how i can plot the multiple condition present in one data using one plot script?
I am using R studio to plot boxplot.
My data looks like --
level Q9HC84 P02768
2 232742108.4 32822363539
2 2886647577 25661800126
1 629319882.2 26745385141
1 1293306218 2173862517
0 632315638.5 994599604.8
0 221394201.3 1659282642
Here is the command I am using to plot a graph:
boxplot(Q9HC84 ~ level , data = x , xlab = "Cases", ylab = "Protein",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("C","T","O"))
This shows me a perfect result that is what I want.
But I have 90 proteins name in the data and I want to change this script in a manner that it will generate boxplot for each protein separately.
Same thing i did with lineplot that was easy, but in boxplot it's hard to find how to apply loop. I tried this script ----
for(i in 3:5)
{
x = data.frame(proteomics$level)
y = data.frame(proteomics[i])
boxplot(y ~ x , xlab = "Cases", ylab = "Metabolite",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("Control","Tobacco","OSCC"))
}
can anybody help me ?
Thank you in advance
r loops boxplot
add a comment |
I am using R studio to plot boxplot.
My data looks like --
level Q9HC84 P02768
2 232742108.4 32822363539
2 2886647577 25661800126
1 629319882.2 26745385141
1 1293306218 2173862517
0 632315638.5 994599604.8
0 221394201.3 1659282642
Here is the command I am using to plot a graph:
boxplot(Q9HC84 ~ level , data = x , xlab = "Cases", ylab = "Protein",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("C","T","O"))
This shows me a perfect result that is what I want.
But I have 90 proteins name in the data and I want to change this script in a manner that it will generate boxplot for each protein separately.
Same thing i did with lineplot that was easy, but in boxplot it's hard to find how to apply loop. I tried this script ----
for(i in 3:5)
{
x = data.frame(proteomics$level)
y = data.frame(proteomics[i])
boxplot(y ~ x , xlab = "Cases", ylab = "Metabolite",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("Control","Tobacco","OSCC"))
}
can anybody help me ?
Thank you in advance
r loops boxplot
I find it hard to see the proteins in your data. Can you point them out?
– Chris Ruehlemann
Nov 27 '18 at 6:58
Q9HC84 and P02768 are the proteins id . header name of column.
– sdabral
Nov 27 '18 at 10:26
add a comment |
I am using R studio to plot boxplot.
My data looks like --
level Q9HC84 P02768
2 232742108.4 32822363539
2 2886647577 25661800126
1 629319882.2 26745385141
1 1293306218 2173862517
0 632315638.5 994599604.8
0 221394201.3 1659282642
Here is the command I am using to plot a graph:
boxplot(Q9HC84 ~ level , data = x , xlab = "Cases", ylab = "Protein",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("C","T","O"))
This shows me a perfect result that is what I want.
But I have 90 proteins name in the data and I want to change this script in a manner that it will generate boxplot for each protein separately.
Same thing i did with lineplot that was easy, but in boxplot it's hard to find how to apply loop. I tried this script ----
for(i in 3:5)
{
x = data.frame(proteomics$level)
y = data.frame(proteomics[i])
boxplot(y ~ x , xlab = "Cases", ylab = "Metabolite",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("Control","Tobacco","OSCC"))
}
can anybody help me ?
Thank you in advance
r loops boxplot
I am using R studio to plot boxplot.
My data looks like --
level Q9HC84 P02768
2 232742108.4 32822363539
2 2886647577 25661800126
1 629319882.2 26745385141
1 1293306218 2173862517
0 632315638.5 994599604.8
0 221394201.3 1659282642
Here is the command I am using to plot a graph:
boxplot(Q9HC84 ~ level , data = x , xlab = "Cases", ylab = "Protein",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("C","T","O"))
This shows me a perfect result that is what I want.
But I have 90 proteins name in the data and I want to change this script in a manner that it will generate boxplot for each protein separately.
