Need to convert char type column to date type
-3
I have a data.table with a column named 'Date' and type char and it looks like below. I need to convert this to date type column so that i can perform date operations.
Date
"10/11/2018"
"13/11/2013"
"22/11/2011"
"--"
"--"
"10/11/2018"
I tried this, but doesn't work
MyTable$Date <- as.POXISlt(MyTable$Date)
r datetime chr
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
asked Nov 23 '18 at 11:18
Yuvaraj
1
add a comment |
-3
I have a data.table with a column named 'Date' and type char and it looks like below. I need to convert this to date type column so that i can perform date operations.
Date
"10/11/2018"
"13/11/2013"
"22/11/2011"
"--"
"--"
"10/11/2018"
I tried this, but doesn't work
MyTable$Date <- as.POXISlt(MyTable$Date)
r datetime chr
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
asked Nov 23 '18 at 11:18
Yuvaraj
1
use lubridate::dmy(Date), you need to install lubridate library
– Hunaidkhan
Nov 23 '18 at 11:19
3
lubridate isn't required, but is nice to use. Alternative isas.Date("01/11/2018", "%d/%m/%Y"). See statmethods.net/input/dates.html
– Jonny Phelps
Nov 23 '18 at 11:24
1
Welcome to StackOverflow! Please read the info about how to ask a good question and how to give a reproducible example. This will make it much easier for others to help you.
– Jaap
Nov 23 '18 at 11:29
@JonnyPhelps - I am getting this error as "character string is not in a standard unambiguous format" for as.Date(MyTable$Date)
– Yuvaraj
Nov 23 '18 at 12:08
add a comment |
-3
-3
-3
I have a data.table with a column named 'Date' and type char and it looks like below. I need to convert this to date type column so that i can perform date operations.
Date
"10/11/2018"
"13/11/2013"
"22/11/2011"
"--"
"--"
"10/11/2018"
I tried this, but doesn't work
MyTable$Date <- as.POXISlt(MyTable$Date)
r datetime chr
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
asked Nov 23 '18 at 11:18
Yuvaraj
1
I have a data.table with a column named 'Date' and type char and it looks like below. I need to convert this to date type column so that i can perform date operations.
Date
"10/11/2018"
"13/11/2013"
"22/11/2011"
"--"
"--"
"10/11/2018"
I tried this, but doesn't work
MyTable$Date <- as.POXISlt(MyTable$Date)
r datetime chr
r datetime chr
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
asked Nov 23 '18 at 11:18
Yuvaraj
1
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
asked Nov 23 '18 at 11:18
Yuvaraj
1
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
edited Nov 23 '18 at 11:57
Henrik
40.8k992107
40.8k992107
asked Nov 23 '18 at 11:18
Yuvaraj
1
asked Nov 23 '18 at 11:18
Yuvaraj
1
asked Nov 23 '18 at 11:18
Yuvaraj
1
1
use lubridate::dmy(Date), you need to install lubridate library
– Hunaidkhan
Nov 23 '18 at 11:19
3
lubridate isn't required, but is nice to use. Alternative isas.Date("01/11/2018", "%d/%m/%Y"). See statmethods.net/input/dates.html
– Jonny Phelps
Nov 23 '18 at 11:24
1
Welcome to StackOverflow! Please read the info about how to ask a good question and how to give a reproducible example. This will make it much easier for others to help you.
– Jaap
Nov 23 '18 at 11:29
@JonnyPhelps - I am getting this error as "character string is not in a standard unambiguous format" for as.Date(MyTable$Date)
– Yuvaraj
Nov 23 '18 at 12:08
add a comment |
use lubridate::dmy(Date), you need to install lubridate library
– Hunaidkhan
Nov 23 '18 at 11:19
3
lubridate isn't required, but is nice to use. Alternative isas.Date("01/11/2018", "%d/%m/%Y"). See statmethods.net/input/dates.html
– Jonny Phelps
Nov 23 '18 at 11:24
1
Welcome to StackOverflow! Please read the info about how to ask a good question and how to give a reproducible example. This will make it much easier for others to help you.
