Initializing an EMGU (NOT OpenCV C++) Mat (C#) with 2D array
I know this "looks" like a duplicate question, but -- it's not answered in any definitive way that I can see.
In C++, OpenCv operation to init a Mat can be done like so:
float[,] camera = new float[,] {
{ 857.483f, 0.0f, 968.06f },
{ 0.0f, 876.72f, 556.37f },
{ 0.0f, 0.0f, 1.0f }
};
A = Mat(3,3, CV_32FC1, &camera);
Note that the array is 2D.
Now, I want to accomplish the same thing in EMGU, //using managed C#; so Mat is constructed as:
Mat _cameraMatrix = new Mat(3, 3, DepthType.Cv64F, 1);
// and a similar 1D Mat:
Mat _distCoeffs = new Mat(8, 1, DepthType.Cv64F, 1);
// to be passed to the method:
CvInvoke.Undistort(bkgimage, ndimage, _cameraMatrix, _distCoeffs);
Unlike cv::Mat, EMGU Mat's constructor doesn't seem to have an obvious way to get that 2D "camera" data into it. Anyone have any success getting this kind of code to work?
emgucv
asked Nov 26 '18 at 20:15
JimJim
112
add a comment |
I know this "looks" like a duplicate question, but -- it's not answered in any definitive way that I can see.
In C++, OpenCv operation to init a Mat can be done like so:
float[,] camera = new float[,] {
{ 857.483f, 0.0f, 968.06f },
{ 0.0f, 876.72f, 556.37f },
{ 0.0f, 0.0f, 1.0f }
};
A = Mat(3,3, CV_32FC1, &camera);
Note that the array is 2D.
Now, I want to accomplish the same thing in EMGU, //using managed C#; so Mat is constructed as:
Mat _cameraMatrix = new Mat(3, 3, DepthType.Cv64F, 1);
// and a similar 1D Mat:
Mat _distCoeffs = new Mat(8, 1, DepthType.Cv64F, 1);
// to be passed to the method:
CvInvoke.Undistort(bkgimage, ndimage, _cameraMatrix, _distCoeffs);
Unlike cv::Mat, EMGU Mat's constructor doesn't seem to have an obvious way to get that 2D "camera" data into it. Anyone have any success getting this kind of code to work?
emgucv
asked Nov 26 '18 at 20:15
JimJim
112
add a comment |
I know this "looks" like a duplicate question, but -- it's not answered in any definitive way that I can see.
In C++, OpenCv operation to init a Mat can be done like so:
float[,] camera = new float[,] {
{ 857.483f, 0.0f, 968.06f },
{ 0.0f, 876.72f, 556.37f },
{ 0.0f, 0.0f, 1.0f }
};
A = Mat(3,3, CV_32FC1, &camera);
Note that the array is 2D.
Now, I want to accomplish the same thing in EMGU, //using managed C#; so Mat is constructed as:
Mat _cameraMatrix = new Mat(3, 3, DepthType.Cv64F, 1);
// and a similar 1D Mat:
Mat _distCoeffs = new Mat(8, 1, DepthType.Cv64F, 1);
// to be passed to the method:
CvInvoke.Undistort(bkgimage, ndimage, _cameraMatrix, _distCoeffs);
Unlike cv::Mat, EMGU Mat's constructor doesn't seem to have an obvious way to get that 2D "camera" data into it. Anyone have any success getting this kind of code to work?
emgucv
asked Nov 26 '18 at 20:15
JimJim
112
I know this "looks" like a duplicate question, but -- it's not answered in any definitive way that I can see.
In C++, OpenCv operation to init a Mat can be done like so:
float[,] camera = new float[,] {
{ 857.483f, 0.0f, 968.06f },
{ 0.0f, 876.72f, 556.37f },
{ 0.0f, 0.0f, 1.0f }
};
A = Mat(3,3, CV_32FC1, &camera);
Note that the array is 2D.
Now, I want to accomplish the same thing in EMGU, //using managed C#; so Mat is constructed as:
Mat _cameraMatrix = new Mat(3, 3, DepthType.Cv64F, 1);
// and a similar 1D Mat:
Mat _distCoeffs = new Mat(8, 1, DepthType.Cv64F, 1);
// to be passed to the method:
CvInvoke.Undistort(bkgimage, ndimage, _cameraMatrix, _distCoeffs);
Unlike cv::Mat, EMGU Mat's constructor doesn't seem to have an obvious way to get that 2D "camera" data into it. Anyone have any success getting this kind of code to work?
emgucv
emgucv
asked Nov 26 '18 at 20:15
JimJim
112
asked Nov 26 '18 at 20:15
JimJim
112
asked Nov 26 '18 at 20:15
JimJim
112
asked Nov 26 '18 at 20:15
JimJim
112
asked Nov 26 '18 at 20:15
JimJim
112
112
add a comment |
add a comment |
1 Answer
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According to the EmguCV documentation, there is a constructor that takes an IntPr as 'data':
see http://www.emgu.com/wiki/files/3.4.3/document/html/c8424736-2d44-c5d6-212f-31dedfe6fb95.htm
The problem is how to get that pointer. Here, maybe this post will help you:
How to get IntPtr from byte in C#
Hopefully, this will get you at least started.
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
add a comment |
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1 Answer
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1 Answer
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active
oldest
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active
oldest
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active
oldest
votes
According to the EmguCV documentation, there is a constructor that takes an IntPr as 'data':
see http://www.emgu.com/wiki/files/3.4.3/document/html/c8424736-2d44-c5d6-212f-31dedfe6fb95.htm
The problem is how to get that pointer. Here, maybe this post will help you:
How to get IntPtr from byte in C#
Hopefully, this will get you at least started.
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
add a comment |
According to the EmguCV documentation, there is a constructor that takes an IntPr as 'data':
see http://www.emgu.com/wiki/files/3.4.3/document/html/c8424736-2d44-c5d6-212f-31dedfe6fb95.htm
The problem is how to get that pointer. Here, maybe this post will help you:
How to get IntPtr from byte in C#
Hopefully, this will get you at least started.
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
add a comment |
According to the EmguCV documentation, there is a constructor that takes an IntPr as 'data':
see http://www.emgu.com/wiki/files/3.4.3/document/html/c8424736-2d44-c5d6-212f-31dedfe6fb95.htm
The problem is how to get that pointer. Here, maybe this post will help you:
How to get IntPtr from byte in C#
Hopefully, this will get you at least started.
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
According to the EmguCV documentation, there is a constructor that takes an IntPr as 'data':
see http://www.emgu.com/wiki/files/3.4.3/document/html/c8424736-2d44-c5d6-212f-31dedfe6fb95.htm
The problem is how to get that pointer. Here, maybe this post will help you:
How to get IntPtr from byte in C#
Hopefully, this will get you at least started.
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
answered Dec 14 '18 at 8:59
Roland DeschainRoland Deschain
16611
16611
add a comment |
add a comment |
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