MYSQL query change column value based on the other column value











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I have a MySQL query .I want to set column hours=0 when the sub task is 'PTO'.I tried below query but it is not working as expected.



 select distinct t.hours, t.subtask,
CASE sub task
WHEN 'PTO' THEN t.hours=0
ELSE t.hours
END as subtask
from task t









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    up vote
    1
    down vote

    favorite












    I have a MySQL query .I want to set column hours=0 when the sub task is 'PTO'.I tried below query but it is not working as expected.



     select distinct t.hours, t.subtask,
    CASE sub task
    WHEN 'PTO' THEN t.hours=0
    ELSE t.hours
    END as subtask
    from task t









    share|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I have a MySQL query .I want to set column hours=0 when the sub task is 'PTO'.I tried below query but it is not working as expected.



       select distinct t.hours, t.subtask,
      CASE sub task
      WHEN 'PTO' THEN t.hours=0
      ELSE t.hours
      END as subtask
      from task t









      share|improve this question















      I have a MySQL query .I want to set column hours=0 when the sub task is 'PTO'.I tried below query but it is not working as expected.



       select distinct t.hours, t.subtask,
      CASE sub task
      WHEN 'PTO' THEN t.hours=0
      ELSE t.hours
      END as subtask
      from task t






      mysql






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 22 at 6:27









      CS_noob

      3951211




      3951211










      asked Nov 22 at 6:16









      sandeep.mishra

      34221131




      34221131
























          1 Answer
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          1
          down vote



          accepted










          You can try below



          select distinct t.hours, t.subtask, 
          CASE t.subtask WHEN 'PTO' THEN 0 ELSE t.hours END as updated_subtask
          from task t





          share|improve this answer





















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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            1
            down vote



            accepted










            You can try below



            select distinct t.hours, t.subtask, 
            CASE t.subtask WHEN 'PTO' THEN 0 ELSE t.hours END as updated_subtask
            from task t





            share|improve this answer

























              up vote
              1
              down vote



              accepted










              You can try below



              select distinct t.hours, t.subtask, 
              CASE t.subtask WHEN 'PTO' THEN 0 ELSE t.hours END as updated_subtask
              from task t





              share|improve this answer























                up vote
                1
                down vote



                accepted







                up vote
                1
                down vote



                accepted






                You can try below



                select distinct t.hours, t.subtask, 
                CASE t.subtask WHEN 'PTO' THEN 0 ELSE t.hours END as updated_subtask
                from task t





                share|improve this answer












                You can try below



                select distinct t.hours, t.subtask, 
                CASE t.subtask WHEN 'PTO' THEN 0 ELSE t.hours END as updated_subtask
                from task t






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 22 at 6:19









                fa06

                10.1k1917




                10.1k1917






























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