Why it only realize the last instance when using python singleton pattern












0














the code is in belows:



class A(object):
__instance = None

def __new__(cls, *args, **kwargs):
if cls.__instance is None:
cls.__instance = object.__new__(cls)
return cls.__instance
else:
return cls.__instance

def __init__(self, book):
self.book = book

def pr(self):
print(self.book)


if __name__ == "__main__":
b = A("wind")
a = A("good")
print(a is b)
print(a.pr())
print(b.pr())


the result is



True
good
None
good
None

why the result is not:


True
wind
good


where is wrong with the code?










share|improve this question
























  • It a is b how should pr() return different values?
    – Klaus D.
    Nov 23 at 2:51










  • The wind is the first instance. Why it not True wind wind,
    – littlely
    Nov 23 at 2:56
















0














the code is in belows:



class A(object):
__instance = None

def __new__(cls, *args, **kwargs):
if cls.__instance is None:
cls.__instance = object.__new__(cls)
return cls.__instance
else:
return cls.__instance

def __init__(self, book):
self.book = book

def pr(self):
print(self.book)


if __name__ == "__main__":
b = A("wind")
a = A("good")
print(a is b)
print(a.pr())
print(b.pr())


the result is



True
good
None
good
None

why the result is not:


True
wind
good


where is wrong with the code?










share|improve this question
























  • It a is b how should pr() return different values?
    – Klaus D.
    Nov 23 at 2:51










  • The wind is the first instance. Why it not True wind wind,
    – littlely
    Nov 23 at 2:56














0












0








0







the code is in belows:



class A(object):
__instance = None

def __new__(cls, *args, **kwargs):
if cls.__instance is None:
cls.__instance = object.__new__(cls)
return cls.__instance
else:
return cls.__instance

def __init__(self, book):
self.book = book

def pr(self):
print(self.book)


if __name__ == "__main__":
b = A("wind")
a = A("good")
print(a is b)
print(a.pr())
print(b.pr())


the result is



True
good
None
good
None

why the result is not:


True
wind
good


where is wrong with the code?










share|improve this question















the code is in belows:



class A(object):
__instance = None

def __new__(cls, *args, **kwargs):
if cls.__instance is None:
cls.__instance = object.__new__(cls)
return cls.__instance
else:
return cls.__instance

def __init__(self, book):
self.book = book

def pr(self):
print(self.book)


if __name__ == "__main__":
b = A("wind")
a = A("good")
print(a is b)
print(a.pr())
print(b.pr())


the result is



True
good
None
good
None

why the result is not:


True
wind
good


where is wrong with the code?







python singleton






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 23 at 2:57

























asked Nov 23 at 2:43









littlely

216313




216313












  • It a is b how should pr() return different values?
    – Klaus D.
    Nov 23 at 2:51










  • The wind is the first instance. Why it not True wind wind,
    – littlely
    Nov 23 at 2:56


















  • It a is b how should pr() return different values?
    – Klaus D.
    Nov 23 at 2:51










  • The wind is the first instance. Why it not True wind wind,
    – littlely
    Nov 23 at 2:56
















It a is b how should pr() return different values?
– Klaus D.
Nov 23 at 2:51




It a is b how should pr() return different values?
– Klaus D.
Nov 23 at 2:51












The wind is the first instance. Why it not True wind wind,
– littlely
Nov 23 at 2:56




The wind is the first instance. Why it not True wind wind,
– littlely
Nov 23 at 2:56












1 Answer
1






active

oldest

votes


















2














for each time of call A(), its __init__ will be invoked, as it is a singleton, the __init__() method invoked twice on the same object.
you could get your expected result with:



b = A("wind")
b.pr()
a = A("good")
a.pr()
print(a is b)





share|improve this answer





















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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    for each time of call A(), its __init__ will be invoked, as it is a singleton, the __init__() method invoked twice on the same object.
    you could get your expected result with:



    b = A("wind")
    b.pr()
    a = A("good")
    a.pr()
    print(a is b)





    share|improve this answer


























      2














      for each time of call A(), its __init__ will be invoked, as it is a singleton, the __init__() method invoked twice on the same object.
      you could get your expected result with:



      b = A("wind")
      b.pr()
      a = A("good")
      a.pr()
      print(a is b)





      share|improve this answer
























        2












        2








        2






        for each time of call A(), its __init__ will be invoked, as it is a singleton, the __init__() method invoked twice on the same object.
        you could get your expected result with:



        b = A("wind")
        b.pr()
        a = A("good")
        a.pr()
        print(a is b)





        share|improve this answer












        for each time of call A(), its __init__ will be invoked, as it is a singleton, the __init__() method invoked twice on the same object.
        you could get your expected result with:



        b = A("wind")
        b.pr()
        a = A("good")
        a.pr()
        print(a is b)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 23 at 3:57









        georgexsh

        10.1k11136




        10.1k11136






























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