python 3 adding multiple values under same key in dictionary [duplicate]

This question already has an answer here:

append multiple values for one key in a dictionary [duplicate]

7 answers

i have a problem with my code, tried looking up how to fix it and tried multiple methods but its just not going

Here is what i got:

with open("people-data.txt") as f:



children= {}

for line in f.readlines():

    parent, child = line.split("->")

    children[parent] = child

I tried using: children[parent].append(child) and other things.

My file looks like this:

Mary->Patricia

Mary->Lisa

Patricia->Barbara

What I would like is when I use children[Mary] I get ['Patricia', 'Lisa'] but what my code does is give my just 'Lisa' and overrides 'Patricia'.

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

asked Nov 25 '18 at 16:21

D. K.

455

marked as duplicate by DeepSpace python
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Nov 25 '18 at 16:25

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

It should be children[parent] = child. In your case you would store the key "parent" and overwrite it.

– Anton vBR
Nov 25 '18 at 16:22

ye sorry, my mistake from copying, let my correct it

– D. K.
Nov 25 '18 at 16:23

You need to use a defaultdict from collections.

– Anton vBR
Nov 25 '18 at 16:24

Of course it overwrites. What else would children[parent] = child do? You need to keep lists in each value of the dict, which can be easily done by using children = defaultdict(list) and children[parent].append(child)

– DeepSpace
Nov 25 '18 at 16:24

add a comment |

This question already has an answer here:

append multiple values for one key in a dictionary [duplicate]

7 answers

i have a problem with my code, tried looking up how to fix it and tried multiple methods but its just not going

Here is what i got:

with open("people-data.txt") as f:



children= {}

for line in f.readlines():

    parent, child = line.split("->")

    children[parent] = child

I tried using: children[parent].append(child) and other things.

My file looks like this:

Mary->Patricia

Mary->Lisa

Patricia->Barbara

What I would like is when I use children[Mary] I get ['Patricia', 'Lisa'] but what my code does is give my just 'Lisa' and overrides 'Patricia'.

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

asked Nov 25 '18 at 16:21

D. K.

455

marked as duplicate by DeepSpace python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.

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Nov 25 '18 at 16:25

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

It should be children[parent] = child. In your case you would store the key "parent" and overwrite it.

– Anton vBR
Nov 25 '18 at 16:22

ye sorry, my mistake from copying, let my correct it

– D. K.
Nov 25 '18 at 16:23

You need to use a defaultdict from collections.

– Anton vBR
Nov 25 '18 at 16:24

Of course it overwrites. What else would children[parent] = child do? You need to keep lists in each value of the dict, which can be easily done by using children = defaultdict(list) and children[parent].append(child)

– DeepSpace
Nov 25 '18 at 16:24

add a comment |

This question already has an answer here:

append multiple values for one key in a dictionary [duplicate]

7 answers

i have a problem with my code, tried looking up how to fix it and tried multiple methods but its just not going

Here is what i got:

with open("people-data.txt") as f:



children= {}

for line in f.readlines():

    parent, child = line.split("->")

    children[parent] = child

I tried using: children[parent].append(child) and other things.

My file looks like this:

Mary->Patricia

Mary->Lisa

Patricia->Barbara

What I would like is when I use children[Mary] I get ['Patricia', 'Lisa'] but what my code does is give my just 'Lisa' and overrides 'Patricia'.

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

asked Nov 25 '18 at 16:21

D. K.

455

This question already has an answer here:

append multiple values for one key in a dictionary [duplicate]

7 answers

i have a problem with my code, tried looking up how to fix it and tried multiple methods but its just not going

Here is what i got:

with open("people-data.txt") as f:



children= {}

for line in f.readlines():

    parent, child = line.split("->")

    children[parent] = child

I tried using: children[parent].append(child) and other things.

My file looks like this:

Mary->Patricia

Mary->Lisa

Patricia->Barbara

What I would like is when I use children[Mary] I get ['Patricia', 'Lisa'] but what my code does is give my just 'Lisa' and overrides 'Patricia'.

This question already has an answer here:

append multiple values for one key in a dictionary [duplicate]

7 answers

python python-3.x dictionary

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

asked Nov 25 '18 at 16:21

D. K.

455

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

asked Nov 25 '18 at 16:21

D. K.

455

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

edited Nov 25 '18 at 16:31

timgeb

50.7k116393

asked Nov 25 '18 at 16:21

D. K.

455

asked Nov 25 '18 at 16:21

D. K.

455

asked Nov 25 '18 at 16:21

D. K.

455

marked as duplicate by DeepSpace python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.

