Command for argmin or argmax?
up vote
176
down vote
favorite
How can you get the argmin or argmax in Latex? Two solutions I found are:
underset{x}{operatorname{argmax}}
DeclareMathOperator*{argmin}{arg,min}
Any other ideas?
[1] http://www.breakthru.altervista.org/?p=27
[2] http://researchonsearch.blogspot.com/2007/05/enter-argmax-argmin-in-latex.html
math-mode symbols math-operators
add a comment |
up vote
176
down vote
favorite
How can you get the argmin or argmax in Latex? Two solutions I found are:
underset{x}{operatorname{argmax}}
DeclareMathOperator*{argmin}{arg,min}
Any other ideas?
[1] http://www.breakthru.altervista.org/?p=27
[2] http://researchonsearch.blogspot.com/2007/05/enter-argmax-argmin-in-latex.html
math-mode symbols math-operators
28
How do these solutions (especially the second) feel not right? TheDeclareMathOperator
is the way to go in this case.
– Pieter
Nov 11 '10 at 17:57
1
Personally, I like the look oftext{arg},maxlimits_{theta},
– Jean-Paul
Sep 7 '16 at 8:11
add a comment |
up vote
176
down vote
favorite
up vote
176
down vote
favorite
How can you get the argmin or argmax in Latex? Two solutions I found are:
underset{x}{operatorname{argmax}}
DeclareMathOperator*{argmin}{arg,min}
Any other ideas?
[1] http://www.breakthru.altervista.org/?p=27
[2] http://researchonsearch.blogspot.com/2007/05/enter-argmax-argmin-in-latex.html
math-mode symbols math-operators
How can you get the argmin or argmax in Latex? Two solutions I found are:
underset{x}{operatorname{argmax}}
DeclareMathOperator*{argmin}{arg,min}
Any other ideas?
[1] http://www.breakthru.altervista.org/?p=27
[2] http://researchonsearch.blogspot.com/2007/05/enter-argmax-argmin-in-latex.html
math-mode symbols math-operators
math-mode symbols math-operators
edited Nov 11 '10 at 18:30
Stefan Kottwitz♦
175k63566756
175k63566756
asked Nov 11 '10 at 17:45
Alejandro
1,31121016
1,31121016
28
How do these solutions (especially the second) feel not right? TheDeclareMathOperator
is the way to go in this case.
– Pieter
Nov 11 '10 at 17:57
1
Personally, I like the look oftext{arg},maxlimits_{theta},
– Jean-Paul
Sep 7 '16 at 8:11
add a comment |
28
How do these solutions (especially the second) feel not right? TheDeclareMathOperator
is the way to go in this case.
– Pieter
Nov 11 '10 at 17:57
1
Personally, I like the look oftext{arg},maxlimits_{theta},
– Jean-Paul
Sep 7 '16 at 8:11
28
28
How do these solutions (especially the second) feel not right? The
DeclareMathOperator
is the way to go in this case.– Pieter
Nov 11 '10 at 17:57
How do these solutions (especially the second) feel not right? The
DeclareMathOperator
is the way to go in this case.– Pieter
Nov 11 '10 at 17:57
1
1
Personally, I like the look of
text{arg},maxlimits_{theta},
– Jean-Paul
Sep 7 '16 at 8:11
Personally, I like the look of
text{arg},maxlimits_{theta},
– Jean-Paul
Sep 7 '16 at 8:11
add a comment |
8 Answers
8
active
oldest
votes
up vote
173
down vote
accepted
As Pieter pointed out, the correct way to define argmin and argmax operators in LaTeX is:
usepackage{amsmath}
DeclareMathOperator*{argmax}{arg,max}
DeclareMathOperator*{argmin}{arg,min}
Actually, using the amsopn
package would be sufficient but it's loaded by amsmath
internally, which is recommended for math typesetting anyway.
The *
in DeclareMathOperator*
places the underscored argument underneath the word rather than to the bottom right of it.
36
If you useDeclareMathOperator*{argmin}{arg!min}
you get rid of the ugly space betweenarg
andmin
.
– rbp
Apr 6 '11 at 21:39
18
@rbp Why should one useargmin
when simplyargmin
does the same?
– egreg
Jul 8 '12 at 15:31
2
@egreg you're right. I arrived at this one from some experimentation with other options, and didn't look back :)
– rbp
Jul 9 '12 at 11:56
4
In ConTeXt that is:definemathcommand [argmin] [limop] {mfunction{arg,min}}
– mb21
Jul 30 '13 at 11:49
3
Explanation: I left the thin space (,) between the arg and min because that's what the original poster had in the question, so I assumed that they wanted the space there. Personally I would just doDeclareMathOperator*{argmin}{argmin}
, without the space.
– Jan Hlavacek
Aug 28 '15 at 1:14
|
show 1 more comment
up vote
65
down vote
Summary
In the sequel, LaTeX is assumed.
Preliminary questions
1. Should a thin space separate “arg” from “min”?
This is a matter of personal preference. The default definition for limsup
has a thin space, on the other hand “arcsin” is usually written without a space between the two components. Consistency is, as always, the keyword: using a macro definition will ensure it and also easiness in modifying the typesetting in the whole document, if switching from one option to another is needed.
2. Should limits go below the operator in display style?
Also this is debatable and conventions used in the field the document is written for should be followed.
3. Should the operator name be typeset upright?
Definitely, like all other operator/function names such as sine and cosine.
Available tools
1. amsmath
With amsmath
one can do, in the preamble,
DeclareMathOperator*{argmin}{arg,min} % thin space, limits underneath in displays
DeclareMathOperator*{argmin}{argmin} % no space, limits underneath in displays
DeclareMathOperator{argmin}{arg,min} % thin space, limits on side in displays
DeclareMathOperator{argmin}{argmin} % no space, limits on side in displays
Of course, only one of these should be used. In the document it's sufficient to type argmin
and the spacing around the operator will be the right one according to the common rules of math typesetting.
The seemingly different
newcommand{argmin}{operatornamewithlimits{argmin}}
is not really so, because it's essentially the same as DeclareMathOperator*{argmin}{argmin}
; moreover it uses a deprecated command, that should be operatorname*
.
2. No package
The following definitions are very similar to the ones above, in the same order
newcommand{argmin}{mathop{mathrm{arg,min}}
newcommand{argmin}{mathop{mathrm{argmin}}
newcommand{argmin}{mathop{mathrm{arg,min}nolimits}
newcommand{argmin}{mathop{mathrm{argmin}nolimits}
With underset
underset{x}{mathrm{argmin}}
This also was mentioned in the question and in one answer, but it is wrong, as the visual comparison will show.
3. Differences
The “no package” version is much more rigid than the amsmath
version, because this package can receive the nonamelimits
option that will automatically change all operators such as lim
, max
that usually have limits underneath (in displays) to have them on the side. The same option would of course act also on newly defined operators, provided DeclareMathOperator*
has been used.