Same thing i did with lineplot that was easy, but in boxplot it's hard to find how to apply loop. I tried this script ----
for(i in 3:5)
{
x = data.frame(proteomics$level)
y = data.frame(proteomics[i])
boxplot(y ~ x , xlab = "Cases", ylab = "Metabolite",
main = "Q9HC84" , notch = FALSE,
varwidth = TRUE, names = c("Control","Tobacco","OSCC"))
}
can anybody help me ?
Thank you in advance
r loops boxplot
r loops boxplot
edited Nov 27 '18 at 6:50
Jon Spring
6,5781726
6,5781726
asked Nov 27 '18 at 6:22
sdabralsdabral
31
31
I find it hard to see the proteins in your data. Can you point them out?
– Chris Ruehlemann
Nov 27 '18 at 6:58
Q9HC84 and P02768 are the proteins id . header name of column.
– sdabral
Nov 27 '18 at 10:26
add a comment |
I find it hard to see the proteins in your data. Can you point them out?
– Chris Ruehlemann
Nov 27 '18 at 6:58
Q9HC84 and P02768 are the proteins id . header name of column.
– sdabral
Nov 27 '18 at 10:26
I find it hard to see the proteins in your data. Can you point them out?
– Chris Ruehlemann
Nov 27 '18 at 6:58
I find it hard to see the proteins in your data. Can you point them out?
– Chris Ruehlemann
Nov 27 '18 at 6:58
Q9HC84 and P02768 are the proteins id . header name of column.
– sdabral
Nov 27 '18 at 10:26
Q9HC84 and P02768 are the proteins id . header name of column.
– sdabral
Nov 27 '18 at 10:26
add a comment |
2 Answers
2
active
oldest
votes
It's difficult to create boxplots with this many groups while still having the plot being readable.
# generate example data
set.seed(1)
np <- 20
level <- rep(1:3, times=c(4, 5, 5))
pnames <- replicate(
np, paste(c(sample(LETTERS, 1), sample(c(0:9, LETTERS), 5)), collapse="")
)
prot <- round(runif(np*length(level), 2213942000, 328223635400), 1)
x <- as.data.frame(cbind(level, matrix(prot, ncol=np)))
colnames(x)[-1] <- pnames
# reshape to long format
library(reshape2)
x.long <- melt(x, id.vars="level")
x.long$level <- c("C","T","O")[x.long$level]
# plot vertically, level + variable
par(xaxs="i", yaxs="i", mar=c(3.5, 3, 0.5, 0.5))
col <- c("orange", "cornflowerblue", "purple")
boxplot(value ~ level + variable, data=x.long, cex=0.5, cex.axis=0.5, las=2,
col=col, border=col, boxwex=0.5)
# plot horizontally, variable + level
par(xaxs="i", yaxs="i", mar=c(2, 3.5, 0.5, 0.5))
col <- rep(c("orange", "cornflowerblue", "purple"),
each=length(unique(x.long$variable)))
boxplot(value ~ variable + level, data=x.long, cex=0.5, cex.axis=0.5, las=1,
horizontal=TRUE, col=col, border=col, boxwex=0.5)
Thank you so much . its really working properly for my data sets.
– sdabral
Jan 24 at 12:28
add a comment |
Here are 2 solutions:
Assuming your data (slightly simplified) look like this (with three proteins, but that number can obviously be extended):
df <- data.frame(
level = c(2,2,1,1,0,0),
prot1 = c(rnorm(6)+1),
prot2 = c(rnorm(6)),
prot3 = c(rnorm(6)-1)
)
you can re-structure the data in such a way that the protein names form one column and the values they have form another column:
df_new <- data.frame(
level = rep(c(2,2,1,1,0,0),3),
protein_names = c(rep("prot1",6),rep("prot2",6),rep("prot3",6)),
protein_values = c(df$prot1, df$prot2, df$prot3)
)
df_new
The first solution is an R base solution:
This line of code plots all boxplots within a single frame:
boxplot(df_new$protein_values ~ df_new$level+df_new$protein_names)
This for
loop plots a separate frame for each protein:
par(mfrow=c(1,3))
for(i in unique(df_new$protein_names)){
boxplot(df_new[df_new$protein_names==i,]$protein_values ~ df_new[df_new$protein_names==i,]$level)
}
The second solution is a ggplot2
solution:
library(ggplot2)
ggplot(df_new, aes(as.factor(level), protein_values)) +
geom_boxplot() +
facet_grid(.~protein_names)
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53493873%2fhow-i-can-plot-the-multiple-condition-present-in-one-data-using-one-plot-script%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
It's difficult to create boxplots with this many groups while still having the plot being readable.
