How to parse external json request and put it into a variable?












1















I'm very new to coding, I'm hoping someone can help me. I have this little bit of code, I am trying to learn this process:




  1. Call Made to URL via GET request (json)

  2. Parse the response from the GET request

  3. Save the response into a variable that I will use later


Any and all help is appreciated!






const XMLHttpRequest = require("xmlhttprequest").XMLHttpRequest;

const awsURL = 'https://cors.io/?http://status.aws.amazon.com/data.json';



function Get(awsURL){

    var request = new XMLHttpRequest();

    request.open("GET", awsURL, false);

    request.send(null);

    return request.responseText;

}



var AWSJson = JSON.parse(Get(awsURL));

console.log("Archived Outages: "+AWSJson.service_name);








javascript amazon-web-services







share|improve this question























  • Possible duplicate of How do I return the response from an asynchronous call?

    – Patrick Hund
    Nov 26 '18 at 20:20











  • So what error[s] are you getting with the above code when you run it?

    – epascarello
    Nov 26 '18 at 20:44


















1















I'm very new to coding, I'm hoping someone can help me. I have this little bit of code, I am trying to learn this process:




  1. Call Made to URL via GET request (json)

  2. Parse the response from the GET request

  3. Save the response into a variable that I will use later


Any and all help is appreciated!






const XMLHttpRequest = require("xmlhttprequest").XMLHttpRequest;

const awsURL = 'https://cors.io/?http://status.aws.amazon.com/data.json';



function Get(awsURL){

    var request = new XMLHttpRequest();

    request.open("GET", awsURL, false);

    request.send(null);

    return request.responseText;

}



var AWSJson = JSON.parse(Get(awsURL));

console.log("Archived Outages: "+AWSJson.service_name);








javascript amazon-web-services







share|improve this question























  • Possible duplicate of How do I return the response from an asynchronous call?

    – Patrick Hund
    Nov 26 '18 at 20:20











  • So what error[s] are you getting with the above code when you run it?

    – epascarello
    Nov 26 '18 at 20:44
















1












1








1








I'm very new to coding, I'm hoping someone can help me. I have this little bit of code, I am trying to learn this process:




  1. Call Made to URL via GET request (json)

  2. Parse the response from the GET request

  3. Save the response into a variable that I will use later


Any and all help is appreciated!






const XMLHttpRequest = require("xmlhttprequest").XMLHttpRequest;

const awsURL = 'https://cors.io/?http://status.aws.amazon.com/data.json';



function Get(awsURL){

    var request = new XMLHttpRequest();

    request.open("GET", awsURL, false);

    request.send(null);

    return request.responseText;

}



var AWSJson = JSON.parse(Get(awsURL));

console.log("Archived Outages: "+AWSJson.service_name);








javascript amazon-web-services







share|improve this question














I'm very new to coding, I'm hoping someone can help me. I have this little bit of code, I am trying to learn this process:




  1. Call Made to URL via GET request (json)

  2. Parse the response from the GET request

  3. Save the response into a variable that I will use later


Any and all help is appreciated!






const XMLHttpRequest = require("xmlhttprequest").XMLHttpRequest;

const awsURL = 'https://cors.io/?http://status.aws.amazon.com/data.json';



function Get(awsURL){

    var request = new XMLHttpRequest();

    request.open("GET", awsURL, false);

    request.send(null);

    return request.responseText;

}



var AWSJson = JSON.parse(Get(awsURL));

console.log("Archived Outages: "+AWSJson.service_name);








const XMLHttpRequest = require("xmlhttprequest").XMLHttpRequest;

const awsURL = 'https://cors.io/?http://status.aws.amazon.com/data.json';



function Get(awsURL){

    var request = new XMLHttpRequest();

    request.open("GET", awsURL, false);

    request.send(null);

    return request.responseText;

}



var AWSJson = JSON.parse(Get(awsURL));

console.log("Archived Outages: "+AWSJson.service_name);





const XMLHttpRequest = require("xmlhttprequest").XMLHttpRequest;

const awsURL = 'https://cors.io/?http://status.aws.amazon.com/data.json';



function Get(awsURL){

    var request = new XMLHttpRequest();

    request.open("GET", awsURL, false);

    request.send(null);

    return request.responseText;

}



var AWSJson = JSON.parse(Get(awsURL));

console.log("Archived Outages: "+AWSJson.service_name);





javascript amazon-web-services




javascript amazon-web-services






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 26 '18 at 20:16









Chamaco AranoChamaco Arano

62




62













  • Possible duplicate of How do I return the response from an asynchronous call?

