Javascript get element by id from a table cell not working












0















I have a HTML table. In this table I have links in last column (with id="delete_row"). I am trying to extract each link and it is not working. I have seen some posts about it and learned it might be a spelling issue but I checked everything twice and still cannot get it going. Here is my code:



var tbl = document.getElementById('my_table'); 
for (var i = 0 ;i<tbl.rows.length-1; i++) { // for each row
row = tbl.rows[i];
row.getElementById('delete_row').className="other_classname";
}


This code however returns error:




Uncaught TypeError: Object #<HTMLTableRowElement> has no method 'getElementById'




Any Idea what might be wrong?










share|improve this question

























  • row.getElementById('delete_row').className="other_classname"; doesn't seem to make any sense - what are you trying to achieve here? Is 'delete_row' a table cell <td>?

    – Barry Kaye
    Jan 15 '13 at 11:12













  • Hi 'delete_row' is an id of a href inside last cell of every row (so last column of a tabale is filled in with hrefs of the same id). I will correct my question in a sec.

    – HoGo
    Jan 15 '13 at 11:28
















0















I have a HTML table. In this table I have links in last column (with id="delete_row"). I am trying to extract each link and it is not working. I have seen some posts about it and learned it might be a spelling issue but I checked everything twice and still cannot get it going. Here is my code:



var tbl = document.getElementById('my_table'); 
for (var i = 0 ;i<tbl.rows.length-1; i++) { // for each row
row = tbl.rows[i];
row.getElementById('delete_row').className="other_classname";
}


This code however returns error:




Uncaught TypeError: Object #<HTMLTableRowElement> has no method 'getElementById'




Any Idea what might be wrong?










share|improve this question

























  • row.getElementById('delete_row').className="other_classname"; doesn't seem to make any sense - what are you trying to achieve here? Is 'delete_row' a table cell <td>?

    – Barry Kaye
    Jan 15 '13 at 11:12













  • Hi 'delete_row' is an id of a href inside last cell of every row (so last column of a tabale is filled in with hrefs of the same id). I will correct my question in a sec.

    – HoGo
    Jan 15 '13 at 11:28














0












0








0


1






I have a HTML table. In this table I have links in last column (with id="delete_row"). I am trying to extract each link and it is not working. I have seen some posts about it and learned it might be a spelling issue but I checked everything twice and still cannot get it going. Here is my code:



var tbl = document.getElementById('my_table'); 
for (var i = 0 ;i<tbl.rows.length-1; i++) { // for each row
row = tbl.rows[i];
row.getElementById('delete_row').className="other_classname";
}


This code however returns error:




Uncaught TypeError: Object #<HTMLTableRowElement> has no method 'getElementById'




Any Idea what might be wrong?










share|improve this question
















I have a HTML table. In this table I have links in last column (with id="delete_row"). I am trying to extract each link and it is not working. I have seen some posts about it and learned it might be a spelling issue but I checked everything twice and still cannot get it going. Here is my code:



var tbl = document.getElementById('my_table'); 
for (var i = 0 ;i<tbl.rows.length-1; i++) { // for each row
row = tbl.rows[i];
row.getElementById('delete_row').className="other_classname";
}


This code however returns error:




Uncaught TypeError: Object #<HTMLTableRowElement> has no method 'getElementById'




Any Idea what might be wrong?







javascript html-table getelementbyid






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Aug 10 '17 at 13:28









Brian Tompsett - 汤莱恩

4,2031338101




4,2031338101










asked Jan 15 '13 at 11:08









HoGoHoGo

3433717




3433717













  • row.getElementById('delete_row').className="other_classname"; doesn't seem to make any sense - what are you trying to achieve here? Is 'delete_row' a table cell <td>?

    – Barry Kaye
    Jan 15 '13 at 11:12













  • Hi 'delete_row' is an id of a href inside last cell of every row (so last column of a tabale is filled in with hrefs of the same id). I will correct my question in a sec.

    – HoGo
    Jan 15 '13 at 11:28



















  • row.getElementById('delete_row').className="other_classname"; doesn't seem to make any sense - what are you trying to achieve here? Is 'delete_row' a table cell <td>?

    – Barry Kaye
    Jan 15 '13 at 11:12













  • Hi 'delete_row' is an id of a href inside last cell of every row (so last column of a tabale is filled in with hrefs of the same id). I will correct my question in a sec.