Test document
In the following test document, the proposed definitions or constructions will be compared.
documentclass{article}
usepackage{amsmath}
% limits underneath
DeclareMathOperator*{argminA}{arg,min} % Jan Hlavacek
DeclareMathOperator*{argminB}{argmin} % Jan Hlavacek
DeclareMathOperator*{argminC}{argmin} % rbp
newcommand{argminD}{arg!min} % AlfC
newcommand{argminE}{mathop{mathrm{argmin}}} % ASdeL
newcommand{argminF}{mathop{mathrm{argmin}}limits} % ASdeL
% limits on side
DeclareMathOperator{argminG}{arg,min} % Jan Hlavacek
DeclareMathOperator{argminH}{argmin} % Jan Hlavacek
newcommand{argminI}{mathop{mathrm{argmin}}nolimits} % ASdeL
newcommand{cs}[1]{texttt{symbol{`\}#1}}
begin{document}
begin{align}
&cs{argminA} & argminA_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminB} & argminB_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminC} & argminC_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminD} & argminD_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminE} & argminE_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminF} & argminF_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{underset} & underset{x}{mathrm{argmin}} f(x) &= {x mid f(x) = min_{x'} f(x')}\
&cs{argminG} & argminG_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminH} & argminH_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminI} & argminI_x f(x) &= {x mid f(x) = min_{x'} f(x')}
end{align}
end{document}
Results
As predicted, many lines typeset the same. However, the macros defined with mathop
will not obey the nonamelimits
option. Also the result of argminD
is clearly wrong, as the limit is typeset below “max” and not below the whole operator name.
The construction with underset
is wrong because it will not use the correct spacing after the operator: a thin space follows all others and it is the right way to typeset. Compare sin x
and mathrm{sin}x
to see this thin space in a different context.
Note that argminC
and argminA
give the same result, as well as argminD
and argminB
. Explanation: arg
and max
are already defined as operators, so TeX inserts a thin space if one directly follows another one. Using argminC
or argminD
just makes TeX spin its wheels a little more, with no advantage over argminA
or argminB
.
This should be the accepted answer.
– Alex
Nov 7 at 21:30
add a comment |
up vote
26
down vote
I use newcommand{argmin}{operatornamewithlimits{argmin}}
.
3
+1 I like this - why overcomplicate things? This looks exactly the same as theDeclareMathOperator*
answer.
– zelanix
Aug 13 '14 at 13:52
3
This yields "argmin". To get "arg min" (arguably the most usual notation), set it to{arg,min}
.
– Waldir Leoncio
Jan 21 '16 at 16:38
1
Google gave me 669,000 answers for "arg min" and 520,000 answers for "argmin", so I'd call it a tie. ;-)
– PatrickT
Dec 3 at 4:49
add a comment |
up vote
12
down vote
Use usepackage{amsmath}
and then:
operatorname*{argmin}_theta f(x)
Or similarly (for adding a space),
operatorname*{arg,max}_theta f(x)
add a comment |
up vote
6
down vote
Just another alternative (in some sense the poorer solution around, see comment below), could be to define argmin
in terms of min
and arg
commands.
newcommand{argmin}{arg!min}
In this way, 1) argmin
will behave always the same way as min
, 2) doesn't need amsmath
or care about operator...
commands 3) yes, the variable in not centered (it is centered in the min
part), but that may even be what you want (since it is centered in the same ways a min
, also the 'g' in arg
doesn't further lower the under-argument).
documentclass[fleqn]{article}
newcommand{argmin}{arg!min}
begin{document}
[ argmin_x f(x) = {x | f(x) = min_{x'} f(x')} ]
[ min_x f(x) = {f(x) | f(x) < f(x_0) forall x_0 in R ]
end{document}
3
This doesn't look like a good idea.argmin_{xin Xcap Y} f(x)
will break it completely.
– boycott.se - yo'
Feb 2 '14 at 18:03
What is thearg
command for anyway?
– Thomas Ahle
Jun 3 '14 at 12:47
1
@ThomasAhle,arg
is for the argument function (angle in the complex plane, $z = |z| e^{i arg z}$. tohecz is right by the way.
– alfC
Jun 3 '14 at 15:33
@boycott.se-yo', good point.
– alfC
22 mins ago
add a comment |
up vote
2
down vote
or you could use the underset command. For example:
R = underset{n} {mathrm{argmax}} ~P(L_n|mathbf{x})
10
Please don't use this. This makesargmin
amathord
rather than amathop
and the spacing is incorrect. Moreover, this will not automatically adjust the limits in inline math mode.
– Aditya
Sep 19 '13 at 15:19
add a comment |
up vote
0
down vote
I would use mathop
and mathrm
, and eventually limits
or nolimits
, depending on the desired behavior when combined with _
and ^
. See below.
documentclass{article}
begin{document}
{
nothing:
newcommand{argmin}{mathop{mathrm{argmin}}}
$argmin_a^b$
$$argmin_a^b$$
}
{
limits:
newcommand{argmin}{mathop{mathrm{argmin}}limits}
$argmin_a^b$
$$argmin_a^b$$
}
{
nolimits:
newcommand{argmin}{mathop{mathrm{argmin}}nolimits}
$argmin_a^b$
$$argmin_a^b$$
}
end{document}
add a comment |
up vote
-1
down vote
This works without any additional package. However it will create a new line.
$$pi(s) = argmax_theta$$
$$...$$
is not recommended to use with LaTeX. Better use[ ... ]
for correct vertical spacing.
– Stefan Kottwitz♦
Dec 20 '15 at 20:17
3
This solution will not typeset argmax correctly. Here arg will be in italic (and with bad spacing), and max will be upright.
– Håkon Marthinsen
Dec 20 '15 at 20:17
add a comment |
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8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
173
down vote
accepted
As Pieter pointed out, the correct way to define argmin and argmax operators in LaTeX is:
usepackage{amsmath}
DeclareMathOperator*{argmax}{arg,max}
DeclareMathOperator*{argmin}{arg,min}
Actually, using the amsopn
package would be sufficient but it's loaded by amsmath
internally, which is recommended for math typesetting anyway.
The *
in DeclareMathOperator*
places the underscored argument underneath the word rather than to the bottom right of it.
36
If you useDeclareMathOperator*{argmin}{arg!min}
you get rid of the ugly space betweenarg
andmin
.
– rbp
Apr 6 '11 at 21:39
18
@rbp Why should one useargmin
when simplyargmin
does the same?
– egreg
Jul 8 '12 at 15:31
2
@egreg you're right. I arrived at this one from some experimentation with other options, and didn't look back :)
– rbp
Jul 9 '12 at 11:56
4
In ConTeXt that is:definemathcommand [argmin] [limop] {mfunction{arg,min}}
– mb21
Jul 30 '13 at 11:49
3
Explanation: I left the thin space (,) between the arg and min because that's what the original poster had in the question, so I assumed that they wanted the space there. Personally I would just doDeclareMathOperator*{argmin}{argmin}
, without the space.
