Check if a div content contain a word from an array and replace it












0














I want to check if a div's contents contains a word from an array and add some tags like <b></b> to that word.



Here is my code:






var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
$( ".mystr" ).each(function() {
mystr = $( this ).html();
if (fruits.some(function(v) { return mystr.indexOf(v) >= 0; })) {
// get the fruit and replace it with <b>thefruit</b>
//and print it in a div
//"<div class='mynewstr'></div>"
}


});

<div class='container'>

<div class='mystr'>I love apple </div>
<div class='mystr'>I don't like banana</div>
<div class='mystr'>I don't like peach</div>
<div class='mystr'>I like both grappe and lemon</div>





</div>





for exemple for



<div class='mystr'>I love apple </div>


must become



<div class='mynewstr'>I love <b>apple</b></div>


Any Idea ?










share|improve this question





























    0














    I want to check if a div's contents contains a word from an array and add some tags like <b></b> to that word.



    Here is my code:






    var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
    $( ".mystr" ).each(function() {
    mystr = $( this ).html();
    if (fruits.some(function(v) { return mystr.indexOf(v) >= 0; })) {
    // get the fruit and replace it with <b>thefruit</b>
    //and print it in a div
    //"<div class='mynewstr'></div>"
    }


    });

    <div class='container'>

    <div class='mystr'>I love apple </div>
    <div class='mystr'>I don't like banana</div>
    <div class='mystr'>I don't like peach</div>
    <div class='mystr'>I like both grappe and lemon</div>





    </div>





    for exemple for



    <div class='mystr'>I love apple </div>


    must become



    <div class='mynewstr'>I love <b>apple</b></div>


    Any Idea ?










    share|improve this question



























      0












      0








      0







      I want to check if a div's contents contains a word from an array and add some tags like <b></b> to that word.



      Here is my code:






      var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
      $( ".mystr" ).each(function() {
      mystr = $( this ).html();
      if (fruits.some(function(v) { return mystr.indexOf(v) >= 0; })) {
      // get the fruit and replace it with <b>thefruit</b>
      //and print it in a div
      //"<div class='mynewstr'></div>"
      }


      });

      <div class='container'>

      <div class='mystr'>I love apple </div>
      <div class='mystr'>I don't like banana</div>
      <div class='mystr'>I don't like peach</div>
      <div class='mystr'>I like both grappe and lemon</div>





      </div>





      for exemple for



      <div class='mystr'>I love apple </div>


      must become



      <div class='mynewstr'>I love <b>apple</b></div>


      Any Idea ?










      share|improve this question















      I want to check if a div's contents contains a word from an array and add some tags like <b></b> to that word.



      Here is my code:






      var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
      $( ".mystr" ).each(function() {
      mystr = $( this ).html();
      if (fruits.some(function(v) { return mystr.indexOf(v) >= 0; })) {
      // get the fruit and replace it with <b>thefruit</b>
      //and print it in a div
      //"<div class='mynewstr'></div>"
      }


      });

      <div class='container'>

      <div class='mystr'>I love apple </div>
      <div class='mystr'>I don't like banana</div>
      <div class='mystr'>I don't like peach</div>
      <div class='mystr'>I like both grappe and lemon</div>





      </div>





      for exemple for



      <div class='mystr'>I love apple </div>


      must become



      <div class='mynewstr'>I love <b>apple</b></div>


      Any Idea ?






      var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
      $( ".mystr" ).each(function() {
      mystr = $( this ).html();
      if (fruits.some(function(v) { return mystr.indexOf(v) >= 0; })) {
      // get the fruit and replace it with <b>thefruit</b>
      //and print it in a div
      //"<div class='mynewstr'></div>"
      }


      });

      <div class='container'>

      <div class='mystr'>I love apple </div>
      <div class='mystr'>I don't like banana</div>
      <div class='mystr'>I don't like peach</div>
      <div class='mystr'>I like both grappe and lemon</div>





      </div>





      var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
      $( ".mystr" ).each(function() {
      mystr = $( this ).html();
      if (fruits.some(function(v) { return mystr.indexOf(v) >= 0; })) {
      // get the fruit and replace it with <b>thefruit</b>
      //and print it in a div
      //"<div class='mynewstr'></div>"
      }