    – HoGo
    Jan 15 '13 at 11:28

















row.getElementById('delete_row').className="other_classname"; doesn't seem to make any sense - what are you trying to achieve here? Is 'delete_row' a table cell <td>?

– Barry Kaye
Jan 15 '13 at 11:12







row.getElementById('delete_row').className="other_classname"; doesn't seem to make any sense - what are you trying to achieve here? Is 'delete_row' a table cell <td>?

– Barry Kaye
Jan 15 '13 at 11:12















Hi 'delete_row' is an id of a href inside last cell of every row (so last column of a tabale is filled in with hrefs of the same id). I will correct my question in a sec.

– HoGo
Jan 15 '13 at 11:28





Hi 'delete_row' is an id of a href inside last cell of every row (so last column of a tabale is filled in with hrefs of the same id). I will correct my question in a sec.

– HoGo
Jan 15 '13 at 11:28












3 Answers
3






active

oldest

votes


















0














I think an ID for entire HTML has to be unique. You are using ID more than one time, which might be the issue. So if you use the class instead of ID and the function getElementsByClassName instead of getElementByID, it might solve your case.






share|improve this answer
























  • Note getElementByID should be getElementById - do not capitalize the final d.

    – Barry Kaye
    Jan 15 '13 at 11:35











  • Hi, I cannot use class name as it is used by other links in table to. Instead I have tried this one: links=tbl.getElementsByName('delete_col'); links[i].className="other_classname"; and it returns Uncaught TypeError: Object #<HTMLTableElement> has no method 'getElementsByName'

    – HoGo
    Jan 15 '13 at 11:43





















0














Further to your comment, to access the last cell in each row, replace:



row.getElementById('delete_row').className="other_classname";


With:



var len = document.getElementById("my_table").rows[i].cells.length;
document.getElementById("my_table").rows[i].cells[len - 1].className="other_classname";





share|improve this answer


























  • Thanks, did it but I have enother error: Uncaught TypeError: Cannot read property 'rows' of null

    – HoGo
    Jan 15 '13 at 11:39













  • This is odd. It does not work and the prowser (chrome) shakes as there was an error, but there is nothing in the consloe, so I do not know what else might be wrong :(

    – HoGo
    Jan 15 '13 at 11:47











  • Create a jsFiddle and provide the link here - I'm sure we can fix this quickly.

    – Barry Kaye
    Jan 15 '13 at 11:49













  • OK here it is jsfiddle.net/qr2BJ/7315 The whole thing is to renumarate ids in onclick event of X href after each deletion, so next time it refers to the apriopriate row.

    – HoGo
    Jan 15 '13 at 13:13





















0














You need to use class structure for your ids. Assume that you will add your rows with a button and delete them with X link like yours.



<input type="button" value="add" id="btnAddRow">

<table id="customFields" align="center" cellspacing="0" cellpadding="0" border="0">
<tr class="HeaderRow"><td colspan="7"></td></tr>
</table>


And this is the javascript code for handle add and remove process:



$("#btnAddRow").click(function () {
counter += 1;
$("#customFields").show();
$("#customFields").append('<tr valign="top"><td> ' + counter + '</td>' + '<td>' + '<a href="javascript:void(0);" class="removeRow">Delete</a></td></tr>');
});

$("#customFields").on('click', '.removeRow', function () {
var rowId = $(this).parent().parent().index() - 1;
$(this).parent().parent().remove();

if ($('#customFields tr').length == 2) {
$("#customFields").hide();
}
});


As you see a dynamic process will be more useful for you.






share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f14336419%2fjavascript-get-element-by-id-from-a-table-cell-not-working%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    I think an ID for entire HTML has to be unique. You are using ID more than one time, which might be the issue. So if you use the class instead of ID and the function getElementsByClassName instead of getElementByID, it might solve your case.






    share|improve this answer
























    • Note getElementByID should be getElementById - do not capitalize the final d.

      – Barry Kaye
      Jan 15 '13 at 11:35











    • Hi, I cannot use class name as it is used by other links in table to. Instead I have tried this one: links=tbl.getElementsByName('delete_col'); links[i].className="other_classname"; and it returns Uncaught TypeError: Object #<HTMLTableElement> has no method 'getElementsByName'

      – HoGo
      Jan 15 '13 at 11:43


















    0














    I think an ID for entire HTML has to be unique. You are using ID more than one time, which might be the issue. So if you use the class instead of ID and the function getElementsByClassName instead of getElementByID, it might solve your case.






    share|improve this answer
























    • Note getElementByID should be getElementById - do not capitalize the final d.