# generate example data
set.seed(1)
np <- 20
level <- rep(1:3, times=c(4, 5, 5))
pnames <- replicate(
np, paste(c(sample(LETTERS, 1), sample(c(0:9, LETTERS), 5)), collapse="")
)
prot <- round(runif(np*length(level), 2213942000, 328223635400), 1)
x <- as.data.frame(cbind(level, matrix(prot, ncol=np)))
colnames(x)[-1] <- pnames
# reshape to long format
library(reshape2)
x.long <- melt(x, id.vars="level")
x.long$level <- c("C","T","O")[x.long$level]
# plot vertically, level + variable
par(xaxs="i", yaxs="i", mar=c(3.5, 3, 0.5, 0.5))
col <- c("orange", "cornflowerblue", "purple")
boxplot(value ~ level + variable, data=x.long, cex=0.5, cex.axis=0.5, las=2,
col=col, border=col, boxwex=0.5)
# plot horizontally, variable + level
par(xaxs="i", yaxs="i", mar=c(2, 3.5, 0.5, 0.5))
col <- rep(c("orange", "cornflowerblue", "purple"),
each=length(unique(x.long$variable)))
boxplot(value ~ variable + level, data=x.long, cex=0.5, cex.axis=0.5, las=1,
horizontal=TRUE, col=col, border=col, boxwex=0.5)
Thank you so much . its really working properly for my data sets.
– sdabral
Jan 24 at 12:28
add a comment |
It's difficult to create boxplots with this many groups while still having the plot being readable.
# generate example data
set.seed(1)
np <- 20
level <- rep(1:3, times=c(4, 5, 5))
pnames <- replicate(
np, paste(c(sample(LETTERS, 1), sample(c(0:9, LETTERS), 5)), collapse="")
)
prot <- round(runif(np*length(level), 2213942000, 328223635400), 1)
x <- as.data.frame(cbind(level, matrix(prot, ncol=np)))
colnames(x)[-1] <- pnames
# reshape to long format
library(reshape2)
x.long <- melt(x, id.vars="level")
x.long$level <- c("C","T","O")[x.long$level]
# plot vertically, level + variable
par(xaxs="i", yaxs="i", mar=c(3.5, 3, 0.5, 0.5))
col <- c("orange", "cornflowerblue", "purple")
boxplot(value ~ level + variable, data=x.long, cex=0.5, cex.axis=0.5, las=2,
col=col, border=col, boxwex=0.5)
# plot horizontally, variable + level
par(xaxs="i", yaxs="i", mar=c(2, 3.5, 0.5, 0.5))
col <- rep(c("orange", "cornflowerblue", "purple"),
each=length(unique(x.long$variable)))
boxplot(value ~ variable + level, data=x.long, cex=0.5, cex.axis=0.5, las=1,
horizontal=TRUE, col=col, border=col, boxwex=0.5)
Thank you so much . its really working properly for my data sets.
– sdabral
Jan 24 at 12:28
add a comment |
It's difficult to create boxplots with this many groups while still having the plot being readable.