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Nov 25 '18 at 16:25

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by DeepSpace python
Users with the python badge can single-handedly close python questions as duplicates and reopen them as needed.

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Nov 25 '18 at 16:25

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

It should be children[parent] = child. In your case you would store the key "parent" and overwrite it.

– Anton vBR
Nov 25 '18 at 16:22

ye sorry, my mistake from copying, let my correct it

– D. K.
Nov 25 '18 at 16:23

You need to use a defaultdict from collections.

– Anton vBR
Nov 25 '18 at 16:24

Of course it overwrites. What else would children[parent] = child do? You need to keep lists in each value of the dict, which can be easily done by using children = defaultdict(list) and children[parent].append(child)

– DeepSpace
Nov 25 '18 at 16:24

add a comment |

It should be children[parent] = child. In your case you would store the key "parent" and overwrite it.

– Anton vBR
Nov 25 '18 at 16:22

ye sorry, my mistake from copying, let my correct it

– D. K.
Nov 25 '18 at 16:23

You need to use a defaultdict from collections.

– Anton vBR
Nov 25 '18 at 16:24

Of course it overwrites. What else would children[parent] = child do? You need to keep lists in each value of the dict, which can be easily done by using children = defaultdict(list) and children[parent].append(child)

– DeepSpace
Nov 25 '18 at 16:24

It should be children[parent] = child. In your case you would store the key "parent" and overwrite it.

– Anton vBR
Nov 25 '18 at 16:22

ye sorry, my mistake from copying, let my correct it

– D. K.
Nov 25 '18 at 16:23

You need to use a defaultdict from collections.

– Anton vBR
Nov 25 '18 at 16:24

Of course it overwrites. What else would children[parent] = child do? You need to keep lists in each value of the dict, which can be easily done by using children = defaultdict(list) and children[parent].append(child)

– DeepSpace
Nov 25 '18 at 16:24

add a comment |

1 Answer
1

active

oldest

votes

I tried using: children[parent].append(child)

That will work as long as you are using lists for your dictionary-values.

The easiest fix to achieve that would be to make children a defaultdict, i.e.

from collections import defaultdict

children = defaultdict(list)

and then use

children[parent].append(child)

in your code.

Demo:

>>> from collections import defaultdict

>>> children = defaultdict(list)

>>> 

>>> children['Peter'].append('Bob')

>>> children['Peter'].append('Alice')

>>> children['Mary'].append('Joe')

>>> 

>>> children

defaultdict(list, {'Mary': ['Joe'], 'Peter': ['Bob', 'Alice']})

edited Nov 25 '18 at 16:32

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

Yes, and don't forget: children[parent].append(child) for a complete solution.

– Anton vBR
Nov 25 '18 at 16:25

Thank you, it is now creating what i wanted, but the problem is that when i call children("Mary") i get that it is not callable, i need the values to work with later on

– D. K.
Nov 25 '18 at 16:27

1

@DávidKačmar children['Mary'].

– timgeb
Nov 25 '18 at 16:28

1

Thank you!!!! i love you guys!! or girls :D saved my day :D thanks alot

– D. K.
Nov 25 '18 at 16:29

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

I tried using: children[parent].append(child)

That will work as long as you are using lists for your dictionary-values.

The easiest fix to achieve that would be to make children a defaultdict, i.e.

from collections import defaultdict

children = defaultdict(list)

and then use

children[parent].append(child)

in your code.

Demo:

>>> from collections import defaultdict

>>> children = defaultdict(list)

>>> 

>>> children['Peter'].append('Bob')

>>> children['Peter'].append('Alice')

>>> children['Mary'].append('Joe')

>>> 

>>> children

defaultdict(list, {'Mary': ['Joe'], 'Peter': ['Bob', 'Alice']})

edited Nov 25 '18 at 16:32

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

Yes, and don't forget: children[parent].append(child) for a complete solution.

– Anton vBR
Nov 25 '18 at 16:25

Thank you, it is now creating what i wanted, but the problem is that when i call children("Mary") i get that it is not callable, i need the values to work with later on

– D. K.
Nov 25 '18 at 16:27

1

@DávidKačmar children['Mary'].