      – Barry Kaye
      Jan 15 '13 at 11:35











    • Hi, I cannot use class name as it is used by other links in table to. Instead I have tried this one: links=tbl.getElementsByName('delete_col'); links[i].className="other_classname"; and it returns Uncaught TypeError: Object #<HTMLTableElement> has no method 'getElementsByName'

      – HoGo
      Jan 15 '13 at 11:43
















    0












    0








    0







    I think an ID for entire HTML has to be unique. You are using ID more than one time, which might be the issue. So if you use the class instead of ID and the function getElementsByClassName instead of getElementByID, it might solve your case.






    share|improve this answer













    I think an ID for entire HTML has to be unique. You are using ID more than one time, which might be the issue. So if you use the class instead of ID and the function getElementsByClassName instead of getElementByID, it might solve your case.







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Jan 15 '13 at 11:29









    Raghavendra KarunanidhiRaghavendra Karunanidhi

    5913




    5913













    • Note getElementByID should be getElementById - do not capitalize the final d.

      – Barry Kaye
      Jan 15 '13 at 11:35











    • Hi, I cannot use class name as it is used by other links in table to. Instead I have tried this one: links=tbl.getElementsByName('delete_col'); links[i].className="other_classname"; and it returns Uncaught TypeError: Object #<HTMLTableElement> has no method 'getElementsByName'

      – HoGo
      Jan 15 '13 at 11:43





















    • Note getElementByID should be getElementById - do not capitalize the final d.

      – Barry Kaye
      Jan 15 '13 at 11:35











    • Hi, I cannot use class name as it is used by other links in table to. Instead I have tried this one: links=tbl.getElementsByName('delete_col'); links[i].className="other_classname"; and it returns Uncaught TypeError: Object #<HTMLTableElement> has no method 'getElementsByName'

      – HoGo
      Jan 15 '13 at 11:43



















    Note getElementByID should be getElementById - do not capitalize the final d.

    – Barry Kaye
    Jan 15 '13 at 11:35





    Note getElementByID should be getElementById - do not capitalize the final d.

    – Barry Kaye
    Jan 15 '13 at 11:35













    Hi, I cannot use class name as it is used by other links in table to. Instead I have tried this one: links=tbl.getElementsByName('delete_col'); links[i].className="other_classname"; and it returns Uncaught TypeError: Object #<HTMLTableElement> has no method 'getElementsByName'

    – HoGo
    Jan 15 '13 at 11:43







    Hi, I cannot use class name as it is used by other links in table to. Instead I have tried this one: links=tbl.getElementsByName('delete_col'); links[i].className="other_classname"; and it returns Uncaught TypeError: Object #<HTMLTableElement> has no method 'getElementsByName'

    – HoGo
    Jan 15 '13 at 11:43















    0














    Further to your comment, to access the last cell in each row, replace:



    row.getElementById('delete_row').className="other_classname";


    With:



    var len = document.getElementById("my_table").rows[i].cells.length;
    document.getElementById("my_table").rows[i].cells[len - 1].className="other_classname";





    share|improve this answer


























    • Thanks, did it but I have enother error: Uncaught TypeError: Cannot read property 'rows' of null

      – HoGo
      Jan 15 '13 at 11:39













    • This is odd. It does not work and the prowser (chrome) shakes as there was an error, but there is nothing in the consloe, so I do not know what else might be wrong :(

      – HoGo
      Jan 15 '13 at 11:47











    • Create a jsFiddle and provide the link here - I'm sure we can fix this quickly.

      – Barry Kaye
      Jan 15 '13 at 11:49













    • OK here it is jsfiddle.net/qr2BJ/7315 The whole thing is to renumarate ids in onclick event of X href after each deletion, so next time it refers to the apriopriate row.