      });

      <div class='container'>

      <div class='mystr'>I love apple </div>
      <div class='mystr'>I don't like banana</div>
      <div class='mystr'>I don't like peach</div>
      <div class='mystr'>I like both grappe and lemon</div>





      </div>






      javascript jquery arrays contains






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 23 at 3:54









      A J

      5341319




      5341319










      asked Nov 23 at 2:42









      mehdi

      247




      247
























          2 Answers
          2






          active

          oldest

          votes


















          1














          This might not be the most performant solution since it is iterating all fruits for each string, but if your fruits and .mystr set is not super big it should not be a problem:



          var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          $( ".mystr" ).each(function() {
          mystr = $( this ).html();
          fruits.forEach(f => {
          mystr = mystr.replace(f,`<b>${f}</b>`, 'g')
          })
          $( this ).html(mystr)
          });


          Here's a codepen with it working
          https://codepen.io/ederdiaz/pen/QJmmvg






          share|improve this answer





















          • yes EderChrono, unfortunately my fruit table is quite big.
            – mehdi
            Nov 23 at 11:14



















          3














          One option would be to join the fruits into a global regular expression (which will match any fruit substring), and then .replace the html() of every .mystr div with <b></b>s surrounding the fruit words:






          const fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          const pattern = new RegExp(fruits.join('|'), 'g');
          $(".mystr").each(function() {
          $(this).html(
          $(this).html().replace(pattern, '<b>$&</b>')
          );
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class='container'>

          <div class='mystr'>I love apple </div>
          <div class='mystr'>I don't like banana</div>
          <div class='mystr'>I don't like peach</div>
          <div class='mystr'>I like both grappe and lemon</div>
          </div>





          (note that $& in a replacement string gets replaced with the entire matched substring for that match)






          share|improve this answer





















          • Thank you for your reply, your solution is working as expected but is it ok if you know that in reality my fruit table may contain more than 4000 entry ?
            – mehdi
            Nov 23 at 11:11










          • I think it'll still work, though if you're working with that much data, it might take a bit longer than expected. Also, for something like this, you should consider fixing it server-side rather than client-side, I think, if it takes up any significant CPU time
            – CertainPerformance
            Nov 23 at 19:30










          • Did it work for you? When an answer solves the problem you're having, consider marking it as Accepted to indicate that the issue is resolved :)
            – CertainPerformance
            Nov 24 at 10:27











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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          This might not be the most performant solution since it is iterating all fruits for each string, but if your fruits and .mystr set is not super big it should not be a problem:



          var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          $( ".mystr" ).each(function() {
          mystr = $( this ).html();
          fruits.forEach(f => {
          mystr = mystr.replace(f,`<b>${f}</b>`, 'g')
          })
          $( this ).html(mystr)
          });


          Here's a codepen with it working
          https://codepen.io/ederdiaz/pen/QJmmvg






          share|improve this answer





















          • yes EderChrono, unfortunately my fruit table is quite big.
            – mehdi
            Nov 23 at 11:14
















          1














          This might not be the most performant solution since it is iterating all fruits for each string, but if your fruits and .mystr set is not super big it should not be a problem:



          var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          $( ".mystr" ).each(function() {
          mystr = $( this ).html();
          fruits.forEach(f => {
          mystr = mystr.replace(f,`<b>${f}</b>`, 'g')
          })
          $( this ).html(mystr)
          });


          Here's a codepen with it working
          https://codepen.io/ederdiaz/pen/QJmmvg






          share|improve this answer





















          • yes EderChrono, unfortunately my fruit table is quite big.
            – mehdi
            Nov 23 at 11:14














          1












          1








          1






          This might not be the most performant solution since it is iterating all fruits for each string, but if your fruits and .mystr set is not super big it should not be a problem:



          var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          $( ".mystr" ).each(function() {
          mystr = $( this ).html();
          fruits.forEach(f => {
          mystr = mystr.replace(f,`<b>${f}</b>`, 'g')
          })
          $( this ).html(mystr)
          });