    – Patrick Hund
    Nov 26 '18 at 20:20











  • So what error[s] are you getting with the above code when you run it?

    – epascarello
    Nov 26 '18 at 20:44





















  • Possible duplicate of How do I return the response from an asynchronous call?

    – Patrick Hund
    Nov 26 '18 at 20:20











  • So what error[s] are you getting with the above code when you run it?

    – epascarello
    Nov 26 '18 at 20:44



















Possible duplicate of How do I return the response from an asynchronous call?

– Patrick Hund
Nov 26 '18 at 20:20





Possible duplicate of How do I return the response from an asynchronous call?

– Patrick Hund
Nov 26 '18 at 20:20













So what error[s] are you getting with the above code when you run it?

– epascarello
Nov 26 '18 at 20:44







So what error[s] are you getting with the above code when you run it?

– epascarello
Nov 26 '18 at 20:44














1 Answer
1






active

oldest

votes


















1














Return value in given address is not in correct json format. Enter the url in your browser and check the output !






share|improve this answer
























  • Also "awsURL" include more than one address.

    – Ramin
    Nov 26 '18 at 20:46











  • URL is using cors to read json file, that's why you see both URLS

    – Chamaco Arano
    Nov 26 '18 at 21:05











  • Anyway, it changes the result

    – Ramin
    Nov 26 '18 at 21:15











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1 Answer
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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Return value in given address is not in correct json format. Enter the url in your browser and check the output !






share|improve this answer
























  • Also "awsURL" include more than one address.

    – Ramin
    Nov 26 '18 at 20:46











  • URL is using cors to read json file, that's why you see both URLS

    – Chamaco Arano
    Nov 26 '18 at 21:05











  • Anyway, it changes the result

    – Ramin
    Nov 26 '18 at 21:15
















1














Return value in given address is not in correct json format. Enter the url in your browser and check the output !






share|improve this answer
























  • Also "awsURL" include more than one address.

    – Ramin
    Nov 26 '18 at 20:46











  • URL is using cors to read json file, that's why you see both URLS

    – Chamaco Arano
    Nov 26 '18 at 21:05











  • Anyway, it changes the result

    – Ramin
    Nov 26 '18 at 21:15














1












1








1







Return value in given address is not in correct json format. Enter the url in your browser and check the output !






share|improve this answer













Return value in given address is not in correct json format. Enter the url in your browser and check the output !







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 26 '18 at 20:43









RaminRamin

1245




1245













  • Also "awsURL" include more than one address.

    – Ramin
    Nov 26 '18 at 20:46











  • URL is using cors to read json file, that's why you see both URLS

    – Chamaco Arano
    Nov 26 '18 at 21:05











  • Anyway, it changes the result

    – Ramin
    Nov 26 '18 at 21:15



















  • Also "awsURL" include more than one address.

    – Ramin
    Nov 26 '18 at 20:46











  • URL is using cors to read json file, that's why you see both URLS

    – Chamaco Arano
    Nov 26 '18 at 21:05











  • Anyway, it changes the result

    – Ramin
    Nov 26 '18 at 21:15

















Also "awsURL" include more than one address.

– Ramin
Nov 26 '18 at 20:46





Also "awsURL" include more than one address.

– Ramin
Nov 26 '18 at 20:46













URL is using cors to read json file, that's why you see both URLS

– Chamaco Arano
Nov 26 '18 at 21:05





URL is using cors to read json file, that's why you see both URLS

– Chamaco Arano
Nov 26 '18 at 21:05













Anyway, it changes the result

– Ramin
Nov 26 '18 at 21:15





Anyway, it changes the result

– Ramin
Nov 26 '18 at 21:15




















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