– Jan Hlavacek
Aug 28 '15 at 1:14
|
show 1 more comment
up vote
173
down vote
accepted
As Pieter pointed out, the correct way to define argmin and argmax operators in LaTeX is:
usepackage{amsmath}
DeclareMathOperator*{argmax}{arg,max}
DeclareMathOperator*{argmin}{arg,min}
Actually, using the amsopn
package would be sufficient but it's loaded by amsmath
internally, which is recommended for math typesetting anyway.
The *
in DeclareMathOperator*
places the underscored argument underneath the word rather than to the bottom right of it.
36
If you useDeclareMathOperator*{argmin}{arg!min}
you get rid of the ugly space betweenarg
andmin
.
– rbp
Apr 6 '11 at 21:39
18
@rbp Why should one useargmin
when simplyargmin
does the same?
– egreg
Jul 8 '12 at 15:31
2
@egreg you're right. I arrived at this one from some experimentation with other options, and didn't look back :)
– rbp
Jul 9 '12 at 11:56
4
In ConTeXt that is:definemathcommand [argmin] [limop] {mfunction{arg,min}}
– mb21
Jul 30 '13 at 11:49
3
Explanation: I left the thin space (,) between the arg and min because that's what the original poster had in the question, so I assumed that they wanted the space there. Personally I would just doDeclareMathOperator*{argmin}{argmin}
, without the space.
– Jan Hlavacek
Aug 28 '15 at 1:14
|
show 1 more comment
up vote
173
down vote
accepted
up vote
173
down vote
accepted
As Pieter pointed out, the correct way to define argmin and argmax operators in LaTeX is:
usepackage{amsmath}
DeclareMathOperator*{argmax}{arg,max}
DeclareMathOperator*{argmin}{arg,min}
Actually, using the amsopn
package would be sufficient but it's loaded by amsmath
internally, which is recommended for math typesetting anyway.
The *
in DeclareMathOperator*
places the underscored argument underneath the word rather than to the bottom right of it.
As Pieter pointed out, the correct way to define argmin and argmax operators in LaTeX is:
usepackage{amsmath}
DeclareMathOperator*{argmax}{arg,max}
DeclareMathOperator*{argmin}{arg,min}
Actually, using the amsopn
package would be sufficient but it's loaded by amsmath
internally, which is recommended for math typesetting anyway.
The *
in DeclareMathOperator*
places the underscored argument underneath the word rather than to the bottom right of it.
edited Feb 8 at 11:52
community wiki
4 revs, 4 users 58%
danijar
36
If you useDeclareMathOperator*{argmin}{arg!min}
you get rid of the ugly space betweenarg
andmin
.
– rbp
Apr 6 '11 at 21:39
18
@rbp Why should one useargmin
when simplyargmin
does the same?
– egreg
Jul 8 '12 at 15:31
2
@egreg you're right. I arrived at this one from some experimentation with other options, and didn't look back :)
– rbp
Jul 9 '12 at 11:56
4
In ConTeXt that is:definemathcommand [argmin] [limop] {mfunction{arg,min}}
– mb21
Jul 30 '13 at 11:49
3
Explanation: I left the thin space (,) between the arg and min because that's what the original poster had in the question, so I assumed that they wanted the space there. Personally I would just doDeclareMathOperator*{argmin}{argmin}
, without the space.
– Jan Hlavacek
Aug 28 '15 at 1:14
|
show 1 more comment
36
If you useDeclareMathOperator*{argmin}{arg!min}
you get rid of the ugly space betweenarg
andmin
.
– rbp
Apr 6 '11 at 21:39
18
@rbp Why should one useargmin
when simplyargmin
does the same?
– egreg
Jul 8 '12 at 15:31
2
@egreg you're right. I arrived at this one from some experimentation with other options, and didn't look back :)
– rbp
Jul 9 '12 at 11:56
4
In ConTeXt that is:definemathcommand [argmin] [limop] {mfunction{arg,min}}
– mb21
Jul 30 '13 at 11:49
3
Explanation: I left the thin space (,) between the arg and min because that's what the original poster had in the question, so I assumed that they wanted the space there. Personally I would just doDeclareMathOperator*{argmin}{argmin}
, without the space.
– Jan Hlavacek
Aug 28 '15 at 1:14
36
36
If you use
DeclareMathOperator*{argmin}{arg!min}
you get rid of the ugly space between arg
and min
.– rbp
Apr 6 '11 at 21:39
If you use
DeclareMathOperator*{argmin}{arg!min}
you get rid of the ugly space between arg
and min
.– rbp
Apr 6 '11 at 21:39
18
18
@rbp Why should one use
argmin
when simply argmin
does the same?– egreg
Jul 8 '12 at 15:31
@rbp Why should one use
argmin
when simply argmin
does the same?– egreg
Jul 8 '12 at 15:31
2
2
@egreg you're right. I arrived at this one from some experimentation with other options, and didn't look back :)
– rbp
Jul 9 '12 at 11:56
@egreg you're right. I arrived at this one from some experimentation with other options, and didn't look back :)
– rbp
Jul 9 '12 at 11:56
4
4
In ConTeXt that is:
definemathcommand [argmin] [limop] {mfunction{arg,min}}
– mb21
Jul 30 '13 at 11:49
In ConTeXt that is:
definemathcommand [argmin] [limop] {mfunction{arg,min}}
– mb21
Jul 30 '13 at 11:49
3
3
Explanation: I left the thin space (,) between the arg and min because that's what the original poster had in the question, so I assumed that they wanted the space there. Personally I would just do
DeclareMathOperator*{argmin}{argmin}
, without the space.– Jan Hlavacek
Aug 28 '15 at 1:14
Explanation: I left the thin space (,) between the arg and min because that's what the original poster had in the question, so I assumed that they wanted the space there. Personally I would just do
DeclareMathOperator*{argmin}{argmin}
, without the space.– Jan Hlavacek
Aug 28 '15 at 1:14
|
show 1 more comment
up vote
65
down vote
Summary
In the sequel, LaTeX is assumed.
Preliminary questions
1. Should a thin space separate “arg” from “min”?
This is a matter of personal preference. The default definition for limsup
has a thin space, on the other hand “arcsin” is usually written without a space between the two components. Consistency is, as always, the keyword: using a macro definition will ensure it and also easiness in modifying the typesetting in the whole document, if switching from one option to another is needed.
2. Should limits go below the operator in display style?
Also this is debatable and conventions used in the field the document is written for should be followed.
3. Should the operator name be typeset upright?
Definitely, like all other operator/function names such as sine and cosine.
Available tools
1. amsmath
With amsmath
one can do, in the preamble,
DeclareMathOperator*{argmin}{arg,min} % thin space, limits underneath in displays
DeclareMathOperator*{argmin}{argmin} % no space, limits underneath in displays
DeclareMathOperator{argmin}{arg,min} % thin space, limits on side in displays
DeclareMathOperator{argmin}{argmin} % no space, limits on side in displays
Of course, only one of these should be used. In the document it's sufficient to type argmin
and the spacing around the operator will be the right one according to the common rules of math typesetting.
