Numpy array function returns inconsistent shapes












2















I'm trying to define a simple function ddf() that outputs the Hessian matrix of a particular mathematical function, given a 2D vector, x as the input :



import numpy as np

def ddf(x):
dd11 = 2*x[1]+8
dd12 = 2*x[0]-8*x[1]-8
dd21 = 2*x[0]-8*x[1]-8
dd22 = -8*x[0]+2
return np.array([[dd11, dd12], [dd21, dd22]])

x0 = np.zeros((2,1))
G = ddf(x0)
print(G)


I expect the output to be a 2x2 square array/matrix, however it yields what appears to be a 4x1 column instead.
Stranger still, using



G.shape


yields (2L, 2L, 1L), not (2L,2L) as expected.
My objective is to obtain G in 2x2 form. Can anyone assist? Thanks










share|improve this question





























    2















    I'm trying to define a simple function ddf() that outputs the Hessian matrix of a particular mathematical function, given a 2D vector, x as the input :



    import numpy as np

    def ddf(x):
    dd11 = 2*x[1]+8
    dd12 = 2*x[0]-8*x[1]-8
    dd21 = 2*x[0]-8*x[1]-8
    dd22 = -8*x[0]+2
    return np.array([[dd11, dd12], [dd21, dd22]])

    x0 = np.zeros((2,1))
    G = ddf(x0)
    print(G)


    I expect the output to be a 2x2 square array/matrix, however it yields what appears to be a 4x1 column instead.
    Stranger still, using



    G.shape


    yields (2L, 2L, 1L), not (2L,2L) as expected.
    My objective is to obtain G in 2x2 form. Can anyone assist? Thanks










    share|improve this question



























      2












      2








      2








      I'm trying to define a simple function ddf() that outputs the Hessian matrix of a particular mathematical function, given a 2D vector, x as the input :



      import numpy as np

      def ddf(x):
      dd11 = 2*x[1]+8
      dd12 = 2*x[0]-8*x[1]-8
      dd21 = 2*x[0]-8*x[1]-8
      dd22 = -8*x[0]+2
      return np.array([[dd11, dd12], [dd21, dd22]])

      x0 = np.zeros((2,1))
      G = ddf(x0)
      print(G)


      I expect the output to be a 2x2 square array/matrix, however it yields what appears to be a 4x1 column instead.
      Stranger still, using



      G.shape


      yields (2L, 2L, 1L), not (2L,2L) as expected.
      My objective is to obtain G in 2x2 form. Can anyone assist? Thanks










      share|improve this question
















      I'm trying to define a simple function ddf() that outputs the Hessian matrix of a particular mathematical function, given a 2D vector, x as the input :



      import numpy as np

      def ddf(x):
      dd11 = 2*x[1]+8
      dd12 = 2*x[0]-8*x[1]-8
      dd21 = 2*x[0]-8*x[1]-8
      dd22 = -8*x[0]+2
      return np.array([[dd11, dd12], [dd21, dd22]])

      x0 = np.zeros((2,1))
      G = ddf(x0)
      print(G)


      I expect the output to be a 2x2 square array/matrix, however it yields what appears to be a 4x1 column instead.
      Stranger still, using



      G.shape


      yields (2L, 2L, 1L), not (2L,2L) as expected.
      My objective is to obtain G in 2x2 form. Can anyone assist? Thanks







      python numpy






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 24 '18 at 15:12









      Deepak Saini

      1,582814




      1,582814










      asked Nov 24 '18 at 12:50









      ruphzruphz

      111




      111
























          2 Answers
          2






          active

          oldest

          votes


















          1














          Your input to the function ddf() is a 2x1 matrix, meaning all of x[0] and x[1] are vectors not scalers(floats or ints). So each element of your output matrix are 1-sized vectors, as all operations in numpy are applied elements wise if arrays are passed to the functions.
          Couple of things, you can do :




          • It seems that you expect x[0], x[1] to be scalars, so change the input to shape (2,) in x0 = np.zeros((2,)).

          • Or reshape the output as G.reshape((2,2)) to remove the extra dimension.






          share|improve this answer































            1














            I'm very new to python, but I think that will work:



            ...
            G = ddf(x0)
            G = np.reshape(G, (2,2))
            print(G)


            It yields a (2,2) as you wanted.






            share|improve this answer


























            • It does indeed, thank you very much. I also found that reshaping the 2x1 vector (x) as a 1x2 vector does the job

              – ruphz
              Nov 24 '18 at 13:06











            Your Answer






            StackExchange.ifUsing("editor", function () {
            StackExchange.using("externalEditor", function () {
            StackExchange.using("snippets", function () {
            StackExchange.snippets.init();
            });
            });
            }, "code-snippets");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "1"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53458326%2fnumpy-array-function-returns-inconsistent-shapes%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            Your input to the function ddf() is a 2x1 matrix, meaning all of x[0] and x[1] are vectors not scalers(floats or ints). So each element of your output matrix are 1-sized vectors, as all operations in numpy are applied elements wise if arrays are passed to the functions.
            Couple of things, you can do :




            • It seems that you expect x[0], x[1] to be scalars, so change the input to shape (2,) in x0 = np.zeros((2,)).

