5

[1] 2 5

[1] 3 5

[1] 1 7

[1] 2 7

[1] 3 7


whereas I want indices



1 3

2 5

3 7


Most importantly, I want my new vector mySen to be properly filled in as mentioned before



> mySen

[1] "third"

[2] "fifth"

[3] "seventh"





r loops for-loop nested







share|improve this question





























    1















    I have 2 vectors : 



    index <- as.integer(c(3, 5, 7))
    
sen <- c("first", "second", "third", "fourth", "fifth", "sixth", "seventh")


    I want to save each string, according to its index in a new vector :



     mySen <- vector(mode = "character", length = length(index))


    such that 



    > mySen
    
[1] "third"
    
[2] "fifth"
    
[3] "seventh"


    I've tried nested loops but they output indices i and j of length 6



    for (j in index){
    
  for(i in 1:length(index)){
    
    print(c(i,j))
    
  }
    
}
    

    
[1] 1 3
    
[1] 2 3
    
[1] 3 3
    
[1] 1 5
    
[1] 2 5
    
[1] 3 5
    
[1] 1 7
    
[1] 2 7
    
[1] 3 7


    whereas I want indices



    1 3
    
2 5
    
3 7


    Most importantly, I want my new vector mySen to be properly filled in as mentioned before



    > mySen
    
[1] "third"
    
[2] "fifth"
    
[3] "seventh"





    r loops for-loop nested







    share|improve this question



























      1












      1








      1








      I have 2 vectors : 



      index <- as.integer(c(3, 5, 7))
      
sen <- c("first", "second", "third", "fourth", "fifth", "sixth", "seventh")


      I want to save each string, according to its index in a new vector :



       mySen <- vector(mode = "character", length = length(index))


      such that 



      > mySen
      
[1] "third"
      
[2] "fifth"
      
[3] "seventh"


      I've tried nested loops but they output indices i and j of length 6



      for (j in index){
      
  for(i in 1:length(index)){
      
    print(c(i,j))
      
  }
      
}
      

      
[1] 1 3
      
[1] 2 3
      
[1] 3 3
      
[1] 1 5
      
[1] 2 5
      
[1] 3 5
      
[1] 1 7
      
[1] 2 7
      
[1] 3 7


      whereas I want indices



      1 3
      
2 5
      
3 7


      Most importantly, I want my new vector mySen to be properly filled in as mentioned before



      > mySen
      
[1] "third"
      
[2] "fifth"
      
[3] "seventh"





      r loops for-loop nested







      share|improve this question
















      I have 2 vectors : 



      index <- as.integer(c(3, 5, 7))
      
sen <- c("first", "second", "third", "fourth", "fifth", "sixth", "seventh")


      I want to save each string, according to its index in a new vector :



       mySen <- vector(mode = "character", length = length(index))


      such that 



      > mySen
      
[1] "third"
      
[2] "fifth"
      
[3] "seventh"


      I've tried nested loops but they output indices i and j of length 6



      for (j in index){
      
  for(i in 1:length(index)){
      
    print(c(i,j))
      
  }
      
}
      

      
[1] 1 3
      
[1] 2 3
      
[1] 3 3
      
[1] 1 5
      
[1] 2 5
      
[1] 3 5
      
[1] 1 7
      
[1] 2 7
      
[1] 3 7


      whereas I want indices



      1 3
      
2 5
      
3 7


      Most importantly, I want my new vector mySen to be properly filled in as mentioned before



      > mySen
      
[1] "third"
      
[2] "fifth"
      
[3] "seventh"





      r loops for-loop nested




      r loops for-loop nested






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 27 '18 at 6:36









      Ronak Shah

      38.6k104161




      38.6k104161










      asked Nov 27 '18 at 6:29









      YeshyyyYeshyyy

      11910




      11910
























          1 Answer
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          1














          You can subset sen with index



          mySen <- sen[index]
          
mySen
          
#[1] "third"   "fifth"   "seventh"





          share|improve this answer
























          • woah i feel stupid. thanks :)

            – Yeshyyy
            Nov 27 '18 at 6:32











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          1 Answer
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          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          You can subset sen with index



          mySen <- sen[index]
          
mySen
          
#[1] "third"   "fifth"   "seventh"





          share|improve this answer
























          • woah i feel stupid. thanks :)

            – Yeshyyy
            Nov 27 '18 at 6:32
















          1














          You can subset sen with index



          mySen <- sen[index]
          
mySen
          
#[1] "third"   "fifth"   "seventh"





          share|improve this answer
























          • woah i feel stupid. thanks :)

            – Yeshyyy
            Nov 27 '18 at 6:32














          1












          1








          1







          You can subset sen with index



          mySen <- sen[index]
          
mySen
          
#[1] "third"   "fifth"   "seventh"





          share|improve this answer













          You can subset sen with index



          mySen <- sen[index]
          
mySen
          
#[1] "third"   "fifth"   "seventh"






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 27 '18 at 6:31









          Ronak ShahRonak Shah

          38.6k104161




          38.6k104161













          • woah i feel stupid. thanks :)

            – Yeshyyy
            Nov 27 '18 at 6:32



















          • woah i feel stupid. thanks :)

            – Yeshyyy
            Nov 27 '18 at 6:32

















          woah i feel stupid. thanks :)

          – Yeshyyy
          Nov 27 '18 at 6:32





          woah i feel stupid. thanks :)

          – Yeshyyy
          Nov 27 '18 at 6:32




















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