I Want Mobile And PC Both Not Allow Character Only Number Allow
I Have Code For Input And Search Button And Code OF Allow Only Number
Into Desktop It Not Allow But character But Into Mobile It Allow I want Both Are Not Allow character
Track
<script>
function isNumber(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57))
return false;
return true;
}
</script>
jquery html
add a comment |
I Have Code For Input And Search Button And Code OF Allow Only Number
Into Desktop It Not Allow But character But Into Mobile It Allow I want Both Are Not Allow character
Track
<script>
function isNumber(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57))
return false;
return true;
}
</script>
jquery html
add a comment |
I Have Code For Input And Search Button And Code OF Allow Only Number
Into Desktop It Not Allow But character But Into Mobile It Allow I want Both Are Not Allow character
Track
<script>
function isNumber(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57))
return false;
return true;
}
</script>
jquery html
I Have Code For Input And Search Button And Code OF Allow Only Number
Into Desktop It Not Allow But character But Into Mobile It Allow I want Both Are Not Allow character
Track
<script>
function isNumber(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57))
return false;
return true;
}
</script>
jquery html
jquery html
asked Nov 24 '18 at 7:19
Sayra QueenSayra Queen
14
14
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Refer This snippet, It will work on both PC n mobile.
$( "input" ).on( "keypress", function(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57)){
return false;
}
return true;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" />
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Refer This snippet, It will work on both PC n mobile.
$( "input" ).on( "keypress", function(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57)){
return false;
}
return true;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" />
add a comment |
Refer This snippet, It will work on both PC n mobile.
$( "input" ).on( "keypress", function(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57)){
return false;
}
return true;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" />
add a comment |
Refer This snippet, It will work on both PC n mobile.
$( "input" ).on( "keypress", function(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57)){
return false;
}
return true;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" />
Refer This snippet, It will work on both PC n mobile.
$( "input" ).on( "keypress", function(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57)){
return false;
}
return true;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" />
$( "input" ).on( "keypress", function(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57)){
return false;
}
return true;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" />
$( "input" ).on( "keypress", function(evt) {
var iKeyCode = (evt.which) ? evt.which : evt.keyCode
if (iKeyCode != 46 && iKeyCode > 31 && (iKeyCode < 48 || iKeyCode > 57)){
return false;
}
return true;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="text" />
answered Nov 24 '18 at 7:43
WC2WC2
1989
1989
add a comment |
add a comment |
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