            • Or reshape the output as G.reshape((2,2)) to remove the extra dimension.






            share|improve this answer




























              1














              Your input to the function ddf() is a 2x1 matrix, meaning all of x[0] and x[1] are vectors not scalers(floats or ints). So each element of your output matrix are 1-sized vectors, as all operations in numpy are applied elements wise if arrays are passed to the functions.
              Couple of things, you can do :




              • It seems that you expect x[0], x[1] to be scalars, so change the input to shape (2,) in x0 = np.zeros((2,)).

              • Or reshape the output as G.reshape((2,2)) to remove the extra dimension.






              share|improve this answer


























                1












                1








                1







                Your input to the function ddf() is a 2x1 matrix, meaning all of x[0] and x[1] are vectors not scalers(floats or ints). So each element of your output matrix are 1-sized vectors, as all operations in numpy are applied elements wise if arrays are passed to the functions.
                Couple of things, you can do :




                • It seems that you expect x[0], x[1] to be scalars, so change the input to shape (2,) in x0 = np.zeros((2,)).

                • Or reshape the output as G.reshape((2,2)) to remove the extra dimension.






                share|improve this answer













                Your input to the function ddf() is a 2x1 matrix, meaning all of x[0] and x[1] are vectors not scalers(floats or ints). So each element of your output matrix are 1-sized vectors, as all operations in numpy are applied elements wise if arrays are passed to the functions.
                Couple of things, you can do :




                • It seems that you expect x[0], x[1] to be scalars, so change the input to shape (2,) in x0 = np.zeros((2,)).

                • Or reshape the output as G.reshape((2,2)) to remove the extra dimension.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 24 '18 at 13:08









                Deepak SainiDeepak Saini

                1,582814




                1,582814

























                    1














                    I'm very new to python, but I think that will work:



                    ...
                    G = ddf(x0)
                    G = np.reshape(G, (2,2))
                    print(G)


                    It yields a (2,2) as you wanted.






                    share|improve this answer


























                    • It does indeed, thank you very much. I also found that reshaping the 2x1 vector (x) as a 1x2 vector does the job

                      – ruphz
                      Nov 24 '18 at 13:06
















                    1














                    I'm very new to python, but I think that will work:



                    ...
                    G = ddf(x0)
                    G = np.reshape(G, (2,2))
                    print(G)


                    It yields a (2,2) as you wanted.






                    share|improve this answer


























                    • It does indeed, thank you very much. I also found that reshaping the 2x1 vector (x) as a 1x2 vector does the job

                      – ruphz
                      Nov 24 '18 at 13:06














                    1












                    1








                    1







                    I'm very new to python, but I think that will work:



                    ...
                    G = ddf(x0)
                    G = np.reshape(G, (2,2))
                    print(G)


                    It yields a (2,2) as you wanted.






                    share|improve this answer















                    I'm very new to python, but I think that will work:



                    ...
                    G = ddf(x0)
                    G = np.reshape(G, (2,2))
                    print(G)


                    It yields a (2,2) as you wanted.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 24 '18 at 13:10

























                    answered Nov 24 '18 at 12:59









                    SlightlySarcasticSlightlySarcastic

                    114




                    114













                    • It does indeed, thank you very much. I also found that reshaping the 2x1 vector (x) as a 1x2 vector does the job

                      – ruphz
                      Nov 24 '18 at 13:06



















                    • It does indeed, thank you very much. I also found that reshaping the 2x1 vector (x) as a 1x2 vector does the job

                      – ruphz
                      Nov 24 '18 at 13:06

















                    It does indeed, thank you very much. I also found that reshaping the 2x1 vector (x) as a 1x2 vector does the job

                    – ruphz
                    Nov 24 '18 at 13:06





                    It does indeed, thank you very much. I also found that reshaping the 2x1 vector (x) as a 1x2 vector does the job

                    – ruphz
                    Nov 24 '18 at 13:06


















                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Stack Overflow!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53458326%2fnumpy-array-function-returns-inconsistent-shapes%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    A CLEAN and SIMPLE way to add appendices to Table of Contents and bookmarks

                    Calculate evaluation metrics using cross_val_predict sklearn

                    Insert data from modal to MySQL (multiple modal on website)