      – HoGo
      Jan 15 '13 at 13:13


















    0














    Further to your comment, to access the last cell in each row, replace:



    row.getElementById('delete_row').className="other_classname";


    With:



    var len = document.getElementById("my_table").rows[i].cells.length;
    document.getElementById("my_table").rows[i].cells[len - 1].className="other_classname";





    share|improve this answer


























    • Thanks, did it but I have enother error: Uncaught TypeError: Cannot read property 'rows' of null

      – HoGo
      Jan 15 '13 at 11:39













    • This is odd. It does not work and the prowser (chrome) shakes as there was an error, but there is nothing in the consloe, so I do not know what else might be wrong :(

      – HoGo
      Jan 15 '13 at 11:47











    • Create a jsFiddle and provide the link here - I'm sure we can fix this quickly.

      – Barry Kaye
      Jan 15 '13 at 11:49













    • OK here it is jsfiddle.net/qr2BJ/7315 The whole thing is to renumarate ids in onclick event of X href after each deletion, so next time it refers to the apriopriate row.

      – HoGo
      Jan 15 '13 at 13:13
















    0












    0








    0







    Further to your comment, to access the last cell in each row, replace:



    row.getElementById('delete_row').className="other_classname";


    With:



    var len = document.getElementById("my_table").rows[i].cells.length;
    document.getElementById("my_table").rows[i].cells[len - 1].className="other_classname";





    share|improve this answer















    Further to your comment, to access the last cell in each row, replace:



    row.getElementById('delete_row').className="other_classname";


    With:



    var len = document.getElementById("my_table").rows[i].cells.length;
    document.getElementById("my_table").rows[i].cells[len - 1].className="other_classname";






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Jan 15 '13 at 11:42

























    answered Jan 15 '13 at 11:34









    Barry KayeBarry Kaye

    6,97353155




    6,97353155













    • Thanks, did it but I have enother error: Uncaught TypeError: Cannot read property 'rows' of null

      – HoGo
      Jan 15 '13 at 11:39













    • This is odd. It does not work and the prowser (chrome) shakes as there was an error, but there is nothing in the consloe, so I do not know what else might be wrong :(

      – HoGo
      Jan 15 '13 at 11:47











    • Create a jsFiddle and provide the link here - I'm sure we can fix this quickly.

      – Barry Kaye
      Jan 15 '13 at 11:49













    • OK here it is jsfiddle.net/qr2BJ/7315 The whole thing is to renumarate ids in onclick event of X href after each deletion, so next time it refers to the apriopriate row.

      – HoGo
      Jan 15 '13 at 13:13





















    • Thanks, did it but I have enother error: Uncaught TypeError: Cannot read property 'rows' of null

      – HoGo
      Jan 15 '13 at 11:39













    • This is odd. It does not work and the prowser (chrome) shakes as there was an error, but there is nothing in the consloe, so I do not know what else might be wrong :(

      – HoGo
      Jan 15 '13 at 11:47











    • Create a jsFiddle and provide the link here - I'm sure we can fix this quickly.

      – Barry Kaye
      Jan 15 '13 at 11:49













    • OK here it is jsfiddle.net/qr2BJ/7315 The whole thing is to renumarate ids in onclick event of X href after each deletion, so next time it refers to the apriopriate row.

      – HoGo
      Jan 15 '13 at 13:13



















    Thanks, did it but I have enother error: Uncaught TypeError: Cannot read property 'rows' of null

    – HoGo
    Jan 15 '13 at 11:39







    Thanks, did it but I have enother error: Uncaught TypeError: Cannot read property 'rows' of null

    – HoGo
    Jan 15 '13 at 11:39















    This is odd. It does not work and the prowser (chrome) shakes as there was an error, but there is nothing in the consloe, so I do not know what else might be wrong :(

    – HoGo
    Jan 15 '13 at 11:47





    This is odd. It does not work and the prowser (chrome) shakes as there was an error, but there is nothing in the consloe, so I do not know what else might be wrong :(

    – HoGo
    Jan 15 '13 at 11:47













    Create a jsFiddle and provide the link here - I'm sure we can fix this quickly.

    – Barry Kaye
    Jan 15 '13 at 11:49







    Create a jsFiddle and provide the link here - I'm sure we can fix this quickly.

    – Barry Kaye
    Jan 15 '13 at 11:49















    OK here it is jsfiddle.net/qr2BJ/7315 The whole thing is to renumarate ids in onclick event of X href after each deletion, so next time it refers to the apriopriate row.

    – HoGo
    Jan 15 '13 at 13:13







    OK here it is jsfiddle.net/qr2BJ/7315 The whole thing is to renumarate ids in onclick event of X href after each deletion, so next time it refers to the apriopriate row.

