How to make rectangular flow chart?
0
I am facing problems with the following diagram given into image: 
How may I code for it in overleaf code? by using tikz package
begin{tikzpicture}
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};
end{tikzpicture}
tikz-pgf
edited 2 hours ago
LianTze Lim
8,69323066
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
add a comment |
0
I am facing problems with the following diagram given into image:
How may I code for it in overleaf code? by using tikz package
begin{tikzpicture}
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};
end{tikzpicture}
tikz-pgf
edited 2 hours ago
LianTze Lim
8,69323066
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
10 hours ago
ok, thank you very much.
– SANJAY GUPTA
10 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
8 hours ago
add a comment |
0
0
0
1
I am facing problems with the following diagram given into image:
How may I code for it in overleaf code? by using tikz package
begin{tikzpicture}
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};
end{tikzpicture}
tikz-pgf
edited 2 hours ago
LianTze Lim
8,69323066
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
I am facing problems with the following diagram given into image:
How may I code for it in overleaf code? by using tikz package
begin{tikzpicture}
draw[black, thick] (0,0) rectangle (3,2) node[pos=.5] {text};
end{tikzpicture}
tikz-pgf
tikz-pgf
edited 2 hours ago
LianTze Lim
8,69323066
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
edited 2 hours ago
LianTze Lim
8,69323066
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
edited 2 hours ago
LianTze Lim
8,69323066
edited 2 hours ago
LianTze Lim
8,69323066
edited 2 hours ago
LianTze Lim
8,69323066
8,69323066
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
asked 10 hours ago
SANJAY GUPTASANJAY GUPTA
232
232
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
10 hours ago
ok, thank you very much.
– SANJAY GUPTA
10 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
8 hours ago
add a comment |
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
10 hours ago
ok, thank you very much.
– SANJAY GUPTA
10 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
8 hours ago
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
10 hours ago
Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
10 hours ago
ok, thank you very much.
– SANJAY GUPTA
10 hours ago
ok, thank you very much.
– SANJAY GUPTA
10 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
8 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
8 hours ago
add a comment |
1 Answer
1
active
oldest
votes
2
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]{standalone}
usetikzlibrary{chains,positioning,calc,shapes.geometric}
begin{document}
begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}]
begin{scope}[local bounding box=upper]
begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]
node[on chain=1](n0) {Training data set};
node[frm](n1) {abc};
node[frm](n2) {abc};
node[frm](n3) {abc};
node[frm](n4) {abc};
end{scope}
node[boxed,right=3cm of n1] (n5) {abc};
node[boxed,right=3mm of n2] (n6) {abc};
node at (n0-|n6) (n7) {Testing data set};
node[boxed,right=1cm of n3] (n8) {abc};
end{scope}
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};
begin{scope}[every edge/.style={draw,-latex,thick}]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
end{scope}
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
112k5144271
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]{standalone}
usetikzlibrary{chains,positioning,calc,shapes.geometric}
begin{document}
begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}]
begin{scope}[local bounding box=upper]
begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]
node[on chain=1](n0) {Training data set};
node[frm](n1) {abc};
node[frm](n2) {abc};
node[frm](n3) {abc};
node[frm](n4) {abc};
end{scope}
node[boxed,right=3cm of n1] (n5) {abc};
node[boxed,right=3mm of n2] (n6) {abc};
node at (n0-|n6) (n7) {Testing data set};
node[boxed,right=1cm of n3] (n8) {abc};
end{scope}
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};
begin{scope}[every edge/.style={draw,-latex,thick}]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
end{scope}
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
112k5144271
add a comment |
2
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]{standalone}
usetikzlibrary{chains,positioning,calc,shapes.geometric}
begin{document}
begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}]
begin{scope}[local bounding box=upper]
begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]
node[on chain=1](n0) {Training data set};
node[frm](n1) {abc};
node[frm](n2) {abc};
node[frm](n3) {abc};
node[frm](n4) {abc};
end{scope}
node[boxed,right=3cm of n1] (n5) {abc};
node[boxed,right=3mm of n2] (n6) {abc};
node at (n0-|n6) (n7) {Testing data set};
node[boxed,right=1cm of n3] (n8) {abc};
end{scope}
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};
begin{scope}[every edge/.style={draw,-latex,thick}]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
end{scope}
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
112k5144271
add a comment |
2
2
2
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]{standalone}
usetikzlibrary{chains,positioning,calc,shapes.geometric}
begin{document}
begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}]
begin{scope}[local bounding box=upper]
begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]
node[on chain=1](n0) {Training data set};
node[frm](n1) {abc};
node[frm](n2) {abc};
node[frm](n3) {abc};
node[frm](n4) {abc};
end{scope}
node[boxed,right=3cm of n1] (n5) {abc};
node[boxed,right=3mm of n2] (n6) {abc};
node at (n0-|n6) (n7) {Testing data set};
node[boxed,right=1cm of n3] (n8) {abc};
end{scope}
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};
begin{scope}[every edge/.style={draw,-latex,thick}]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
end{scope}
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
112k5144271
This is to give you a start. For each of the features you will find many posts on this site, perhaps not yet in precisely this combination.
documentclass[border=3.14mm,tikz]{standalone}
usetikzlibrary{chains,positioning,calc,shapes.geometric}
begin{document}
begin{tikzpicture}[font=sffamily,boxed/.style={minimum width=3cm,minimum height=2cm,draw,thick}]
begin{scope}[local bounding box=upper]
begin{scope}[start chain=1 going below,every join/.style={-latex,thick},frm/.style={boxed,on chain=1,join}]
node[on chain=1](n0) {Training data set};
node[frm](n1) {abc};
node[frm](n2) {abc};
node[frm](n3) {abc};
node[frm](n4) {abc};
end{scope}
node[boxed,right=3cm of n1] (n5) {abc};
node[boxed,right=3mm of n2] (n6) {abc};
node at (n0-|n6) (n7) {Testing data set};
node[boxed,right=1cm of n3] (n8) {abc};
end{scope}
draw let p1=($(upper.east)-(upper.west)$) in
node[boxed,below=5mm of upper,minimum width=x1] (n9) {abc};
node[below=3mm of n9,
trapezium,trapezium left angle=60,trapezium right angle=120,
minimum width=3cm,minimum height=1cm,draw,thick] (n10) {abc};
begin{scope}[every edge/.style={draw,-latex,thick}]
path (n7) edge (n6) (n6.-140) edge (n9.north-|n6.-140)
(n1) edge (n5) (n5) edge (n9.north-|n5.south)
(n6.south-|n8) edge (n8) (n8) edge (n9.north-|n8.south)
(n4) edge (n9.north-|n4) (n9) edge (n10);
end{scope}
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
112k5144271
answered 9 hours ago
marmotmarmot
112k5144271
answered 9 hours ago
marmotmarmot
112k5144271
answered 9 hours ago
marmotmarmot
112k5144271
112k5144271
add a comment |
add a comment |
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Maybe some starting point: tex.stackexchange.com/questions/350513/…
– samcarter
10 hours ago
ok, thank you very much.
– SANJAY GUPTA
10 hours ago
The next time you can probably edit your previous question in place to create a new one that is an "edit" of the first one ;)
– Kpym
8 hours ago