The seemingly different
newcommand{argmin}{operatornamewithlimits{argmin}}
is not really so, because it's essentially the same as DeclareMathOperator*{argmin}{argmin}
; moreover it uses a deprecated command, that should be operatorname*
.
2. No package
The following definitions are very similar to the ones above, in the same order
newcommand{argmin}{mathop{mathrm{arg,min}}
newcommand{argmin}{mathop{mathrm{argmin}}
newcommand{argmin}{mathop{mathrm{arg,min}nolimits}
newcommand{argmin}{mathop{mathrm{argmin}nolimits}
With underset
underset{x}{mathrm{argmin}}
This also was mentioned in the question and in one answer, but it is wrong, as the visual comparison will show.
3. Differences
The “no package” version is much more rigid than the amsmath
version, because this package can receive the nonamelimits
option that will automatically change all operators such as lim
, max
that usually have limits underneath (in displays) to have them on the side. The same option would of course act also on newly defined operators, provided DeclareMathOperator*
has been used.
Test document
In the following test document, the proposed definitions or constructions will be compared.
documentclass{article}
usepackage{amsmath}
% limits underneath
DeclareMathOperator*{argminA}{arg,min} % Jan Hlavacek
DeclareMathOperator*{argminB}{argmin} % Jan Hlavacek
DeclareMathOperator*{argminC}{argmin} % rbp
newcommand{argminD}{arg!min} % AlfC
newcommand{argminE}{mathop{mathrm{argmin}}} % ASdeL
newcommand{argminF}{mathop{mathrm{argmin}}limits} % ASdeL
% limits on side
DeclareMathOperator{argminG}{arg,min} % Jan Hlavacek
DeclareMathOperator{argminH}{argmin} % Jan Hlavacek
newcommand{argminI}{mathop{mathrm{argmin}}nolimits} % ASdeL
newcommand{cs}[1]{texttt{symbol{`\}#1}}
begin{document}
begin{align}
&cs{argminA} & argminA_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminB} & argminB_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminC} & argminC_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminD} & argminD_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminE} & argminE_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminF} & argminF_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{underset} & underset{x}{mathrm{argmin}} f(x) &= {x mid f(x) = min_{x'} f(x')}\
&cs{argminG} & argminG_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminH} & argminH_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminI} & argminI_x f(x) &= {x mid f(x) = min_{x'} f(x')}
end{align}
end{document}
Results
As predicted, many lines typeset the same. However, the macros defined with mathop
will not obey the nonamelimits
option. Also the result of argminD
is clearly wrong, as the limit is typeset below “max” and not below the whole operator name.
The construction with underset
is wrong because it will not use the correct spacing after the operator: a thin space follows all others and it is the right way to typeset. Compare sin x
and mathrm{sin}x
to see this thin space in a different context.
Note that argminC
and argminA
give the same result, as well as argminD
and argminB
. Explanation: arg
and max
are already defined as operators, so TeX inserts a thin space if one directly follows another one. Using argminC
or argminD
just makes TeX spin its wheels a little more, with no advantage over argminA
or argminB
.
This should be the accepted answer.
– Alex
Nov 7 at 21:30
add a comment |
up vote
65
down vote
Summary
In the sequel, LaTeX is assumed.
Preliminary questions
1. Should a thin space separate “arg” from “min”?
This is a matter of personal preference. The default definition for limsup
has a thin space, on the other hand “arcsin” is usually written without a space between the two components. Consistency is, as always, the keyword: using a macro definition will ensure it and also easiness in modifying the typesetting in the whole document, if switching from one option to another is needed.
2. Should limits go below the operator in display style?
Also this is debatable and conventions used in the field the document is written for should be followed.
3. Should the operator name be typeset upright?
Definitely, like all other operator/function names such as sine and cosine.
Available tools
1. amsmath
With amsmath
one can do, in the preamble,
DeclareMathOperator*{argmin}{arg,min} % thin space, limits underneath in displays
DeclareMathOperator*{argmin}{argmin} % no space, limits underneath in displays
DeclareMathOperator{argmin}{arg,min} % thin space, limits on side in displays
DeclareMathOperator{argmin}{argmin} % no space, limits on side in displays
Of course, only one of these should be used. In the document it's sufficient to type argmin
and the spacing around the operator will be the right one according to the common rules of math typesetting.
The seemingly different
newcommand{argmin}{operatornamewithlimits{argmin}}
is not really so, because it's essentially the same as DeclareMathOperator*{argmin}{argmin}
; moreover it uses a deprecated command, that should be operatorname*
.
2. No package
The following definitions are very similar to the ones above, in the same order
newcommand{argmin}{mathop{mathrm{arg,min}}
newcommand{argmin}{mathop{mathrm{argmin}}
newcommand{argmin}{mathop{mathrm{arg,min}nolimits}
newcommand{argmin}{mathop{mathrm{argmin}nolimits}
With underset
underset{x}{mathrm{argmin}}
This also was mentioned in the question and in one answer, but it is wrong, as the visual comparison will show.
3. Differences
The “no package” version is much more rigid than the amsmath
version, because this package can receive the nonamelimits
option that will automatically change all operators such as lim
, max
that usually have limits underneath (in displays) to have them on the side. The same option would of course act also on newly defined operators, provided DeclareMathOperator*
has been used.
Test document
In the following test document, the proposed definitions or constructions will be compared.
documentclass{article}
usepackage{amsmath}
% limits underneath
DeclareMathOperator*{argminA}{arg,min} % Jan Hlavacek
DeclareMathOperator*{argminB}{argmin} % Jan Hlavacek
DeclareMathOperator*{argminC}{argmin} % rbp
newcommand{argminD}{arg!min} % AlfC
newcommand{argminE}{mathop{mathrm{argmin}}} % ASdeL
newcommand{argminF}{mathop{mathrm{argmin}}limits} % ASdeL
% limits on side
DeclareMathOperator{argminG}{arg,min} % Jan Hlavacek
DeclareMathOperator{argminH}{argmin} % Jan Hlavacek
newcommand{argminI}{mathop{mathrm{argmin}}nolimits} % ASdeL
newcommand{cs}[1]{texttt{symbol{`\}#1}}
begin{document}
begin{align}
&cs{argminA} & argminA_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminB} & argminB_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminC} & argminC_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminD} & argminD_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminE} & argminE_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminF} & argminF_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{underset} & underset{x}{mathrm{argmin}} f(x) &= {x mid f(x) = min_{x'} f(x')}\
&cs{argminG} & argminG_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminH} & argminH_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminI} & argminI_x f(x) &= {x mid f(x) = min_{x'} f(x')}
end{align}
end{document}
Results
As predicted, many lines typeset the same. However, the macros defined with mathop
will not obey the nonamelimits
option. Also the result of argminD
is clearly wrong, as the limit is typeset below “max” and not below the whole operator name.