    – HoGo
    Jan 15 '13 at 13:13













    0














    You need to use class structure for your ids. Assume that you will add your rows with a button and delete them with X link like yours.



    <input type="button" value="add" id="btnAddRow">

    <table id="customFields" align="center" cellspacing="0" cellpadding="0" border="0">
    <tr class="HeaderRow"><td colspan="7"></td></tr>
    </table>


    And this is the javascript code for handle add and remove process:



    $("#btnAddRow").click(function () {
    counter += 1;
    $("#customFields").show();
    $("#customFields").append('<tr valign="top"><td> ' + counter + '</td>' + '<td>' + '<a href="javascript:void(0);" class="removeRow">Delete</a></td></tr>');
    });

    $("#customFields").on('click', '.removeRow', function () {
    var rowId = $(this).parent().parent().index() - 1;
    $(this).parent().parent().remove();

    if ($('#customFields tr').length == 2) {
    $("#customFields").hide();
    }
    });


    As you see a dynamic process will be more useful for you.






    share|improve this answer




























      0














      You need to use class structure for your ids. Assume that you will add your rows with a button and delete them with X link like yours.



      <input type="button" value="add" id="btnAddRow">

      <table id="customFields" align="center" cellspacing="0" cellpadding="0" border="0">
      <tr class="HeaderRow"><td colspan="7"></td></tr>
      </table>


      And this is the javascript code for handle add and remove process:



      $("#btnAddRow").click(function () {
      counter += 1;
      $("#customFields").show();
      $("#customFields").append('<tr valign="top"><td> ' + counter + '</td>' + '<td>' + '<a href="javascript:void(0);" class="removeRow">Delete</a></td></tr>');
      });

      $("#customFields").on('click', '.removeRow', function () {
      var rowId = $(this).parent().parent().index() - 1;
      $(this).parent().parent().remove();

      if ($('#customFields tr').length == 2) {
      $("#customFields").hide();
      }
      });


      As you see a dynamic process will be more useful for you.






      share|improve this answer


























        0












        0








        0







        You need to use class structure for your ids. Assume that you will add your rows with a button and delete them with X link like yours.



        <input type="button" value="add" id="btnAddRow">

        <table id="customFields" align="center" cellspacing="0" cellpadding="0" border="0">
        <tr class="HeaderRow"><td colspan="7"></td></tr>
        </table>


        And this is the javascript code for handle add and remove process:



        $("#btnAddRow").click(function () {
        counter += 1;
        $("#customFields").show();
        $("#customFields").append('<tr valign="top"><td> ' + counter + '</td>' + '<td>' + '<a href="javascript:void(0);" class="removeRow">Delete</a></td></tr>');
        });

        $("#customFields").on('click', '.removeRow', function () {
        var rowId = $(this).parent().parent().index() - 1;
        $(this).parent().parent().remove();

        if ($('#customFields tr').length == 2) {
        $("#customFields").hide();
        }
        });


        As you see a dynamic process will be more useful for you.






        share|improve this answer













        You need to use class structure for your ids. Assume that you will add your rows with a button and delete them with X link like yours.



        <input type="button" value="add" id="btnAddRow">

        <table id="customFields" align="center" cellspacing="0" cellpadding="0" border="0">
        <tr class="HeaderRow"><td colspan="7"></td></tr>
        </table>


        And this is the javascript code for handle add and remove process:



        $("#btnAddRow").click(function () {
        counter += 1;
        $("#customFields").show();
        $("#customFields").append('<tr valign="top"><td> ' + counter + '</td>' + '<td>' + '<a href="javascript:void(0);" class="removeRow">Delete</a></td></tr>');
        });

        $("#customFields").on('click', '.removeRow', function () {
        var rowId = $(this).parent().parent().index() - 1;
        $(this).parent().parent().remove();

        if ($('#customFields tr').length == 2) {
        $("#customFields").hide();
        }
        });


        As you see a dynamic process will be more useful for you.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 9 '16 at 6:14









        tdogtdog

        309113




        309113






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f14336419%2fjavascript-get-element-by-id-from-a-table-cell-not-working%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            A CLEAN and SIMPLE way to add appendices to Table of Contents and bookmarks

            Calculate evaluation metrics using cross_val_predict sklearn

            Insert data from modal to MySQL (multiple modal on website)