          Here's a codepen with it working
          https://codepen.io/ederdiaz/pen/QJmmvg






          share|improve this answer












          This might not be the most performant solution since it is iterating all fruits for each string, but if your fruits and .mystr set is not super big it should not be a problem:



          var fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          $( ".mystr" ).each(function() {
          mystr = $( this ).html();
          fruits.forEach(f => {
          mystr = mystr.replace(f,`<b>${f}</b>`, 'g')
          })
          $( this ).html(mystr)
          });


          Here's a codepen with it working
          https://codepen.io/ederdiaz/pen/QJmmvg







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 23 at 3:01









          EderChrono

          1847




          1847












          • yes EderChrono, unfortunately my fruit table is quite big.
            – mehdi
            Nov 23 at 11:14


















          • yes EderChrono, unfortunately my fruit table is quite big.
            – mehdi
            Nov 23 at 11:14
















          yes EderChrono, unfortunately my fruit table is quite big.
          – mehdi
          Nov 23 at 11:14




          yes EderChrono, unfortunately my fruit table is quite big.
          – mehdi
          Nov 23 at 11:14













          3














          One option would be to join the fruits into a global regular expression (which will match any fruit substring), and then .replace the html() of every .mystr div with <b></b>s surrounding the fruit words:






          const fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          const pattern = new RegExp(fruits.join('|'), 'g');
          $(".mystr").each(function() {
          $(this).html(
          $(this).html().replace(pattern, '<b>$&</b>')
          );
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class='container'>

          <div class='mystr'>I love apple </div>
          <div class='mystr'>I don't like banana</div>
          <div class='mystr'>I don't like peach</div>
          <div class='mystr'>I like both grappe and lemon</div>
          </div>





          (note that $& in a replacement string gets replaced with the entire matched substring for that match)






          share|improve this answer





















          • Thank you for your reply, your solution is working as expected but is it ok if you know that in reality my fruit table may contain more than 4000 entry ?
            – mehdi
            Nov 23 at 11:11










          • I think it'll still work, though if you're working with that much data, it might take a bit longer than expected. Also, for something like this, you should consider fixing it server-side rather than client-side, I think, if it takes up any significant CPU time
            – CertainPerformance
            Nov 23 at 19:30










          • Did it work for you? When an answer solves the problem you're having, consider marking it as Accepted to indicate that the issue is resolved :)
            – CertainPerformance
            Nov 24 at 10:27
















          3














          One option would be to join the fruits into a global regular expression (which will match any fruit substring), and then .replace the html() of every .mystr div with <b></b>s surrounding the fruit words:






          const fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          const pattern = new RegExp(fruits.join('|'), 'g');
          $(".mystr").each(function() {
          $(this).html(
          $(this).html().replace(pattern, '<b>$&</b>')
          );
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class='container'>

          <div class='mystr'>I love apple </div>
          <div class='mystr'>I don't like banana</div>
          <div class='mystr'>I don't like peach</div>
          <div class='mystr'>I like both grappe and lemon</div>
          </div>





          (note that $& in a replacement string gets replaced with the entire matched substring for that match)






          share|improve this answer





















          • Thank you for your reply, your solution is working as expected but is it ok if you know that in reality my fruit table may contain more than 4000 entry ?
            – mehdi
            Nov 23 at 11:11










          • I think it'll still work, though if you're working with that much data, it might take a bit longer than expected. Also, for something like this, you should consider fixing it server-side rather than client-side, I think, if it takes up any significant CPU time
            – CertainPerformance
            Nov 23 at 19:30










          • Did it work for you? When an answer solves the problem you're having, consider marking it as Accepted to indicate that the issue is resolved :)
            – CertainPerformance
            Nov 24 at 10:27














          3












          3








          3






          One option would be to join the fruits into a global regular expression (which will match any fruit substring), and then .replace the html() of every .mystr div with <b></b>s surrounding the fruit words:






          const fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          const pattern = new RegExp(fruits.join('|'), 'g');
          $(".mystr").each(function() {
          $(this).html(
          $(this).html().replace(pattern, '<b>$&</b>')
          );
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class='container'>

          <div class='mystr'>I love apple </div>
          <div class='mystr'>I don't like banana</div>
          <div class='mystr'>I don't like peach</div>
          <div class='mystr'>I like both grappe and lemon</div>
          </div>





