How to reference and modify a std::unique_ptr's underlying value in another function?
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I am trying to modify the value within a unique_ptr, but inside another function which doesn't actually own the unique_ptr, as follows:
void my_func(Foo* foo) {
foo->set_bar("a");
}
int main() {
auto foo = std::MakeUnique<Foo>();
my_func(foo.get());
cout << foo->bar;
}
I thought this would work, except I'm met with an error complaining of a deleted constructor. Is there a way to make this pattern work?
c++ unique-ptr
add a comment |
I am trying to modify the value within a unique_ptr, but inside another function which doesn't actually own the unique_ptr, as follows:
void my_func(Foo* foo) {
foo->set_bar("a");
}
int main() {
auto foo = std::MakeUnique<Foo>();
my_func(foo.get());
cout << foo->bar;
}
I thought this would work, except I'm met with an error complaining of a deleted constructor. Is there a way to make this pattern work?
c++ unique-ptr
what is aMakeUnique
? What is aFoo
? Please post a Minimal, Complete, and Verifiable example
– xaxxon
Nov 29 '18 at 1:33
Inside? That's a pointer. Managed by? That's what the pointer refers to.
– Deduplicator
Nov 29 '18 at 1:41
Once I make the required corrections and fill in the blanks I'm not seeing any problems: ideone.com/zZwgZv . Minimal, Complete, and Verifiable example definitely required.
– user4581301
Nov 29 '18 at 1:45
Unrelated suggestion: If you makemy_func
look more likevoid my_func(const std::unique_ptr<Foo> & foo)
, the ownership offoo
remains clear. Last thing you want is some knucklehead coming along and dropping adelete foo;
somewhere in there.
– user4581301
Nov 29 '18 at 1:51
add a comment |
I am trying to modify the value within a unique_ptr, but inside another function which doesn't actually own the unique_ptr, as follows:
void my_func(Foo* foo) {
foo->set_bar("a");
}
int main() {
auto foo = std::MakeUnique<Foo>();
my_func(foo.get());
cout << foo->bar;
}
I thought this would work, except I'm met with an error complaining of a deleted constructor. Is there a way to make this pattern work?
c++ unique-ptr
I am trying to modify the value within a unique_ptr, but inside another function which doesn't actually own the unique_ptr, as follows:
void my_func(Foo* foo) {
foo->set_bar("a");
}
int main() {
auto foo = std::MakeUnique<Foo>();
my_func(foo.get());
cout << foo->bar;
}
I thought this would work, except I'm met with an error complaining of a deleted constructor. Is there a way to make this pattern work?
c++ unique-ptr
c++ unique-ptr
asked Nov 29 '18 at 1:29
bonnoz05bonnoz05
71
71
what is aMakeUnique
? What is aFoo
? Please post a Minimal, Complete, and Verifiable example
– xaxxon
Nov 29 '18 at 1:33
Inside? That's a pointer. Managed by? That's what the pointer refers to.
– Deduplicator
Nov 29 '18 at 1:41
Once I make the required corrections and fill in the blanks I'm not seeing any problems: ideone.com/zZwgZv . Minimal, Complete, and Verifiable example definitely required.
– user4581301
Nov 29 '18 at 1:45
Unrelated suggestion: If you makemy_func
look more likevoid my_func(const std::unique_ptr<Foo> & foo)
, the ownership offoo
remains clear. Last thing you want is some knucklehead coming along and dropping adelete foo;
somewhere in there.
– user4581301
Nov 29 '18 at 1:51
add a comment |
what is aMakeUnique
? What is aFoo
? Please post a Minimal, Complete, and Verifiable example
– xaxxon
Nov 29 '18 at 1:33
Inside? That's a pointer. Managed by? That's what the pointer refers to.
– Deduplicator
Nov 29 '18 at 1:41
Once I make the required corrections and fill in the blanks I'm not seeing any problems: ideone.com/zZwgZv . Minimal, Complete, and Verifiable example definitely required.
– user4581301
Nov 29 '18 at 1:45
Unrelated suggestion: If you makemy_func
look more likevoid my_func(const std::unique_ptr<Foo> & foo)
, the ownership offoo
remains clear. Last thing you want is some knucklehead coming along and dropping adelete foo;
somewhere in there.
– user4581301
Nov 29 '18 at 1:51
what is a
MakeUnique
? What is a Foo
? Please post a Minimal, Complete, and Verifiable example– xaxxon
Nov 29 '18 at 1:33
what is a
MakeUnique
? What is a Foo
? Please post a Minimal, Complete, and Verifiable example– xaxxon
Nov 29 '18 at 1:33
Inside? That's a pointer. Managed by? That's what the pointer refers to.
– Deduplicator
Nov 29 '18 at 1:41
Inside? That's a pointer. Managed by? That's what the pointer refers to.
– Deduplicator
Nov 29 '18 at 1:41
Once I make the required corrections and fill in the blanks I'm not seeing any problems: ideone.com/zZwgZv . Minimal, Complete, and Verifiable example definitely required.
– user4581301
Nov 29 '18 at 1:45
Once I make the required corrections and fill in the blanks I'm not seeing any problems: ideone.com/zZwgZv . Minimal, Complete, and Verifiable example definitely required.
