split XML node by half (XSLT transformation)












1














Could you please help how to split in half node with subnodes.



Input:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Output:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.



Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy



xslt:



            <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />

<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &lt;= $half]" />

</FileHashCondition>
</Conditions>
</FileHashRule>

<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &gt; $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>


</RuleCollection>
</xsl:template>

</xsl:stylesheet>


Output:



        <?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>









share|improve this question
























  • Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
    – michael.hor257k
    Nov 23 '18 at 12:12










  • @michael.hor257k, corrected, about half, doesnt matter
    – Alexander
    Nov 23 '18 at 12:22










  • When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
    – Michael Kay
    Nov 23 '18 at 12:26










  • You keep changing your input XML format. Now that you have added the RuleCollection wrapper, you must change the fileHash variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" /> - see: xsltfiddle.liberty-development.net/jyH9rNq/4
    – michael.hor257k
    Nov 24 '18 at 9:01












  • @michael.hor257k, Thanks a lot, works great. what I need
    – Alexander
    Nov 24 '18 at 20:37
















1














Could you please help how to split in half node with subnodes.



Input:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Output:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.



Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy



xslt:



            <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />

<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &lt;= $half]" />

</FileHashCondition>
</Conditions>
</FileHashRule>

<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &gt; $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>


</RuleCollection>
</xsl:template>

</xsl:stylesheet>


Output:



        <?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>









share|improve this question
























  • Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
    – michael.hor257k
    Nov 23 '18 at 12:12










  • @michael.hor257k, corrected, about half, doesnt matter
    – Alexander
    Nov 23 '18 at 12:22










  • When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
    – Michael Kay
    Nov 23 '18 at 12:26










  • You keep changing your input XML format. Now that you have added the RuleCollection wrapper, you must change the fileHash variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" /> - see: xsltfiddle.liberty-development.net/jyH9rNq/4
    – michael.hor257k
    Nov 24 '18 at 9:01












  • @michael.hor257k, Thanks a lot, works great. what I need
    – Alexander
    Nov 24 '18 at 20:37














1












1








1







Could you please help how to split in half node with subnodes.



Input:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Output:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.



Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy



xslt:



            <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />

<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &lt;= $half]" />

</FileHashCondition>
</Conditions>
</FileHashRule>

<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &gt; $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>


</RuleCollection>
</xsl:template>

</xsl:stylesheet>


Output:



        <?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>









share|improve this question















Could you please help how to split in half node with subnodes.



Input:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Output:



<RuleCollection Type="Exe" EnforcementMode="Enabled">
<FileHashRule Id="hard-coded guid1">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xCC864"></FileHash>
<FileHash Type="SHA256" Data="0x9D973"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
<FileHashRule Id="hard-coded guid2">
<Conditions>
<FileHashCondition>
<FileHash Type="SHA256" Data="0xA92EF"></FileHash>
<FileHash Type="SHA256" Data="0x279CD"></FileHash>
</FileHashCondition>
</Conditions>
</FileHashRule>
</RuleCollection>


Unfortunatly I dont have expirience with xslt and did not find such an examples how to do it.



Updated
I tried one of the suggested approach below and have this https://xsltfiddle.liberty-development.net/jyH9rNq/3 nodes doesn't copy



xslt:



            <?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:variable name="fileHash" select="/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />

<xsl:template match="/">
<RuleCollection>
<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfa</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &lt;= $half]" />

</FileHashCondition>
</Conditions>
</FileHashRule>

<FileHashRule>
<xsl:attribute name="Id">ad22d301-eb88-485d-ae1d-537790bdebfb</xsl:attribute>
<Conditions>

<FileHashCondition>
<xsl:copy-of select="$fileHash[position() &gt; $half]" />
</FileHashCondition>
</Conditions>
</FileHashRule>


</RuleCollection>
</xsl:template>

</xsl:stylesheet>


Output:



        <?xml version="1.0" encoding="UTF-8"?>
<RuleCollection>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfa">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
<FileHashRule Id="ad22d301-eb88-485d-ae1d-537790bdebfb">
<Conditions>
<FileHashCondition/>
</Conditions>
</FileHashRule>
</RuleCollection>






xml xslt-1.0






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 8:21

























asked Nov 23 '18 at 11:15









Alexander

103




103












  • Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
    – michael.hor257k
    Nov 23 '18 at 12:12










  • @michael.hor257k, corrected, about half, doesnt matter
    – Alexander
    Nov 23 '18 at 12:22










  • When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
    – Michael Kay
    Nov 23 '18 at 12:26










  • You keep changing your input XML format. Now that you have added the RuleCollection wrapper, you must change the fileHash variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" /> - see: xsltfiddle.liberty-development.net/jyH9rNq/4
    – michael.hor257k
    Nov 24 '18 at 9:01












  • @michael.hor257k, Thanks a lot, works great. what I need
    – Alexander
    Nov 24 '18 at 20:37


















  • Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
    – michael.hor257k
    Nov 23 '18 at 12:12










  • @michael.hor257k, corrected, about half, doesnt matter
    – Alexander
    Nov 23 '18 at 12:22










  • When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
    – Michael Kay
    Nov 23 '18 at 12:26










  • You keep changing your input XML format. Now that you have added the RuleCollection wrapper, you must change the fileHash variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" /> - see: xsltfiddle.liberty-development.net/jyH9rNq/4
    – michael.hor257k
    Nov 24 '18 at 9:01












  • @michael.hor257k, Thanks a lot, works great. what I need
    – Alexander
    Nov 24 '18 at 20:37
















Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12




Define "half", esp. in the case of odd number of nodes. -- Note also that the output you show is not well-formed XML (lacks a single root element).
– michael.hor257k
Nov 23 '18 at 12:12












@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22




@michael.hor257k, corrected, about half, doesnt matter
– Alexander
Nov 23 '18 at 12:22












When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26




When you're learning a new language, you don't need experience and you don't need an example that solves the exact problem you're tackling, you need a good book or tutorial that teaches the concepts, and you should learn by doing simple exercises first before you try and tackle a more difficult problem.
– Michael Kay
Nov 23 '18 at 12:26












You keep changing your input XML format. Now that you have added the RuleCollection wrapper, you must change the fileHash variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" /> - see: xsltfiddle.liberty-development.net/jyH9rNq/4
– michael.hor257k
Nov 24 '18 at 9:01






You keep changing your input XML format. Now that you have added the RuleCollection wrapper, you must change the fileHash variable definition to: <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" /> - see: xsltfiddle.liberty-development.net/jyH9rNq/4
– michael.hor257k
Nov 24 '18 at 9:01














@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37




@michael.hor257k, Thanks a lot, works great. what I need
– Alexander
Nov 24 '18 at 20:37












3 Answers
3






active

oldest

votes


















0














You could find the half point quite simply by:



<xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
<xsl:variable name="half" select="count($fileHash) div 2" />


Then just create the two FileHashRule elements and use:



<xsl:copy-of select="$fileHash[position() &lt;= $half]" />


to populate the first one, and:



<xsl:copy-of select="$fileHash[position() &gt; $half]" />


for the second one.






share|improve this answer































    1














    You can start from something like (XSLT Fiddle):



    <?xml version="1.0" encoding="UTF-8"?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="//xs">
    <xsl:copy>
    <xsl:apply-templates select="@*"/>
    <xsl:apply-templates select='x[position() &lt;= last() div 2]'/>
    </xsl:copy>

    <xsl:copy>
    <xsl:apply-templates select="@*"/>
    <xsl:apply-templates select='x[position() &gt; last() div 2]'/>
    </xsl:copy>
    </xsl:template>

    <xsl:template match="@* | node()">
    <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
    </xsl:copy>
    </xsl:template>

