how to capture group within capture group?
0
for example, string:
bla bla bla (bla oops bla
bla bla bla
bla bla bla) bla oops
bla bla bla
oops bla (bla bla oops
bla)
how i can get 'oops' between brackets?
first, i get text between brackets:
(?<=()([wW]*?)(?=))
can i in the same regex capture group within capture group (find 'oops' within capture group)?
regex pcre
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
|
show 2 more comments
0
for example, string:
bla bla bla (bla oops bla
bla bla bla
bla bla bla) bla oops
bla bla bla
oops bla (bla bla oops
bla)
how i can get 'oops' between brackets?
first, i get text between brackets:
(?<=()([wW]*?)(?=))
can i in the same regex capture group within capture group (find 'oops' within capture group)?
regex pcre
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
If you have PHP,([^()]*Koops(?=[^()]*)). In .NET,(?<=([^()]*)oops(?=[^()]*)).
– Wiktor Stribiżew
Nov 27 '18 at 17:31
See stackoverflow.com/questions/23342679/…, too
– Wiktor Stribiżew
Nov 27 '18 at 17:34
Eventually, a lot depends on what you need to get in the end (usually, extract or replace).
– Wiktor Stribiżew
Nov 27 '18 at 17:46
What is the language?
– JohnyL
Nov 27 '18 at 19:58
@WiktorStribiżew thank you so much for php-regex!!!!!!!!! Now I understand howKworks.
– Alexander
Nov 28 '18 at 4:28
|
show 2 more comments
0
0
0
for example, string:
bla bla bla (bla oops bla
bla bla bla
bla bla bla) bla oops
bla bla bla
oops bla (bla bla oops
bla)
how i can get 'oops' between brackets?
first, i get text between brackets:
(?<=()([wW]*?)(?=))
can i in the same regex capture group within capture group (find 'oops' within capture group)?
regex pcre
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
for example, string:
bla bla bla (bla oops bla
bla bla bla
bla bla bla) bla oops
bla bla bla
oops bla (bla bla oops
bla)
how i can get 'oops' between brackets?
first, i get text between brackets:
(?<=()([wW]*?)(?=))
can i in the same regex capture group within capture group (find 'oops' within capture group)?
regex pcre
regex pcre
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
edited Nov 28 '18 at 8:17
Wiktor Stribiżew
321k16141223
321k16141223
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
asked Nov 27 '18 at 17:30
AlexanderAlexander
255
255
If you have PHP,([^()]*Koops(?=[^()]*)). In .NET,(?<=([^()]*)oops(?=[^()]*)).
– Wiktor Stribiżew
Nov 27 '18 at 17:31
See stackoverflow.com/questions/23342679/…, too
– Wiktor Stribiżew
Nov 27 '18 at 17:34
Eventually, a lot depends on what you need to get in the end (usually, extract or replace).
– Wiktor Stribiżew
Nov 27 '18 at 17:46
What is the language?
– JohnyL
Nov 27 '18 at 19:58
@WiktorStribiżew thank you so much for php-regex!!!!!!!!! Now I understand howKworks.
– Alexander
Nov 28 '18 at 4:28
|
show 2 more comments
If you have PHP,([^()]*Koops(?=[^()]*)). In .NET,(?<=([^()]*)oops(?=[^()]*)).
– Wiktor Stribiżew
Nov 27 '18 at 17:31
See stackoverflow.com/questions/23342679/…, too
– Wiktor Stribiżew
Nov 27 '18 at 17:34
Eventually, a lot depends on what you need to get in the end (usually, extract or replace).
– Wiktor Stribiżew
Nov 27 '18 at 17:46
What is the language?
– JohnyL
Nov 27 '18 at 19:58
@WiktorStribiżew thank you so much for php-regex!!!!!!!!! Now I understand howKworks.
– Alexander
Nov 28 '18 at 4:28
If you have PHP,
([^()]*Koops(?=[^()]*)). In .NET, (?<=([^()]*)oops(?=[^()]*)).– Wiktor Stribiżew
Nov 27 '18 at 17:31
If you have PHP,
([^()]*Koops(?=[^()]*)). In .NET, (?<=([^()]*)oops(?=[^()]*)).– Wiktor Stribiżew
Nov 27 '18 at 17:31
See stackoverflow.com/questions/23342679/…, too
– Wiktor Stribiżew
Nov 27 '18 at 17:34
See stackoverflow.com/questions/23342679/…, too
– Wiktor Stribiżew
Nov 27 '18 at 17:34
Eventually, a lot depends on what you need to get in the end (usually, extract or replace).
– Wiktor Stribiżew
Nov 27 '18 at 17:46
Eventually, a lot depends on what you need to get in the end (usually, extract or replace).
– Wiktor Stribiżew
Nov 27 '18 at 17:46
What is the language?
– JohnyL
Nov 27 '18 at 19:58
What is the language?
– JohnyL
Nov 27 '18 at 19:58
@WiktorStribiżew thank you so much for php-regex!!!!!!!!! Now I understand how
K works.– Alexander
Nov 28 '18 at 4:28
@WiktorStribiżew thank you so much for php-regex!!!!!!!!! Now I understand how
K works.– Alexander
Nov 28 '18 at 4:28
|
show 2 more comments
2 Answers
2
active
oldest
votes
1
You may use
(?:G(?!A)|()[^()]*?Koops
Or, if you must check for the closing parentheses, add a lookahead at the end:
(?:G(?!A)|()[^()]*?Koops(?=[^()]*))
See the regex demo.