– user4581301
Nov 29 '18 at 1:45
Unrelated suggestion: If you make
my_func
look more like void my_func(const std::unique_ptr<Foo> & foo)
, the ownership of foo
remains clear. Last thing you want is some knucklehead coming along and dropping a delete foo;
somewhere in there.– user4581301
Nov 29 '18 at 1:51
Unrelated suggestion: If you make
my_func
look more like void my_func(const std::unique_ptr<Foo> & foo)
, the ownership of foo
remains clear. Last thing you want is some knucklehead coming along and dropping a delete foo;
somewhere in there.– user4581301
Nov 29 '18 at 1:51
add a comment |
1 Answer
1
active
oldest
votes
I will assume you are actually using std::make_unique<Foo>()
.
Since it is an error with construction, this is most likely a problem with the Foo
type, not with what you are trying to do with it. Although, it could also stem from the set_bar()
function.
Using std::make_unique<Foo>()
will attempt to use the default constructor (the one with no arguments). It would appear that your Foo
type does not have a default constructor. Although, without the implementation of Foo
at hand, this is just a guess. You need to give std::make_unique<Foo>()
arguments that correspond to one of the defined constructors of Foo 1.
Re: What you are trying to do - this seems like it should work. Although, since it is taking a raw pointer, you should consider doing some nullptr
checks.
1: If there is at least one constructor defined, where one is not the default constructor, the default constructor is deleted.
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I will assume you are actually using std::make_unique<Foo>()
.
Since it is an error with construction, this is most likely a problem with the Foo
type, not with what you are trying to do with it. Although, it could also stem from the set_bar()
function.
Using std::make_unique<Foo>()
will attempt to use the default constructor (the one with no arguments). It would appear that your Foo
type does not have a default constructor. Although, without the implementation of Foo
at hand, this is just a guess. You need to give std::make_unique<Foo>()
arguments that correspond to one of the defined constructors of Foo 1.
Re: What you are trying to do - this seems like it should work. Although, since it is taking a raw pointer, you should consider doing some nullptr
checks.
1: If there is at least one constructor defined, where one is not the default constructor, the default constructor is deleted.
add a comment |
I will assume you are actually using std::make_unique<Foo>()
.
Since it is an error with construction, this is most likely a problem with the Foo
type, not with what you are trying to do with it. Although, it could also stem from the set_bar()
function.
Using std::make_unique<Foo>()
will attempt to use the default constructor (the one with no arguments). It would appear that your Foo
type does not have a default constructor. Although, without the implementation of Foo
at hand, this is just a guess. You need to give std::make_unique<Foo>()
arguments that correspond to one of the defined constructors of Foo 1.
Re: What you are trying to do - this seems like it should work. Although, since it is taking a raw pointer, you should consider doing some nullptr
checks.
1: If there is at least one constructor defined, where one is not the default constructor, the default constructor is deleted.
add a comment |
I will assume you are actually using std::make_unique<Foo>()
.
Since it is an error with construction, this is most likely a problem with the Foo
type, not with what you are trying to do with it. Although, it could also stem from the set_bar()
function.
Using std::make_unique<Foo>()
will attempt to use the default constructor (the one with no arguments). It would appear that your Foo
type does not have a default constructor. Although, without the implementation of Foo
at hand, this is just a guess. You need to give std::make_unique<Foo>()
arguments that correspond to one of the defined constructors of Foo 1.
Re: What you are trying to do - this seems like it should work. Although, since it is taking a raw pointer, you should consider doing some nullptr
checks.
1: If there is at least one constructor defined, where one is not the default constructor, the default constructor is deleted.
I will assume you are actually using std::make_unique<Foo>()
.
Since it is an error with construction, this is most likely a problem with the Foo
type, not with what you are trying to do with it. Although, it could also stem from the set_bar()
function.
Using std::make_unique<Foo>()
will attempt to use the default constructor (the one with no arguments). It would appear that your Foo
type does not have a default constructor. Although, without the implementation of Foo
at hand, this is just a guess. You need to give std::make_unique<Foo>()
arguments that correspond to one of the defined constructors of Foo 1.
Re: What you are trying to do - this seems like it should work. Although, since it is taking a raw pointer, you should consider doing some nullptr
checks.
1: If there is at least one constructor defined, where one is not the default constructor, the default constructor is deleted.
edited Nov 29 '18 at 2:01
Remy Lebeau
342k19267461
342k19267461
answered Nov 29 '18 at 1:53
Bar StoolBar Stool
1735
1735
add a comment |
add a comment |
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what is a
MakeUnique
? What is aFoo
? Please post a Minimal, Complete, and Verifiable example– xaxxon
Nov 29 '18 at 1:33
Inside? That's a pointer. Managed by? That's what the pointer refers to.
– Deduplicator
Nov 29 '18 at 1:41
Once I make the required corrections and fill in the blanks I'm not seeing any problems: ideone.com/zZwgZv . Minimal, Complete, and Verifiable example definitely required.
– user4581301
Nov 29 '18 at 1:45
Unrelated suggestion: If you make
my_func
look more likevoid my_func(const std::unique_ptr<Foo> & foo)
, the ownership offoo
remains clear. Last thing you want is some knucklehead coming along and dropping adelete foo;
somewhere in there.– user4581301
Nov 29 '18 at 1:51