# generate example data
set.seed(1)
np <- 20
level <- rep(1:3, times=c(4, 5, 5))
pnames <- replicate(
np, paste(c(sample(LETTERS, 1), sample(c(0:9, LETTERS), 5)), collapse="")
)
prot <- round(runif(np*length(level), 2213942000, 328223635400), 1)
x <- as.data.frame(cbind(level, matrix(prot, ncol=np)))
colnames(x)[-1] <- pnames
# reshape to long format
library(reshape2)
x.long <- melt(x, id.vars="level")
x.long$level <- c("C","T","O")[x.long$level]
# plot vertically, level + variable
par(xaxs="i", yaxs="i", mar=c(3.5, 3, 0.5, 0.5))
col <- c("orange", "cornflowerblue", "purple")
boxplot(value ~ level + variable, data=x.long, cex=0.5, cex.axis=0.5, las=2,
col=col, border=col, boxwex=0.5)
# plot horizontally, variable + level
par(xaxs="i", yaxs="i", mar=c(2, 3.5, 0.5, 0.5))
col <- rep(c("orange", "cornflowerblue", "purple"),
each=length(unique(x.long$variable)))
boxplot(value ~ variable + level, data=x.long, cex=0.5, cex.axis=0.5, las=1,
horizontal=TRUE, col=col, border=col, boxwex=0.5)
It's difficult to create boxplots with this many groups while still having the plot being readable.
# generate example data
set.seed(1)
np <- 20
level <- rep(1:3, times=c(4, 5, 5))
pnames <- replicate(
np, paste(c(sample(LETTERS, 1), sample(c(0:9, LETTERS), 5)), collapse="")
)
prot <- round(runif(np*length(level), 2213942000, 328223635400), 1)
x <- as.data.frame(cbind(level, matrix(prot, ncol=np)))
colnames(x)[-1] <- pnames
# reshape to long format
library(reshape2)
x.long <- melt(x, id.vars="level")
x.long$level <- c("C","T","O")[x.long$level]
# plot vertically, level + variable
par(xaxs="i", yaxs="i", mar=c(3.5, 3, 0.5, 0.5))
col <- c("orange", "cornflowerblue", "purple")
boxplot(value ~ level + variable, data=x.long, cex=0.5, cex.axis=0.5, las=2,
col=col, border=col, boxwex=0.5)
# plot horizontally, variable + level
par(xaxs="i", yaxs="i", mar=c(2, 3.5, 0.5, 0.5))
col <- rep(c("orange", "cornflowerblue", "purple"),
each=length(unique(x.long$variable)))
boxplot(value ~ variable + level, data=x.long, cex=0.5, cex.axis=0.5, las=1,
horizontal=TRUE, col=col, border=col, boxwex=0.5)
edited Nov 27 '18 at 15:42
answered Nov 27 '18 at 15:08
AkselAAkselA
4,56421325
4,56421325
Thank you so much . its really working properly for my data sets.
– sdabral
Jan 24 at 12:28
add a comment |
Thank you so much . its really working properly for my data sets.
– sdabral
Jan 24 at 12:28
Thank you so much . its really working properly for my data sets.
– sdabral
Jan 24 at 12:28
Thank you so much . its really working properly for my data sets.
– sdabral
Jan 24 at 12:28
add a comment |
Here are 2 solutions:
Assuming your data (slightly simplified) look like this (with three proteins, but that number can obviously be extended):
df <- data.frame(
level = c(2,2,1,1,0,0),
prot1 = c(rnorm(6)+1),
prot2 = c(rnorm(6)),
prot3 = c(rnorm(6)-1)
)
you can re-structure the data in such a way that the protein names form one column and the values they have form another column:
df_new <- data.frame(
level = rep(c(2,2,1,1,0,0),3),
protein_names = c(rep("prot1",6),rep("prot2",6),rep("prot3",6)),
protein_values = c(df$prot1, df$prot2, df$prot3)
)
df_new
The first solution is an R base solution:
This line of code plots all boxplots within a single frame:
boxplot(df_new$protein_values ~ df_new$level+df_new$protein_names)
This for
loop plots a separate frame for each protein:
par(mfrow=c(1,3))
for(i in unique(df_new$protein_names)){
boxplot(df_new[df_new$protein_names==i,]$protein_values ~ df_new[df_new$protein_names==i,]$level)
}
The second solution is a ggplot2
solution:
library(ggplot2)
ggplot(df_new, aes(as.factor(level), protein_values)) +
geom_boxplot() +
facet_grid(.~protein_names)
add a comment |
Here are 2 solutions:
Assuming your data (slightly simplified) look like this (with three proteins, but that number can obviously be extended):
df <- data.frame(
level = c(2,2,1,1,0,0),
prot1 = c(rnorm(6)+1),
prot2 = c(rnorm(6)),
prot3 = c(rnorm(6)-1)
)
you can re-structure the data in such a way that the protein names form one column and the values they have form another column:
df_new <- data.frame(
level = rep(c(2,2,1,1,0,0),3),
protein_names = c(rep("prot1",6),rep("prot2",6),rep("prot3",6)),
protein_values = c(df$prot1, df$prot2, df$prot3)
)
df_new
The first solution is an R base solution:
This line of code plots all boxplots within a single frame:
boxplot(df_new$protein_values ~ df_new$level+df_new$protein_names)
This for
loop plots a separate frame for each protein:
par(mfrow=c(1,3))
for(i in unique(df_new$protein_names)){
boxplot(df_new[df_new$protein_names==i,]$protein_values ~ df_new[df_new$protein_names==i,]$level)
}
The second solution is a ggplot2
solution:
library(ggplot2)
ggplot(df_new, aes(as.factor(level), protein_values)) +
geom_boxplot() +
facet_grid(.~protein_names)
add a comment |
Here are 2 solutions:
Assuming your data (slightly simplified) look like this (with three proteins, but that number can obviously be extended):
df <- data.frame(
level = c(2,2,1,1,0,0),
prot1 = c(rnorm(6)+1),
prot2 = c(rnorm(6)),
prot3 = c(rnorm(6)-1)
)
you can re-structure the data in such a way that the protein names form one column and the values they have form another column:
df_new <- data.frame(
level = rep(c(2,2,1,1,0,0),3),
protein_names = c(rep("prot1",6),rep("prot2",6),rep("prot3",6)),
protein_values = c(df$prot1, df$prot2, df$prot3)
)
df_new
The first solution is an R base solution:
This line of code plots all boxplots within a single frame:
boxplot(df_new$protein_values ~ df_new$level+df_new$protein_names)
This for
loop plots a separate frame for each protein:
par(mfrow=c(1,3))
for(i in unique(df_new$protein_names)){
boxplot(df_new[df_new$protein_names==i,]$protein_values ~ df_new[df_new$protein_names==i,]$level)
}
The second solution is a ggplot2
solution:
library(ggplot2)
ggplot(df_new, aes(as.factor(level), protein_values)) +
geom_boxplot() +
facet_grid(.~protein_names)
Here are 2 solutions:
Assuming your data (slightly simplified) look like this (with three proteins, but that number can obviously be extended):
df <- data.frame(
level = c(2,2,1,1,0,0),
prot1 = c(rnorm(6)+1),
prot2 = c(rnorm(6)),
prot3 = c(rnorm(6)-1)
)
you can re-structure the data in such a way that the protein names form one column and the values they have form another column:
df_new <- data.frame(
level = rep(c(2,2,1,1,0,0),3),
protein_names = c(rep("prot1",6),rep("prot2",6),rep("prot3",6)),
protein_values = c(df$prot1, df$prot2, df$prot3)
)
df_new
The first solution is an R base solution:
This line of code plots all boxplots within a single frame:
boxplot(df_new$protein_values ~ df_new$level+df_new$protein_names)
This for
loop plots a separate frame for each protein:
par(mfrow=c(1,3))
for(i in unique(df_new$protein_names)){
boxplot(df_new[df_new$protein_names==i,]$protein_values ~ df_new[df_new$protein_names==i,]$level)
}
The second solution is a ggplot2
solution:
library(ggplot2)
ggplot(df_new, aes(as.factor(level), protein_values)) +
geom_boxplot() +
facet_grid(.~protein_names)
answered Nov 27 '18 at 14:44
Chris RuehlemannChris Ruehlemann
46229
46229
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53493873%2fhow-i-can-plot-the-multiple-condition-present-in-one-data-using-one-plot-script%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
I find it hard to see the proteins in your data. Can you point them out?
– Chris Ruehlemann
Nov 27 '18 at 6:58
Q9HC84 and P02768 are the proteins id . header name of column.
– sdabral
Nov 27 '18 at 10:26