Regex - matching brazilian phone numbers











up vote
2
down vote

favorite












I'm trying to use Regex to validate brazilian phone numbers.



For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.



RegEX:



(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}


Valid numbers:



(00)0000-0000; true

(00)000000000; true 

(00) 00000 0000; true

00 00000 0000; true

(000)00000 0000; true


Invalid numbers:



23232443243243423432; true

(0000)000000000; true

a00 00000-0000 ; true


Thanks!






javascript regex







share|improve this question
























  • If you match the whole string by enclosing the whole regex with ^ and $, will it be OK?
    – Wiktor Stribiżew
    Nov 21 at 17:15










  • Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
    – Havenard
    Nov 21 at 17:16










  • @Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
    – Zeca Novaes
    Nov 21 at 17:19










  • @WiktorStribiżew Not working :(
    – Zeca Novaes
    Nov 21 at 17:19






  • 1




    Try (?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
    – Wiktor Stribiżew
    Nov 21 at 17:21

















up vote
2
down vote

favorite












I'm trying to use Regex to validate brazilian phone numbers.



For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.



RegEX:



(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}


Valid numbers:



(00)0000-0000; true

(00)000000000; true 

(00) 00000 0000; true

00 00000 0000; true

(000)00000 0000; true


Invalid numbers:



23232443243243423432; true

(0000)000000000; true

a00 00000-0000 ; true


Thanks!






javascript regex







share|improve this question
























  • If you match the whole string by enclosing the whole regex with ^ and $, will it be OK?
    – Wiktor Stribiżew
    Nov 21 at 17:15










  • Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
    – Havenard
    Nov 21 at 17:16










  • @Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
    – Zeca Novaes
    Nov 21 at 17:19










  • @WiktorStribiżew Not working :(
    – Zeca Novaes
    Nov 21 at 17:19






  • 1




    Try (?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
    – Wiktor Stribiżew
    Nov 21 at 17:21















up vote
2
down vote

favorite









up vote
2
down vote

favorite











I'm trying to use Regex to validate brazilian phone numbers.



For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.



RegEX:



(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}


Valid numbers:



(00)0000-0000; true

(00)000000000; true 

(00) 00000 0000; true

00 00000 0000; true

(000)00000 0000; true


Invalid numbers:



23232443243243423432; true

(0000)000000000; true

a00 00000-0000 ; true


Thanks!






javascript regex







share|improve this question















I'm trying to use Regex to validate brazilian phone numbers.



For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.



RegEX:



(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}


Valid numbers:



(00)0000-0000; true

(00)000000000; true 

(00) 00000 0000; true

00 00000 0000; true

(000)00000 0000; true


Invalid numbers:



23232443243243423432; true

(0000)000000000; true

a00 00000-0000 ; true


Thanks!






javascript regex




javascript regex






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 at 18:12









Poul Bak

5,38331132




5,38331132










asked Nov 21 at 17:12









Zeca Novaes

14510




14510












  • If you match the whole string by enclosing the whole regex with ^ and $, will it be OK?
    – Wiktor Stribiżew
    Nov 21 at 17:15










  • Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
    – Havenard
    Nov 21 at 17:16










  • @Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
    – Zeca Novaes
    Nov 21 at 17:19










  • @WiktorStribiżew Not working :(
    – Zeca Novaes
    Nov 21 at 17:19






  • 1




    Try (?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
    – Wiktor Stribiżew
    Nov 21 at 17:21




















  • If you match the whole string by enclosing the whole regex with ^ and $, will it be OK?
    – Wiktor Stribiżew
    Nov 21 at 17:15










  • Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
    – Havenard
    Nov 21 at 17:16










  • @Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
    – Zeca Novaes
    Nov 21 at 17:19










  • @WiktorStribiżew Not working :(
    – Zeca Novaes
    Nov 21 at 17:19






  • 1




    Try (?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
    – Wiktor Stribiżew
    Nov 21 at 17:21


















If you match the whole string by enclosing the whole regex with ^ and $, will it be OK?
– Wiktor Stribiżew
Nov 21 at 17:15




If you match the whole string by enclosing the whole regex with ^ and $, will it be OK?
– Wiktor Stribiżew
Nov 21 at 17:15












Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16




Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16












@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19




@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19












@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19




@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19




1




1




Try (?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 at 17:21






Try (?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 at 17:21














1 Answer
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up vote
3
down vote



accepted










You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.



(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b

   ^^                                                                   ^^


See the regex demo



If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.






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    active

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    1 Answer
    1






    active

    oldest

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    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    3
    down vote



    accepted










    You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.



    (?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
    
   ^^                                                                   ^^


    See the regex demo



    If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.






    share|improve this answer

























      up vote
      3
      down vote



      accepted










      You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.



      (?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
      
   ^^                                                                   ^^


      See the regex demo



      If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.






      share|improve this answer























        up vote
        3
        down vote



        accepted







        up vote
        3
        down vote



        accepted






        You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.



        (?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
        
   ^^                                                                   ^^


        See the regex demo



        If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.






        share|improve this answer












        You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.



        (?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
        
   ^^                                                                   ^^


        See the regex demo



        If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 at 17:25









        Wiktor Stribiżew

        303k16123199




        303k16123199






























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