          (note that $& in a replacement string gets replaced with the entire matched substring for that match)






          share|improve this answer












          One option would be to join the fruits into a global regular expression (which will match any fruit substring), and then .replace the html() of every .mystr div with <b></b>s surrounding the fruit words:






          const fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          const pattern = new RegExp(fruits.join('|'), 'g');
          $(".mystr").each(function() {
          $(this).html(
          $(this).html().replace(pattern, '<b>$&</b>')
          );
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class='container'>

          <div class='mystr'>I love apple </div>
          <div class='mystr'>I don't like banana</div>
          <div class='mystr'>I don't like peach</div>
          <div class='mystr'>I like both grappe and lemon</div>
          </div>





          (note that $& in a replacement string gets replaced with the entire matched substring for that match)






          const fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          const pattern = new RegExp(fruits.join('|'), 'g');
          $(".mystr").each(function() {
          $(this).html(
          $(this).html().replace(pattern, '<b>$&</b>')
          );
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class='container'>

          <div class='mystr'>I love apple </div>
          <div class='mystr'>I don't like banana</div>
          <div class='mystr'>I don't like peach</div>
          <div class='mystr'>I like both grappe and lemon</div>
          </div>





          const fruits = ["banana", "peach", "grappe", "lemon", "apple"];
          const pattern = new RegExp(fruits.join('|'), 'g');
          $(".mystr").each(function() {
          $(this).html(
          $(this).html().replace(pattern, '<b>$&</b>')
          );
          });

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <div class='container'>

          <div class='mystr'>I love apple </div>
          <div class='mystr'>I don't like banana</div>
          <div class='mystr'>I don't like peach</div>
          <div class='mystr'>I like both grappe and lemon</div>
          </div>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 23 at 2:45









          CertainPerformance

          74.6k143659




          74.6k143659












          • Thank you for your reply, your solution is working as expected but is it ok if you know that in reality my fruit table may contain more than 4000 entry ?
            – mehdi
            Nov 23 at 11:11










          • I think it'll still work, though if you're working with that much data, it might take a bit longer than expected. Also, for something like this, you should consider fixing it server-side rather than client-side, I think, if it takes up any significant CPU time
            – CertainPerformance
            Nov 23 at 19:30










          • Did it work for you? When an answer solves the problem you're having, consider marking it as Accepted to indicate that the issue is resolved :)
            – CertainPerformance
            Nov 24 at 10:27


















          • Thank you for your reply, your solution is working as expected but is it ok if you know that in reality my fruit table may contain more than 4000 entry ?
            – mehdi
            Nov 23 at 11:11










          • I think it'll still work, though if you're working with that much data, it might take a bit longer than expected. Also, for something like this, you should consider fixing it server-side rather than client-side, I think, if it takes up any significant CPU time
            – CertainPerformance
            Nov 23 at 19:30










          • Did it work for you? When an answer solves the problem you're having, consider marking it as Accepted to indicate that the issue is resolved :)
            – CertainPerformance
            Nov 24 at 10:27
















          Thank you for your reply, your solution is working as expected but is it ok if you know that in reality my fruit table may contain more than 4000 entry ?
          – mehdi
          Nov 23 at 11:11




          Thank you for your reply, your solution is working as expected but is it ok if you know that in reality my fruit table may contain more than 4000 entry ?
          – mehdi
          Nov 23 at 11:11












          I think it'll still work, though if you're working with that much data, it might take a bit longer than expected. Also, for something like this, you should consider fixing it server-side rather than client-side, I think, if it takes up any significant CPU time
          – CertainPerformance
          Nov 23 at 19:30




          I think it'll still work, though if you're working with that much data, it might take a bit longer than expected. Also, for something like this, you should consider fixing it server-side rather than client-side, I think, if it takes up any significant CPU time
          – CertainPerformance
          Nov 23 at 19:30












          Did it work for you? When an answer solves the problem you're having, consider marking it as Accepted to indicate that the issue is resolved :)
          – CertainPerformance
          Nov 24 at 10:27




          Did it work for you? When an answer solves the problem you're having, consider marking it as Accepted to indicate that the issue is resolved :)
          – CertainPerformance
          Nov 24 at 10:27


















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