Details
(?:G(?!A)|()-(or end of the previous match (G(?!A))
[^()]*?- any 0+ chars other than(and)
K- match reset operator
oops- the word you need (wrap withbif you need a whole word match)
(?=[^()]*))- a positive lookahead that requires 0+ chars other than(and)up to the first)to appear immediately to the right of the current location.
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
thank you very much. You made me study regular espressions in more detail. thanks again.
– Alexander
Nov 28 '18 at 8:39
add a comment |
0
You can use the following regex:
(?<=()([wW]*?(oops)[wW]*?)(?=))
Basically it injects a Group looking for 'oops' then it doubles the '[wW]*?' matching both before and after the captured Group.
Now 'oops' will be in Group 2.
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You may use
(?:G(?!A)|()[^()]*?Koops
Or, if you must check for the closing parentheses, add a lookahead at the end:
(?:G(?!A)|()[^()]*?Koops(?=[^()]*))
See the regex demo.
Details
(?:G(?!A)|()-(or end of the previous match (G(?!A))
[^()]*?- any 0+ chars other than(and)
K- match reset operator
oops- the word you need (wrap withbif you need a whole word match)
(?=[^()]*))- a positive lookahead that requires 0+ chars other than(and)up to the first)to appear immediately to the right of the current location.
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
thank you very much. You made me study regular espressions in more detail. thanks again.
– Alexander
Nov 28 '18 at 8:39
add a comment |
1
You may use
(?:G(?!A)|()[^()]*?Koops
Or, if you must check for the closing parentheses, add a lookahead at the end:
(?:G(?!A)|()[^()]*?Koops(?=[^()]*))
See the regex demo.
Details
(?:G(?!A)|()-(or end of the previous match (G(?!A))
[^()]*?- any 0+ chars other than(and)
K- match reset operator
oops- the word you need (wrap withbif you need a whole word match)
(?=[^()]*))- a positive lookahead that requires 0+ chars other than(and)up to the first)to appear immediately to the right of the current location.
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
thank you very much. You made me study regular espressions in more detail. thanks again.
– Alexander
Nov 28 '18 at 8:39
add a comment |
1
1
1
You may use
(?:G(?!A)|()[^()]*?Koops
Or, if you must check for the closing parentheses, add a lookahead at the end:
(?:G(?!A)|()[^()]*?Koops(?=[^()]*))
See the regex demo.
Details
(?:G(?!A)|()-(or end of the previous match (G(?!A))
[^()]*?- any 0+ chars other than(and)
K- match reset operator
oops- the word you need (wrap withbif you need a whole word match)
(?=[^()]*))- a positive lookahead that requires 0+ chars other than(and)up to the first)to appear immediately to the right of the current location.
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
You may use
(?:G(?!A)|()[^()]*?Koops
Or, if you must check for the closing parentheses, add a lookahead at the end:
(?:G(?!A)|()[^()]*?Koops(?=[^()]*))
See the regex demo.
Details
(?:G(?!A)|()-(or end of the previous match (G(?!A))
[^()]*?- any 0+ chars other than(and)
K- match reset operator
oops- the word you need (wrap withbif you need a whole word match)
(?=[^()]*))- a positive lookahead that requires 0+ chars other than(and)up to the first)to appear immediately to the right of the current location.
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
answered Nov 28 '18 at 8:15
Wiktor StribiżewWiktor Stribiżew
321k16141223
321k16141223
thank you very much. You made me study regular espressions in more detail. thanks again.
– Alexander
Nov 28 '18 at 8:39
add a comment |
thank you very much. You made me study regular espressions in more detail. thanks again.
– Alexander
Nov 28 '18 at 8:39
thank you very much. You made me study regular espressions in more detail. thanks again.
– Alexander
Nov 28 '18 at 8:39
thank you very much. You made me study regular espressions in more detail. thanks again.
– Alexander
Nov 28 '18 at 8:39
add a comment |
0
You can use the following regex:
(?<=()([wW]*?(oops)[wW]*?)(?=))
Basically it injects a Group looking for 'oops' then it doubles the '[wW]*?' matching both before and after the captured Group.
Now 'oops' will be in Group 2.
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
add a comment |
0
You can use the following regex:
(?<=()([wW]*?(oops)[wW]*?)(?=))
Basically it injects a Group looking for 'oops' then it doubles the '[wW]*?' matching both before and after the captured Group.
Now 'oops' will be in Group 2.
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
add a comment |
0
0
0
You can use the following regex:
(?<=()([wW]*?(oops)[wW]*?)(?=))
Basically it injects a Group looking for 'oops' then it doubles the '[wW]*?' matching both before and after the captured Group.
Now 'oops' will be in Group 2.
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
You can use the following regex:
(?<=()([wW]*?(oops)[wW]*?)(?=))
Basically it injects a Group looking for 'oops' then it doubles the '[wW]*?' matching both before and after the captured Group.
Now 'oops' will be in Group 2.
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
answered Nov 27 '18 at 17:39
Poul BakPoul Bak
5,48831233
5,48831233
add a comment |
add a comment |
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If you have PHP,
([^()]*Koops(?=[^()]*)). In .NET,(?<=([^()]*)oops(?=[^()]*)).– Wiktor Stribiżew
Nov 27 '18 at 17:31
See stackoverflow.com/questions/23342679/…, too
– Wiktor Stribiżew
Nov 27 '18 at 17:34
Eventually, a lot depends on what you need to get in the end (usually, extract or replace).
– Wiktor Stribiżew
Nov 27 '18 at 17:46
What is the language?
– JohnyL
Nov 27 '18 at 19:58
@WiktorStribiżew thank you so much for php-regex!!!!!!!!! Now I understand how
Kworks.– Alexander
Nov 28 '18 at 4:28