Start with closed nodes in indented tree
I used this indentend tree : https://bl.ocks.org/mbostock/1093025
And i want to start like this :
And not like this :
The transition to change the node is this :
// Transition exiting nodes to the parent's new position.
node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.style("opacity", 0)
.remove();
How can i do it ? Thank you again for the help :)
javascript d3.js
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
add a comment |
I used this indentend tree : https://bl.ocks.org/mbostock/1093025
And i want to start like this :
And not like this :
The transition to change the node is this :
// Transition exiting nodes to the parent's new position.
node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.style("opacity", 0)
.remove();
How can i do it ? Thank you again for the help :)
javascript d3.js
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
add a comment |
I used this indentend tree : https://bl.ocks.org/mbostock/1093025
And i want to start like this :
And not like this :
The transition to change the node is this :
// Transition exiting nodes to the parent's new position.
node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.style("opacity", 0)
.remove();
How can i do it ? Thank you again for the help :)
javascript d3.js
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
I used this indentend tree : https://bl.ocks.org/mbostock/1093025
And i want to start like this :
And not like this :
The transition to change the node is this :
// Transition exiting nodes to the parent's new position.
node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.style("opacity", 0)
.remove();
How can i do it ? Thank you again for the help :)
javascript d3.js
javascript d3.js
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
edited Nov 23 '18 at 17:13
chazsolo
5,1171233
5,1171233
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
asked Nov 23 '18 at 16:38
Zahreddine Laidi
13612
13612
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Adding this at the end of the initial loading (after the call to update(root)) does the trick. It relies on the _children concept utilized here to store children not currently displayed.
root.each(function(d) {
if (d.depth > 0) {
d._children = d.children;
d.children = null;
}
update(d)
});
answered Nov 23 '18 at 16:50
Shushan
1,1171814
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Adding this at the end of the initial loading (after the call to update(root)) does the trick. It relies on the _children concept utilized here to store children not currently displayed.
root.each(function(d) {
if (d.depth > 0) {
d._children = d.children;
d.children = null;
}
update(d)
});
answered Nov 23 '18 at 16:50
Shushan
1,1171814
add a comment |
Adding this at the end of the initial loading (after the call to update(root)) does the trick. It relies on the _children concept utilized here to store children not currently displayed.
root.each(function(d) {
if (d.depth > 0) {
d._children = d.children;
d.children = null;
}
update(d)
});
answered Nov 23 '18 at 16:50
Shushan
1,1171814
add a comment |
Adding this at the end of the initial loading (after the call to update(root)) does the trick. It relies on the _children concept utilized here to store children not currently displayed.
root.each(function(d) {
if (d.depth > 0) {
d._children = d.children;
d.children = null;
}
update(d)
});
answered Nov 23 '18 at 16:50
Shushan
1,1171814
Adding this at the end of the initial loading (after the call to update(root)) does the trick. It relies on the _children concept utilized here to store children not currently displayed.
root.each(function(d) {
if (d.depth > 0) {
d._children = d.children;
d.children = null;
}
update(d)
});
answered Nov 23 '18 at 16:50
Shushan
1,1171814
answered Nov 23 '18 at 16:50
Shushan
1,1171814
answered Nov 23 '18 at 16:50
Shushan
1,1171814
answered Nov 23 '18 at 16:50
Shushan
1,1171814
1,1171814
add a comment |
add a comment |
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