– Jaap
Nov 23 '18 at 11:29
@JonnyPhelps - I am getting this error as "character string is not in a standard unambiguous format" for as.Date(MyTable$Date)
– Yuvaraj
Nov 23 '18 at 12:08
use lubridate::dmy(Date), you need to install lubridate library
– Hunaidkhan
Nov 23 '18 at 11:19
use lubridate::dmy(Date), you need to install lubridate library
– Hunaidkhan
Nov 23 '18 at 11:19
3
3
lubridate isn't required, but is nice to use. Alternative is
as.Date("01/11/2018", "%d/%m/%Y"). See statmethods.net/input/dates.html– Jonny Phelps
Nov 23 '18 at 11:24
lubridate isn't required, but is nice to use. Alternative is
as.Date("01/11/2018", "%d/%m/%Y"). See statmethods.net/input/dates.html– Jonny Phelps
Nov 23 '18 at 11:24
1
1
Welcome to StackOverflow! Please read the info about how to ask a good question and how to give a reproducible example. This will make it much easier for others to help you.
– Jaap
Nov 23 '18 at 11:29
Welcome to StackOverflow! Please read the info about how to ask a good question and how to give a reproducible example. This will make it much easier for others to help you.
– Jaap
Nov 23 '18 at 11:29
@JonnyPhelps - I am getting this error as "character string is not in a standard unambiguous format" for as.Date(MyTable$Date)
– Yuvaraj
Nov 23 '18 at 12:08
@JonnyPhelps - I am getting this error as "character string is not in a standard unambiguous format" for as.Date(MyTable$Date)
– Yuvaraj
Nov 23 '18 at 12:08
add a comment |
1 Answer
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Welcome to SO!
Using data.table I'd suggest the following:
library(data.table)
MyTable <- data.table(Date = c(
"10/11/2018",
"13/11/2013",
"22/11/2011",
"--",
"--",
"10/11/2018"
))
MyTable[, posixDate := as.POSIXct(Date, format = "%d/%m/%Y")]
If you need to get rid of the NA rows use: na.omit(MyTable)
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
add a comment |
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1 Answer
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0
Welcome to SO!
Using data.table I'd suggest the following:
library(data.table)
MyTable <- data.table(Date = c(
"10/11/2018",
"13/11/2013",
"22/11/2011",
"--",
"--",
"10/11/2018"
))
MyTable[, posixDate := as.POSIXct(Date, format = "%d/%m/%Y")]
If you need to get rid of the NA rows use: na.omit(MyTable)
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
add a comment |
0
Welcome to SO!
Using data.table I'd suggest the following:
library(data.table)
MyTable <- data.table(Date = c(
"10/11/2018",
"13/11/2013",
"22/11/2011",
"--",
"--",
"10/11/2018"
))
MyTable[, posixDate := as.POSIXct(Date, format = "%d/%m/%Y")]
If you need to get rid of the NA rows use: na.omit(MyTable)
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
add a comment |
0
0
0
Welcome to SO!
Using data.table I'd suggest the following:
library(data.table)
MyTable <- data.table(Date = c(
"10/11/2018",
"13/11/2013",
"22/11/2011",
"--",
"--",
"10/11/2018"
))
MyTable[, posixDate := as.POSIXct(Date, format = "%d/%m/%Y")]
If you need to get rid of the NA rows use: na.omit(MyTable)
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
Welcome to SO!
Using data.table I'd suggest the following:
library(data.table)
MyTable <- data.table(Date = c(
"10/11/2018",
"13/11/2013",
"22/11/2011",
"--",
"--",
"10/11/2018"
))
MyTable[, posixDate := as.POSIXct(Date, format = "%d/%m/%Y")]
If you need to get rid of the NA rows use: na.omit(MyTable)
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
answered Nov 23 '18 at 12:17
ismirsehregal
1,2111210
1,2111210
add a comment |
add a comment |
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use lubridate::dmy(Date), you need to install lubridate library
– Hunaidkhan
Nov 23 '18 at 11:19
3
lubridate isn't required, but is nice to use. Alternative is
as.Date("01/11/2018", "%d/%m/%Y"). See statmethods.net/input/dates.html– Jonny Phelps
Nov 23 '18 at 11:24
1
Welcome to StackOverflow! Please read the info about how to ask a good question and how to give a reproducible example. This will make it much easier for others to help you.
– Jaap
Nov 23 '18 at 11:29
@JonnyPhelps - I am getting this error as "character string is not in a standard unambiguous format" for as.Date(MyTable$Date)
– Yuvaraj
Nov 23 '18 at 12:08