Zip file being corrupted while downloading using Python
I have a link to a zip file, which on accessing via browser directly downloads me the zip file. However, when I download that using urllib, file gets corrupted.
I'm using below code:
import urllib.request
import zipfile
request = urllib.request.urlopen( url )
#save
output = open("install.zip", "wb")
output.write(request.read())
output.close()
archive = zipfile.ZipFile('install.zip', 'r')
archive.extractall()
I found one question on similar lines, but it's not answered and seems abandoned.
Thanks!
python-3.x urllib zipfile
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
add a comment |
I have a link to a zip file, which on accessing via browser directly downloads me the zip file. However, when I download that using urllib, file gets corrupted.
I'm using below code:
import urllib.request
import zipfile
request = urllib.request.urlopen( url )
#save
output = open("install.zip", "wb")
output.write(request.read())
output.close()
archive = zipfile.ZipFile('install.zip', 'r')
archive.extractall()
I found one question on similar lines, but it's not answered and seems abandoned.
Thanks!
python-3.x urllib zipfile
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
add a comment |
I have a link to a zip file, which on accessing via browser directly downloads me the zip file. However, when I download that using urllib, file gets corrupted.
I'm using below code:
import urllib.request
import zipfile
request = urllib.request.urlopen( url )
#save
output = open("install.zip", "wb")
output.write(request.read())
output.close()
archive = zipfile.ZipFile('install.zip', 'r')
archive.extractall()
I found one question on similar lines, but it's not answered and seems abandoned.
Thanks!
python-3.x urllib zipfile
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
I have a link to a zip file, which on accessing via browser directly downloads me the zip file. However, when I download that using urllib, file gets corrupted.
I'm using below code:
import urllib.request
import zipfile
request = urllib.request.urlopen( url )
#save
output = open("install.zip", "wb")
output.write(request.read())
output.close()
archive = zipfile.ZipFile('install.zip', 'r')
archive.extractall()
I found one question on similar lines, but it's not answered and seems abandoned.
Thanks!
python-3.x urllib zipfile
python-3.x urllib zipfile
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
asked Nov 28 '18 at 18:05
tikiabbastikiabbas
5115
5115
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Can you use requests? I've found the cleanest way to do this is as follows:
import io
import requests
import zipfile
r = requests.get(url)
z = zipfile.ZipFile(io.BytesIO(r.content))
z.extractall()
answered Nov 28 '18 at 18:13
codycody
8,23631326
This works perfectly, thanks! Though couldn't understand what was going wrong with urllib.
– tikiabbas
Nov 28 '18 at 18:44
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Can you use requests? I've found the cleanest way to do this is as follows:
import io
import requests
import zipfile
r = requests.get(url)
z = zipfile.ZipFile(io.BytesIO(r.content))
z.extractall()
answered Nov 28 '18 at 18:13
codycody
8,23631326
This works perfectly, thanks! Though couldn't understand what was going wrong with urllib.
– tikiabbas
Nov 28 '18 at 18:44
add a comment |
Can you use requests? I've found the cleanest way to do this is as follows:
import io
import requests
import zipfile
r = requests.get(url)
z = zipfile.ZipFile(io.BytesIO(r.content))
z.extractall()
answered Nov 28 '18 at 18:13
codycody
8,23631326
This works perfectly, thanks! Though couldn't understand what was going wrong with urllib.
– tikiabbas
Nov 28 '18 at 18:44
add a comment |
Can you use requests? I've found the cleanest way to do this is as follows:
import io
import requests
import zipfile
r = requests.get(url)
z = zipfile.ZipFile(io.BytesIO(r.content))
z.extractall()
answered Nov 28 '18 at 18:13
codycody
8,23631326
Can you use requests? I've found the cleanest way to do this is as follows:
import io
import requests
import zipfile
r = requests.get(url)
z = zipfile.ZipFile(io.BytesIO(r.content))
z.extractall()
answered Nov 28 '18 at 18:13
codycody
8,23631326
answered Nov 28 '18 at 18:13
codycody
8,23631326
answered Nov 28 '18 at 18:13
codycody
8,23631326
answered Nov 28 '18 at 18:13
codycody
8,23631326
8,23631326
This works perfectly, thanks! Though couldn't understand what was going wrong with urllib.
– tikiabbas
Nov 28 '18 at 18:44
add a comment |
This works perfectly, thanks! Though couldn't understand what was going wrong with urllib.
– tikiabbas
Nov 28 '18 at 18:44
This works perfectly, thanks! Though couldn't understand what was going wrong with urllib.
– tikiabbas
Nov 28 '18 at 18:44
This works perfectly, thanks! Though couldn't understand what was going wrong with urllib.
– tikiabbas
Nov 28 '18 at 18:44
add a comment |
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