The construction with underset
is wrong because it will not use the correct spacing after the operator: a thin space follows all others and it is the right way to typeset. Compare sin x
and mathrm{sin}x
to see this thin space in a different context.
Note that argminC
and argminA
give the same result, as well as argminD
and argminB
. Explanation: arg
and max
are already defined as operators, so TeX inserts a thin space if one directly follows another one. Using argminC
or argminD
just makes TeX spin its wheels a little more, with no advantage over argminA
or argminB
.
This should be the accepted answer.
– Alex
Nov 7 at 21:30
add a comment |
up vote
65
down vote
up vote
65
down vote
Summary
In the sequel, LaTeX is assumed.
Preliminary questions
1. Should a thin space separate “arg” from “min”?
This is a matter of personal preference. The default definition for limsup
has a thin space, on the other hand “arcsin” is usually written without a space between the two components. Consistency is, as always, the keyword: using a macro definition will ensure it and also easiness in modifying the typesetting in the whole document, if switching from one option to another is needed.
2. Should limits go below the operator in display style?
Also this is debatable and conventions used in the field the document is written for should be followed.
3. Should the operator name be typeset upright?
Definitely, like all other operator/function names such as sine and cosine.
Available tools
1. amsmath
With amsmath
one can do, in the preamble,
DeclareMathOperator*{argmin}{arg,min} % thin space, limits underneath in displays
DeclareMathOperator*{argmin}{argmin} % no space, limits underneath in displays
DeclareMathOperator{argmin}{arg,min} % thin space, limits on side in displays
DeclareMathOperator{argmin}{argmin} % no space, limits on side in displays
Of course, only one of these should be used. In the document it's sufficient to type argmin
and the spacing around the operator will be the right one according to the common rules of math typesetting.
The seemingly different
newcommand{argmin}{operatornamewithlimits{argmin}}
is not really so, because it's essentially the same as DeclareMathOperator*{argmin}{argmin}
; moreover it uses a deprecated command, that should be operatorname*
.
2. No package
The following definitions are very similar to the ones above, in the same order
newcommand{argmin}{mathop{mathrm{arg,min}}
newcommand{argmin}{mathop{mathrm{argmin}}
newcommand{argmin}{mathop{mathrm{arg,min}nolimits}
newcommand{argmin}{mathop{mathrm{argmin}nolimits}
With underset
underset{x}{mathrm{argmin}}
This also was mentioned in the question and in one answer, but it is wrong, as the visual comparison will show.
3. Differences
The “no package” version is much more rigid than the amsmath
version, because this package can receive the nonamelimits
option that will automatically change all operators such as lim
, max
that usually have limits underneath (in displays) to have them on the side. The same option would of course act also on newly defined operators, provided DeclareMathOperator*
has been used.
Test document
In the following test document, the proposed definitions or constructions will be compared.
documentclass{article}
usepackage{amsmath}
% limits underneath
DeclareMathOperator*{argminA}{arg,min} % Jan Hlavacek
DeclareMathOperator*{argminB}{argmin} % Jan Hlavacek
DeclareMathOperator*{argminC}{argmin} % rbp
newcommand{argminD}{arg!min} % AlfC
newcommand{argminE}{mathop{mathrm{argmin}}} % ASdeL
newcommand{argminF}{mathop{mathrm{argmin}}limits} % ASdeL
% limits on side
DeclareMathOperator{argminG}{arg,min} % Jan Hlavacek
DeclareMathOperator{argminH}{argmin} % Jan Hlavacek
newcommand{argminI}{mathop{mathrm{argmin}}nolimits} % ASdeL
newcommand{cs}[1]{texttt{symbol{`\}#1}}
begin{document}
begin{align}
&cs{argminA} & argminA_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminB} & argminB_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminC} & argminC_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminD} & argminD_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminE} & argminE_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminF} & argminF_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{underset} & underset{x}{mathrm{argmin}} f(x) &= {x mid f(x) = min_{x'} f(x')}\
&cs{argminG} & argminG_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminH} & argminH_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminI} & argminI_x f(x) &= {x mid f(x) = min_{x'} f(x')}
end{align}
end{document}
Results
As predicted, many lines typeset the same. However, the macros defined with mathop
will not obey the nonamelimits
option. Also the result of argminD
is clearly wrong, as the limit is typeset below “max” and not below the whole operator name.
The construction with underset
is wrong because it will not use the correct spacing after the operator: a thin space follows all others and it is the right way to typeset. Compare sin x
and mathrm{sin}x
to see this thin space in a different context.
Note that argminC
and argminA
give the same result, as well as argminD
and argminB
. Explanation: arg
and max
are already defined as operators, so TeX inserts a thin space if one directly follows another one. Using argminC
or argminD
just makes TeX spin its wheels a little more, with no advantage over argminA
or argminB
.
Summary
In the sequel, LaTeX is assumed.
Preliminary questions
1. Should a thin space separate “arg” from “min”?
This is a matter of personal preference. The default definition for limsup
has a thin space, on the other hand “arcsin” is usually written without a space between the two components. Consistency is, as always, the keyword: using a macro definition will ensure it and also easiness in modifying the typesetting in the whole document, if switching from one option to another is needed.
2. Should limits go below the operator in display style?
Also this is debatable and conventions used in the field the document is written for should be followed.
3. Should the operator name be typeset upright?
Definitely, like all other operator/function names such as sine and cosine.
Available tools
1. amsmath
With amsmath
one can do, in the preamble,
DeclareMathOperator*{argmin}{arg,min} % thin space, limits underneath in displays
DeclareMathOperator*{argmin}{argmin} % no space, limits underneath in displays
DeclareMathOperator{argmin}{arg,min} % thin space, limits on side in displays
DeclareMathOperator{argmin}{argmin} % no space, limits on side in displays
Of course, only one of these should be used. In the document it's sufficient to type argmin
and the spacing around the operator will be the right one according to the common rules of math typesetting.
The seemingly different
newcommand{argmin}{operatornamewithlimits{argmin}}
is not really so, because it's essentially the same as DeclareMathOperator*{argmin}{argmin}
; moreover it uses a deprecated command, that should be operatorname*
.
2. No package
The following definitions are very similar to the ones above, in the same order
newcommand{argmin}{mathop{mathrm{arg,min}}
newcommand{argmin}{mathop{mathrm{argmin}}
newcommand{argmin}{mathop{mathrm{arg,min}nolimits}
newcommand{argmin}{mathop{mathrm{argmin}nolimits}
With underset
underset{x}{mathrm{argmin}}
This also was mentioned in the question and in one answer, but it is wrong, as the visual comparison will show.
3. Differences
The “no package” version is much more rigid than the amsmath
version, because this package can receive the nonamelimits
option that will automatically change all operators such as lim
, max
that usually have limits underneath (in displays) to have them on the side. The same option would of course act also on newly defined operators, provided DeclareMathOperator*
has been used.