    </xsl:stylesheet>


    It will split



    <?xml version="1.0" encoding="utf-8" ?>
    <data>
    <xs a="b">
    <will-not-be-copied/>
    <x>1</x>
    <x>2</x>
    <x>3</x>
    <x>4</x>
    </xs>
    </data>


    into



    <?xml version="1.0" encoding="UTF-8"?>
    <data>
    <xs a="b">
    <x>1</x>
    <x>2</x>
    </xs>
    <xs a="b">
    <x>3</x>
    <x>4</x>
    </xs>
    </data>


    Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied> and you might want to add your id values to the splitted <xs> tags.






    share|improve this answer





















    • Your wrappers are identical - unlike the expected output.
      – michael.hor257k
      Nov 23 '18 at 12:37



















    0














    Here's one way:



    <xsl:template match="@*|node()" mode="#all">
    <xsl:copy>
    <xsl:apply-templates select="@*|node()" mode="#current"/>
    </xsl:copy>
    </xsl:template>

    <xsl:template match="FileHashRule">
    <FileHashRule Id="{@Id}">
    <xsl:apply-templates mode="one"/>
    </FileHashRule>
    <FileHashRule Id="{@Id + 1}">
    <xsl:apply-templates mode="two"/>
    </FileHashRule>
    </xsl:template>

    <xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
    <xsl:template match="FileHash[position() &lt;= last() div 2]" mode="two"/>


    The first rule says: by default, copy nodes unchanged.



    The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.



    The third rule says: during the first phase, skip any FileHash element in the second half of the list.



    The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.






    share|improve this answer





















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      3 Answers
      3






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      3 Answers
      3






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      0














      You could find the half point quite simply by:



      <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
      <xsl:variable name="half" select="count($fileHash) div 2" />


      Then just create the two FileHashRule elements and use:



      <xsl:copy-of select="$fileHash[position() &lt;= $half]" />


      to populate the first one, and:



      <xsl:copy-of select="$fileHash[position() &gt; $half]" />


      for the second one.






      share|improve this answer




























        0














        You could find the half point quite simply by:



        <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
        <xsl:variable name="half" select="count($fileHash) div 2" />


        Then just create the two FileHashRule elements and use:



        <xsl:copy-of select="$fileHash[position() &lt;= $half]" />


        to populate the first one, and:



        <xsl:copy-of select="$fileHash[position() &gt; $half]" />


        for the second one.






        share|improve this answer


























          0












          0








          0






          You could find the half point quite simply by:



          <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
          <xsl:variable name="half" select="count($fileHash) div 2" />


          Then just create the two FileHashRule elements and use:



          <xsl:copy-of select="$fileHash[position() &lt;= $half]" />


          to populate the first one, and:



          <xsl:copy-of select="$fileHash[position() &gt; $half]" />


          for the second one.






          share|improve this answer














          You could find the half point quite simply by:



          <xsl:variable name="fileHash" select="/RuleCollection/FileHashRule/Conditions/FileHashCondition/FileHash" />
          <xsl:variable name="half" select="count($fileHash) div 2" />


          Then just create the two FileHashRule elements and use:



          <xsl:copy-of select="$fileHash[position() &lt;= $half]" />


          to populate the first one, and:



          <xsl:copy-of select="$fileHash[position() &gt; $half]" />


          for the second one.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 24 '18 at 9:02

























          answered Nov 23 '18 at 12:34









          michael.hor257k

          73.7k42236




          73.7k42236

























              1














              You can start from something like (XSLT Fiddle):



              <?xml version="1.0" encoding="UTF-8"?>
              <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
              <xsl:output method="xml" indent="yes"/>

              <xsl:template match="//xs">
              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &lt;= last() div 2]'/>
              </xsl:copy>

              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &gt; last() div 2]'/>
              </xsl:copy>
              </xsl:template>

              <xsl:template match="@* | node()">
              <xsl:copy>
              <xsl:apply-templates select="@* | node()"/>
              </xsl:copy>
              </xsl:template>

              </xsl:stylesheet>


              It will split



              <?xml version="1.0" encoding="utf-8" ?>
              <data>
              <xs a="b">
              <will-not-be-copied/>
              <x>1</x>
              <x>2</x>
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              into



