Unique key constraint in sql server for new values in a column
I want to implement unique key constraint on my table for new values, previous data is duplicate
e.g
declare @temp table
(
id int identity,
PolicyNO varchar(30)
)
insert into @temp values('abc')
insert into @temp values('abc')
insert into @temp values('abc')
now I want to add a unique constraints on @temp table. The new record on id=3 or greater will have to be unique and here third record should be restricted for insertion
ALTER TABLE @TEMP
ADD CONSTRAINT Unique_PolicyNo UNIQUE (PolicyNO ) where id>3
some thing like that I am facing trouble in syntax any help will be appreciated.
sql
sql-server tsql unique-constraint edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
add a comment |
I want to implement unique key constraint on my table for new values, previous data is duplicate
e.g
declare @temp table
(
id int identity,
PolicyNO varchar(30)
)
insert into @temp values('abc')
insert into @temp values('abc')
insert into @temp values('abc')
now I want to add a unique constraints on @temp table. The new record on id=3 or greater will have to be unique and here third record should be restricted for insertion
ALTER TABLE @TEMP
ADD CONSTRAINT Unique_PolicyNo UNIQUE (PolicyNO ) where id>3
some thing like that I am facing trouble in syntax any help will be appreciated.
sql
sql-server tsql unique-constraint edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
add a comment |
I want to implement unique key constraint on my table for new values, previous data is duplicate
e.g
declare @temp table
(
id int identity,
PolicyNO varchar(30)
)
insert into @temp values('abc')
insert into @temp values('abc')
insert into @temp values('abc')
now I want to add a unique constraints on @temp table. The new record on id=3 or greater will have to be unique and here third record should be restricted for insertion
ALTER TABLE @TEMP
ADD CONSTRAINT Unique_PolicyNo UNIQUE (PolicyNO ) where id>3
some thing like that I am facing trouble in syntax any help will be appreciated.
sql
sql-server tsql unique-constraint edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
I want to implement unique key constraint on my table for new values, previous data is duplicate
e.g
declare @temp table
(
id int identity,
PolicyNO varchar(30)
)
insert into @temp values('abc')
insert into @temp values('abc')
insert into @temp values('abc')
now I want to add a unique constraints on @temp table. The new record on id=3 or greater will have to be unique and here third record should be restricted for insertion
ALTER TABLE @TEMP
ADD CONSTRAINT Unique_PolicyNo UNIQUE (PolicyNO ) where id>3
some thing like that I am facing trouble in syntax any help will be appreciated.
sql
sql-server tsql unique-constraint sql
sql-server tsql unique-constraint edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
edited Nov 28 '18 at 11:23
gotqn
20.8k32119194
20.8k32119194
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
asked Nov 28 '18 at 11:13
Khayam KhanKhayam Khan
306
306
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Try this:
CREATE TABLE dbo.temp
(
id int identity,
PolicyNO varchar(30)
)
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3
Then try to insert one new value twice.
or
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3 AND PolicyNO IS NOT NULL
in order to allow insertion of null values.
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this:
CREATE TABLE dbo.temp
(
id int identity,
PolicyNO varchar(30)
)
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3
Then try to insert one new value twice.
or
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3 AND PolicyNO IS NOT NULL
in order to allow insertion of null values.
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
add a comment |
Try this:
CREATE TABLE dbo.temp
(
id int identity,
PolicyNO varchar(30)
)
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3
Then try to insert one new value twice.
or
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3 AND PolicyNO IS NOT NULL
in order to allow insertion of null values.
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
add a comment |
Try this:
CREATE TABLE dbo.temp
(
id int identity,
PolicyNO varchar(30)
)
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3
Then try to insert one new value twice.
or
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3 AND PolicyNO IS NOT NULL
in order to allow insertion of null values.
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
Try this:
CREATE TABLE dbo.temp
(
id int identity,
PolicyNO varchar(30)
)
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
insert into dbo.temp values('abc')
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3
Then try to insert one new value twice.
or
CREATE UNIQUE NONCLUSTERED INDEX [IX__tem]
ON dbo.temp (PolicyNO)
WHERE id>3 AND PolicyNO IS NOT NULL
in order to allow insertion of null values.
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
edited Nov 28 '18 at 12:16
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
answered Nov 28 '18 at 11:22
gotqngotqn
20.8k32119194
20.8k32119194
add a comment |
add a comment |
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