Test document
In the following test document, the proposed definitions or constructions will be compared.
documentclass{article}
usepackage{amsmath}
% limits underneath
DeclareMathOperator*{argminA}{arg,min} % Jan Hlavacek
DeclareMathOperator*{argminB}{argmin} % Jan Hlavacek
DeclareMathOperator*{argminC}{argmin} % rbp
newcommand{argminD}{arg!min} % AlfC
newcommand{argminE}{mathop{mathrm{argmin}}} % ASdeL
newcommand{argminF}{mathop{mathrm{argmin}}limits} % ASdeL
% limits on side
DeclareMathOperator{argminG}{arg,min} % Jan Hlavacek
DeclareMathOperator{argminH}{argmin} % Jan Hlavacek
newcommand{argminI}{mathop{mathrm{argmin}}nolimits} % ASdeL
newcommand{cs}[1]{texttt{symbol{`\}#1}}
begin{document}
begin{align}
&cs{argminA} & argminA_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminB} & argminB_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminC} & argminC_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminD} & argminD_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminE} & argminE_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminF} & argminF_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{underset} & underset{x}{mathrm{argmin}} f(x) &= {x mid f(x) = min_{x'} f(x')}\
&cs{argminG} & argminG_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminH} & argminH_x f(x) &= {x mid f(x) = min_{x'} f(x')} \
&cs{argminI} & argminI_x f(x) &= {x mid f(x) = min_{x'} f(x')}
end{align}
end{document}
Results
As predicted, many lines typeset the same. However, the macros defined with mathop
will not obey the nonamelimits
option. Also the result of argminD
is clearly wrong, as the limit is typeset below “max” and not below the whole operator name.
The construction with underset
is wrong because it will not use the correct spacing after the operator: a thin space follows all others and it is the right way to typeset. Compare sin x
and mathrm{sin}x
to see this thin space in a different context.
Note that argminC
and argminA
give the same result, as well as argminD
and argminB
. Explanation: arg
and max
are already defined as operators, so TeX inserts a thin space if one directly follows another one. Using argminC
or argminD
just makes TeX spin its wheels a little more, with no advantage over argminA
or argminB
.
answered Dec 20 '15 at 21:45
community wiki
egreg
This should be the accepted answer.
– Alex
Nov 7 at 21:30
add a comment |
This should be the accepted answer.
– Alex
Nov 7 at 21:30
This should be the accepted answer.
– Alex
Nov 7 at 21:30
This should be the accepted answer.
– Alex
Nov 7 at 21:30
add a comment |
up vote
26
down vote
I use newcommand{argmin}{operatornamewithlimits{argmin}}
.
3
+1 I like this - why overcomplicate things? This looks exactly the same as theDeclareMathOperator*
answer.
– zelanix
Aug 13 '14 at 13:52
3
This yields "argmin". To get "arg min" (arguably the most usual notation), set it to{arg,min}
.
– Waldir Leoncio
Jan 21 '16 at 16:38
1
Google gave me 669,000 answers for "arg min" and 520,000 answers for "argmin", so I'd call it a tie. ;-)
– PatrickT
Dec 3 at 4:49
add a comment |
up vote
26
down vote
I use newcommand{argmin}{operatornamewithlimits{argmin}}
.
3
+1 I like this - why overcomplicate things? This looks exactly the same as theDeclareMathOperator*
answer.
– zelanix
Aug 13 '14 at 13:52
3
This yields "argmin". To get "arg min" (arguably the most usual notation), set it to{arg,min}
.
– Waldir Leoncio
Jan 21 '16 at 16:38
1
Google gave me 669,000 answers for "arg min" and 520,000 answers for "argmin", so I'd call it a tie. ;-)
– PatrickT
Dec 3 at 4:49
add a comment |
up vote
26
down vote
up vote
26
down vote
I use newcommand{argmin}{operatornamewithlimits{argmin}}
.
I use newcommand{argmin}{operatornamewithlimits{argmin}}
.
answered May 22 '12 at 19:55
Michael Litvin
36132
36132
3
+1 I like this - why overcomplicate things? This looks exactly the same as theDeclareMathOperator*
answer.
– zelanix
Aug 13 '14 at 13:52
3
This yields "argmin". To get "arg min" (arguably the most usual notation), set it to{arg,min}
.
– Waldir Leoncio
Jan 21 '16 at 16:38
1
Google gave me 669,000 answers for "arg min" and 520,000 answers for "argmin", so I'd call it a tie. ;-)
– PatrickT
Dec 3 at 4:49
add a comment |
3
+1 I like this - why overcomplicate things? This looks exactly the same as theDeclareMathOperator*
answer.
– zelanix
Aug 13 '14 at 13:52
3
This yields "argmin". To get "arg min" (arguably the most usual notation), set it to{arg,min}
.
– Waldir Leoncio
Jan 21 '16 at 16:38
1
Google gave me 669,000 answers for "arg min" and 520,000 answers for "argmin", so I'd call it a tie. ;-)
– PatrickT
Dec 3 at 4:49
3
3
+1 I like this - why overcomplicate things? This looks exactly the same as the
DeclareMathOperator*
answer.– zelanix
Aug 13 '14 at 13:52
+1 I like this - why overcomplicate things? This looks exactly the same as the
DeclareMathOperator*
answer.– zelanix
Aug 13 '14 at 13:52
3
3
This yields "argmin". To get "arg min" (arguably the most usual notation), set it to
{arg,min}
.– Waldir Leoncio
Jan 21 '16 at 16:38
This yields "argmin". To get "arg min" (arguably the most usual notation), set it to
{arg,min}
.– Waldir Leoncio
Jan 21 '16 at 16:38
1
1
Google gave me 669,000 answers for "arg min" and 520,000 answers for "argmin", so I'd call it a tie. ;-)
– PatrickT
Dec 3 at 4:49
Google gave me 669,000 answers for "arg min" and 520,000 answers for "argmin", so I'd call it a tie. ;-)
– PatrickT
Dec 3 at 4:49
add a comment |
up vote
12
down vote
Use usepackage{amsmath}
and then:
operatorname*{argmin}_theta f(x)
Or similarly (for adding a space),
operatorname*{arg,max}_theta f(x)
add a comment |
up vote
12
down vote
Use usepackage{amsmath}
and then:
operatorname*{argmin}_theta f(x)
Or similarly (for adding a space),
operatorname*{arg,max}_theta f(x)
add a comment |
up vote
12
down vote
up vote
12
down vote
Use usepackage{amsmath}
and then:
operatorname*{argmin}_theta f(x)
Or similarly (for adding a space),
operatorname*{arg,max}_theta f(x)
Use usepackage{amsmath}
and then:
operatorname*{argmin}_theta f(x)
Or similarly (for adding a space),
operatorname*{arg,max}_theta f(x)
answered May 25 '17 at 16:54
iamaziz
25125
25125
add a comment |
add a comment |
up vote
6
down vote
Just another alternative (in some sense the poorer solution around, see comment below), could be to define argmin
in terms of min
and arg
commands.
newcommand{argmin}{arg!min}
In this way, 1) argmin
will behave always the same way as min
, 2) doesn't need amsmath
or care about operator...
commands 3) yes, the variable in not centered (it is centered in the min
part), but that may even be what you want (since it is centered in the same ways a min
, also the 'g' in arg
doesn't further lower the under-argument).
documentclass[fleqn]{article}
newcommand{argmin}{arg!min}
begin{document}
[ argmin_x f(x) = {x | f(x) = min_{x'} f(x')} ]
[ min_x f(x) = {f(x) | f(x) < f(x_0) forall x_0 in R ]
end{document}
3
This doesn't look like a good idea.argmin_{xin Xcap Y} f(x)
will break it completely.