– timgeb
Nov 25 '18 at 16:28

1

Thank you!!!! i love you guys!! or girls :D saved my day :D thanks alot

– D. K.
Nov 25 '18 at 16:29

add a comment |

I tried using: children[parent].append(child)

That will work as long as you are using lists for your dictionary-values.

The easiest fix to achieve that would be to make children a defaultdict, i.e.

from collections import defaultdict

children = defaultdict(list)

and then use

children[parent].append(child)

in your code.

Demo:

>>> from collections import defaultdict

>>> children = defaultdict(list)

>>> 

>>> children['Peter'].append('Bob')

>>> children['Peter'].append('Alice')

>>> children['Mary'].append('Joe')

>>> 

>>> children

defaultdict(list, {'Mary': ['Joe'], 'Peter': ['Bob', 'Alice']})

edited Nov 25 '18 at 16:32

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

Yes, and don't forget: children[parent].append(child) for a complete solution.

– Anton vBR
Nov 25 '18 at 16:25

Thank you, it is now creating what i wanted, but the problem is that when i call children("Mary") i get that it is not callable, i need the values to work with later on

– D. K.
Nov 25 '18 at 16:27

1

@DávidKačmar children['Mary'].

– timgeb
Nov 25 '18 at 16:28

1

Thank you!!!! i love you guys!! or girls :D saved my day :D thanks alot

– D. K.
Nov 25 '18 at 16:29

add a comment |

I tried using: children[parent].append(child)

That will work as long as you are using lists for your dictionary-values.

The easiest fix to achieve that would be to make children a defaultdict, i.e.

from collections import defaultdict

children = defaultdict(list)

and then use

children[parent].append(child)

in your code.

Demo:

>>> from collections import defaultdict

>>> children = defaultdict(list)

>>> 

>>> children['Peter'].append('Bob')

>>> children['Peter'].append('Alice')

>>> children['Mary'].append('Joe')

>>> 

>>> children

defaultdict(list, {'Mary': ['Joe'], 'Peter': ['Bob', 'Alice']})

edited Nov 25 '18 at 16:32

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

I tried using: children[parent].append(child)

That will work as long as you are using lists for your dictionary-values.

The easiest fix to achieve that would be to make children a defaultdict, i.e.

from collections import defaultdict

children = defaultdict(list)

and then use

children[parent].append(child)

in your code.

Demo:

>>> from collections import defaultdict

>>> children = defaultdict(list)

>>> 

>>> children['Peter'].append('Bob')

>>> children['Peter'].append('Alice')

>>> children['Mary'].append('Joe')

>>> 

>>> children

defaultdict(list, {'Mary': ['Joe'], 'Peter': ['Bob', 'Alice']})

edited Nov 25 '18 at 16:32

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

edited Nov 25 '18 at 16:32

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

answered Nov 25 '18 at 16:23

timgeb

50.7k116393

Yes, and don't forget: children[parent].append(child) for a complete solution.

– Anton vBR
Nov 25 '18 at 16:25

Thank you, it is now creating what i wanted, but the problem is that when i call children("Mary") i get that it is not callable, i need the values to work with later on

– D. K.
Nov 25 '18 at 16:27

1

@DávidKačmar children['Mary'].

– timgeb
Nov 25 '18 at 16:28

1

Thank you!!!! i love you guys!! or girls :D saved my day :D thanks alot

– D. K.
Nov 25 '18 at 16:29

add a comment |

Yes, and don't forget: children[parent].append(child) for a complete solution.

– Anton vBR
Nov 25 '18 at 16:25

Thank you, it is now creating what i wanted, but the problem is that when i call children("Mary") i get that it is not callable, i need the values to work with later on

– D. K.
Nov 25 '18 at 16:27

1

@DávidKačmar children['Mary'].

– timgeb
Nov 25 '18 at 16:28

1

Thank you!!!! i love you guys!! or girls :D saved my day :D thanks alot

– D. K.
Nov 25 '18 at 16:29

Yes, and don't forget: children[parent].append(child) for a complete solution.

– Anton vBR
Nov 25 '18 at 16:25

Thank you, it is now creating what i wanted, but the problem is that when i call children("Mary") i get that it is not callable, i need the values to work with later on

– D. K.
Nov 25 '18 at 16:27

@DávidKačmar children['Mary'].

– timgeb
Nov 25 '18 at 16:28

Thank you!!!! i love you guys!! or girls :D saved my day :D thanks alot

– D. K.
Nov 25 '18 at 16:29

add a comment |

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