Create single tuple from two tuples python3
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I'm a newbie at python and want to create a single tuple from two tuples such that the order of the two tuples is maintained eg the result should be:
final_tup = ((75, 57), (77, 6), (55, 64), (93, 36), (41, 63), (62, 53), (70, 26), (30, 71), (74, 88), (97, 66))
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
I am nearly there but I can't seem to get the final tuple out. I have:
tup = zip()
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
lx = list(x)
ly = list(y)
tup = zip(lx, ly)
for value in tup:
print(value)
Also I'm sure there is a more elegant way in python without having to convert to a list
python
asked Nov 29 '18 at 1:08
zoezoe
376
add a comment |
I'm a newbie at python and want to create a single tuple from two tuples such that the order of the two tuples is maintained eg the result should be:
final_tup = ((75, 57), (77, 6), (55, 64), (93, 36), (41, 63), (62, 53), (70, 26), (30, 71), (74, 88), (97, 66))
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
I am nearly there but I can't seem to get the final tuple out. I have:
tup = zip()
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
lx = list(x)
ly = list(y)
tup = zip(lx, ly)
for value in tup:
print(value)
Also I'm sure there is a more elegant way in python without having to convert to a list
python
asked Nov 29 '18 at 1:08
zoezoe
376
add a comment |
I'm a newbie at python and want to create a single tuple from two tuples such that the order of the two tuples is maintained eg the result should be:
final_tup = ((75, 57), (77, 6), (55, 64), (93, 36), (41, 63), (62, 53), (70, 26), (30, 71), (74, 88), (97, 66))
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
I am nearly there but I can't seem to get the final tuple out. I have:
tup = zip()
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
lx = list(x)
ly = list(y)
tup = zip(lx, ly)
for value in tup:
print(value)
Also I'm sure there is a more elegant way in python without having to convert to a list
python
asked Nov 29 '18 at 1:08
zoezoe
376
I'm a newbie at python and want to create a single tuple from two tuples such that the order of the two tuples is maintained eg the result should be:
final_tup = ((75, 57), (77, 6), (55, 64), (93, 36), (41, 63), (62, 53), (70, 26), (30, 71), (74, 88), (97, 66))
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
I am nearly there but I can't seem to get the final tuple out. I have:
tup = zip()
x = (75, 77, 55, 93, 41, 62, 70, 30, 74, 97)
y = (57, 6, 64, 36, 63, 53, 26, 71, 88, 66)
lx = list(x)
ly = list(y)
tup = zip(lx, ly)
for value in tup:
print(value)
Also I'm sure there is a more elegant way in python without having to convert to a list
python
python
asked Nov 29 '18 at 1:08
zoezoe
376
asked Nov 29 '18 at 1:08
zoezoe
376
asked Nov 29 '18 at 1:08
zoezoe
376
asked Nov 29 '18 at 1:08
zoezoe
376
asked Nov 29 '18 at 1:08
zoezoe
376
376
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Actually you are pretty close. Try this:
final_tuple = tuple(zip(x,y))
Out[3]:
((75, 57),
(77, 6),
(55, 64),
(93, 36),
(41, 63),
(62, 53),
(70, 26),
(30, 71),
(74, 88),
(97, 66))
Explanation:
zip method can take any iterable argument including tuples, so you don't have to make it a list first. It returns an iterator of zipped tuples, in order to get tuple of tuples, you have to use tuple method on that iterator.
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
Ha! Brilliant! I have been stuck on this for a couple of hours....I knew it would be a one liner. Thanks @KevinFang
– zoe
Nov 29 '18 at 1:16
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Actually you are pretty close. Try this:
final_tuple = tuple(zip(x,y))
Out[3]:
((75, 57),
(77, 6),
(55, 64),
(93, 36),
(41, 63),
(62, 53),
(70, 26),
(30, 71),
(74, 88),
(97, 66))
Explanation:
zip method can take any iterable argument including tuples, so you don't have to make it a list first. It returns an iterator of zipped tuples, in order to get tuple of tuples, you have to use tuple method on that iterator.
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
Ha! Brilliant! I have been stuck on this for a couple of hours....I knew it would be a one liner. Thanks @KevinFang
– zoe
Nov 29 '18 at 1:16
add a comment |
Actually you are pretty close. Try this:
final_tuple = tuple(zip(x,y))
Out[3]:
((75, 57),
(77, 6),
(55, 64),
(93, 36),
(41, 63),
(62, 53),
(70, 26),
(30, 71),
(74, 88),
(97, 66))
Explanation:
zip method can take any iterable argument including tuples, so you don't have to make it a list first. It returns an iterator of zipped tuples, in order to get tuple of tuples, you have to use tuple method on that iterator.
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
Ha! Brilliant! I have been stuck on this for a couple of hours....I knew it would be a one liner. Thanks @KevinFang
– zoe
Nov 29 '18 at 1:16
add a comment |
Actually you are pretty close. Try this:
final_tuple = tuple(zip(x,y))
Out[3]:
((75, 57),
(77, 6),
(55, 64),
(93, 36),
(41, 63),
(62, 53),
(70, 26),
(30, 71),
(74, 88),
(97, 66))
Explanation:
zip method can take any iterable argument including tuples, so you don't have to make it a list first. It returns an iterator of zipped tuples, in order to get tuple of tuples, you have to use tuple method on that iterator.
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
Actually you are pretty close. Try this:
final_tuple = tuple(zip(x,y))
Out[3]:
((75, 57),
(77, 6),
(55, 64),
(93, 36),
(41, 63),
(62, 53),
(70, 26),
(30, 71),
(74, 88),
(97, 66))
Explanation:
zip method can take any iterable argument including tuples, so you don't have to make it a list first. It returns an iterator of zipped tuples, in order to get tuple of tuples, you have to use tuple method on that iterator.
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
answered Nov 29 '18 at 1:12
Kevin FangKevin Fang
1,296318
1,296318
Ha! Brilliant! I have been stuck on this for a couple of hours....I knew it would be a one liner. Thanks @KevinFang
– zoe
Nov 29 '18 at 1:16
add a comment |
Ha! Brilliant! I have been stuck on this for a couple of hours....I knew it would be a one liner. Thanks @KevinFang
– zoe
Nov 29 '18 at 1:16
Ha! Brilliant! I have been stuck on this for a couple of hours....I knew it would be a one liner. Thanks @KevinFang
– zoe
Nov 29 '18 at 1:16
Ha! Brilliant! I have been stuck on this for a couple of hours....I knew it would be a one liner. Thanks @KevinFang
– zoe
Nov 29 '18 at 1:16
add a comment |
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