– boycott.se - yo'
Feb 2 '14 at 18:03
What is thearg
command for anyway?
– Thomas Ahle
Jun 3 '14 at 12:47
1
@ThomasAhle,arg
is for the argument function (angle in the complex plane, $z = |z| e^{i arg z}$. tohecz is right by the way.
– alfC
Jun 3 '14 at 15:33
@boycott.se-yo', good point.
– alfC
22 mins ago
add a comment |
up vote
6
down vote
Just another alternative (in some sense the poorer solution around, see comment below), could be to define argmin
in terms of min
and arg
commands.
newcommand{argmin}{arg!min}
In this way, 1) argmin
will behave always the same way as min
, 2) doesn't need amsmath
or care about operator...
commands 3) yes, the variable in not centered (it is centered in the min
part), but that may even be what you want (since it is centered in the same ways a min
, also the 'g' in arg
doesn't further lower the under-argument).
documentclass[fleqn]{article}
newcommand{argmin}{arg!min}
begin{document}
[ argmin_x f(x) = {x | f(x) = min_{x'} f(x')} ]
[ min_x f(x) = {f(x) | f(x) < f(x_0) forall x_0 in R ]
end{document}
3
This doesn't look like a good idea.argmin_{xin Xcap Y} f(x)
will break it completely.
– boycott.se - yo'
Feb 2 '14 at 18:03
What is thearg
command for anyway?
– Thomas Ahle
Jun 3 '14 at 12:47
1
@ThomasAhle,arg
is for the argument function (angle in the complex plane, $z = |z| e^{i arg z}$. tohecz is right by the way.
– alfC
Jun 3 '14 at 15:33
@boycott.se-yo', good point.
– alfC
22 mins ago
add a comment |
up vote
6
down vote
up vote
6
down vote
Just another alternative (in some sense the poorer solution around, see comment below), could be to define argmin
in terms of min
and arg
commands.
newcommand{argmin}{arg!min}
In this way, 1) argmin
will behave always the same way as min
, 2) doesn't need amsmath
or care about operator...
commands 3) yes, the variable in not centered (it is centered in the min
part), but that may even be what you want (since it is centered in the same ways a min
, also the 'g' in arg
doesn't further lower the under-argument).
documentclass[fleqn]{article}
newcommand{argmin}{arg!min}
begin{document}
[ argmin_x f(x) = {x | f(x) = min_{x'} f(x')} ]
[ min_x f(x) = {f(x) | f(x) < f(x_0) forall x_0 in R ]
end{document}
Just another alternative (in some sense the poorer solution around, see comment below), could be to define argmin
in terms of min
and arg
commands.
newcommand{argmin}{arg!min}
In this way, 1) argmin
will behave always the same way as min
, 2) doesn't need amsmath
or care about operator...
commands 3) yes, the variable in not centered (it is centered in the min
part), but that may even be what you want (since it is centered in the same ways a min
, also the 'g' in arg
doesn't further lower the under-argument).
documentclass[fleqn]{article}
newcommand{argmin}{arg!min}
begin{document}
[ argmin_x f(x) = {x | f(x) = min_{x'} f(x')} ]
[ min_x f(x) = {f(x) | f(x) < f(x_0) forall x_0 in R ]
end{document}
edited 23 mins ago
answered Nov 27 '13 at 23:15
alfC
7,672550111
7,672550111
3
This doesn't look like a good idea.argmin_{xin Xcap Y} f(x)
will break it completely.
– boycott.se - yo'
Feb 2 '14 at 18:03
What is thearg
command for anyway?
– Thomas Ahle
Jun 3 '14 at 12:47
1
@ThomasAhle,arg
is for the argument function (angle in the complex plane, $z = |z| e^{i arg z}$. tohecz is right by the way.
– alfC
Jun 3 '14 at 15:33
@boycott.se-yo', good point.
– alfC
22 mins ago
add a comment |
3
This doesn't look like a good idea.argmin_{xin Xcap Y} f(x)
will break it completely.
– boycott.se - yo'
Feb 2 '14 at 18:03
What is thearg
command for anyway?
– Thomas Ahle
Jun 3 '14 at 12:47
1
@ThomasAhle,arg
is for the argument function (angle in the complex plane, $z = |z| e^{i arg z}$. tohecz is right by the way.
– alfC
Jun 3 '14 at 15:33
@boycott.se-yo', good point.
– alfC
22 mins ago
3
3
This doesn't look like a good idea.
argmin_{xin Xcap Y} f(x)
will break it completely.– boycott.se - yo'
Feb 2 '14 at 18:03
This doesn't look like a good idea.
argmin_{xin Xcap Y} f(x)
will break it completely.– boycott.se - yo'
Feb 2 '14 at 18:03
What is the
arg
command for anyway?– Thomas Ahle
Jun 3 '14 at 12:47
What is the
arg
command for anyway?– Thomas Ahle
Jun 3 '14 at 12:47
1
1
@ThomasAhle,
arg
is for the argument function (angle in the complex plane, $z = |z| e^{i arg z}$. tohecz is right by the way.– alfC
Jun 3 '14 at 15:33
@ThomasAhle,
arg
is for the argument function (angle in the complex plane, $z = |z| e^{i arg z}$. tohecz is right by the way.– alfC
Jun 3 '14 at 15:33
@boycott.se-yo', good point.
– alfC
22 mins ago
@boycott.se-yo', good point.
– alfC
22 mins ago
add a comment |
up vote
2
down vote
or you could use the underset command. For example:
R = underset{n} {mathrm{argmax}} ~P(L_n|mathbf{x})
10
Please don't use this. This makesargmin
amathord
rather than amathop
and the spacing is incorrect. Moreover, this will not automatically adjust the limits in inline math mode.
– Aditya
Sep 19 '13 at 15:19
add a comment |
up vote
2
down vote
or you could use the underset command. For example:
R = underset{n} {mathrm{argmax}} ~P(L_n|mathbf{x})
10
Please don't use this. This makesargmin
amathord
rather than amathop
and the spacing is incorrect. Moreover, this will not automatically adjust the limits in inline math mode.