              <?xml version="1.0" encoding="UTF-8"?>
              <data>
              <xs a="b">
              <x>1</x>
              <x>2</x>
              </xs>
              <xs a="b">
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied> and you might want to add your id values to the splitted <xs> tags.






              share|improve this answer





















              • Your wrappers are identical - unlike the expected output.
                – michael.hor257k
                Nov 23 '18 at 12:37
















              1














              You can start from something like (XSLT Fiddle):



              <?xml version="1.0" encoding="UTF-8"?>
              <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
              <xsl:output method="xml" indent="yes"/>

              <xsl:template match="//xs">
              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &lt;= last() div 2]'/>
              </xsl:copy>

              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &gt; last() div 2]'/>
              </xsl:copy>
              </xsl:template>

              <xsl:template match="@* | node()">
              <xsl:copy>
              <xsl:apply-templates select="@* | node()"/>
              </xsl:copy>
              </xsl:template>

              </xsl:stylesheet>


              It will split



              <?xml version="1.0" encoding="utf-8" ?>
              <data>
              <xs a="b">
              <will-not-be-copied/>
              <x>1</x>
              <x>2</x>
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              into



              <?xml version="1.0" encoding="UTF-8"?>
              <data>
              <xs a="b">
              <x>1</x>
              <x>2</x>
              </xs>
              <xs a="b">
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied> and you might want to add your id values to the splitted <xs> tags.






              share|improve this answer





















              • Your wrappers are identical - unlike the expected output.
                – michael.hor257k
                Nov 23 '18 at 12:37














              1












              1








              1






              You can start from something like (XSLT Fiddle):



              <?xml version="1.0" encoding="UTF-8"?>
              <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
              <xsl:output method="xml" indent="yes"/>

              <xsl:template match="//xs">
              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &lt;= last() div 2]'/>
              </xsl:copy>

              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &gt; last() div 2]'/>
              </xsl:copy>
              </xsl:template>

              <xsl:template match="@* | node()">
              <xsl:copy>
              <xsl:apply-templates select="@* | node()"/>
              </xsl:copy>
              </xsl:template>

              </xsl:stylesheet>


              It will split



              <?xml version="1.0" encoding="utf-8" ?>
              <data>
              <xs a="b">
              <will-not-be-copied/>
              <x>1</x>
              <x>2</x>
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              into



              <?xml version="1.0" encoding="UTF-8"?>
              <data>
              <xs a="b">
              <x>1</x>
              <x>2</x>
              </xs>
              <xs a="b">
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied> and you might want to add your id values to the splitted <xs> tags.






              share|improve this answer












              You can start from something like (XSLT Fiddle):



              <?xml version="1.0" encoding="UTF-8"?>
              <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
              <xsl:output method="xml" indent="yes"/>

              <xsl:template match="//xs">
              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &lt;= last() div 2]'/>
              </xsl:copy>

              <xsl:copy>
              <xsl:apply-templates select="@*"/>
              <xsl:apply-templates select='x[position() &gt; last() div 2]'/>
              </xsl:copy>
              </xsl:template>

              <xsl:template match="@* | node()">
              <xsl:copy>
              <xsl:apply-templates select="@* | node()"/>
              </xsl:copy>
              </xsl:template>

              </xsl:stylesheet>


              It will split



              <?xml version="1.0" encoding="utf-8" ?>
              <data>
              <xs a="b">
              <will-not-be-copied/>
              <x>1</x>
              <x>2</x>
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              into



              <?xml version="1.0" encoding="UTF-8"?>
              <data>
              <xs a="b">
              <x>1</x>
              <x>2</x>
              </xs>
              <xs a="b">
              <x>3</x>
              <x>4</x>
              </xs>
              </data>


              Note though, that you need to clarify how you want to deal with tags like <will-not-be-copied> and you might want to add your id values to the splitted <xs> tags.







