Regex - matching brazilian phone numbers
up vote
2
down vote
favorite
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
edited Nov 21 at 18:12
Poul Bak
5,38331132
asked Nov 21 at 17:12
Zeca Novaes
14510
|
show 1 more comment
up vote
2
down vote
favorite
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
edited Nov 21 at 18:12
Poul Bak
5,38331132
asked Nov 21 at 17:12
Zeca Novaes
14510
If you match the whole string by enclosing the whole regex with^and$, will it be OK?
– Wiktor Stribiżew
Nov 21 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19
1
Try(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 at 17:21
|
show 1 more comment
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
edited Nov 21 at 18:12
Poul Bak
5,38331132
asked Nov 21 at 17:12
Zeca Novaes
14510
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
javascript regex
edited Nov 21 at 18:12
Poul Bak
5,38331132
asked Nov 21 at 17:12
Zeca Novaes
14510
edited Nov 21 at 18:12
Poul Bak
5,38331132
asked Nov 21 at 17:12
Zeca Novaes
14510
edited Nov 21 at 18:12
Poul Bak
5,38331132
edited Nov 21 at 18:12
Poul Bak
5,38331132
edited Nov 21 at 18:12
Poul Bak
5,38331132
5,38331132
asked Nov 21 at 17:12
Zeca Novaes
14510
asked Nov 21 at 17:12
Zeca Novaes
14510
asked Nov 21 at 17:12
Zeca Novaes
14510
14510
If you match the whole string by enclosing the whole regex with^and$, will it be OK?
– Wiktor Stribiżew
Nov 21 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19
1
Try(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 at 17:21
|
show 1 more comment
If you match the whole string by enclosing the whole regex with^and$, will it be OK?
– Wiktor Stribiżew
Nov 21 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19
1
Try(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 at 17:21
If you match the whole string by enclosing the whole regex with
^ and $, will it be OK?– Wiktor Stribiżew
Nov 21 at 17:15
If you match the whole string by enclosing the whole regex with
^ and $, will it be OK?– Wiktor Stribiżew
Nov 21 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19
1
1
Try
(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.– Wiktor Stribiżew
Nov 21 at 17:21
Try
(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.– Wiktor Stribiżew
Nov 21 at 17:21
|
show 1 more comment
1 Answer
1
active
oldest
votes
up vote
3
down vote
accepted
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
add a comment |
up vote
3
down vote
accepted
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
answered Nov 21 at 17:25
Wiktor Stribiżew
303k16123199
303k16123199
add a comment |
add a comment |
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If you match the whole string by enclosing the whole regex with
^and$, will it be OK?– Wiktor Stribiżew
Nov 21 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 at 17:19
1
Try
(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.– Wiktor Stribiżew
Nov 21 at 17:21