– Aditya
Sep 19 '13 at 15:19
add a comment |
up vote
2
down vote
up vote
2
down vote
or you could use the underset command. For example:
R = underset{n} {mathrm{argmax}} ~P(L_n|mathbf{x})
or you could use the underset command. For example:
R = underset{n} {mathrm{argmax}} ~P(L_n|mathbf{x})
answered Sep 19 '13 at 13:07
drben
291
291
10
Please don't use this. This makesargmin
amathord
rather than amathop
and the spacing is incorrect. Moreover, this will not automatically adjust the limits in inline math mode.
– Aditya
Sep 19 '13 at 15:19
add a comment |
10
Please don't use this. This makesargmin
amathord
rather than amathop
and the spacing is incorrect. Moreover, this will not automatically adjust the limits in inline math mode.
– Aditya
Sep 19 '13 at 15:19
10
10
Please don't use this. This makes
argmin
a mathord
rather than a mathop
and the spacing is incorrect. Moreover, this will not automatically adjust the limits in inline math mode.– Aditya
Sep 19 '13 at 15:19
Please don't use this. This makes
argmin
a mathord
rather than a mathop
and the spacing is incorrect. Moreover, this will not automatically adjust the limits in inline math mode.– Aditya
Sep 19 '13 at 15:19
add a comment |
up vote
0
down vote
I would use mathop
and mathrm
, and eventually limits
or nolimits
, depending on the desired behavior when combined with _
and ^
. See below.
documentclass{article}
begin{document}
{
nothing:
newcommand{argmin}{mathop{mathrm{argmin}}}
$argmin_a^b$
$$argmin_a^b$$
}
{
limits:
newcommand{argmin}{mathop{mathrm{argmin}}limits}
$argmin_a^b$
$$argmin_a^b$$
}
{
nolimits:
newcommand{argmin}{mathop{mathrm{argmin}}nolimits}
$argmin_a^b$
$$argmin_a^b$$
}
end{document}
add a comment |
up vote
0
down vote
I would use mathop
and mathrm
, and eventually limits
or nolimits
, depending on the desired behavior when combined with _
and ^
. See below.
documentclass{article}
begin{document}
{
nothing:
newcommand{argmin}{mathop{mathrm{argmin}}}
$argmin_a^b$
$$argmin_a^b$$
}
{
limits:
newcommand{argmin}{mathop{mathrm{argmin}}limits}
$argmin_a^b$
$$argmin_a^b$$
}
{
nolimits:
newcommand{argmin}{mathop{mathrm{argmin}}nolimits}
$argmin_a^b$
$$argmin_a^b$$
}
end{document}
add a comment |
up vote
0
down vote
up vote
0
down vote
I would use mathop
and mathrm
, and eventually limits
or nolimits
, depending on the desired behavior when combined with _
and ^
. See below.
documentclass{article}
begin{document}
{
nothing:
newcommand{argmin}{mathop{mathrm{argmin}}}
$argmin_a^b$
$$argmin_a^b$$
}
{
limits:
newcommand{argmin}{mathop{mathrm{argmin}}limits}
$argmin_a^b$
$$argmin_a^b$$
}
{
nolimits:
newcommand{argmin}{mathop{mathrm{argmin}}nolimits}
$argmin_a^b$
$$argmin_a^b$$
}
end{document}
I would use mathop
and mathrm
, and eventually limits
or nolimits
, depending on the desired behavior when combined with _
and ^
. See below.
documentclass{article}
begin{document}
{
nothing:
newcommand{argmin}{mathop{mathrm{argmin}}}
$argmin_a^b$
$$argmin_a^b$$
}
{
limits:
newcommand{argmin}{mathop{mathrm{argmin}}limits}
$argmin_a^b$
$$argmin_a^b$$
}
{
nolimits:
newcommand{argmin}{mathop{mathrm{argmin}}nolimits}
$argmin_a^b$
$$argmin_a^b$$
}
end{document}
answered Sep 21 '15 at 13:35
ASdeL
1,91531220
1,91531220
add a comment |
add a comment |
up vote
-1
down vote
This works without any additional package. However it will create a new line.
$$pi(s) = argmax_theta$$
$$...$$
is not recommended to use with LaTeX. Better use[ ... ]
for correct vertical spacing.
– Stefan Kottwitz♦
Dec 20 '15 at 20:17
3
This solution will not typeset argmax correctly. Here arg will be in italic (and with bad spacing), and max will be upright.
– Håkon Marthinsen
Dec 20 '15 at 20:17
add a comment |
up vote
-1
down vote
This works without any additional package. However it will create a new line.
$$pi(s) = argmax_theta$$
$$...$$
is not recommended to use with LaTeX. Better use[ ... ]
for correct vertical spacing.
– Stefan Kottwitz♦
Dec 20 '15 at 20:17
3
This solution will not typeset argmax correctly. Here arg will be in italic (and with bad spacing), and max will be upright.
– Håkon Marthinsen
Dec 20 '15 at 20:17
add a comment |
up vote
-1
down vote
up vote
-1
down vote
This works without any additional package. However it will create a new line.
$$pi(s) = argmax_theta$$
This works without any additional package. However it will create a new line.
$$pi(s) = argmax_theta$$
answered Dec 20 '15 at 20:12
MiaeKim
1012
1012
$$...$$
is not recommended to use with LaTeX. Better use[ ... ]
for correct vertical spacing.
– Stefan Kottwitz♦
Dec 20 '15 at 20:17
3
This solution will not typeset argmax correctly. Here arg will be in italic (and with bad spacing), and max will be upright.
– Håkon Marthinsen
Dec 20 '15 at 20:17
add a comment |
$$...$$
is not recommended to use with LaTeX. Better use[ ... ]
for correct vertical spacing.
– Stefan Kottwitz♦
Dec 20 '15 at 20:17
3
This solution will not typeset argmax correctly. Here arg will be in italic (and with bad spacing), and max will be upright.
– Håkon Marthinsen
Dec 20 '15 at 20:17
$$...$$
is not recommended to use with LaTeX. Better use [ ... ]
for correct vertical spacing.– Stefan Kottwitz♦
Dec 20 '15 at 20:17
$$...$$
is not recommended to use with LaTeX. Better use [ ... ]
for correct vertical spacing.– Stefan Kottwitz♦
Dec 20 '15 at 20:17
3
3
This solution will not typeset argmax correctly. Here arg will be in italic (and with bad spacing), and max will be upright.
– Håkon Marthinsen
Dec 20 '15 at 20:17
This solution will not typeset argmax correctly. Here arg will be in italic (and with bad spacing), and max will be upright.
– Håkon Marthinsen
Dec 20 '15 at 20:17
add a comment |
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28
How do these solutions (especially the second) feel not right? The
DeclareMathOperator
is the way to go in this case.– Pieter
Nov 11 '10 at 17:57
1
Personally, I like the look of
text{arg},maxlimits_{theta},
– Jean-Paul
Sep 7 '16 at 8:11