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Nov 23 '18 at 12:32









              Micha Wiedenmann

              10.3k1364103




              10.3k1364103












              • Your wrappers are identical - unlike the expected output.
                – michael.hor257k
                Nov 23 '18 at 12:37


















              • Your wrappers are identical - unlike the expected output.
                – michael.hor257k
                Nov 23 '18 at 12:37
















              Your wrappers are identical - unlike the expected output.
              – michael.hor257k
              Nov 23 '18 at 12:37




              Your wrappers are identical - unlike the expected output.
              – michael.hor257k
              Nov 23 '18 at 12:37











              0














              Here's one way:



              <xsl:template match="@*|node()" mode="#all">
              <xsl:copy>
              <xsl:apply-templates select="@*|node()" mode="#current"/>
              </xsl:copy>
              </xsl:template>

              <xsl:template match="FileHashRule">
              <FileHashRule Id="{@Id}">
              <xsl:apply-templates mode="one"/>
              </FileHashRule>
              <FileHashRule Id="{@Id + 1}">
              <xsl:apply-templates mode="two"/>
              </FileHashRule>
              </xsl:template>

              <xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
              <xsl:template match="FileHash[position() &lt;= last() div 2]" mode="two"/>


              The first rule says: by default, copy nodes unchanged.



              The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.



              The third rule says: during the first phase, skip any FileHash element in the second half of the list.



              The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.






              share|improve this answer


























                0














                Here's one way:



                <xsl:template match="@*|node()" mode="#all">
                <xsl:copy>
                <xsl:apply-templates select="@*|node()" mode="#current"/>
                </xsl:copy>
                </xsl:template>

                <xsl:template match="FileHashRule">
                <FileHashRule Id="{@Id}">
                <xsl:apply-templates mode="one"/>
                </FileHashRule>
                <FileHashRule Id="{@Id + 1}">
                <xsl:apply-templates mode="two"/>
                </FileHashRule>
                </xsl:template>

                <xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
                <xsl:template match="FileHash[position() &lt;= last() div 2]" mode="two"/>


                The first rule says: by default, copy nodes unchanged.



                The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.



                The third rule says: during the first phase, skip any FileHash element in the second half of the list.



                The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.






                share|improve this answer
























                  0












                  0








                  0






                  Here's one way:



                  <xsl:template match="@*|node()" mode="#all">
                  <xsl:copy>
                  <xsl:apply-templates select="@*|node()" mode="#current"/>
                  </xsl:copy>
                  </xsl:template>

                  <xsl:template match="FileHashRule">
                  <FileHashRule Id="{@Id}">
                  <xsl:apply-templates mode="one"/>
                  </FileHashRule>
                  <FileHashRule Id="{@Id + 1}">
                  <xsl:apply-templates mode="two"/>
                  </FileHashRule>
                  </xsl:template>

                  <xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
                  <xsl:template match="FileHash[position() &lt;= last() div 2]" mode="two"/>


                  The first rule says: by default, copy nodes unchanged.



                  The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.



                  The third rule says: during the first phase, skip any FileHash element in the second half of the list.



                  The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.






                  share|improve this answer












                  Here's one way:



                  <xsl:template match="@*|node()" mode="#all">
                  <xsl:copy>
                  <xsl:apply-templates select="@*|node()" mode="#current"/>
                  </xsl:copy>
                  </xsl:template>

                  <xsl:template match="FileHashRule">
                  <FileHashRule Id="{@Id}">
                  <xsl:apply-templates mode="one"/>
                  </FileHashRule>
                  <FileHashRule Id="{@Id + 1}">
                  <xsl:apply-templates mode="two"/>
                  </FileHashRule>
                  </xsl:template>

                  <xsl:template match="FileHash[position() > last() div 2]" mode="one"/>
                  <xsl:template match="FileHash[position() &lt;= last() div 2]" mode="two"/>


                  The first rule says: by default, copy nodes unchanged.



                  The second rule says: For a FileHashRule, create two copies, incrementing the @Id attribute in the second.



                  The third rule says: during the first phase, skip any FileHash element in the second half of the list.



                  The fourth rule says: during the second phase, skip any FileHash element in the first half of the list.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 23 '18 at 12:38









                  Michael Kay

                  108k660114




                  108k660114






























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